In 8,574.1 which digit is in the tenths place?

Answer:

no soultion

Step-by-step explanation:

did on paper

Answer:

exactly one solution

Step-by-step explanation:

got it right on khan lol

1)

=(3x)² - 2 × 3x × 5+5²

=3²x²2 × 3x × 5+5²

=9x² -2 × 3x × 5 + 5²

=9x² -2 x 3x x 5 + 25

=9x²30x + 25

Answer:

1/3

Step-by-step explanation:

the formula of common ratio is given as

[tex]r = \frac{a2}{a1} [/tex]

a1= 27 ,a2=9

r= 9/27

r= 1/3

Answer:

2

Step-by-step explanation:

first multiply everything by 6 to get rid of the fractions

then we get 5m-4 -6 = 24m -9m -30

simplify the equation 5m-10=15m-30

subtract 5m from both sides and add 30 to both sides 10m=20

divide by 10, m=2

Answer:

She didn't change the direction of the sign

Step-by-step explanation:

When dividing both sides by a negative number in an inequality, you must change the sign.

15:-

[tex]\\ \qquad\quad\sf\longmapsto \dfrac{x^5y^6}{xy^2}[/tex]

[tex]\\ \qquad\quad\sf\longmapsto x^{5-1}y^{6-2}[/tex]

[tex]\\ \qquad\quad\sf\longmapsto x^4y^4[/tex]

16:-

[tex]\\ \qquad\quad\sf\longmapsto \dfrac{x^2y^5}{xy^4}[/tex]

[tex]\\ \qquad\quad\sf\longmapsto x^{2-1}y^{5-4}[/tex]

[tex]\\ \qquad\quad\sf\longmapsto xy[/tex]

17;-

[tex]\\ \qquad\quad\sf\longmapsto \left(\dfrac{4x^5y}{16xy^4}\right)^3[/tex]

[tex]\\ \qquad\quad\sf\longmapsto (4^{1-2}x^{5-1}y^{1-4})^3[/tex]

[tex]\\ \qquad\quad\sf\longmapsto (4^{-1}x^4y^{-3})^3[/tex]

[tex]\\ \qquad\quad\sf\longmapsto 4^{-3}x^{12}y^{-9}[/tex]

18:-

[tex]\\ \qquad\quad\sf\longmapsto \left(\dfrac{5x^3y}{20xy^5}\right)^4[/tex]

[tex]\\ \qquad\quad\sf\longmapsto (4^{-1}x^{2}y^{-4})^4[/tex]

[tex]\\ \qquad\quad\sf\longmapsto 4^{-4}x^8y^{-16}[/tex]

19:-

[tex]\\ \qquad\quad\sf\longmapsto y^{-7}[/tex]

[tex]\\ \qquad\quad\sf\longmapsto \dfrac{1}{y^7}[/tex]

20:-

[tex]\\ \qquad\quad\sf\longmapsto 7^{-2}[/tex]

[tex]\\ \qquad\quad\sf\longmapsto \dfrac{1}{7^2}[/tex]

[tex]\\ \qquad\quad\sf\longmapsto \dfrac{1}{49}[/tex]

21:-

[tex]\\ \qquad\quad\sf\longmapsto \dfrac{1}{x^{-5}}[/tex]

[tex]\\ \qquad\quad\sf\longmapsto x^5[/tex]

22:-

[tex]\\ \qquad\quad\sf\longmapsto \dfrac{1}{2^{-4}}[/tex]

[tex]\\ \qquad\quad\sf\longmapsto 2^4[/tex]

[tex]\\ \qquad\quad\sf\longmapsto 16[/tex]

23:-

[tex]\\ \qquad\quad\sf\longmapsto x^5\times x^{-1}[/tex]

[tex]\\ \qquad\quad\sf\longmapsto x^{5-1}[/tex]

[tex]\\ \qquad\quad\sf\longmapsto x^4[/tex]

24:-.

[tex]\\ \qquad\quad\sf\longmapsto x^{-6}[/tex]

[tex]\\ \qquad\quad\sf\longmapsto \dfrac{1}{x^6}[/tex]

25:-

[tex]\\ \qquad\quad\sf\longmapsto x^9(x^{-7})[/tex]

[tex]\\ \qquad\quad\sf\longmapsto x^{9-7}[/tex]

[tex]\\ \qquad\quad\sf\longmapsto x^2[/tex]

Answer:

0.0300300030000...

Step-by-step explanation:

An irrational number has endless non-repeating digits to the right of the decimal point. They can be written as decimals, but not as fractions.

1632 can be written as 3264/2

0.25 can be written as 1/4

0 could be written as 0/0

but 0.0300300030000 cannot be written as a fraction, and it satisfies the condition of an irrational number having endless non-repeating digits to the right of the decimal point.

Answer:

cause shes smart?

Step-by-step explanation:

Answer:

[tex] \frac{5}{8} k = 25 \\ \frac{5k}{8} = 25 \\ 5k = 25 \times 8 \\ 5k = 200 \\ k = \frac{200}{5} \\ k = 40[/tex]

I hope it helped U

stay safe stay happy

Answer:

k=1/40

Step-by-step explanation:

multiple both sides by 8k

5= 25×8k

simplify 25×8k to 200k

5=200k

divide both sides by 200

5/200=k

simplify 5/200 to 1/40

1/40= k

switch sides

k=1/40

[tex] \dashrightarrow \sf \dfrac{1}{3}[3 + 7 \times 3][/tex]

[tex] \\ \\ [/tex]

write the equation

[tex] \\ \\ [/tex]

[tex] \dashrightarrow \sf \dfrac{1}{3}[3 +21][/tex]

[tex] \\ \\ [/tex]

[tex] \dashrightarrow \sf \dfrac{1}{3} \times 24[/tex]

[tex] \\ \\ [/tex]

[tex] \dashrightarrow \sf \dfrac{24}{3}[/tex]

[tex] \\ \\ [/tex]

[tex] \cancel{ \dashrightarrow \sf \dfrac{24}{3}}[/tex]

[tex] \\ \\ [/tex]

[tex]\dashrightarrow \sf8[/tex]

Answer :- 8

Answer:

Step-by-step explanation:

By proportion it takes

3/5 * 10

= 6 days.

Answer:

81[tex]y^{8}[/tex][tex]z^{4}[/tex]

Step-by-step explanation:

Step-by-step explanation:

hopefully it makes sense and is visible

:)

Step-by-step explanation:

ABCD is a quadrilateral triangle,where AD=BC and <DAB =<CBA.

In ∆ABD and ∆BAC

•AD=BC. (given)

•<DAB=<CBA (given)

•AB=BA. (common side)

Therefore, ∆ABD ≌ ΔBAC. {SAS congruence rule}

Answer:

f(-3)=g(-4)

Step-by-step explanation:

both functions intersect at point (-3;-4)..

Answer:

A

Step-by-step explanation:

e 2021

Answer:

...

Step-by-step explanation:

Answer:

answer) the change is $7.90

Answer:

x = -3

Step-by-step explanation:

5(x-2)+3x-4 = -38

=> 5x-10+3x-4 = -38

=> 5x+3x-10-4 = -38

=> 8x-14 = -38

=> 8x = -38+14

=> 8x = -24

=> x = -24/8

=> x = -3

Answer:

10

Step-by-step explanation:

f(x)=x

subtitute 10 in the place of x:

f(10)=10

Answer:

(G)77

Step-by-step explanation:

44+11=55.

55+22=77.

77+33=110.

110+44=154.

154+55=209.

Answer:gggggggggg

Step-by-step explanation:

gggggggggggggggggggggggggggggggggggggg

Answer:

-16

Step-by-step explanation:

x = -3 is less than -2, so you should use the first equation 5x-1

thus, 5(-3)-1 = -16

Answer:

12. (2, -3)

13. AH: +15   B: +721   CB: 0   N: +462   WB: -1200

Step-by-step explanation:

12.

When a point is reflected over the x-axis, the y coordinate becomes opposite because you are changing its y value, not its x-value. So (-2, 3) reflecting over the x-axis becomes (-2, -3).

The same concept goes for reflecting over the y-axis. The x coordinate becomes opposite because you are changing its x value. (It's like folding the graph in half and seeing where the point matches up with. So (-2, -3) reflecting over the y-axis becomes (2, -3).

13.

All you have to do is list each artifact and where they were found in relation the sea level (0). If it is above sea level then it is a positive number, below sea level is a negative number.

Arrow head: +15 (since it is 15 feet above sea level)

Woven basket: -1200 (since it is 1200 feet below sea level)

Answer:

Parallel lines

Step-by-step explanation:

Answer:

31000 or 31 × 10^3

6.2 (5× 10^3)

Answer:

When x takes the value of 4, the expression takes the value of 9.

Step-by-step explanation:

We are given that the expression:

[tex]\displaystyle ax^2 + bx + c[/tex]

Evaluates to 0, 1, and 4 when x = 1, 2, and 3, respectively.

And we want to determine the value of the expression when x = 4.

The expression evaluates to 0 when x = 1. In other words:

[tex]\displaystyle a(1)^2 + b(1) +c = a + b + c = 0[/tex]

We can complete the same for the other two:

[tex]\displaystyle a(2)^2 + b(2) + c = 4a + 2b + c = 1\text{ and } \\ \\ a(3)^2 + b(3) + c = 9a + 3b + c = 4[/tex]

This yields a triple system of equations:

[tex]\displaystyle \left\{ \begin{array}{l} a + b + c = 0 \\ 4a + 2b + c = 1 \\ 9a + 3b + c = 4 \end{array}[/tex]

Solve. We can cancel out the c by multiplying the first equation by negative one and adding it to both the second and the third:

[tex]\displaystyle \begin{aligned} (4a + 2b + c) + (-a - b -c ) &= (-0) + (1) \\ \\ 3a +b &= 1\end{aligned}[/tex]

And:

[tex]\displaystyle \begin{aligned} (9a + 3b + c) + (-a - b -c) &= (-0) + (4) \\ \\ 8a + 2b &= 4\end{aligned}[/tex]

Solve for the two resulting equations. We can multiply the first by negative two and add it to the second:

[tex]\displaystyle \begin{aligned}(8a + 2b) + (-6a -2b) &= (4) + (-2) \\ \\ 2a &= 2 \end{aligned}[/tex]

Hence:

[tex]a = 1[/tex]

Solve for b:

[tex]\displaystyle \begin{aligned} 3a + b &= 1 \\ b&= 1 - 3a \\ b&= 1 - 3(1) \\ b &= -2\end{aligned}[/tex]

And finally, solve for c:

[tex]\displaystyle \begin{aligned} a + b + c &= 0 \\ (1) + (-2) + c &= 0 \\ c &= 1\end{aligned}[/tex]

Hence, our expression is:

[tex]\displaystyle x^2 -2x + 1[/tex]

Then when x = 4:

[tex]\displaystyle (4)^2 - 2(4) + 1= 9[/tex]

In conclusion, when x = 4, the resulting value is 9.

Answer:

[tex] \displaystyle - 3 \sqrt{5n} + 4 \sqrt{15} n[/tex]

Step-by-step explanation:

we would like to simplify the following expression:

[tex] \displaystyle \sqrt{15} ( - \sqrt{3n} + 4n)[/tex]

recall distribution property thus:

[tex] \displaystyle - \sqrt{3n} \sqrt{15} + 4n \sqrt{15} [/tex]

remember that,

so assign variables:

simplify Multiplication:

[tex] \displaystyle - \sqrt{45n} + 4 \sqrt{15} n[/tex]

rewrite 45 as 9×5:

[tex] \displaystyle - \sqrt{9 \times 5n} + 4 \sqrt{15} n[/tex]

utilize the formula:

[tex] \displaystyle - \sqrt{9 } \sqrt{5n} + 4 \sqrt{15} n[/tex]

simplify square:

[tex] \displaystyle \boxed{- 3 \sqrt{5n} + 4 \sqrt{15} n}[/tex]

and we're done!

[tex]\boxed{\sf a(b+c)=ab+bc}[/tex]

[tex]\boxed{\sf \sqrt{p}\sqrt{q}=\sqrt{pq}}[/tex]

[tex]\\ \rm\longmapsto \sqrt{15}(-\sqrt{3n}+4n)[/tex]

[tex]\\ \rm\longmapsto -\sqrt{15}\sqrt{3n}+4\sqrt{15}n[/tex]

[tex]\\ \rm\longmapsto -\sqrt{3(15)n}+4\sqrt{15}n[/tex]

[tex]\\ \rm\longmapsto -\sqrt{3(3)(5)n}+4\sqrt{15}n[/tex]

[tex]\\ \rm\longmapsto -3\sqrt{5}n+4\sqrt{15n}[/tex]

Or we can break 15n

[tex]\\ \rm\longmapsto -3\sqrt{5}n+4\sqrt{3(5)n}[/tex]

[tex]\\ \rm\longmapsto -3\sqrt{5}n+4\sqrt{3}\sqrt{5n}[/tex]