In a binomial experiment :________

a. the probability does not change from trial to trial
b. the probability does change from trial to trial
c. the probability could change from trial to trial, depending on the situation under consideration
d. None of these alternatives is correct.

Answer:

d. higher blood cholesterol causes more severe heart attacks.

Step-by-step explanation:

Two tailed tests are a method for hypothesis testing when data is distributed on the two sides. P value is determined to identify whether the hypothesis is true or false. When rs is 0.89 between blood cholesterols and severity of heart attacks then these is significant relation between them.

Answer:

A. Whole numbers less than or equal to 100

Step-by-step explanation:

The domain is the set of x numbers that can be plugged in to a certain equation.

Since the capacity of this movie theater is 100, x can be between 0 and 100, inclusive.

Answer choice A makes sense because whole numbers are definitionally positive integers and this choice caps out at 100.

Answer:

Letter B, C and E are correct

Step-by-step explanation:

hope this helps

tell if you got it right

Answer:

Letter B, C and E are correct

Step-by-step explanation:

hope this helps

Step-by-step explanation:

-3,4 Is the answer Is it right or wrong if it is true plz mark me as brainliest

Answer:

Ano is correct

Step-by-step explanation:

-3,4is theoretically correct answer

Answer:

false

Step-by-step explanation:

Answer:

[tex] {x}^{2} + 26x = 11 \\ x = 0.4 \: and \: - 26.4[/tex]

Answer:

What do you need help with?

Step-by-step explanation:

You didn't put a question

Answer:

a) correct

b) 70 degrees

Step-by-step explanation:

since in the triangle BXC the sides BX and XC have the same length, they must also have the same angles with the baseline BC.

so, we know, XBC = 55 degrees.

and therefore BCX = 55 degrees.

the sum of all angles in a triangle is always 180 degrees.

so,

BXC = 180 - 55 - 55 = 70 degrees

Answer:

C. she is not beautiful and not clever.

Step-by-step explanation:

A. she is beautiful but not clever. B. she is beautiful and clever

C. she is not beautiful and not clever.

D. she is beautiful or not clever.

p: she is beautiful

q :she is clever

~p^ (~q) in verbal form

~p = she is not beautiful

~q = she is not clever

~p^ (~q) = she is not beautiful and not clever.

C. she is not beautiful and not clever.

Answer: The height of the triangle is 23.3 cm

Step-by-step explanation:

To calculate the area of a triangle, we use the equation:

[tex]Area=\frac{1}{2}\times b\times h[/tex]

where,

b = base of the triangle = 3 cm

h = height of the triangle = ?

Area of the triangle = [tex]35cm^2[/tex]

Putting values in above equation, we get:

[tex]35cm^2=\frac{1}{2}\times 3cm\times h\\\\h=\frac{2\times 35}{1\times 3}=23.3cm[/tex]

Hence, the height of the triangle is 23.3 cm

Answer:

0.837

Step-by-step explanation:

3850*4.65%=179.025

150/179.025=0.837

0.837

Aver si le entiendes bro

Answer:

C

Step-by-step explanation:

I think you have to call a = 14/32 and b = 7/4

3a = 3 * 14/32 = 42/32

b = 1 3/4 = (4 + 3)/4 = 7/4

42/32 // 7/4                        Invert and multiply

42/32 * 4/7                         Cancel 4 into 32 and 7 into 42

6/8 = 3/4

I make the answer C

Answer:

So the square seems to multiply the first number by three and then divide it by the second number.

So,

14/32 * 3

=

42/32

Simplify

21/16

And now for division, we flip the diveding fraction and multiply.

21/16 * 4/7

Which is after some fraction simplifing:

3/4

Answer:

[tex]x = 97[/tex]

Step-by-step explanation:

Given

[tex]t = 20[/tex] --- time (years)

[tex]A =1000[/tex] --- amount

[tex]r = 10\%[/tex] --- rate of interest

Required

The last 10 payments (x)

First, calculate the end of year 1 payment

[tex]y_1(end) = 10\% * 1000 * 150\%[/tex]

[tex]y_1(end) = 150[/tex]

Amount at end of year 1

[tex]A_1=A - y_1(end) - r * A[/tex]

[tex]A_1=1000 - (150 - 10\% * 1000)[/tex]

[tex]A_1 =1000 - (150- 100)[/tex]

[tex]A_1 =950[/tex]

Rewrite as:

[tex]A_1 = 0.95 * 1000^1[/tex]

Next, calculate the end of year 1 payment

[tex]y_2(end) = 10\% * 950 * 150\%[/tex]

[tex]y_2(end) = 142.5[/tex]

Amount at end of year 2

[tex]A_2=A_1 - (y_2(end) - r * A_1)[/tex]

[tex]A_2=950 - (142.5 - 10\%*950)[/tex]

[tex]A_2 = 902.5[/tex]

Rewrite as:

[tex]A_2 = 0.95 * 1000^2[/tex]

We have been able to create a pattern:

[tex]A_1 = 1000 * 0.95^1 = 950[/tex]

[tex]A_2 = 1000 * 0.95^2 = 902.5[/tex]

So, the payment till the end of the 10th year is:

[tex]A_{10} = 1000*0.95^{10}[/tex]

[tex]A_{10} = 598.74[/tex]

To calculate X (the last 10 payments), we make use of the following geometric series:

[tex]Amount = \sum\limits^{9}_{n=0} x * (1 + r)^n[/tex]

[tex]Amount = \sum\limits^{9}_{n=0} x * (1 + 10\%)^n[/tex]

[tex]Amount = \sum\limits^{9}_{n=0} x * (1 + 0.10)^n[/tex]

[tex]Amount = \sum\limits^{9}_{n=0} x * (1.10)^n[/tex]

The amount to be paid is:

[tex]Amount = A_{10}*(1 + r)^{10}[/tex] --- i.e. amount at the end of the 10th year * rate of 10 years

[tex]Amount = 1000 * 0.95^{10} * (1+r)^{10}[/tex]

So, we have:

[tex]Amount = \sum\limits^{9}_{n=0} x * (1.10)^n[/tex]

[tex]\sum\limits^{9}_{n=0} x * (1.10)^n = 1000 * 0.95^{10} * (1+r)^{10}[/tex]

[tex]\sum\limits^{9}_{n=0} x * (1.10)^n = 1000 * 0.95^{10} * (1+10\%)^{10}[/tex]

[tex]\sum\limits^{9}_{n=0} x * (1.10)^n = 1000 * 0.95^{10} * (1+0.10)^{10}[/tex]

[tex]\sum\limits^{9}_{n=0} x * (1.10)^n = 1000 * 0.95^{10} * (1.10)^{10}[/tex]

The geometric sum can be rewritten using the following formula:

[tex]S_n = \sum\limits^{9}_{n=0} x * (1.10)^n[/tex]

[tex]S_n =\frac{a(r^n - 1)}{r -1}[/tex]

In this case:

[tex]a = x[/tex]

[tex]r = 1.10[/tex]

[tex]n =10[/tex]

So, we have:

[tex]\frac{x(r^{10} - 1)}{r -1} = \sum\limits^{9}_{n=0} x * (1.10)^n[/tex]

[tex]\frac{x((1.10)^{10} - 1)}{1.10 -1} = \sum\limits^{9}_{n=0} x * (1.10)^n[/tex]

[tex]\frac{x((1.10)^{10} - 1)}{0.10} = \sum\limits^{9}_{n=0} x * (1.10)^n[/tex]

[tex]x * \frac{1.10^{10} - 1}{0.10} = \sum\limits^{9}_{n=0} x * (1.10)^n[/tex]

So, the equation becomes:

[tex]x * \frac{1.10^{10} - 1}{0.10} = 1000 * 0.95^{10} * (1.10)^{10}[/tex]

Solve for x

[tex]x = \frac{1000 * 0.95^{10} * 1.10^{10} * 0.10}{1.10^{10} - 1}[/tex]

[tex]x = 97.44[/tex]

Approximate

[tex]x = 97[/tex]

Hi there!  

»»————-　★　————-««

I believe your answer is:  

[tex]3v + 8 \geq 22[/tex]

»»————-　★　————-««  

Here’s why:

⸻⸻⸻⸻

[tex]\boxed{\text{Breaking down the phrase...}}\\\\\text{Three times a number, v, added to eight is greater than or equal to twenty-two. }\\------------------\\\rightarrow \text{"Three times a number, v..."} - 3v \text{ This expresses the product of '3' and 'v'.}\\\\\rightarrow \text{"added to eight..."} - + 8 \text{ The product gets added to eight.}\\\\--------------\\\text{The First Part Is:}}\\\\3v + 8\\---------------\\\rightarrow \text{is greater than or equal to twenty-two. } - \geq 22[/tex]

[tex]\text{The value of '3v + 8' is greater than or equal to 22.}\\---------------\\\text{\underline{Putting it together, we would have:}}\\\\\boxed{3v + 8 \geq 22}}[/tex]

⸻⸻⸻⸻

»»————-　★　————-««  

Hope this helps you. I apologize if it’s incorrect.  

(a) By the fundamental theorem of calculus,

v(t) = v(0) + ∫₀ᵗ a(u) du

The particle starts at rest, so v(0) = 0. Computing the integral gives

v(t) = [2/3 u ³ + 2u ²]₀ᵗ = 2/3 t ³ + 2t ²

(b) Use the FTC again, but this time you want the distance, which means you need to integrate the speed of the particle, i.e. the absolute value of v(t). Fortunately, for t ≥ 0, we have v(t) ≥ 0 and |v(t) | = v(t), so speed is governed by the same function. Taking the starting point to be the origin, after 8 seconds the particle travels a distance of

∫₀⁸ v(u) du = ∫₀⁸ (2/3 u ³ + 2u ²) du = [1/6 u ⁴ + 2/3 u ³]₀⁸ = 1024

9514 1404 393

Answer:

  4.5765%

Step-by-step explanation:

Apparently, you have to figure out how long it would take to accumulate a balance of $10,457.65 with interest compounded, then use that time period to compute the equivalent simple interest rate. The relevant formulas are ...

  A = P(1 +r/n)^(nt) . . . . amount of P at rate r compounded n times per year for t years

  A = P(1 +rt) . . . . amount of P at rate r simple interest for t years

We need to use the first formula to find t, then use the second formula to find r. In both cases A=10457.65 and P=10000. Quarterly compounding means n=4. The interest rate is r=0.045 for the first formula.

Looking for t:

  A/P = (1 +r/n)^(nt) . . . . . . . . . . divide by P

  log(A/P) = nt·log(1 +r/n) . . . . . take logs

  t = log(A/P)/(n·log(1 +r/n)) . . . divide by the coefficient of t

Filling in the given values, we find t to be ...

  t = log(10457.65/10000)/(4·log(1 +0.045/4)) = 0.999998 ≈ 1.0

The compound interest is applied for 1 year (t=1), so now we can find r using the second formula.

  A = P(1 +rt)

  A/P -1 = rt

Filling in the known values, we have ...

  1.045765 -1 = r = 0.045765 = 4.5765%

The equivalent simple interest rate on the deposit is 4.5765%.

Answer:

39 feet

Step-by-step explanation:

p = 15 + 8 + 10 + 6

p = 39

39 feet

Answer:

1. The first set of number is

1,2,3,4,5

Mean= 1+2+3+4+5/5

= 15/5

= 3

Median= 3

Mode= N/A

The next set of numbers is

2,3,4,5,6,6

Mean= 2+3+4+5+6+6/6

= 26/6

= 4.3

Median=4+5/2

= 9/2

= 4.5

Mode= 6

The next set of number is

6,7,5,4,5,6,2,5

Mean= 2+4+5+5+5+6+6+7/8

= 40/8

= 5

Median= 5+5/2

= 10/2

= 5

Mode= 5

Answer:

b. S = AUB

Step-by-step explanation:

Since the coins are tossed  3 times and each coin has head, H and tail, T(2 sides), the sample space is S = 2 × 2 × 2 = 2³ = 8

All the possible outcomes are HTT, HHT, HHH, THH, TTH, HTH,THT and TTT

Since S denote the sample space

S = {HTT, HHT, HHH, THH, TTH, HTH,THT, TTT}

Since A denote the event that at least 1 of the coins comes to rest with its heads side upwards, the possible outcomes are HTT, HHT, HHH, THH, TTH, HTH and THT

So, A = {HTT, HHT, HHH, THH, TTH, HTH,THT}

Also B denote the event that none of the coins comes to rest with its heads side upwards, that is no heads. The possible outcome is TTT

So, B = {TTT}

Since S denote the sample space

S = {HTT, HHT, HHH, THH, TTH, HTH,THT, TTT}

So, A ∪ B = {HTT, HHT, HHH, THH, TTH, HTH,THT} ∪  {TTT} = {HTT, HHT, HHH, THH, TTH, HTH,THT, TTT} = S

So, S = A ∪ B

So, S = A ∪ B does not denote an abuse of notation.

The answer is b.

Answer:

5/8

Step-by-step explanation: Keep, Change and Flip so you do 1/2 times 5/4

Answer:

5/8

Step-by-step explanation:

To divide by a fraction. multiply by the reciprocal of that fraction.

1/2 * 5/4

Multiply the fractions across.

so 1*5=5, then do 2*4= 8

5/8

Answer:

6

Step-by-step explanation:

Answer:

6

Step-by-step explanation:

Vertices are the vertex points. there are 4 vertices at the bottom and 2 vertices at the top which makes 6.

Hope this helps

Answer:

1/8 Of the animals are rabbits.

Step-by-step explanation:

3/8 Cats + 4/8 Dogs = 7/8

1/8 Is all you have room left for so 1/8 would be rabbits.

Answer:

1/8.

Step-by-step explanation:

Fraction of rabbits = 1 - (3/7 + 4/8)

= 1 - 7/8

= 8/8 - 7/8

= 1/8.

Answer:

13inches

Step-by-step explanation:

hope it works boy

answer:

thanks for the points luv

Answer:

The modulus of z is [tex]\sqrt{10}[/tex]

Step-by-step explanation:

Complex number:

A complex number, given by:

[tex]z = x + iy[/tex]

Can be represented also as a point (x,y).

The modulus is given by:

[tex]|z| = \sqrt{x^2 + y^2}[/tex]

Point z is at (negative 3, 1). What is the modulus of z?

[tex]x = -3, y = 1[/tex]. So

[tex]|z| = \sqrt{x^2 + y^2} = \sqrt{(-3)^2+1^2} = \sqrt{10}[/tex]

The modulus of z is [tex]\sqrt{10}[/tex]

Answer:

-2

Step-by-step explanation:

if this is the right problem it is -2

Answer:

Area of square = Side²

Step-by-step explanation:

The area of a 2-D region, form, or flattened lamina in the planes is the quantity that represents its extent. On the 2-D surface or 3-D object, surface is its counterpart. A shape's area can be calculated by comparing it to squares of a specific size.

Area of square = Side²

Answer:

1.tenisha

2.1\5+1\3=1\×

3.n-12=1\3(n+2)

4.500×=120