Answer: hello options related to your question is missing attached below is the missing option
answer :
4/9 ≤ r < 1/2 ----- ( c )
Step-by-step explanation:
Given that G denotes the centroid of triangle ABC and points M, N are points found in the interiors of segments AB,AC
also Given that r denotes ratio of triangles AMN to triangle ABC
attached below is a detailed solution
Use Hooke's Law to determine the work done by the variable force in the spring problem. A force of 450 newtons stretches a spring 30 centimeters. How much work is done in stretching the spring from 30 centimeters to 60 centimeters?
Answer:
The work done is 202.50Nm
Step-by-step explanation:
Given
[tex]F =450N[/tex]
[tex]x_1 = 30cm[/tex]
[tex]x_2 = 60cm[/tex]
Required
The work done
First, we calculate the spring constant (k)
[tex]F = kx_1[/tex]
[tex]450N = k *30cm[/tex]
[tex]k = \frac{450N}{30cm}[/tex]
[tex]k =15N/cm[/tex]
So:
[tex]F = kx_1[/tex]
[tex]F(x) = 15x[/tex]
The work done using Hooke's law is:
[tex]W =\int\limits^a_b {F(x)} \, dx[/tex]
This gives:
[tex]W =\int\limits^{60}_{30} {15x} \, dx[/tex]
Rewrite as:
[tex]W =15\int\limits^{60}_{30} {x} \, dx[/tex]
Integrate
[tex]W =15 \frac{x^2}{2}|\limits^{60}_{30}[/tex]
This gives:
[tex]W =15 *\frac{60^2 - 30^2}{2}[/tex]
[tex]W =15 *\frac{2700}{2}[/tex]
[tex]W =15 *1350[/tex]
[tex]W =20250N-cm[/tex]
Convert to Nm
[tex]W =\frac{20250Nm}{100}[/tex]
[tex]W =202.50Nm[/tex]
what is the mean mark of 847 ÷ 30?
Answer:
Step-by-step explanation:
Can y’all help me? Thanks :)
Answer:
Step-by-step explanation:
Soooo, by looking at the picture we can tell that it is a right trapezoid
The formula for the area is
(b1+b2)/2*h
(Base 1+ Base 2)/ 2 * height
Now we can plug in the numbers:
(5+15)/2*6
20/2*6
10*6
=60
1 gallon of paint per sq. foot
So Isha needs 60 gallons of paint
A privately owned lake contains two types of game fish, bass and trout. The owner provides two types of food, A and B, for these fish. Bass require 2 units of food A and 4 units of food B,
and trout require 5 units of food A and 2 units of food B. If the owner has 400 units of each food, find the maximum number of fish the lake can support.
fish
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Answer:
133 fishes
Step-by-step explanation:
Units of food A = 400 units
Units of food B = 400 units
Fish Bass required 2 units of A and 4 units of B.
Fish Trout requires 5 units of A and 2 units of B.
i. For food A,
total units of food A required = 2 + 5
= 7 units
number of bass and trout that would consume food A = 2 x [tex]\frac{400}{7}[/tex]
= 114.3
number of bass and trout that would consume food A = 114
ii. For food B,
total units of food B required = 4 + 2
= 6 units
number of bass and trout that would consume food B = 2 x [tex]\frac{400}{6}[/tex]
= 133.3
number of bass and trout that would consume food B = 133
Thus, the maximum number of fish that the lake can support is 133.
3p(2p - 9) - 2p(-9 + p)
Answer:
4p² - 9p
General Formulas and Concepts:
Pre-Algebra
Order of Operations: BPEMDAS
Brackets Parenthesis Exponents Multiplication Division Addition Subtraction Left to RightDistributive Property
Algebra I
Terms/CoefficientsStep-by-step explanation:
Step 1: Define
Identify
3p(2p - 9) - 2p(-9 + p)
Step 2: Simplify
[Distributive Property] Distribute 3p: 6p² - 27p - 2p(-9 + p)[Distributive Property] Distribute -2p: 6p² - 27p + 18p - 2p²[Subtraction] Combine like terms (p²): 4p² - 27p + 18p[Addition] Combine like terms (p): 4p² - 9pFor the sequence an = an-1 + an-2 and ai = 2, a2 = 3,
its first term is
its second term is
its third term is
its fourth term is
its fifth term is
Answer:
[tex]a_1 = 2[/tex]
[tex]a_2 = 3[/tex]
[tex]a_3 = 5[/tex]
[tex]a_4 = 8[/tex]
[tex]a_5 = 13[/tex]
Step-by-step explanation:
Given
[tex]a_n = a_{n-1} + a_{n-2}[/tex]
[tex]a_1 = 2[/tex]
[tex]a_2 = 3[/tex]
Solving (a): The first term
This has already been given as:
[tex]a_1 = 2[/tex]
Solving (b): The second term
This has already been given as:
[tex]a_2 = 3[/tex]
Solving (c): The third term
This is calculated as:
[tex]a_n = a_{n-1} + a_{n-2}[/tex]
[tex]a_3 = a_{3-1} +a_{3-2}[/tex]
[tex]a_3 = a_2 +a_1[/tex]
[tex]a_3 = 3 +2[/tex]
[tex]a_3 = 5[/tex]
Solving (d): The fourth term
This is calculated as:
[tex]a_n = a_{n-1} + a_{n-2}[/tex]
[tex]a_4 = a_{4-1} +a_{4-2}[/tex]
[tex]a_4 = a_3 +a_2[/tex]
[tex]a_4 = 5+3[/tex]
[tex]a_4 = 8[/tex]
Solving (e): The fifth term
This is calculated as:
[tex]a_n = a_{n-1} + a_{n-2}[/tex]
[tex]a_5 = a_{5-1} +a_{5-2}[/tex]
[tex]a_5 = a_4 +a_3[/tex]
[tex]a_5 = 8+5[/tex]
[tex]a_5 = 13[/tex]
Please help will give brainliest answer
D none of the above
as it should be ([tex]\sqrt[5]{x}[/tex])^4
Katy runs a day care center . So far this year , the enrollment has consisted of 2 toddlers and 8 children of other ages . Considering this data, how many of the next 20 children to enroll should you expect to be toddlers?
Answer:
You should expect 4 of the next 20 children to enroll to be toddlers.
Step-by-step explanation:
This question is solved by proportions.
So far:
We have that of 2 + 8 = 10 children, 2 are toddlers, so the proportion of toddlers is 2/10 = 0.2.
How many of the next 20 children to enroll should you expect to be toddlers?
0.2 out of 20, so: 0.2*20 = 4
You should expect 4 of the next 20 children to enroll to be toddlers.
I need help with this pls help and write the Correct answer
Suppose a quadratic equation is given as follows:
(k – 1)x² + x + 1 = 0
Select all values of k for which the above equation has two real and unequal roots
0
.25
0.5
0.75
1
1.25
1.5
1.75
Answer:
k>1.25
Step-by-step explanation:
The given quadratic equation is :
(k – 1)x² + x + 1 = 0
We need to find all values of k for which the above equation has two real and unequal roots.
For a quadratic equation ax²+bx+c=0, for real and unequal roots,
b²-4ac>0
Here, a = (k-1), b = 1 and c = 1
Put all the values,
1²-4×(k-1)1>0
1-4k+4>0
5-4k>0
k>1.25
S, k can take values more than 1.25. Hence, it can take values 1.5, 1.75.
3. The simple interest on $6,000 for 4 years is $1,680. *
A rectangular prism has a base area of 2 square feet and a height of 5 feet. What
is the volume of the prism in cubic feet?
10
15
12
11
Submit
A company that manufactures vehicle trailers estimates that the monthly profit for selling its midsize trailer is represented by function p, where t is the number of trailers sold. p(t)= -25t^3+625t^2-2500t Use the key features of function p to complete these statements. The company makes a profit when it sells _____trailers. The maximum profit of approximately $____ occurs when it sells approximately____ trailers.
Answer:
The answer is below
Step-by-step explanation:
The profit equation is given by:
p(t)= -25t³+625t²-2500t
The maximum profit is the maximum profit that can be gotten from selling t trailers. The maximum profit is at point p'(t) = 0. Hence:
p'(t) = -75t² + 1250t - 2500
-75t² + 1250t - 2500 = 0
t = 2.3 and t = 14.3
Therefore t = 3 trailers and t = 15 trailers
p(15) = -25(15³) + 625(15²) - 2500(15) = 18750
Therefore the company makes a maximum profit of approximately $18750 when it sells approximately 15 trailers.
Answer:
See below
Step-by-step explanation:
Since t is number of trailers, the domain includes only those values greater than 0.
On the relevant domain, the graph crosses the x-axis at the points (5,0) and (20,0). Between these points, the value of p(t) is positive. So the company makes a profit when it sells between 5 and 20 trailers.
On the positive interval between these points, the graph reaches a relative maximum when t roughly equals 14 and p(t) roughly equals $19,000.
So the maximum profit of approximately $19,000 occurs when it sells approximately 14 trailers.
Solve the solution as an ordered pair
X + 9 = y
X = 4y - 6
Answer:
-10, -1
Step-by-step explanation:
See Image below:)
NO LINKS!!!
What is the volume of this solid?
220 cubic units.
Answer:
Solution given:
for small cylinder
r=1
and for large cylinder
R=5+1=6
height for both [h]=2
Now
Volume of solid=πR²h-πr²h=πh(R²-r²)
=3.14*2(6²-1²)=219.8 =220 units ³.
Small cylinder is r=1
Large cylinder is R= 5+1 =6
Height (h) =2
Volume of solid,
→ πR²h-πr²h
→ πh(R²-r²)
→ 3.14 × 2(6²-1²)
→ 219.8
→ 220 cubic units
You buy items costing $1900 and finance the cost with a fixed installment loan for 24 months at 8% simple interest per year.
1. What is the finance charge?
2. What is your monthly payment?
* Please explain how you got the answer*
9514 1404 393
Answer:
$304$91.83Step-by-step explanation:
1. The finance charge is found from the simple interest formula;
I = Prt
where P is the principal amount, r is the annual rate, and t is the number of years.
24 months is 2 years, so the interest charged is ...
I = $1900×0.08×2 = $304
The finance charge is $304.
__
2. The monthly payment will be the total amount due, divided by the number of months.
payment = ($1900 +304)/24 = $2204/24 ≈ $91.83
The monthly payment is $91.83.
If ∠1 = 3x, ∠2 = 5x + 18, and s ⊥ r, find m∠1.
I hope it will help you.
Answer:
x = 9
Step-by-step explanation:
angle <1 and angle <2 is complementary and their sum is 90 degrees
3x + 5x + 18 = 90 add like terms
8x + 18 = 90 subtract 18 from both sides
8x = 72 divide both sides by 8
x = 9 to find the measure of angle <1 replace x with the value we found
What is the equivalent recursive definition for an = 12+ (n - 1)3?
A. a1 = 3, An = An-1 + 12
B. a1 = 12, An = 30n-1
C. a1 = 12, Un = On-1 +3
D. a1 = n, an= 1201-1+3
Answer:
[tex]A_1 = 12[/tex]
[tex]A_n = A_{n-1} + 3[/tex]
Step-by-step explanation:
Given
[tex]A_n =12+(n-1)3[/tex]
Required
Write as recursive
We have:
[tex]A_n =12+(n-1)3[/tex]
Open bracket
[tex]A_n =12+3n-3[/tex]
[tex]A_n =12-3+3n[/tex]
[tex]A_n =9+3n[/tex]
Calculate few terms
[tex]A_1 =9+3*1 = 9 + 3 = 12[/tex]
[tex]A_2 =9+3*2 = 9 + 6 = 15[/tex]
[tex]A_3 =9+3*3 = 9 + 9 = 18[/tex]
The above shows that the rule is to add 3.
So, we have:
[tex]A_1 = 12[/tex]
[tex]A_n = A_{n-1} + 3[/tex]
A stamp gets more expensive each year. It increases in value by 60 % each year. Wha
is the growth FACTOR?
9514 1404 393
Answer:
1.60
Step-by-step explanation:
The growth factor is 1 more than the growth rate:
1 + 60% = 1 + 0.60 = 1.60 = growth factor
The following hypothetical data represent a sample of the annual numbers of home fires started by candles for the past several years.
5640, 5090, 6590, 6380, 7165, 8440, 9980
The population has a standard deviation equal to 1210. Assuming that the data is from a distribution that is approximately normal, construct a 90 % confidence interval for the mean number of home fires started by candles each year
Answer:
(6290.678 ; 7790.742)
Step-by-step explanation:
Given the data :
5640, 5090, 6590, 6380, 7165, 8440, 9980
The sample mean, xbar = Σx / n = 49285 / 7 = 7040.71
The 90% confidence interval :
Xbar ± Margin of error
Margin of Error = Zcritical * σ/√n
Since the σ is known, we use the z- distribution
Zcritical at 90% confidence = 1.64
Hence,
Margin of Error = 1.64 * 1210/√7
Margin of Error = 750.032
90% confidence interval is :
7040.71 ± 750.032
Lower boundary = 7040.71 - 750.032 = 6290.678
Upper boundary = 7040.71 + 750.032 = 7790.742
(6290.678 ; 7790.742)
help me out pleaseeee
Answer:
The correct option is (b).
Step-by-step explanation:
The solution of the given polynomial is :
[tex](-\dfrac{1}{3},4)[/tex]
x = 1/3 and y = -4
i.e.
Sum of roots = (1/3-4) = -11/3
Product of roots = (1/3)(-4) = -4/3
The quadratic equation is as follows :
[tex]x^2+(\text{sum of roots})x+\text{Product of roots}=0[/tex]
Put all the values,
[tex]x^2+\dfrac{-11}{3}x+\dfrac{-4}{3}=0\\\\3x^2-11x-4=0[/tex]
So, the correct option is (b).
An item was marked down 64% from its original price, x. The amount discounted was $30. Which equation can be
used to find the original price?
0.64(x) = 30
0.64(30) = x
30 +0.64 = x
x + 0.064 = 30
Answer:
0.64(x) = 30
Step-by-step explanation:
Hope that's correct.
Choose which two numbers the following will fall between: *
V156 PLEASE HELP ME FASTTTTT
[tex]\sf\purple{A.\:Between \:12\:and\:13.}[/tex] ✅
[tex]\large\mathfrak{{\pmb{\underline{\red{Step-by-step\:explanation}}{\orange{:}}}}}[/tex]
[tex] \sqrt{156} \\ = 12.4899 \\ = 12.49[/tex]
Therefore, [tex] \sqrt{156} [/tex] will fall in between 12 and 13.
[tex]\large\mathfrak{{\pmb{\underline{\orange{Happy\:learning }}{\orange{!}}}}}[/tex]
find the derivative
f (x ) = (x-5)^2 (3-x)^2
Given:
The function is
[tex]f(x)=(x-5)^2(3-x)^2[/tex]
To find:
The derivative of the given function.
Solution:
Chain rule of differentiation:
[tex][f(g(x))]'=f'(g(x))g'(x)[/tex]
Product rule of differentiation:
[tex][f(x)g(x)]'=f(x)g'(x)+g(x)f'(x)[/tex]
We have,
[tex]f(x)=(x-5)^2(3-x)^2[/tex]
Differentiate with respect to x.
[tex]f'(x)=(x-5)^2\dfrac{d}{dx}(3-x)^2+(3-x)^2\dfrac{d}{dx}(x-5)^2[/tex]
[tex]f'(x)=(x-5)^2[2(3-x)(0-1)]+(3-x)^2[2(x-5)(1-0)][/tex]
[tex]f'(x)=(x^2-10x+25)(-6+2x)+(9-6x+x^2)(2x-10)[/tex]
[tex]f'(x)=(x^2)(-6)+(-10x)(-6)+(25)(-6)+(x^2)(2x)-10x(2x)+25(2x)+(9)(2x)+(-6x)(2x)+x^2(2x)+9(-10)+(-6x)(-10)+x^2(-10)[/tex]
On further simplification, we get
[tex]f'(x)=-6x^2+60x-150+2x^3-20x^2+50x+18x-12x^2+2x^3-90+60x-10x^2[/tex]
[tex]f'(x)=(2x^3+2x^3)+(-6x^2-20x^2-12x^2-10x^2)+(60x+50x+18x+60x)+(-90-150)[/tex]
[tex]f'(x)=4x^3-48x^2+188x-240[/tex]
Therefore, the derivative of the given function is [tex]f'(x)=4x^3-48x^2+188x-240[/tex].
the sumof 8pq and -17 pq is
Answer:
= -9pq
Step-by-step explanation:
=8pq + (-17pq)
=8pq-17pq
= -9pq
The perimter of a rectangle is 34 units. Its width is 6.5 units. Write an equation to determine the length (l) if the rectangle
Answer:
Step-by-step explanation:
P=2(w)+2(l)
34=2(6.5)+2(l)
34=13+2(l)
21=2(l)
10.5=l
Find the area of the sector in
terms of pi.
90°
24
Area = [?]
Enter
Step-by-step explanation:
area of a circle is r x r x pi
so one quarter of it us r x r x pi /4
The product of two consecutive negative integers is 600. What is the value of the lesser integer?
–60
–30
–25
–15
Answer:
-25
Step-by-step explanation:
-24×(-25)=600
Hope this helps! :)
Answer: It's -25
edg 2023
Ariana owns a food truck that sells tacos and burritos. She sells each taco for $4 and each burrito for $8.25. Ariana must sell at least $960 worth of tacos and burritos each day. Write an inequality that could represent the possible values for the number of tacos sold, tt, and the number of burritos sold, bb, that would satisfy the constraint.
Answer:
09
Step-by-step explanation:
1 squared + 1= 2 sqaured - 2
2 sqaured + 2 = 3 squared - 3
3 squared + 3= 4 squared - 4
a) make a conjecture about this pattern. write your conjecture in words
b) generalise your conjecture for this pattern
c) prove that your conjecture is true
Answer:
It would be the letter B :)