IM NOT SMART SO PLZ HELP :) BRAINLIEST WILL BE MARKED

Step-by-step explanation:

i. 3x-1=20

or, 3x= 21

x= 7

ii. 3x+1= 22

3x= 21

x= 7

iii. 2x-5=99

2x= 104

x=52

iv. g(3)= 3+5/2= 11/2

g(0)= 0+ 5/2=5/2

g(-3)= -3+5/2 = -1/2

x+5/2= 0

so, x= -5/2

=========================================================

Explanation:

Focus solely on triangle ABD.

Let x be the length of AD. This is the unknown horizontal leg of the triangle. The vertical leg is known, so we'll say b = 16.

The hypotenuse is 20, so c = 20.

Use the pythagorean theorem to find x

a^2 + b^2 = c^2

x^2 + 16^2 = 20^2

x^2 + 256 = 400

x^2 = 400 - 256

x^2 = 144

x = sqrt(144)

x = 12

Segment AD is 12 cm long.

Answer:

root 324=18

root 441=21

root 529=23

Step-by-step explanation:

root 324 = 18

root 441 = 21

root 524 = 23

Answer:

[tex]\displaystyle \sec A=\frac{65}{63}[/tex]

Step-by-step explanation:

We are given that:

[tex]\displaystyle \csc A=\frac{65}{16}[/tex]

Where A is in QI.

And we want to find sec(A).

Recall that cosecant is the ratio of the hypotenuse to the opposite side. So, find the adjacent side using the Pythagorean Theorem:

[tex]a=\sqrt{65^2-16^2}=\sqrt{3969}=63[/tex]

So, with respect to A, our adjacent side is 63, our opposite side is 16, and our hypotenuse is 65.

Since A is in QI, all of our trigonometric ratios will be positive.

Secant is the ratio of the hypotenuse to the adjacent. Hence:

[tex]\displaystyle \sec A=\frac{65}{63}[/tex]

Answer:

Step-by-step explanation:

cosec A =60/16

hypotenuse/opposite = 60/16 =15/4 (in simplest form)

therefore hypotenuse = 15 , opposite = 4  

then adjacent =? (let be x)

using pythagoras theorem to find adjacent

opposite^2 + adjacent^2 = hypotenuse^2

4^2 + x^2 = 15^2

16 + x^2 = 225

x^2 = 225 - 16

x^2 = 209

[tex]x=\sqrt{209}[/tex]

sec A =hypotenuse/adjacent

[tex]=\frac{15}{\sqrt{209} }[/tex]

[tex]=\frac{15}{\sqrt{209} } * \frac{\sqrt{209} }{\sqrt{209} }[/tex]

=[tex]\frac{15\sqrt{209} }{209}[/tex]

Answer:

[tex]n=1.3\times 10^{12}[/tex]

Step-by-step explanation:

Given that,

The radius of a cell, r = 10⁻³ cm

The density of the cell, d = 1.1 g/cm³

The weight of the Koala, m = 6 kg = 6000 grams

The density of an object is given by:

[tex]d=\dfrac{m}{V}[/tex]

For n cells,

[tex]nd=\dfrac{m}{V}\\\\n=\dfrac{m}{dV}[/tex]

Put all the values,

[tex]n=\frac{6000}{\frac{4}{3}\cdot\pi\cdot\left(10^{-3}\right)^{3}\cdot1.1}\\\\n=1.3\times 10^{12}[/tex]

So, there are [tex]1.3\times 10^{12}[/tex]cells in the average koala.

Answer:

9x-7

Step-by-step explanation:

2(3x-5) = 6x - 10

3(x+3) = 3x + 3

= 9x-7

Answer:

Step-by-step explanation:

2*(3x-5)+3(x+3)=2*3x - 5*2 + x*3 + 3*3

                         = 6x - 10 + 3x + 9

                         = 6x + 3x - 10 + 9   {Combine like terms}

                         = 9x - 1

Answer:

B maybe

Step-by-step explanation:

Answer:

true. true. false.

Step-by-step explanation: i’m in love with the shape of u. we push and pull like magnet whatever

Step-by-step explanation:

Assuming figure to be trapezoid,

Perimeter=6+4+7+4yd

=21 yd

Area of trapezoid=((6+7)/2) x ((4)^2-(0.5)^2)

=(13/2)x(16-0.25)

=6.5 x 15.75

=102.375 Sq yards

Answer:

Option A

Step-by-step explanation:

From the graph attached,

Distance of point A of rectangle ABCD = 5 units

Distance of point E of rectangle EFGH = 5 units

Similarly, all the vertices of the rectangles ABCD and EFGH are equidistant from the y-axis.

Therefore, rectangle ABCD and rectangle EFGH may overlap each other by reflecting each other across y-axis.

Let's check by the rule of reflection,

Rule for the reflection of a point (x, y) across y-axis is given by,

(x, y) → (-x, y)

Following this rule,

A(-5, 5) → E(5, 5)

B(-3, 4) → F(3, 4)

C(-4, 1) → G(4, 1)

D(-6, 2) → H(6, 2)

Therefore, rule for the reflection is applicable in this question.

Option A will be the answer.

Answer:

[tex]\frac{3y+2}{6y^2}\\[/tex]

Step-by-step explanation:

Given the expression

[tex]\frac{3y+2}{3y}/\frac{6y^2+4y}{3y+2} \\= \frac{3y+2}{3y} * \frac{3y+2}{6y^2+4y}\\= \frac{3y+2}{3y} * \frac{3y+2}{2y(3y+2)}\\= \frac{3y+2}{3y} * \frac{1}{2y}\\= \frac{3y+2}{6y^2}\\[/tex]

Answer:

6500

Step-by-step explanation:

(3)1% of 5000 = (3)50= 150

150x 10= 1500

1500+5000=6500

Answer:

2

Step-by-step explanation:

The line the puck traveled is the hypotenuse of a right triangle.

Using the Pythagorean theorem:

Travel = sqrt( 4^2 + 30^2)

Travel = sqrt( 16 + 900)

Travel = sqrt(916)

Travel = 30.265 feet ( round the answer as needed)

Answer:

2011: 567 2012: 567*(1-.015) 2013: 567*(1-.015)*(1-.015) 2014: 567*(1-.015)567*(1-.015)*(1-.015) you see the pattern; and, if so, you can build an little equation giving you the answer

Answer:

339

Step-by-step explanation:

a = 567 (.95)¹⁰

a = 339.4838445482

Rounded

339

Answer:

121

Step-by-step explanation:

(4 - 3+2·5)²

Multiply

(4-3+10)²

Now add and subtract

(1+10)²

11²

121

Answer:

-3

Step-by-step explanation:

Step-by-step explanation:

P O R N G I R L S O N L Y

xni-jwtm-twb

Answer:

8

General Formulas and Concepts:

Pre-Algebra

Order of Operations: BPEMDAS

Step-by-step explanation:

Step 1: Define

Identify

6t - 20 - 32u

t = 6

u = 1/4

Step 2: Evaluate

Answer:

8

Step-by-step explanation:

Given

6t - 20 - 32u ( substitute the given values into the expression )

= 6(6) - 20 - (32 × [tex]\frac{1}{4}[/tex] )

= 36 - 20 - 8

= 16 - 8

= 8

Answer:

[tex]y=\frac{15}{18} x+13[/tex]

Step-by-step explanation:

Use a graphing calculator,

hope it helps

Answer:

3.

Step-by-step explanation:

R = √[(2)^2 + (√5)^2]

= √(4 + 5)

= √9

= 3.

Answer:

3

Step-by-step explanation:

[tex]R =\sqrt{a^{2}+b^{2}}\\\\= \sqrt{2^{2}+(\sqrt{5})^{2}}\\\\= \sqrt{4+5}\\\\=\sqrt{9}\\\\= \sqrt{3*3}\\\\= 3[/tex]

Hint:  (√5)² = [tex]\sqrt{5}*\sqrt{5} = \sqrt{5*5}=5[/tex]

Answer:

-9≤y≤5

Step-by-step explanation:

The range is the values that the output can take

The smallest value that the output takes is -9 and the largest value is 5

-9≤y≤5

Answer:

Option C is the correct one

Step-by-step explanation:

given equation of a line is y=-1/3x+1

comparing the given equation with y=mx+c

therefore,slope(m)=-1/3

then,

slope of line perpendicular to the line having slope -1/3 is (m2)=3

Equation of line having slope (m2)=3 and passing through point (2,7) is

y-y1=m2*(x-x1)

or,y-7=3(x-2)

or,y-7=3x-6

or,3x-y-6+7=0

or,3x-y+1=0

or,3x-y=-1 is the req.equation.

Answer:

x > -2.5

Step-by-step explanation:

1) 5.1 (3 + 2.2x) > -14.25 - 6 (1.7x + 4)

2) 15.3 + 11.22x > -14.25 - 10.2x - 24

3) 15.3 + 11.22x > -38.25 - 10.2x

4) 11.22x + 10.2x > -38.25 - 15.3

5) 21.42x > -53.55

6) x > -2.5

Alternate forms

x > -5/2x or x > -2 1/2

Answer:

second option is correct (for question no 20)

Step-by-step explanation:

coordinate points are:

(3,1) = (x1,y1)

(5,9) = (x2,y2)

slope (m) = y2-y1/x2-x1

=9-1/5-3

=8/2

=4

Now using slope intercept form

y=mx + b

y=4x + b

since the line passes through the point (3,1) it satisfies the equation

y=4x + b

1=4*3 + b

1-12 = b

-11 = b

substituting the value of b in equation

y=4x + b

y=4x +(-11)

y=4x - 11

Step-by-step explanation:

the answer is in the above image

but I do not get the meaning of Dy