The 90% confidence interval for the proportion of district residents in favor of starting the school day 15 minutes later is (0.392, 0.548). The true proportion is estimated to lie within this interval with 90% confidence.
To calculate the 90% confidence interval for the true proportion of district residents who are in favor of starting the school day 15 minutes later, we can use the following formula:
CI = p ± z*(√(p*(1-p)/n))
where:
CI: confidence interval
p: proportion of residents in favor of starting the day later
z: z- score based on the confidence level (90% in this case)
n: sample size
First, we need to calculate the sample proportion:
p = 94/200 = 0.47
Next, we need to find the z- score corresponding to the 90% confidence level. Since we want a two-tailed test, we need to find the z- score that cuts off 5% of the area in each tail of the standard normal distribution. Using a z-table, we find that the z- score is 1.645.
Substituting the values into the formula, we get:
CI = 0.47 ± 1.645*(√(0.47*(1-0.47)/200))
Simplifying this expression gives:
CI = 0.47 ± 0.078
Therefore, the 90% confidence interval for the true proportion of district residents who are in favor of starting the school day 15 minutes later is (0.392, 0.548). We can be 90% confident that the true proportion lies within this interval.
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-4
-2
Intro
ty
8
4
-4
-8
N
X
Find the indicated function values.
f(-4)=
f(0) =
f(1) =
O
(>
De
Answer: 1
Step-by-step explanation:
because it not zero and not 4
Roll a fair die three times. What is the probability that it is 1 or 2 on the first roll, 3 or 4 on the second roll, or 5 or 6 on the third roll?
The probability that it is 1 or 2 on the first roll, 3 or 4 on the second roll, or 5 or 6 on the third roll when a fair die is rolled three times is 1/4.
Probability is the study of random events. It is a measure of the likelihood of an event occurring. Probability can be expressed as a decimal, a fraction, or a percentage. There are two types of probability - empirical probability and theoretical probability.
Empirical probability is calculated by conducting experiments or collecting data. It is calculated using the following formula:
Empirical probability = Number of favourable outcomes/Total number of outcomes
Theoretical probability is calculated using probability formulas. It is calculated using the following formula:
Theoretical probability = Number of favourable outcomes/Total number of possible outcomes
In the given problem, a fair die is rolled three times. We need to find the probability that it is 1 or 2 on the first roll, 3 or 4 on the second roll, or 5 or 6 on the third roll. There are 2 favourable outcomes for the first roll, 2 favourable outcomes for the second roll, and 2 favourable outcomes for the third roll.
Total number of outcomes = 6×6×6 = 216
Number of favourable outcomes = 2×2×2 = 8
Probability = Number of favourable outcomes/Total number of outcomes
Probability = 8/216
Probability = 1/27
Therefore, the probability that it is 1 or 2 on the first roll, 3 or 4 on the second roll, or 5 or 6 on the third roll when a fair die is rolled three times is 1/4.
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Keilantra and Samantha work at a dry cleaners ironing shirts. Keilantra can iron 30 shirts per hour, and Samantha can iron 15 shirts per hour. Keilantra and Samantha worked a combined 11 hours and ironed 240 shirts. Graphically solve a system of equations in order to determine the number of hours Keilantra worked, x, and the number hours Samantha worked, y.
Answer: Kelinatra (x) worked 5 hours and Samantha (y) worked 6 hours
Step-by-step explanation:
We will use the variables x and y the question provides. We know the time worked by each person added together will equal the combined total time. We can write an equation to show this using addition.
x + y = 11 hours
Next, we know that Keilantra ironed 30 per hour, Samantha ironed 15 per hour and that they ironed 240 shirts. We can write another equation to represent this using addition and multiplication.
30x + 15y = 240
Next, we will graph these two equations. See attached. The solution is the point of intersection written as (x, y). This is (5, 6) meaning that Kelinatra (x) worked 5 hours and Samantha (y) worked 6 hours.
Using the inverse transform method for discrete distribution, define a process for generating random variates from a binomial distribution with N 6 and p 0.4. (sixth decimal place.)
The another random variate from a binomial distribution with n=6 and p=0.4 has been generated as X=3.
The process of generating random variates from a binomial distribution using the inverse transform method for discrete distribution is done as follows:Step 1: Determine the probability mass function (pmf) of the binomial distribution with parameters n and p. For example, for a binomial distribution with n = 6 and p = 0.4, the pmf is given by:P(X=k) = (6 choose k)(0.4)^k(1-0.4)^(6-k), where k=0,1,2,3,4,5,6Step 2: Calculate the cumulative distribution function (CDF) of the binomial distribution by summing the pmf up to each value of k. The CDF is given by:F(k) = P(X ≤ k) = ΣP(X=i) for i=0 to k, where k=0,1,2,3,4,5,6Step 3: Generate a uniform random variate, U, between 0 and 1. For example, U=0.23456.Step 4: Find the smallest value of k such that F(k) ≥ U. This value of k is the random variate X. For example, if U=0.23456, then F(0)=0.10737, F(1)=0.38223, and F(2)=0.74304. Since F(1) is the smallest value of F(k) that is greater than or equal to U, X=1. Therefore, a random variate from a binomial distribution with n=6 and p=0.4 has been generated as X=1.To find another random variate from the same distribution, repeat steps 3 and 4. For example, U=0.987654, F(0)=0.10737, F(1)=0.38223, F(2)=0.74304, F(3)=0.91892, F(4)=0.98544, and F(5)=0.99856. Since F(3) is the smallest value of F(k) that is greater than or equal to U, X=3. Therefore, another random variate from a binomial distribution with n=6 and p=0.4 has been generated as X=3.
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two people standing at different locations are looking at a tall building. person a angle of elevation to the building is 35 degrees. person b angle of elevation is 77 degrees. the building is 8 miles away from person b. how far away is person a from the building?
Therefore, Person A is approximately 95.17 miles away from the building.
To find out how far person A is from the building, we'll need to use trigonometry. The diagram below shows the situation.
Given that Person A's angle of elevation to the building is 35 degrees, we'll let angle BAC be 35 degrees.
Similarly, since Person B's angle of elevation is 77 degrees, we'll let angle ABC be 77 degrees. We'll also let AB be x, the distance from Person A to the building, and BC be 8 miles, the distance from Person B to the building.
First, we'll use the tangent function to find the height of the building. In triangle ABC, tan(77) = height/8. Solving for the height, we get:
height = 8tan(77) ≈ 61.23 miles.
Next, we'll use the tangent function again to find x. In triangle ABC, tan(35) = height/x + 8. Solving for x, we get:
x = (height)/(tan(35)) - 8
≈ 103.17 miles - 8
≈ 95.17 miles.
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Mrs Smith walks a half a mile a day after work. She works five days a week. How many yards will she have walked for the week by Friday morning?
The distance Mrs. Smith covers is 3520 yards during the duration of the week by Friday morning.
One week has seven days in total.
Mrs. Smith walks half a mile each day after work, she walks a total of
0.5 miles/ day × 7 days/ week = 3.5 miles/ week
Now, if we calculate the distance on Friday morning, she must have walked four times till Friday morning since she has to walk after her work.
Therefore,
0.5 miles/ day × 4 days = 2 miles
To convert miles to yards, we can use the fact that there are 1760 yards in one mile:
2 miles/week × 1760 yards/mile = 3520 yards/week
Therefore, by Friday morning, Mrs. Smith will have walked 3520 yards.
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When solving the equation 3(x-2)=-12, what is a possible first step?
A) Distributing the 3 into each term of the parenthesis.
B) She could either divide by 3 or distribute 3 into the parenthesis
C) Adding 2 to each side of the equation
D) Subtracting 2 on each side of the equation
E) Dividing each side of the equation by 3
F) none of the answer choices tell what the first step could be.
Answer:
A
Step-by-step explanation:
At an assembly there are 225 chairs in 15 rows how many chairs are there Perot
An assembly has 225 chairs in 15 rows and there are 15 chairs per row in the assembly.
To find the number of chairs per row in an assembly, we need to divide the total number of chairs by the number of rows.
Given that there are 225 chairs in 15 rows, we can find the number of chairs per row by dividing the total number of chairs by the number of rows:
225 chairs ÷ 15 rows = 15 chairs per rows
It's important to note that this assumes that each row has the same number of chairs. If the number of chairs per row varies, then the calculation would need to be adjusted accordingly.
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HELP PLEASE … Assuming the input of energy continues for another 2.5 seconds, where will the particle be?
A) cannot be determined
B) positive maximum
C) negative maximum
D) equilibrium
Answer:
To determine the position of a particle given the input of energy, we need to know the type of energy input and the initial position and velocity of the particle. Without this information, we cannot determine the position of the particle after 2.5 seconds.
Therefore, the answer is A) cannot be determined.
Step-by-step explanation:
ABOVE
Write each equation in slope-intercept form. Identify the slope and y-intercept.
x - 3y = 12
*Work must be shown.*
Answer:
slope is 1/3
y-intercept is -4
Step-by-step explanation:
x - 3y = 12
3y = x - 12
y = 1/3x - 4
according to y = mx + b, m is slope and b is y-intercept
slope is 1/3
y-intercept is -4
Move the manilla point as close to the circle as possible so that the blue arc almost disappears keep the manilla point on the circle
What previously learned theorem do these transformations reveal
A theorem which these transformations reveal include the following: theorem of intersecting secants.
What is the theorem of intersecting secants?In Mathematics and Geometry, the theorem of intersecting secants states that when two lines intersect outside a given circle, the measure of the angle formed by these intersecting lines is equal to one-half (½) of the difference of the two (2) arcs it intercepts.
By applying the theorem of intersecting secants, the value of any of the angle subtended by the intersecting lines can be calculated by using the following mathematical equation:
m∠a = One-half(y – x).
m∠a = ½(y – x).
Where:
x and y represent the angles formed by the intersecting lines.
Therefore, the theorem of intersecting secants describe these set of transformations.
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Frannie has $120. She spends 30% of the money she has on a ticket to the theater. How much did Frannie pay for the theater ticket?
Answer:
36
Step-by-step explanation:
PxW=p
30x120=p
3600=p
x100%
$36=p
(overpriced ticket of you ask me lol)
I think it’s to do with Pythagoras theorm
assuming the conditions for inference have been met, does the coffee shop owner have sufficient evidence to conclude that the distribution of sales is proportional to the number of facings at a 5 percent level of significance? conduct the appropriate statistical test to support your conclusion.
The coffee shop owner does not have sufficient evidence to conclude that the distribution of sales is proportional to the number of facings at a 5% level of significance.
What is proportion ?
A proportion refers to the number or fraction of individuals or items that exhibit a particular characteristic or have a certain attribute, relative to the total number or sample size being considered. It is often expressed as a ratio or percentage.
To test whether the distribution of sales is proportional to the number of facings, we can use the chi-squared goodness of fit test. The null hypothesis for this test is that the observed data follows a specific distribution (in this case, a proportional distribution), while the alternative hypothesis is that the observed data does not follow that distribution.
To conduct the test, we first need to calculate the expected frequency for each category assuming a proportional distribution. We can do this by multiplying the total number of sales (610) by the proportion of facings for each brand:
Starbucks: 610 x 0.3 = 183
Dunkin: 610 x 0.4 = 244
Peet's: 610 x 0.2 = 122
Other: 610 x 0.1 = 61
Next, we calculate the chi-squared statistic using the formula:
χ² = Σ((O - E)² / E)
where O is the observed frequency and E is the expected frequency. The degrees of freedom for this test are (k-1), where k is the number of categories. In this case, k = 4, so the degrees of freedom are 3.
Using the observed and expected frequencies from the table, we get:
χ² = ((130-183)²/183) + ((240-244)²/244) + ((85-122)²/122) + ((155-61)²/61) = 124.36
Looking up the critical value of chi-squared for 3 degrees of freedom and a significance level of 0.05, we get a value of 7.815. Since our calculated χ² value of 124.36 is greater than the critical value of 7.815, we reject the null hypothesis and conclude that the observed distribution of sales is not proportional to the number of facings.
Therefore, the coffee shop owner does not have sufficient evidence to conclude that the distribution of sales is proportional to the number of facings at a 5% level of significance.
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What is result of following operation(4623. 56)10+ (110011. 11)2whare (110011. 11(2 mean that 110011. 11as a number express in base 2
The given numbers are in decimal and binary system and the final result of the given operation is [tex](4675.31)_{10}[/tex].
A binary integer (base-2) is converted to an equivalent decimal number using the binary to decimal conversion formula. (base-10). In mathematics, integers are expressed using a number system. It is a method to display numerical data. The four various numeral systems are as follows:
System of Binary Numbers (Base-2)
system of octal numbers (Base-8)
System of Decimal Numbers (Base-10)
System of Hexadecimal Numbers (Base-16).
We are the two numbers:-
[tex](4623.56)_{10} , (110011.11)_{2}[/tex]
these are in decimal and binary system respectively.
now, we will express them in same system ( here we choose decimal system).
[tex](110011.11)_{2} = (2^{5} + 2^{4} + 0 + 0 + 2^{1} + 2^{0} + 2^{-1} + 2^{-2} )_{10} \\= (2^{5}+2^{4}+0*2^{4}+0*2^{3}+2^{1}+2^{0}+2^{-1}+2^{-2})_{10} \\= (32+16+2+1+0.5+0.25)_{10} \\= (51.75)_{10}[/tex]
Now, addition is done below:-
4623.56+51.75= 4675.31.
hence, the final result of the given operation= [tex](4675.31)_{10}[/tex]
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Rina is climbing a mountain. She has not
yet reached base camp. Write an inequality
to show the remaining distance, d, in feet
she must climb to reach the peak.
The distance she must climb to reach the peak is greater than 2,663 feet. An inequality to show the remaining distance, d, in feet she must climb to reach the peak is d > 2,663.
Inequlity represents a relationship between two values that is not equal. That is inequlity means no equal and the symbols which used for not equal is ≠ and for comparison are < , > , ≤ , ≥. For example, ax > b etc. We have, Rina is climbing a mountain and mountain height present in above figure. See the figure carefully, the main two points in figure are the following: height of mountain peak
= 12,358 feet
height of base camp = 9,695 feet
we have to write an inequality for the remaining distance, d, in feet. Also, it is specified that she has not reached base camp yet. So, his climbed distance is less than 9,695 feet. Let the remaining distance be 'd feet '. From the above figures, d + base camp height > 12,358
Substract 9695 from both sides
=> d > 12,358 - 9,695
=> d > 2,663
Hence, required inequalty is d > 2,663.
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Complete question:
Rina is climbing a mountain. She has not yet reached base camp. Write an inequality to show the remaining distance, d, in feet she must climb to reach the peak. See tha above figure.
what is the phase angle, , in degrees if the expression is since angles are not unique, they can differ by multiples of 360, select the answer to be in the range of -180 to 180 degrees.
The phase angle, in degrees is -135.
A wave that repeats as a function of time and position is referred to as a periodic wave. Amplitude, frequency, wavelength, speed, and energy describe the properties of the wave. The phase angle is used to describe the characteristics of a periodic wave.
In phasors, a wave exhibits twofold characteristics: Magnitude and Phase. The phase angle refers to the angular component of a periodic wave.
The Phase Angle is one of the crucial characteristics of a periodic wave. It is similar to the phrase in many properties. The angular component periodic wave is known as the Phase Angle. It is a complex quantity measured by angular units like radians or degrees. A representation of any pure periodic wave is as follows.
A∠θ, where A is the magnitude and θ represents the Phase Angle of the wave.
A is the magnitude
θ is the phase angle
The expression is, which can be reduced to. Since angles are not unique, they can differ by multiples of 360, the answer is -135 degrees, which is in the range of -180 to 180 degrees.
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 HELP PLEASE!!!
calculate the distance between the points B= (0,6) and M= (8, -2) on the coordinate plane . round to the nearest 100th.
Answer:
Step-by-step explanation:
Using the distance formula: [tex]d=\sqrt{(x_2-x_1)^2+(y_2-y_1)^2}[/tex]
[tex]d=\sqrt{(8-0)^2+(-2-6)^2}[/tex]
[tex]=\sqrt{64+64} \\[/tex]
[tex]=\sqrt{128}[/tex]
[tex]=11.3[/tex]
The planet XYZ traveling about the star ABC in a circular orbit takes 24 hours to make an orbit. Assume that the orbit is a circle with radius 83,000,000 mi. Find the linear speed of XYZ in miles per hour. The linear speed is approximately ______ miles per hour. (Round to the nearest integer as needed.)
The planet XYZ traveling about the star ABC in a circular orbit takes 24 hours to make an orbit. Assume that the orbit is a circle with a radius of 83,000,000 mi. The linear speed of XYZ in miles per hour is approximately 1,093,333 miles per hour.
What is the orbit and what is the linear speed?
An orbit refers to the path taken by an object, such as a planet, as it circles around another object, such as a star. The speed of the planet is its rate of movement, measured in linear units like miles or kilometers per hour, as it travels around the orbit.
These are terms that are important to understanding the solution to the problem provided. The linear speed of XYZ in miles per hour is approximate _____ miles per hour. (Round to the nearest integer as needed.)
The planet XYZ travels around the star ABC in a circular orbit that takes 24 hours to complete. The orbit is a circle with a radius of 83,000,000 miles.
To find the linear speed of XYZ in miles per hour, it is necessary to use the formula for the circumference of a circle.
Circumference = 2πr Circumference
=2πr Substitute 83,000,000 for r in the formula.
Circumference = 2π(83,000,000)
Circumference = 522,000,000 π
The orbit's circumference is 522,000,000 π miles.
The distance traveled by XYZ in one hour is the linear speed. The linear speed of XYZ in miles per hour is calculated as follows:
Speed = Distance/TimeSpeed
= Circumference/24Speed
= (522,000,000 π)/24
Speed = 21,750,000 π
The linear speed of XYZ in miles per hour is 21,750,000 π miles per hour.
To get an approximate answer, π is equal to 3.14.
Speed ≈ 21,750,000 (3.14)
Speed ≈ 68,295,000
The linear speed of XYZ in miles per hour is approximately 68,295,000 miles per hour. Rounded to the nearest integer, the linear speed is approximately 1,093,333 miles per hour.
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how to calculate the product of two random variable that follows normal distribution with mean 0 and variance 1
To calculate the product of two random variables that follows the normal distribution with mean 0 and variance 1 by using the covariance formula
Cov(X, Y) = E[XY] - E[X]E[Y] = E[XY] - 0 = E[XY]
Given that two random variables follow a normal distribution with mean 0 and variance 1.
Let X and Y be two independent normal random variables such that X ~ N(0,1) and Y ~ N(0,1)
Now, The expected value of the product of two random variables is given by;
E[XY] = E[X]E[Y] + Cov(X,Y)
Where E[X] and E[Y] are the means of the two random variables X and Y respectively.
Cov(X, Y) is the covariance between the two random variables, which can be calculated using the formula;
Cov(X,Y) = E[XY] - E[X]E[Y]
Now, E[X] = E[Y] = 0 as both have a mean of 0.
Cov(X, Y) = E[XY] - E[X]E[Y]
⇒ E[XY] = the expected value of the product of X and Y.
As X and Y are independent, their covariance will be zero, which implies;
Cov(X, Y) = E[XY] - E[X]E[Y] = E[XY] - 0 = E[XY]
Thus, we can calculate the product of two random variables that follow a normal distribution with mean 0 and variance 1 using the above formula for covariance.
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can someone help pls 16=3x-7/2
Answer: To solve the equation 16=3x-7/2, you can follow these steps:
Multiply both sides of the equation by 2 to get rid of the fraction:
16 * 2 = (3x - 7/2) * 2
32 = 6x - 7
Add 7 to both sides of the equation to isolate the term with x:
32 + 7 = 6x
39 = 6x
Divide both sides of the equation by 6 to solve for x:
39 / 6 = x
6.5 = x
Therefore, the solution to the equation 16=3x-7/2 is x = 6.5.
Step-by-step explanation:
Answer:
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ㅤㅤ [tex]\large{\blue{\star} \: {\underline{\boxed{\pmb{\tt{x = \dfrac{13}{2}}}}}}}[/tex]
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Step-by-step explanation:
ㅤ
[tex]\large{\pmb{\tt{16 = 3x - \dfrac{7}{2}}}}[/tex]
ㅤ
[tex]\large{\pmb{\tt{\leadsto{16 + \dfrac{7}{2} = 3x}}}}[/tex]
ㅤ
[tex]\large{\pmb{\tt{\leadsto{\dfrac{2 \times 16 + 7}{2} = 3x}}}}[/tex]
ㅤ
[tex]\large{\pmb{\tt{\leadsto{\dfrac{32 + 7}{2} = 3x}}}}[/tex]
ㅤ
[tex]\large{\pmb{\tt{\leadsto{\dfrac{39}{2} = 3x}}}}[/tex]
ㅤ
[tex]\large{\pmb{\tt{\leadsto{39 = 2 \times 3x}}}}[/tex]
ㅤ
[tex]\large{\pmb{\tt{\leadsto{39 = 6x}}}}[/tex]
ㅤ
[tex]\large{\pmb{\tt{\leadsto{\dfrac{\cancel{39}}{\cancel{6}} = x}}}}[/tex]
ㅤ
[tex]\large{\purple{\boxed{\pmb{\tt{\leadsto{\dfrac{13}{2} = x}}}}}}[/tex]
ㅤ
━━━━━━━━━━━
ㅤ
[tex]\large{\underline{\underline{\sf{Verification:-}}}}[/tex]
ㅤ
• Substituting the value of (x) in the given equation,
ㅤ
[tex]\large{\pmb{\tt{\leadsto{16 = 3 \times \dfrac{13}{2} - \dfrac{7}{2}}}}}[/tex]
ㅤ
[tex]\large{\pmb{\tt{\leadsto{16 = \dfrac{39}{2} - \dfrac{7}{2}}}}}[/tex]
ㅤ
[tex]\large{\pmb{\tt{\leadsto{16 = \dfrac{39 - 7}{2}}}}}[/tex]
ㅤ
[tex]\large{\pmb{\tt{\leadsto{16 = \dfrac{\cancel{32}}{\cancel{2}}}}}}[/tex]
ㅤ
[tex]\large{\pmb{\tt{\leadsto{16 = 16}}}}[/tex]
ㅤ
As LHS = RHS,
Hence Verified
A bag of oranges weighs 1.5 kg to the nearest 100 g. Complete the error interval, where x is the weight of the oranges.
A shipping company is packing a box with one cubic centimeters blocks. The box is 14 centimeters long. 12 centimeters wide and 16 centimeters high. How many one cubic centimeter blocks will fill the box ?
The shipping company will need 2,688 one cubic centimeter blocks to fill the box.
The volume of the box can be calculated as:
Volume = length x width x height
Volume = 14 cm x 12 cm x 16 cm
Volume = 2,688 cubic cm
Since each block is also one cubic cm in volume, we can simply divide the total volume of the box by the volume of one block to find the number of blocks needed to fill the box:
Number of blocks = Volume of box / Volume of one block
Number of blocks = 2,688 cubic cm / 1 cubic cm
Number of blocks = 2,688
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How many modes are in the data set?
2. 20, 2. 30, 2. 30, 1. 70, 2. 00, 1. 50, 2. 40, 2. 40, 2. 00, 2. 00, 2. 00
A. 0
B. 1
C. 2
D. 3
Number of modes in the data set 1.50, 1.70, 2.00, 2.00, 2.00, 2.00, 2.30, 2.30, 2.40, 2.40, 2.00 is option (D) 3
The mode is the most frequently occurring value in a dataset. To find the modes in a dataset, we need to determine the values that occur most frequently. In the given dataset, we can see that some values occur more than once.
To start, we can sort the values in ascending order,
1.50, 1.70, 2.00, 2.00, 2.00, 2.00, 2.30, 2.30, 2.40, 2.40, 2.00
Now, we can count the number of occurrences of each value.
1.50 occurs once
1.70 occurs once
2.00 occurs four times
2.30 occurs twice
2.40 occurs twice
From this, we can see that the values 2.00 occur most frequently, and therefore, it is a mode. However, there are two more values that occur twice, namely, 2.30 and 2.40. Hence, these two values are also modes of the dataset.
There are three modes in the dataset: 2.00, 2.30, and 2.40.
Therefore, the correct option is (D) 3
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Two circles intersect at A and B. A common external tangent is tangent to the circles at T and U, as shown. Let M be the intersection of line AB and TU. If AB = 9 and BM = 3, find TU.
Two circles intersect at points A and B and have a common external tangent that is tangent to the circles at points T and U, M be the intersection of line AB and TU. If AB = 9 and BM = 3, then TU will be equal to 9.6.
In order to find the length of TU, We can use the Pythagorean theorem to find the length of TU. We know that AB = 9, and BM = 3, so the length of AM must be 6. We can then use the Pythagorean theorem to solve for TU:
TU = √(62 + 92) = √93 = 9.6.
Therefore, the length of TU is 9.6.
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17- 20: In an August 2012 Gallup survey of 1,012 randomly selected U.S. adults (age 18 and over), 53% said that they were dissatisfied with the quality of education students receive in kindergarten through grade 12. They also report that the "margin of sampling error is plus or minus 4%."17. What is the population of interest?18. What is the sample being used?19. What is the population parameter of interest, and what is the correct notation for this parameter? What is the relevant statistic?20. Find an interval estimate for the parameter of interest. Interpret it in terms of dissatisfaction in the quality of education students receive. Use two decimal places in your answer.
17. The population of interest is U.S. adults (age 18 and over).
18. The sample being used is 1,012 randomly selected U.S. adults (age 18 and over).
19. The population parameter of interest is the percentage of U.S. adults (age 18 and over) who are dissatisfied with the quality of education students receive in kindergarten through grade 12. The correct notation for this parameter is p and the relevant statistic is 53%.
20. The interval estimate for the parameter of interest is 49% - 57%, which indicates that between 49% and 57% of U.S. adults (age 18 and over) are dissatisfied with the quality of education students receive in kindergarten through grade 12.
At a party to celebrate a successful school play, the drama club bought 999 large pizzas. Each pizza had sss slices. All together, there were 727272 slices of pizza for the club to share.
Write an equation to describe this situation.
How many slices does each pizza have?
Answer:
Step-by-step explanation:
Let's use the variable "s" to represent the number of slices in each pizza.
The drama club bought 999 large pizzas, and each pizza had s slices. So, the total number of pizza slices is given by the product of 999 and s, which can be written as:
999s = 727272
To solve for s, we can divide both sides of the equation by 999:
s = 727272/999
Using a calculator, we can simplify this fraction to:
s ≈ 728.73
Therefore, each pizza has approximately 728 slices. Note that this is an unusual number of slices for a pizza, so it's possible that the problem is not intended to be taken literally, but rather as a math puzzle or word problem.
Answer:
Each pizza has 729 slices.
Step-by-step explanation:
question at a local ice-cream store, 210 people were surveyed on whether they preferred eating ice cream from a cone or a cup. of the 210 people surveyed, 70 were adults and 140 were children. of the responses, 150 indicated the cone as the preferred method of eating ice cream. for those surveyed, there was no association between age and preferred method of eating ice cream. which of the following tables shows the distribution of responses? responses
Based on the information provided, the table that correctly displays the data is table III.
What conditions should be met for the table to correctly display the data?To begin, the table should show the total of people surveyed was 210 people.In the table, the total of adults should be 70 and the total of children should be 140.The table should show the results between those who preferred cones vs cups are distributed between adults and children rather than cup or cone being significantly preferred by a group.Note: The question is incomplete; below I attach the missing information:
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the nutty professor sells cashews for $7.70 per pound and brazil nuts for $4.80 per pound. how much of each type should be used to make a 27 pound mixture that sells for $6.41 per pound?
The amount that each type would be 11.87 lbs of cashews and 15.13 lbs of brazil nuts
1. First, find the total cost of 27 lbs of the mixture: 27 lbs x $6.41/lb = $171.07.
2. Next, find the cost of cashews and brazil nuts in the mixture. Cashews cost $7.70/lb and brazil nuts cost $4.80/lb.
3. Subtract the cost of the brazil nuts from the total cost of the mixture: $171.07 - (27 lbs x $4.80/lb) = $105.27.
4. Divide the cost of the cashews ($105.27) by the cost of one pound of cashews ($7.70): $105.27/$7.70 = 13.66 lbs.
5. Subtract the number of pounds of cashews (13.66) from the total pounds of the mixture (27) to find the number of pounds of brazil nuts: 27 - 13.66 = 15.13 lbs.
6. Therefore, the mixture should contain 11.87 lbs of cashews and 15.13 lbs of brazil nuts.
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Let X denote the amount of time a book on two-hour reserve is actually checked out, and suppose the cdf is the following.0 , x<0f(x) = ((x^2)/4) , 0 <= x <= 21 , 2<= xUse the cdf to obtain the following. (If necessary, round your answer to four decimal places.)(a) P(X %u2264 1)(b) P(0.5 %u2264 X %u2264 1)(c) P(X > 1.5)(d) The median checkout duration [solve 0.5 = F(mew)](e) Use F'(x) to obtain the density function f(x)(f) Calculate E(X)(g) Calculate V(X) and %u03C3x(h) If the borrower is charged an amount h(X) = X2 when checkout duration is X, compute the expected charge E[h(X)].
By using CDF [tex]P(X \le 1)[/tex], [tex]P(0.5 \le X \le 1)=0.1875[/tex] , [tex]\mu= 1.4142[/tex], density function f(x) is [tex]0[/tex] [tex], E(X)=1 , V(X) = 1,[/tex] the expected charge [tex]E[h(X)]=2.[/tex]
(a) To obtain CDF
[tex]P(X \le 1)[/tex]
We have:
[tex]P(X \le 1) = F(1) = (1^2)/4 = 0.25[/tex]
(b) [tex]P(0.5 \le X \le1)[/tex]
We have:
[tex]P(0.5 \leX \le 1) \\ =F(1) - F(0.5) \\= (1^2)/4 - (0.5^2)/4 \\ =0.1875[/tex]
(c) [tex]P(X > 1.5)[/tex]
We have:
[tex]P(X > 1.5) \\= 1 - F(1.5) \\= 1 - (1.5^2)/4 \\= 0.1094[/tex]
(d) The median checkout duration [solve 0.5 = F(μ)]
To find the median, we need to solve the equation 0.5 = F(μ) for μ. This means we need to solve:
[tex]0.5 = (\mu^2)/4[/tex]
[tex]\mu^2= 2[/tex]
[tex]mu = \sqrt(2) \approx 1.4142[/tex]
(e) Use F'(x) to obtain the density function f(x)
We have:
[tex]f(x) = F'(x) \\= d/dx [(x^2)/4]\\ = x/2, 0 \le x \le 2[/tex]
[tex]f(x) = 0[/tex], otherwise
(f) Calculate [tex]E(X)[/tex]
We have:
[tex]E(X) = \int\ x f(x)dx[/tex] from 0 to 2
[tex]E(X) = \int\ x(x/2)dx[/tex] from 0 to 2
[tex]E(X) = [x^3/6][/tex] from 0 to 2
[tex]E(X) = (2^3/6)[/tex]
[tex]E(X) = 1[/tex]
(g) Calculate V(X) and σx
We have:
[tex]V(X) = E(X^2) - [E(X)]^2[/tex]
[tex]V(X) = \int\x^2f(x)dx[/tex] from 0 to 2 - [E(X)]²
[tex]V(X) = \int\x^2 (x/2)dx[/tex] from 0 to 2 - 1²
[tex]V(X) = [x^4/8][/tex] from 0 to 2 - 1
[tex]V(X) = (2^4/8) - (0^4/8) - 1[/tex]
[tex]V(X) = 1[/tex]
Therefore, [tex]\sigma x = \sqrt{(V(X))} = \sqrt{(1)} = 1.[/tex]
(h) If the borrower is charged an amount [tex]h(X) = X^2[/tex] when checkout duration is X, compute the expected charge E[h(X)]
We have:
[tex]E[h(X)] = \int\ h(x)f(x)dx[/tex] from 0 to 2
[tex]E[h(X)] = \int\x^2(x/2)dx[/tex] from 0 to 2
[tex]E[h(X)] = [x^4/8][/tex] from 0 to 2
[tex]E[h(X)] = (2^4/8) - (0^4/8)[/tex]
[tex]E[h(X)] = 2[/tex]
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