Answer:
Explanation:
We know there are 21 students in all, so that should be the denominator in this answer.
Then, to find the numerator, we need to find the number of students that play basketball and the number of students that play baseball, assuming that none of them play both sports. Just add those two numbers to get the numerator, and then put it on top of the 21.
You either typed this question incorrectly, or there is a mistake, because there are more kids that play basketball or baseball than there are students in the class.
[tex]3x + 2y + 2z = 19\\3x + y + z = 14\\[/tex]
If the equations above are true, which of the following is the value of y + z?
(A.) -5
(B.) -4
(C.) 0
(D.) 4
(E.) 5
Answer:
The answer is E
Explanation:
Before we find the value of 5, let's find x by using the elimination process for the two given equation.
2(3x + y + z = 14) → 6x + 2y + 2z = 28
3x + 2y + 2z = 19
-6x + 2y + 2z = 28
-3x = -9
x = 3
Now plug in 3 into both of the given equations, which will give you your new equation, then subtract them:
3(3) + 2y + 2z = 19 → 9 + 2y + 2z = 19
3(3) + y + z = 14 → - 9 + y + z = 14
Our answer is: y + z = 5
Our value is 5
Optional: If you want to make sure it's 5, plug-in any random numbers for y and z that equals 5. For example: 3 + 2, 1 + 4, 5 + 0, 6 + (-1), etc...
Once you choose the numbers you can plug them into the two new given equations. For me, I decided to let y = 1 and z = 4:
9 + 2(1) + 2(4) = 19 9 + (1) + (4) = 14
9 + 2 + 8 = 19 9 + 1 + 4 = 14
19 = 19 14 = 14
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