Answer:
Two sample t test
Step-by-step explanation:
The two sample t test can be used in the scenario described above, where two independent samples are obtained, we take a certain sample of children with autism and then another sample of children without autism. The number of children chosen for each sample should be random and could be of equal or unequal sizes. The mean and standard deviation of each of sample A and B are deternined and used to perform the analysis to determine if the mean of each sample are equal or not. This test is also called the WELCH T TEST
Simultaneous equations 5x-4y=19
X+2y=8
Answer:
x=5
y=3/2
Step-by-step explanation:
Take it or leave it, that's what the computer said.
A card is drawn from a well shuffled pack of 52 cards . find the probability of '2' of spades
Answer:
[tex] \frac{1}{52} [/tex]Step-by-step explanation:
Given,
Total no. of cards = 52
No. of 2 of spades cards = 1
Therefore,
Probability of getting 2 of spades
[tex] = \frac{no. \: of \: required \: outcomes}{total \: outcomes} [/tex]
[tex] = \frac{1}{52} (ans)[/tex]
Plz help I’ll mark you
Answer:
option (B) is the answer
which equation has the steepest graph ?
Answer:
Step-by-step explanation:
A.
[tex] \green{\huge{\red{\boxed{\green{\mathfrak{QUESTION}}}}}} [/tex]
which equation has the steepest graph ?
[tex] \red{ \bold{ \textit{STANDARD \: EQUATION}}}[/tex]
[tex]y = mx + c[/tex]
[tex]WHERE \\ m = SLOPE \\ c = Y - INTERCEPT[/tex]
[tex] \huge\green{\boxed{\huge\mathbb{\red A \pink{N}\purple{S} \blue{W} \orange{ER}}}}[/tex]
[tex] \blue{A.T.Q}[/tex]
PART A:-
[tex]y = mx + c \sim y= -14x+1 [/tex]
[tex] \orange{SO}[/tex]
m= (-14)
which is equal to the slope of the equation .
PART B:-
[tex]y = mx + c \sim y= ¾x-9 [/tex]
[tex] \orange{SO}[/tex]
m= (¾)
PART C:-
[tex]y = mx + c \sim y= 10x-5[/tex]
[tex] \orange{SO}[/tex]
m= (10)
PART D:-
[tex]y = mx + c \sim y= 2x+8[/tex]
[tex] \orange{SO}[/tex]
m= (2)
SO MAXIMUM SLOPE IS :-( -14 )Negative shows Slope is in negative direction.
[tex] \red \star{Thanks \: And \: Brainlist} \blue\star \\ \green\star If \: U \: Liked \: My \: Answer \purple \star[/tex]
El prestigioso hotel Los Cisnes, cobra la recepción a las delegaciones extranjeras de acuerdo con la siguiente política: Las delegaciones con menos de 30 personas pagan $10 por persona, mientras que las delegaciones con 30 personas o más pagan una tarifa reducida de $9.50 por persona.
a) Determine el costo que pagaran las delegaciones extranjeras por la recepción en función a la cantidad de personas (1.5 puntos)
b) Trace un bosquejo de la gráfica del inciso a) (1.5 puntos)
c) Cuánto dinero ahorrará la delegación de 29 personas si pudiera incluir un miembro adicional (1 punto)
d) Halle el dominio y rango de la función costo por la recepción (1 punto)
Answer:
"x" cantidad de personas, que será igual a
f(x) = $10x Si x < 30
f(x) = $9.5x si x ≥ 30
Si tenemos que son 29 personas entonces el costo es de:
f(x) = $10*29 = $290
Si incluye un miembro adicional
f(x) = $9.5*30 = $285
Ahorra un total de: $290 - $285 = $5
Find f(6), f(0), and f(-1)
f(x)=-7X
Answer:
f(6)=-42
f(0)=0
f(-1)=7
Step-by-step explanation:
since f(x) =-7x
it implies that f(6),f(0) and f(-1) are all equal to f(x)
which is equal to -7x .
so wherever you find x you out it in the
function
Evaluate the expression when c = 3 and x= -5,
-C+5x
Answer:
-28
Step-by-step explanation:
if c = 3 and x = -5 than,
-c + 5x = -3 + 5 * (-5) = -3 + (-25) = - 28
Which one is the correct answer? help pls!!
Answer:
(2k, k)
Step-by-step explanation:
x + y = 3k
x - y = k
Add the equations.
2x = 4k
x = 2k
2k + y = 3k
y = k
Answer: (2k, k)
the voltage in a lightbulb is given by the equation V= IR. in this equation V is the voltage, I is the current , and R is the resistance. what is the current in a lightbulb with a voltage of 35.0 V and a resistance of 175
Answer:
a
Step-by-step explanation:
Tiham is the only striker of his team. He can catch one of the four passes delivered to him and when he get a pass he takes the shot. One of his four shots go towards the net but the goal keeper of the opposite team stop one of every two shots. What is the minimum number of passes have to be delivered to Tiham to score minimum one goal?
Answer:
1/4 *1/4*1/2 =0.03125
which as a fraction is 1/32
so the minimuim number of passes that will get him a goal is 1 since he could get it on the first try
Hope This Helps!!!
If a/b=7/2, then 2a= ______
A) 7b
B) 4b
C) 2b
D) 14b
Answer:
Option A, 7b
Step-by-step explanation:
a/b=7/2
or, 2a=7b
Answered by GAUTHMATH
Answer:
A)7b
its yr ans.
hope it helps.
stay safe healthy and happy. ..The mean points obtained in an aptitude examination is 167 points with a standard deviation of 20 points. What is the probability that the mean of the sample would differ from the population mean by less than 3.8 points if 76 exams are sampled
Answer:
0.9029 = 90.29% probability that the mean of the sample would differ from the population mean by less than 3.8 points if 76 exams are sampled
Step-by-step explanation:
To solve this question, we need to understand the normal probability distribution and the central limit theorem.
Normal Probability Distribution:
Problems of normal distributions can be solved using the z-score formula.
In a set with mean [tex]\mu[/tex] and standard deviation [tex]\sigma[/tex], the z-score of a measure X is given by:
[tex]Z = \frac{X - \mu}{\sigma}[/tex]
The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the p-value, we get the probability that the value of the measure is greater than X.
Central Limit Theorem
The Central Limit Theorem establishes that, for a normally distributed random variable X, with mean [tex]\mu[/tex] and standard deviation [tex]\sigma[/tex], the sampling distribution of the sample means with size n can be approximated to a normal distribution with mean [tex]\mu[/tex] and standard deviation [tex]s = \frac{\sigma}{\sqrt{n}}[/tex].
For a skewed variable, the Central Limit Theorem can also be applied, as long as n is at least 30.
For a proportion p in a sample of size n, the sampling distribution of the sample proportion will be approximately normal with mean [tex]\mu = p[/tex] and standard deviation [tex]s = \sqrt{\frac{p(1-p)}{n}}[/tex]
The mean points obtained in an aptitude examination is 167 points with a standard deviation of 20 points
This means that [tex]\mu = 167, \sigma = 20[/tex]
Sample of 76:
This means that [tex]n = 76, s = \frac{20}{\sqrt{76}}[/tex]
What is the probability that the mean of the sample would differ from the population mean by less than 3.8 points?
P-value of Z when X = 167 + 3.8 = 170.8 subtracted by the p-value of Z when X = 167 - 3.8 = 163.2. So
X = 170.8
[tex]Z = \frac{X - \mu}{\sigma}[/tex]
By the Central Limit Theorem
[tex]Z = \frac{X - \mu}{s}[/tex]
[tex]Z = \frac{170.8 - 167}{\frac{20}{\sqrt{76}}}[/tex]
[tex]Z = 1.66[/tex]
[tex]Z = 1.66[/tex] has a p-value of 0.9515
X = 163.2
[tex]Z = \frac{X - \mu}{s}[/tex]
[tex]Z = \frac{163.2 - 167}{\frac{20}{\sqrt{76}}}[/tex]
[tex]Z = -1.66[/tex]
[tex]Z = -1.66[/tex] has a p-value of 0.0485
0.9514 - 0.0485 = 0.9029
0.9029 = 90.29% probability that the mean of the sample would differ from the population mean by less than 3.8 points if 76 exams are sampled
A seller of the property listed at $200,000 excepted a 90% offer the home appraised at $185,000 and the buyers obtained a loan for 85% for 30 years at 5% interest what is the first months interest
Answer:
$637.50
Step-by-step explanation:
According to the Question,
Given That, A seller of the property listed at $200,000 excepted a 90% offer the home appraised at $185,000 and the buyers obtained a loan for 85% for 30 years at 5% interestThus, the first months interest is
$200,000 list price x 0.90 = $180,000 contract sales price.
Since lender always uses the less of the appraised value or the contract sales price, use $180,00 for the remainder of the calculations.
$180,000 contract sales price x 0.85 LTV = $153,000 loan. $153,000 loan x 0.05 interest rate = $7,650 annual interest. $7,650 ÷ 12 = $637.50 monthly interest payment for the first month.Answer:
$637.50
Step-by-step explanation:
The appraised value is irrelevant. The lender will consider the lower of the appraised value or the agreed purchase price.
The term of the loan is also irrelevant. It is not an amortization problem.
The first month’s interest is $637.50.
The mean per capita consumption of milk per year is 131 liters with a variance of 841. If a sample of 132 people is randomly selected, what is the probability that the sample mean would be less than 133.5 liters
Answer:
0.8389 = 83.89% probability that the sample mean would be less than 133.5 liters.
Step-by-step explanation:
To solve this question, we need to understand the normal probability distribution and the central limit theorem.
Normal Probability Distribution:
Problems of normal distributions can be solved using the z-score formula.
In a set with mean [tex]\mu[/tex] and standard deviation [tex]\sigma[/tex], the z-score of a measure X is given by:
[tex]Z = \frac{X - \mu}{\sigma}[/tex]
The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the p-value, we get the probability that the value of the measure is greater than X.
Central Limit Theorem
The Central Limit Theorem establishes that, for a normally distributed random variable X, with mean [tex]\mu[/tex] and standard deviation [tex]\sigma[/tex], the sampling distribution of the sample means with size n can be approximated to a normal distribution with mean [tex]\mu[/tex] and standard deviation [tex]s = \frac{\sigma}{\sqrt{n}}[/tex].
For a skewed variable, the Central Limit Theorem can also be applied, as long as n is at least 30.
The mean per capita consumption of milk per year is 131 liters with a variance of 841.
This means that [tex]\mu = 131, \sigma = \sqrt{841} = 29[/tex]
Sample of 132 people
This means that [tex]n = 132, s = \frac{29}{\sqrt{132}}[/tex]
What is the probability that the sample mean would be less than 133.5 liters?
This is the p-value of Z when X = 133.5. So
[tex]Z = \frac{X - \mu}{\sigma}[/tex]
By the Central Limit Theorem
[tex]Z = \frac{X - \mu}{s}[/tex]
[tex]Z = \frac{133.5 - 131}{\frac{29}{\sqrt{132}}}[/tex]
[tex]Z = 0.99[/tex]
[tex]Z = 0.99[/tex] has a p-value of 0.8389
0.8389 = 83.89% probability that the sample mean would be less than 133.5 liters.
List the angles in order from the smallest to the largest.
Answer:
D. <S, <R, <T
Step-by-step explanation:
Recall: On a triangle, the bigger an angle measure the longer the side opposite it and vice versa.
In ∆RST,
The longest side, SR = 22, is opposite to <T
Therefore, <T is the biggest angle.
Medium side, ST = 21, is opposite to <R, therefore,
<R is the medium angle measure
The smallest angle measure <S is opposite to the shortest side, RT.
Angels I'm order form the smallest to largest will be:
<S, <R, <T
Name the following segment or point.
Given:
L, M, N are midpoints
orthocenter of triangle ABC
Answer:
P
Step-by-step explanation:
It's where the altitudes meet
What is the standard form equation of the quadratic function shown in this graph?
Answer:
A is the equation in standard form
Step-by-step explanation:
Winning the jackpot in a particular lottery requires that you select the correct two numbers between 1 and 65 and, in a separate drawing, you must also select the correct single number between 1 and 60. Find the probability of winning the jackpot.
Answer: 1/ 233856 chance changed to 233856 x 2 = 467712
= 1 / 467712 chance as there are 2 drawings
Workings;
1 and 65 = 64
1 and 65 - 1 ball drawn = 63
1 and 60 -1 = 58
1/64 x 1/63 x 1/58 = 233856
1/4032 x 1/58 and to make these the same we 4038/58 = 69.62
then convert properly = 1/4032 x 69.62/4032 4032 x 4032 = 69.62/16257024 then 16257024/69.62 =233510.83
= 233511 chance if rounding before
1/ (233511 x 2) = 1/467022
Then one part is our actual probability
P) = 1/233856
But as they specified a special drawing
you need to repeat this as 64 x 63 x 58 x 2 as the last one cannot be in 1 drawing it has to be in 2nd drawing
233856 x 2 = 467712
= 1 / 467712 chance not rounding down before hand.
A confided aquifer has a piezometric height of 30 feet before being pumped. The well is then pumped at 250 gallons/day for a very long time and results in a drawdown of 10 feet at the well. If the transmissivity in the aquifer is 10.0 ft2/day and the radius of the well is 0.5 feet, estimate the drawdown in feet for a well 50 feet away
Answer:
[tex]d_2=-8.32ft[/tex]
Step-by-step explanation:
From the question we are told that:
Height of first draw down [tex]h=30[/tex]
Pump Discharge [tex]Q=250gallons/day[/tex]
Well 1 depth [tex]d_1=10ft[/tex]
Transmissivity[tex]\=T 10.0 ft2/day[/tex]
Radius[tex]r=0.5[/tex]
Well 2 depth [tex]d_2=50ft[/tex]
Generally the Thiem's equation for Discharge is mathematically given by
[tex]Q=\frac{2\piT(h_2-h_1)}{ln(\frac{r_2}{r_1})}[/tex]
[tex]250=\frac{2*\pi 10 (10-d_2)}{ln(\frac{50}{0.5})}[/tex]
[tex]1151.293=2*\pi 10 (10-d_2)[/tex]
[tex]d_2=-8.32ft[/tex]
The length of a rectangle is 12 m and its diagonal is 15 m. find
the breadth and area of the rectangle.
Answer:
108 square metres
Step-by-step explanation:
A=√d square - l square
here
A = area
d= diagonal
l= length
Can you answer this an help me with this question an others ??
Answer:
D. The y-intercept of the new graph would shift down 2 units.
Step-by-step explanation:
y = -9x + 3 has a y-intercept of 3 (0, 3).
y = -9x + 1 has a y-intercept of 1 (0, 1).
3 - 1 = 2
So, down two units.
Find the approximate circumstance of a circle with a diameter of 80 yards
Answer:
251.33
Step-by-step explanation:
C=3.14(d)
C=3.14(80)
How many solutions are there for the system of nonlinear equations
represented by this graph?
10
8
0
4
2
-
BE
-10-8
-6
0
-2
-2
2
4
8
10
4
-
-8
-10
O A. Two
O B. None
C. One
the focus of a parabola is (-5,-1) and the directrix is y= -3.
what is an equation of the parabola? (one of the answered above)
Answer:
Step-by-step explanation:
-2
Evaluate the expression below for m=2/3 and n= 1/3
Answer:
Evaluación de expresiones y polinomios
Purplemath
"Evaluación" significa principalmente "simplificar una expresión a un solo valor numérico". A veces se le dará una expresión numérica, donde todo lo que tiene que hacer es simplificar; esa es más una cuestión de orden de operaciones. En esta lección, me concentraré en el aspecto de la evaluación de "conectar y tragar": introducir valores para las variables y "avanzar" hasta llegar a la respuesta simplificada.
(Por cierto, sí, "plug-n-chug" es una terminología bastante estándar. No es un término "técnico", por lo que probablemente no lo verá en su libro de texto, pero seguramente lo escuchará de otros estudiantes. , y quizás también su instructor.)
MathHelp.com
Evaluar expresiones en MathHelp.com
Evaluar expresiones
Por lo general, la única parte difícil de la evaluación es hacer un seguimiento de los signos "menos". Le recomiendo encarecidamente que utilice los paréntesis libremente, especialmente cuando recién está comenzando.
Evalúe a2b para a = –2, b = 3, c = –4 y d = 4.
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Para encontrar mi respuesta, simplemente conecto los valores dados, teniendo cuidado de usar paréntesis, particularmente alrededor de los signos "menos". Especialmente cuando recién estoy comenzando, dibujar los paréntesis primero puede ser útil:
a2 b
() 2 ()
(–2) 2 (3)
(4) (3)
12
Observe cómo el uso de paréntesis me ayudó a realizar un seguimiento del signo "menos" en el valor de a. Esto era importante, porque de otro modo podría haber elevado al cuadrado solo el 2, terminando con –4, lo que habría estado mal.
Por cierto, resultó que no necesitábamos los valores de las variables c y d. Cuando se le da un gran conjunto de expresiones para evaluar, debe esperar que a menudo haya una u otra de las variables que no se incluirán en ningún ejercicio en particular del conjunto.
Evalúe a - cd para a = –2, b = 3, c = –4 y d = 4.
En este ejercicio, me dieron información adicional. No hay una b en la expresión que quieren que evalúe, por lo que puedo ignorar este valor en mi trabajo:
(–2) - (–4) (4)
–2 - (–16)
–2 + 16
16 - 2
14
Step-by-step explanation:
hola
Can someone help me out here please? I do not know how to solve this problem nor where to start?
Answer:
200 test tubes will fill the container
Step-by-step explanation:
Hi there!
We need to find out how many 5 milliliter tubes will fill a 1 liter container
First, let's convert everything to the same unit, as the tubes and the container are in different units.
Let's do milliliters, as those are smaller than liters and we will avoid having decimals.
there are 1,000 milliliters in a liter (the unit prefix "milli-" means "thousand")
Let's say the number of test tubes needed to fill the container is x
As each tube has 5 milliliters of water, 5x milliliters will equal 1,000 milliliters (1 liter)
as an equation, that's
5x=1,000
divide both sides by 5
x=200
So that means 200 test tubes will fill the container
Hope this helps! :)
Answer:
Here is how to start
Step-by-step explanation: 7 2 13 42
1 milliliter is one one thousands of a liter 1 milliliter = 0.001 liter
1000 milliliter is equal to 1 liter
How many 5 milliliter test tubes are in 1 liter?
1000 milliliter / 5 milliliter per test tube = ________ test tubes
X^2-y^2=k need the answer
Answer:
Let's solve for k.
x2−y2=k
Step 1: Flip the equation.
k=x2−y2
Answer:
k=x2−y2
Step-by-step explanation:
Which of the following lists of ordered pairs is a function? A. (1,8), (2, 9), (3, 10), (3, 11) B. (-1,4), (1,7), (2, 10) C. (3,7),(4, 5), (3, 8) D. (-2,3), (1, 3), (3, 7), (1, 4)
Answer:
B
Step-by-step explanation:
B is the only one that doesnt share x-values
Identify the level of measurement of the data, and explain what is wrong with the given calculation. Ina set of data, alert levels are represented as 1 for low, 2 for medium, and 3 for high. The average mean of the 522 alert levels is 1.3. The data are at the ________ level of measurement. a. Nominalb. Ordinalc. Ratiod. IntervalWhat is wrong with the given calculation?a. Such data should not be used for calculations such as an average.b. One must use a different method to take the average of such datac. The true average is 2.5d. There is nothing wrong with the given calculation.
Answer:
(1) Ordinal
(2) Such data should not be used for calculations such as an average.
Step-by-step explanation:
Given
[tex]1 \to Low[/tex]
[tex]2 \to Medium[/tex]
[tex]3 \to High[/tex]
[tex]Average = 1.3[/tex]
Solving (a): The level of measurement
When observations are presented in ranks such as:
[tex]1 \to Low[/tex]
[tex]2 \to Medium[/tex]
[tex]3 \to High[/tex]
The level of measurement of such observation is ordinal
Solving (b): What is wrong with the computation?
Ordinal level of measurement are not numerical values whose average can be calculated because they are used as ranks.
Hence, (a) is correct
Give at least four different symbols that have been used to represent specific statistical measures. Describe what measure each represents.
can you show a picture of the symbols
