In the coordinate plane, two vertices of square ABCD are A (0, 0) and B (0, m). What are the coordinates of points C and D? Do not introduce any new variables.

Even function:

A function is said to be even if its graph is symmetric with respect to the , that is:

Odd function:

A function is said to be odd if its graph is symmetric with respect to the origin, that is:

So let's analyze each question for each type of functions using examples of polynomial functions. Thus:

FOR EVEN FUNCTIONS:

1. When  becomes  

1.1 Effects on the y-intercept

We need to find out the effects on the y-intercept when shifting the function  into:

We know that the graph  intersects the y-axis when , therefore:

So:

So the y-intercept of  is one unit less than the y-intercept of

1.2. Effects on the regions where the graph is increasing and decreasing

Given that you are shifting the graph downward on the y-axis, there is no any effect on the intervals of the domain. The function  increases and decreases in the same intervals of

1.3 The end behavior when the following changes are made.

The function is shifted one unit downward, so each point of  has the same x-coordinate but the output is one unit less than the output of . Thus, each point will be sketched as:

FOR ODD FUNCTIONS:

2. When  becomes  

2.1 Effects on the y-intercept

In this case happens the same as in the previous case. The new y-intercept is one unit less. So the graph is shifted one unit downward again.

An example is shown in Figure 1. The graph in blue is the function:

and the function in red is:

So you can see that:

2.2. Effects on the regions where the graph is increasing and decreasing

The effects are the same just as in the previous case. So the new function increases and decreases in the same intervals of

In Figure 1 you can see that both functions increase at:

and decrease at:

2.3 The end behavior when the following changes are made.

It happens the same, the output is one unit less than the output of . So, you can write the points just as they were written before.

So you can realize this concept by taking a point with the same x-coordinate of both graphs in Figure 1.

FOR EVEN FUNCTIONS:

3. When  becomes  

3.1 Effects on the y-intercept

We need to find out the effects on the y-intercept when shifting the function  into:

As we know, the graph  intersects the y-axis when , therefore:

And:

So the new y-intercept is the negative of the previous intercept shifted one unit upward.

3.2. Effects on the regions where the graph is increasing and decreasing

In the intervals when the function  increases, the function  decreases. On the other hand, in the intervals when the function  decreases, the function  increases.

3.3 The end behavior when the following changes are made.

Each point of the function  has the same x-coordinate just as the function  and the y-coordinate is the negative of the previous coordinate shifted one unit upward, that is:

FOR ODD FUNCTIONS:

4. When  becomes  

4.1 Effects on the y-intercept

In this case happens the same as in the previous case. The new y-intercept is the negative of the previous intercept shifted one unit upward.

4.2. Effects on the regions where the graph is increasing and decreasing

In this case it happens the same. So in the intervals when the function  increases, the function  decreases. On the other hand, in the intervals when the function  decreases, the function  increases.

4.3 The end behavior when the following changes are made.

Similarly, each point of the function  has the same x-coordinate just as the function  and the y-coordinate is the negative of the previous coordinate shifted one unit upward.

Answer:

x = 91

Step-by-step explanation:

Opposite angles of an inscribed quadrilateral are supplementary.

x + 89 = 180

x = 91

Answer:

1. The third quartile

2. The quartile

3. Four

4. 25

5. The second quartile, Q₂

6. 20th percentile

7. Decile

8. Percentile

9. D₈

10. The third quartile, Q₃

Step-by-step explanation:

1. The other term(s) for Q₃ is third quartile (or upper quartile). It is the mid point between the distribution's largest number and the median

2. The measure of position divided into four equal parts is the quartile

3. The quartile is the division of the data at three points (Q₁, Q₂, and Q₃) into four equal parts equal parts

4. Q₁, which is the first quartile is equivalent to the 25th percentile

5. The other term for the median is the second quartile, Q₂

6. D₂ which is the second decile (a decile divides the data into 10 equal parts) is equivalent to 20th percentile

7. The decile, D, divides a given data into 10 equal parts

8. The percentile divides a given data into 100 equal parts

9. The decile equivalent to P80, which is the 80th percentile, is D₈

10. The quartile equivalent to P75, which is the 75th percentile or the three quarter mark point of the data is equivalent to the the third quartile, Q₃

[tex]\displaystyle\ 2x^2+7x+5\sqrt{2} =0 \\\\\boxed{D=7^2-4\cdot2\cdot 5\sqrt{2} =49-40\sqrt{2} }[/tex]

Answer:

5%

.35x = 2800

x = 8000

p(160,000)=8000

p=.05 = 5%

Step-by-step explanation:

Step-by-step explanation:

hope it helps thnak you

brainliest pls ❤

Answer:

x = 25.5

Step-by-step explanation:

suppose RS and MQ are parallel the sum of angle MRS and RMN would be 180 degrees

2x + x + x 78 = 180 add like terms then subtract 78 from both sides

4x = 102 divide both sides by 4

x = 25.5

Answer:

[tex]{ \tt{f(x) = 2}} \\ when \: y = 2 \\ { \bf{x = - 0.5}}[/tex]

Answer:

17.5

Step-by-step explanation:

as the triangles are similar, when oriented in the same direction they have the same angles, and the lengths of all sides of DEF are the lengths of the sides of ABC but multiplied by the same scaling factor f for all sides.

so, we see that

A ~ D

B ~ E

C ~ F

and therefore

AB ~ DE

BC ~ EF

CA ~ FD

that means

DE = AB × f

EF = BC × f

FD = CA × f

we know DE and AB.

so,

4 = 10 × f

f = 4/10 = 2/5

and now we know

EF = 7 = BC × f

BC = 7/f = (7/1) / (2/5) = (5×7)/(2×1) = 35/2 = 17.5

Answer:

17.5

Step-by-step explanation:

Answer:

Step-by-step explanation:

Here's the game plan. In order to find a point on the x-axis that makes AC = BC, we need to find the midpoint of AB and the slope of AB. From there, we can find the equation of the line that is perpendicular to AB so we can then fit a 0 in for y and solve for x. This final coordinate will be the answer you're looking for. First and foremost, the midpoint of AB:

and

Now for the slope of AB:

and

 So if the slope of AB is 1/3, then the slope of a line perpendicular to that line is -3. What we are finding now is the equation of the line perpendicular to AB and going through (0, 3):

and filling in:

y - 3 = -3(x - 0) and

y - 3 = -3x + 0 and

y - 3 = -3x so

y = -3x + 3. Filling in a 0 for y will give us the coordinate we want for the x-intercept (the point where this line goes through the x-axis):

0 = -3x + 3 and

-3 = -3x so

x = 1

The coordinate on the x-axis such that AC = BC is (1, 0)

Answer:

AB= A. (50)^1/2

BC= B. (65)^1/2

AC= D. (145)^1/2

<ABC≈ 105

Answer:

y = 7x and y = 28

Step-by-step explanation:

Given y varies directly with x then the equation relating them is

y = kx ← k is the constant of variation

To find k use the condition y = 56 when x = 8 , then

56 = 8k ( divide both sides by 8 )

7 = k

y = 7x ← equation of variation

When x = 4

y = 7 × 4 = 28

Answer:

the answer is probably complicated but this is POSSIBLY similar to your problem

Step-by-step explanation:

x^2 - 1x - 3x + 3

x^2 - 4x + 3

Answer:

3√2

Step-by-step explanation:

* means multiply

-7√2 + 10 √2

take √2 out of the expression

√2 (-7 + 10)

√2 (3)

3√2

Answer:

[tex]\begin{array}{cccccc}x & {0} & {1} & {2} & {3} & {4} \ \\ P(x) & {0.0256} & {0.1536} & {0.3456} & {0.3456} & {0.1296} \ \end{array}[/tex]

Step-by-step explanation:

Given

[tex]p = 60\%[/tex]

[tex]n = 4[/tex]

Required

The distribution of x

The above is an illustration of binomial theorem where:

[tex]P(x) = ^nC_x * p^x *(1 - p)^{n-x}[/tex]

This gives:

[tex]P(x) = ^4C_x * (60\%)^x *(1 - 60\%)^{n-x}[/tex]

Express percentage as decimal

[tex]P(x) = ^4C_x * (0.60)^x *(1 - 0.60)^{n-x}[/tex]

[tex]P(x) = ^4C_x * (0.60)^x *(0.40)^{4-x}[/tex]

When x = 0, we have:

[tex]P(x=0) = ^4C_0 * (0.60)^0 *(0.40)^{4-0}[/tex]

[tex]P(x=0) = 1 * 1 *(0.40)^4[/tex]

[tex]P(x=0) = 0.0256[/tex]

When x = 1

[tex]P(x=1) = ^4C_1 * (0.60)^1 *(0.40)^{4-1}[/tex]

[tex]P(x=1) = 4 * (0.60) *(0.40)^3[/tex]

[tex]P(x=1) = 0.1536[/tex]

When x = 2

[tex]P(x=2) = ^4C_2 * (0.60)^2 *(0.40)^{4-2}[/tex]

[tex]P(x=2) = 6 * (0.60)^2 *(0.40)^2[/tex]

[tex]P(x=2) = 0.3456[/tex]

When x = 3

[tex]P(x=3) = ^4C_3 * (0.60)^3 *(0.40)^{4-3}[/tex]

[tex]P(x=3) = 4 * (0.60)^3 *(0.40)[/tex]

[tex]P(x=3) = 0.3456[/tex]

When x = 4

[tex]P(x=4) = ^4C_4 * (0.60)^4 *(0.40)^{4-4}[/tex]

[tex]P(x=4) = 1 * (0.60)^4 *(0.40)^0[/tex]

[tex]P(x=4) = 0.1296[/tex]

So, the probability distribution is:

[tex]\begin{array}{cccccc}x & {0} & {1} & {2} & {3} & {4} \ \\ P(x) & {0.0256} & {0.1536} & {0.3456} & {0.3456} & {0.1296} \ \end{array}[/tex]

Answer:

y=43x-210

Step-by-step explanation:

Distribute 43

then add five on each side

you get y=43x-210, 43 and 210 cannot be sipilified so that is the answer.

Answer:

y=43x-210

Step-by-step explanation:

Distribute 43 through the parenthesis.

y-5=43x-215

Move the constant to the right and change its sign.

y=43x-215+5

Calculate sum.

y=43x-210

Hope i helped :)

Answer:

([tex]\frac{-7}{3}[/tex], [tex]\frac{4}{3}[/tex])

Step-by-step explanation:

Hi there!

We are given the following system of equations:

-3x-3y=3

-5x+y=13

and we need to find the solution (the point at which the 2 lines intersect)  

let's solve this by substitution, where we will set one variable equal to an expression containing the other variable, and then substitute that expression into the other equation to solve for the variable that the expression from earlier contains, and then use the value of the solved variable to find the value of the first variable

in the second equation, add 5x to both sides to isolate y by itself

y=5x+13

now substitute 5x+13 as y in -3x-3y=3

-3x-3(5x+13)=3

do the distributive property

-3x-15x-39=3

combine like terms

-18x-39=3

add 39 to both sides

-18x=42

divide both sides by -18

x=[tex]\frac{-7}{3}[/tex]

now we need to find y

remember: y=5x+13

substitute [tex]\frac{-7}{3}[/tex] as x in y=5x+13

y=5([tex]\frac{-7}{3}[/tex])+13

multiply

y=[tex]\frac{-35}{3}[/tex]+13

add

y=[tex]\frac{4}{3}[/tex]

So the answer is x=[tex]\frac{-7}{3}[/tex], y=[tex]\frac{4}{3}[/tex]. As a point, it's ([tex]\frac{-7}{3}[/tex], [tex]\frac{4}{3}[/tex])

Hope this helps! :)

Answer:

well I'm not gonna explain it but

#1 is C or the 3rd one (DOMIAN)

#2 is B or the second one (RANGE)

Answer:

DOMAIN OF THE FUNCTION :-

all real numbers

RANGE :-

all real numbers greater than or equal to - 2

as we the graph's vertex is at -2 so basically -2 is the lowest value of the function.

Answer:

There are 325 seats in each row

Step-by-step explanation:

78 × 325 = 25,350

Answer:

Segment XY congruent to Segment IJ is required.

Step-by-step explanation:

It's asking for Side-Angle-Side postulate and you already have a side and an angle. WX=HI and <x=<I. Order matters, so the angle should be directly between the first set of segments and the second.

Answer:

x + (x-42.2) = 90

2x - 42.2 = 90

add 42.2 to both sides

2x = 132.2

divide each side by 2

x = 66.1

find the measure of the other angle

66.1 - 42.2 = 23.9

Step-by-step explanation:

Answer:

66.1° and 23.9°

Step-by-step explanation:

Complementary angles are angles that sum up to 90°

So equation : x + x - 42.2 = 90

2x - 42.2 = 90

2x = 132.2

x = 66.1

66.1° is the "other complementary angle"

This angle is 66.1 - 42.2 = 23.9°

If my answer is incorrect, pls correct me!

If you like my answer and explanation, mark me as brainliest!

-Chetan K

Answer:

Null set

Step-by-step explanation:

Odd(0)

Even (E)

Prime (P)

Answer:

Its A since the other person didnt say it

Step-by-step explanation:

Answer:

270 & 30

Step-by-step explanation:

let the number is n,

the equation :

n× 1/9 n= 27(n +1/9 n)

1/9 n² = 27n + 3n

1/9 n² = 30n

1/9n²- 30n = 0

n(1/9n -30)= 0

n = 0 or

1/9n = 30 => n = 30×9 = 270

270 is a number,

the other : 270/9 = 30

Answer:

Step-by-step explanation:

1.

7 > 0.7 > 0.07 > 0.007

2.

5h - 15hg

taking 5h common

5h (1 - 3g)

3.

5(2x- 1) = 35

dividing both sides by 5

2x - 1 = 7

2x = 7 + 1

2x = 8

x = 4

4.

if x is an odd number x + 2 will also be odd.

for example

11 is an odd number

on adding 2 we get 13 which is also an odd number.

Answer:

Step-by-step explanation:

First of all the first term is a1 and that's equal to -3

Every term is multiplied by 7

So the recursive formula is

an = 7*a_(n-1)

a2 = 7*a_(1 -1)

a2 = 7*-3

a2 = - 21

Now try a_4

a_4 = 7*a_3

a_3 = -147

a_4 = 7*(-147)

a_4 = -1029

Answers:

Domain = {-1, 2, 1, 8, 9}

Range = {2, 51, 3, 22}

==================================

Explanation:

The domain is the set of allowed inputs of a function. So it's the set of possible x values. We simply list the x coordinates of each point to form the domain.

The range is the set of possible y values or y outputs. So we simply list the y coordinates of the points. We toss out any duplicates. Since order doesn't matter in a set, we can have the values listed any way we want.

Side notes:

Answer:

La ecuación genérica para un círculo centrado en el punto (a, b), de radio R, es:

(x - a)^2 + (x - b)^2 = R^2

Entonces si miramos a nuestra ecuación:

(x + 2)^2 + (y - 3)^2 = 121

Tendremos el centro en:

(-2, 3)

el radio está dado por:

R^2 = 121

R = √121 = 11

La gráfica de esta circunferencia se puede ver en la imagen de abajo.

Answer:

1 day=10outfits

5days=10outfits×5

=50outfits

Step-by-step explanation:

hope this is helpful

Based on the calculation, you can wear the 10 outfits in 50 different ways throughout the week.

To calculate the number of ways you can wear 10 outfits to school each day in a 5-day week, you need to consider the total number of outfits across all days. Since there are 10 outfits and 5 days, the total number of outfit combinations can be calculated by multiplying the number of outfits per day by the number of days:

10 outfits/day × 5 days = 50 outfit combinations

Therefore, you can wear the 10 outfits in 50 different ways throughout the week.

Learn more about permutations

https://brainly.com/question/4658834

#SPJ2

Answer:

16.26°

Step-by-step explanation:

1. tanΘ= 7/24

2.[tex]tan^-1(\frac{7}{24} ) =[/tex]Θ

3. Θ = 16.26°