Answer:
1568
Step-by-step explanation:
The computation of the minimum sample size is shown below:
Given that
Error E = 11
The population standard deviation [tex]\sigma[/tex] =217
Confidence level 1-α = 95%
Now following formula should be used
n > (Zalpha ÷ 2 × sigma ÷ E)^2
As we know that
Zalpha ÷ 2= 1.96
Now the sample size is
n> (1.96 × 202 ÷ 10)^2
= 1568
o The day before the exam, Rebecca does a practice run. She attempts 20 glass vases and breaks 3 of them. What is her success rate, shown as a decimal?
Answer:
If the goal is to break the vases: 3/20 = 15.0% or 0.15
If the goal is to not break the vases: 17/20 = 85.0% or 0.85
Find the value of x in the parallelogram below.
Answer:
B) x = 12
Step-by-step explanation:
m∡EOU = m∡TQE
m∡EOU =180 - (39+45) = 96°
m∡TQE: 7x + 12 = 96
7x = 84
x = 12
answer of the question
Answer:
The number of milk chocolate pieces is between 115 and 120 pieces.
Step-by-step explanation:
Pls answer just the answer
Answer:
588000
Step-by-step explanation:
if i am wrong pls tell me cause i think there's a different answer gl g
Answer:
$103,421.88
Step-by-step explanation:
Given:
P = 70000
r = 0.05
n = 1
t = 8
Work:
[tex]A=P(1+\frac{r}{n} )^{nt}\\\\A=70000(1+\frac{0.05}{1} )^{1*8}\\\\A=70000(1.05)^8\\\\A=103421.88[/tex]
Of the 31 teachers at Keenan's high school, 14 are female. What is the ratio of the number of female teachers to the number of male teachers?
Answer:
The answer is 14:17
Step-by-step explanation:
31-14 is 17 and 14 are female and 17 are male so we do 14:17
Please help meeeeeeeeeeeeeeeee
Answer:
Step-by-step explanation:
h = 4.2 in
Volume = 3.6 cubic inches
[tex]\frac{1}{3}\pi r^{2}h = 3.6\\\\\frac{1}{3}*3.14*r^{2}*4.2 = 3.6\\\\r^{2}= \frac{3.6*3}{3.14*4.2}\\\\ = 0.81\\r=\sqrt{0.81}\\\\[/tex]
r = 0.9 in
Answer:
.... ..................
A manufacturer of potato chips would like to know whether its bag filling machine works correctly at the 434 gram setting. It is believed that the machine is underfilling the bags. A 9 bag sample had a mean of 431 grams with a variance of 144. A level of significance of 0.01 will be used. Assume the population distribution is approximately normal. Is there sufficient evidence to support the claim that the bags are underfilled
Answer:
No, there is not sufficient evidence to support the claim that the bags are underfilled
Step-by-step explanation:
A manufacturer of potato chips would like to know whether its bag filling machine works correctly at the 434 gram setting.
This means that the null hypothesis is:
[tex]H_{0}: \mu = 434[/tex]
It is believed that the machine is underfilling the bags.
This means that the alternate hypothesis is:
[tex]H_{a}: \mu < 434[/tex]
The test statistic is:
[tex]z = \frac{X - \mu}{\frac{\sigma}{\sqrt{n}}}[/tex]
In which X is the sample mean, [tex]\mu[/tex] is the value tested at the null hypothesis, [tex]\sigma[/tex] is the standard deviation and n is the size of the sample.
434 is tested at the null hypothesis:
This means that [tex]\mu = 434[/tex]
A 9 bag sample had a mean of 431 grams with a variance of 144.
This means that [tex]X = 431, n = 9, \sigma = \sqrt{144} = 12[/tex]
Value of the test-statistic:
[tex]z = \frac{X - \mu}{\frac{\sigma}{\sqrt{n}}}[/tex]
[tex]z = \frac{431 - 434}{\frac{12}{\sqrt{9}}}[/tex]
[tex]z = -0.75[/tex]
P-value of the test:
The pvalue of the test is the pvalue of z = -0.75, which is 0.2266
0.2266 > 0.01, which means that there is not sufficient evidence to support the claim that the bags are underfilled.
