In a wire, when elongation is 4 cm energy stored is E. if it is stretched by 4 cm,
then what amount of elastic potential energy will be stored in it?
plz don't spam
answer fast in imp

Answers

Answer 1

Answer:

4E

Explanation:

From the question given above, the following data were obtained:

Initial elongation (e₁) = 4 cm = 4/100 = 0.04 m

Initial energy (E₁) = E

Final elongation (e₂) = 0.04 + 0.04 = 0.08 m

Final energy (E₂) =?

The energy stored in a s spring is given by:

E = ½Ke²

Where

E => is the energy

K => is the spring constant

e => is the elongation

From:

E = ½Ke²

Energy is directly proportional to the elongation. Thus,

E₁/e₁² = E₂/e₂²

With the above formula, we can obtain the final energy as follow:

Initial elongation (e₁) = 0.04 m

Initial energy (E₁) = E

Final elongation (e₂) = 0.08 m

Final energy (E₂) =?

E₁/e₁² = E₂/e₂²

E / 0.04² = E₂ / 0.08²

E / 0.0016 = E₂ / 0.0064

Cross multiply

0.0016 × E₂ = 0.0064E

Divide both side by 0.0016

E₂ = 0.0064E / 0.0016

E₂ = 4E

Therefore, the final energy is 4 times the initial energy i.e 4E


Related Questions

Select the correct answer. A truck moves 60 kilometers east from point A to point B. At point B, it turns back west and stops 15 kilometers away from point A. What are the total distance and total displacement of the truck? A. The total distance is 105 kilometers, and the total displacement is 15 kilometers east. B. The total distance is 105 kilometers, and the total displacement is 45 kilometers east. C. The total distance is 60 kilometers, and the total displacement is 60 kilometers east. D. The total distance is 60 kilometers, and the total displacement is 45 kilometers east. E. The total distance is 105 kilometers, and the total displacement is 75 kilometers east.

Answers

Answer:

Option a

Explanation:

Una persona pesa 700 N al nivel del mar. ¿Cuándo sube a un avión a 10000 m de altura pesará más, igual o menos?

Answers

Answer:

La persona pesa menos

Explanation:

Generalmente, definimos el peso como la fuerza gravitacional que actúa sobre un objeto.

Dado que la constante gravitacional depende del cuadrado de la distancia medida desde el centro de la Tierra, podemos concluir que el peso de un objeto disminuye a medida que aumenta la distancia entre el objeto y el centro de la Tierra (mayor altitud).

Por lo tanto, la persona que pesa 700 N al nivel del mar pesará menos cuando esté en un avión a una altitud de 10,000 m.


An object is placed closer to the lens than f for a diverging lens. The image will be located:
a) between f and 2f

b) between the lens and f

c) A or B or C

d) farther than 2f

Answers

It’s b i took the test

(b) How much energy must be supplied to boil 2kg of water? providing that the specific latent heat of vaporization of water is 330 kJ/kg.

Answers

Complete question:

(b) How much energy must be supplied to boil 2kg of water? providing that the specific latent heat of vaporization of water is 330 kJ/kg. The initial temperature of the water is 20 ⁰C

Answer:

The energy that must be supplied to boil the given mass of the water is 672,000 J

Explanation:

Given;

mass of water, m = 2 kg

heat of vaporization of water, L =  330 kJ/kg

initial temperature of water, t = 20 ⁰C

specific heat capacity of water, c = 4200 J/kg⁰C

Assuming no mass of the water is lost through vaporization, the energy needed to boil the given water is calculated as;

Q = mc(100 - 20)

Q = 2 x 4200 x (80)  

Q = 672,000 J

Q = 672,000 J

Q = 672,000 J

Therefore, the energy that must be supplied to boil the given mass of the water is 672,000 J

A hot cube of iron was heated up using 1500 J of thermal energy and was placed in a beaker of water. Before it was heated, the iron cube was 20.0 ˚C. The cube of iron raised the temperature of the water to 45.0 ˚C. If the iron cube has a mass of 133 g, what is the specific heat capacity of iron?

Answers

Answer:

451.13 J/kg.°C

Explanation:

Applying,

Q = cm(t₂-t₁)............... Equation 1

Where Q = Heat, c = specific heat capacity of iron, m = mass of iron, t₂= Final temperature, t₁ = initial temperature.

Make c the subject of the equation

c = Q/m(t₂-t₁).............. Equation 2

From the question,

Given: Q = 1500 J, m = 133 g = 0.113 kg, t₁ = 20 °C, t₂ = 45 °C

Substitute these values into equation 2

c = 1500/[0.133(45-20)]

c = 1500/(0.133×25)

c = 1500/3.325

c = 451.13 J/kg.°C

Which one of the following is an example of a solution?
a. Sand particles in water
b. Orange Squash
c. Vinegar
d. Paint

Answers

Answer:

it is maybe A but i'm not 100% sure

Explanation:

its the only one that is mixed

The rate at which electric
charges flow through a
circuit

Answers

Answer:

The answer is Current.

HELP PLEASE ?? can u answer this multiple choice for me please?

Answers

Answer:

.04 kg m/s

Explanation:

Momentum is simply mass multiplied by velocity given by p = mv. You can consider momentum as mass in motion.

Before the collision, the data given for the toy train:

v = 0.5m/s

m = 75g

We need to convert grams into the SI unit of mass, kg.

75g / 1000g * 1kg = 0.075kg

Using p = mv, we can determine:

p = 0.075kg * 0.5m/s = 0.0375 kg m/s

Rounding to the value of 1 sig-fig, it comes out to be 0.04 kg m/s.

A man exerts more pressure while standing on one foot than by two foot​

Answers

Yes? Ok? That’s right??

Answer:While walking, one foot is in contact with the ground at a time. The surface area of one foot is less than two feet. Therefore, the pressure is more than the pressure exerted while standing, as the surface area of both feet is more.

Gold is more active than copper? A. True B. False​

Answers

Answer:

false

Explanation:

sana po maktulong

A 5L container has a ​

Answers

Answer:a gas at pressure of 0.8 m column of H g

Explanation:I think

If a train traveled 400 miles north and traveled back 275 miles south and the total trip took 5 hours to complete, what was the average velocity of the train in mph?

Answers

The average velocity is 25 mph north.

Average velocity = displacement/time

Displacement =

(400 mi north) + (275 mi south)

Displacement = 125 mi north

Average V = (125 mi north) / 5 hours.

Average V = 25 mph north

Tom is throwing an baseball at an aluminum can,
present an argument about the likely kinetic energy of the ball before and after.
describe the evidence that would support the argument.
present an argument about the likely kinetic energy of the can before and after.
describe the evidence that would support the argument.

Answers

Answer:

The question relates to the conservation of energy principle, the conservation of the linear momentum, and Newton's Laws of motion

Part A

1) Tom throwing a baseball at a can

The initial velocity of the baseball = v₂

The initial kinetic energy of the baseball, K.E.₂ = (1/2)·m₂·v₂²

∴ The final kinetic energy of the baseball, K.E.₂' = (1/2)·m₂·v₂'² < (1/2)·m₂·v₂²

Therefore, the energy of the ball before the collision is lesser than the energy of the ball after the collision

2) The evidence that would likely support the claim is that the baseball's height above the ground reduces rapidly immediately after the collision which is due to the reduced velocity, and therefore, the reduced (kinetic) energy

The final velocity of the baseball v₂' < v₂

Part B

1) The argument

The initial velocity of the can = v₁ = 0 (The can is initially  at rest)

The initial kinetic energy of the can, K.E.₁ = (1/2)·m₁·v₁² = 0

The final velocity of the can v₁' > v₁ = 0

∴ The final kinetic energy of the can, K.E.₁ = (1/2)·m₁·v₁² > 0

Given that the velocity of the can increases from zero to a positive value after collision with the baseball, the kinetic energy of the can is increased from zero before the collision to a positive value after the collision

2) An evidence in support of the argument is the motion of the can which was initially at rest which is an indication of increase in energy podded by the can

Explanation:

I need help

please help me with this​

Answers

Djdjjdjdjdjjfjfhshdhehe

4. A cell membrane contains all of the following EXCEPT:*
O glycolipids
phospholipids
sphingolipids
steroids
none of the above

Answers

Answer:

The correct answer is - none of the above.

Explanation:

Cell membranes or plasma membranes of the cell are composed mainly of fatty-acid-based lipids and proteins. Membrane lipids are of two types majorly, glucolipids, phospholipids, and sterols (generally cholesterol).

Sphingolipids are also a structural component of the cell membrane that helps in segregation into distinct membrane domains. Glycolipids are present on the surface of the plasma membrane.

Multiple Choice Identify the letter of the choice that best completes the statement or answers the question. The best type of graph to illustrate the change in air temperature over a period of time would be a _________ graph. a. circle b. line c. bar d. all of these Please select the best answer from the choices provided A B C D

Answers

Answer:

B line graph

Explanation:

sorry if I am wrong

Answer:

b

Explanation:

what revovles around the sun and is made out of rock,ice,gas,and dust?

Answers

Answer:

Comets are cosmic snowballs of frozen gases, rock and dust that orbit the Sun. When frozen, they are the size of a small town. When a comet's orbit brings it close to the Sun, it heats up and spews dust and gases into a giant glowing head larger than most planets.Hope this is fine for you,,!!

A train increases speed from 10 m/s to 20 m/s. What is the average speed while increasing the speed? And how far dies it travel while increasing the speed?

Answers

Ok so basically.. and then if you.. you get …

Explanation:

average speed =(first velocity + second velocity)/2

=(10 +20)/2=15m/s

distance=average speed × time

= 15 × t ( but time not given)

2 Ten identical lengths of wire are laid closely side-by-
side. Their combined width is measured and found
to be 14.2 mm. Calculate:
a the radius of a single wire
b the volume in mm' of a single wire if its length is
10.0 cm. (Volume of a cylinder = ferih, where r =
radius and h = height.

Answers

Answer:

(a) 0.71 mm

(b) 0.158 cubic cm

Explanation:

The width of one wire is the diameter of the wire.

(a) Let the diameter of each wire is d.

So, 10 d = 14.2 mm

d = 1.42 mm

radius of each wire, r = d/2 = 1.42/2 = 0.71 mm

(b) Length, L = 10 cm

The volume of the single wire is given by

[tex]V =\pi\times r^2\times h \\\\V =3.14\times 0.071^2\times 10\\\\V =0.158 cm^3[/tex]

Find equivalent resistance.

Answer asap and please, please don't spam.​

Answers

Answer:

R = 4.77 ohms

Explanation:

Four resistors are given such that,

R₁ = 2 ohms

R₂ = 3 ohms

R₃ = 5 ohms

R₄ = 10 ohms

Here, R₁ and R₂ in series. The equivalent is given by :

R₁₂ = R₁ + R₂

= 2 + 5

R₁₂ = 7 ohms

Similarly, R₃ and R₄ are in series. so,

R₃₄ = R₃ + R₄

= 10+5

R₃₄ = 15 ohms

Now, R₁₂ and R₃₄ are in parallel. So,

[tex]\dfrac{1}{R}=\dfrac{1}{R_{12}}+\dfrac{1}{R_{34}}\\\\\dfrac{1}{R}=\dfrac{1}{7}+\dfrac{1}{15}\\\\R=4.77\ \Omega[/tex]

So, the equivalent resistance s 4.77 ohms.

An electron with a charge of -1.6 x 10-19 C experiences a force of 9.2 x 10-15 N. What is the intensity of the electric field?

Answers

Answer:

Explanation:

[tex]E=\frac{q}{F}[/tex] where q is the charge of the electron and F is the electrostatic force. Filling in:

[tex]E=\frac{-1.6*10^{-19}}{9.2*10^{-15}}[/tex] which gives you an electric field magnitude of

E = -1.7 × [tex]10^{-5[/tex] C/N

When should a bar graph be used?
A. When the independent variable is composed of categories and does not show a
relationship
B. When the independent variable is continuous and does not show a relationship to the
dependent variable.
C. When the independent variable is continuous and shows a causal link to the
dependent variable,
D. When there is no independent variable.

Answers

Answer:

B. When the independent variable composed of categories and does not show a relationship to the dependent variable

Explanation:

A bar graph, is a graph used for presenting data grouped into categories, which are the independent variables of the graph, and the measurement of each category, which are represented as rectangular bars having lengths proportional to the value of the category, on a chart

In the bar graph or chart, there is no direct relationship between the categories, which are the x-values and the dependent variables , which are the length of the bars, the y-values, as the length of the rectangular bar in one category, cannot be obtained from another category through a relationship

Therefore, the correct option is option is when the independent variable composed of categories and does not show a relationship to the dependent variable

A force of 20 N acted on a 5 kg object, moving it a distance of 4 m. How much work was done on the object?

Answers

Answer:

400J

Explanation:

The work done by the force on the object is 80 J.

What is work ?

The work is defined by the product of force and displacement. Its unit of measurement is joule. And the formula is,

Work = Force ×Displacement

Or mathematically it is W = F.d

In the question given data ,

     [tex]F = 20N , d = 4m\\[/tex]

putting in the above formula ,

       W = 20 × 4

       W = 80 J

Hence the work done by the force is 80J.

Find out more information about work here:

https://brainly.com/question/11367798    

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a ball of mass 0.2 kg is dropped from a height of 20m on impact to the ground it loses in 30 joule of energy calculate the height it reaches on rebound​

Answers

Answer:

5 m

Explanation:

We'll begin by calculating the original potential energy. This can be obtained as follow:

Mass (m) = 0.2 Kg

Height (h) = 20 m

Acceleration due to gravity (g) = 10 m/s²

Energy (E₀) =?

E₀ = mgh

E₀ = 0.2 × 10 × 20

E₀ = 40 J

Next, we shall determine the new energy of the ball.

Energy (E₀) = 40 J

Energy lost (Eₗ) = 30 J

New energy (E) =?

E = E₀ – Eₗ

E = 40 – 30

E = 10 J

Finally, we shall determine height of the ball on rebound. This can be obtained as follow:

New energy (E) = 10 J

Mass (m) = 0.2 Kg

Acceleration due to gravity (g) = 10 m/s²

Height (h) =?

E = mgh

10 = 0.2 × 10 × h

10 = 2 × h

Divide both side by 2

h= 10 / 2

h = 5 m

Thus, the height of the ball on rebound is 5 m

HELP ME ILL MARK YOU THE BRAINLIEST

Answers

Option C: Later in the day, less power is developed in lifting each box

Answer:

Later in the day, less power is developed in lifting each box.

power= workdone÷time

Which wave shows the loudest sound below?​

Answers

Answer:

I think C

Explanation:

If im right give brainliest :)

Answer: C the right answer

A mass hanging from a pendulum at the end of a string of negligible mass. The string has a length of 0.84 m. With the string hanging vertically, the object is given an initial velocity of 1.4 m/s parallel to the ground and swings upward on a circular arc. Eventually, the object comes to a momentary halt at a point where the string makes an angle θ with its initial vertical orientation and then swings back downward. Find the angle θ.

Answers

Explanation:

tan(theta)=(v^2)/(length of string × g)

=(1.4^2)/(0.84 × 9.8m/s )

=1.96/(8.232)

=0.2380952381

theta=arctan(0.2380952381)

=13.4°

which is the correct equation for the elastic potential energy stored in a spring
A EPE = mv
B EPE = 1/2kx^2
C EPE = F(delta)t
D EPE = -kx

Answers

(B)

Explanation:

[tex]pe = \frac{1}{2} k {x}^{2} [/tex]

The equation of the elastic potential energy stored in the spring can be represented as: EPE = (1/2)kx². Therefore, option (B) is correct.

What is elastic potential energy?

The elastic potential energy can be described as the total energy obtained as a result of deformation in the shape of an object. The elastic potential energy implies any object which is capable of regaining its actual shape and size after deformation.

The deformation is only possible as a result of the gained potential energy which is called the elastic potential energy. The elastic potential energy can be stored energy of a compressible or stretchable in other words stored energy of perfectly elastic materials.

The mathematical equation of the elastic potential energy formula is given by:

U = 1/2 (Force × Displacement)

U = (1/2) (kx) (x)

U = (1/2)kx²

Where k is the spring constant and x is the displacement as a result of applied external force.

Learn more about elastic potential energy, here:

https://brainly.com/question/14687790

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A person weighs 60 kg. The area under the foot of the person is 150 cm2. Find the pressure exerted on the ground by the person. (Take g 10m/s2)

Answers

Answer:

40000 N/m²

Explanation:

Applying,

P =  F/A................... Equation 1

Where P = Pressure, F = Force, A = Area.

From the question,

The force(F) exerted by the person's foot is thesame as it's weight.

F = W = mg............ Equation 2

Where m = mass of the person, g = acceleration due to gravity.

Substitute equation 2 into equation 1

P = mg/A................ Equation 3

Given: m = 60 kg, g = 10 m/s², A = 150 cm² = (150/10000) m² = 0.015 m²

Substitute these values into equation 3

P = (60×10)/0.015

P = 600/0.015

P = 40000 N/m²

Wire B has twice the length and twice the radius of wire A. both wires are made from the same material. if wire A has a resistance R, what is the resistance of wire B?

Answers

Answer:

Hello There!!

Explanation:

1/2R because wire B has twice the radius,it has four times the cross-sectional area of wire A.

hope this helps,have a great day!!

~Pinky~

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