In the Diagram, DEC is a ____ of ABC across line k.

rotation
glide reflection
reflection
translation

In The Diagram, DEC Is A ____ Of ABC Across Line K.rotationglide Reflectionreflection Translation

Answers

Answer 1

Answer:

Reflection

Step-by-step explanation:

A reflection is a mirrored image of a shape.  Notice how DEC seems to be a "flipped" version of ABC, hence a mirrored image.

Cheers.


Related Questions

Use the drop-down menus to label the graph according to its type. On a coordinate plane, a graph has two straight lines that connect at (0, 0). One line has a positive slope from (0, 0) going through (3, 2) and the other has a negative slope from (0,0) going through (4, negative 3). The graph above:

Answers

The point of intersection of the graph of y = (2/3)x and y = (-3/4)x is at point (0, 0).

What is an equation?

An equation is an expression that shows the relationship between two or more numbers and variables.

The straight line passing through (0, 0) and (3, 2) have an equation of y = (2/3)x while the straight line passing through (0, 0) and (4, -3) have an equation of y = (-3/4)x

The point of intersection of the graph of y = (2/3)x and y = (-3/4)x is at point (0, 0).

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Answer:

Relation (But not a function) Your welcome.

Step-by-step explanation:

Michael is drawing a card from a standard 52-card deck, which includes 4 aces: the ace of clubs, the ace of diamonds, the ace of hearts, and the ace of spades. For each trial, he drews a card, records which cards he drew, and returns it to the deck. He draws an ace 240 times

Answers

Michael is drawing a card from a standard 52-card deck, which includes 4 aces: the ace of clubs, the ace of diamonds, the ace of hearts, and the ace of spades. For each trial, he draws a card, records which cards he drew, and returns it to the deck. He draws an ace 240 times

Of the times he draws an ace, which of the following would be a good estimate for the number of times the ace drawn is the ace of hearts?

Answer:

Step-by-step explanation:

From the information:

Let consider the following variables,

assume p to be the number of times an ace was drawn,

also, q should be the number of aces  and r to be the number of outcomes.

Thus ;

[tex]\mathtt{r = \dfrac{p}{q}}[/tex]

where;

p = 240

q = 4

[tex]\mathtt{r = \dfrac{240}{4}}[/tex]

r = 60

It is literally unlikely that exactly 25% of the drawings are going to be the ace of hearts, therefore, the best answer will be 60 or the value closest to 60

A boy is twice as tall as his little sister and he is 30 cm shorter than his father. The
combined height of these three family members is 3.8m.Write an appropriate
equation, using h' as the sister's height and use this to find the boy's height in cm.​

Answers

Boy = x

His Sister = y

Father = z

x = 2*y  

y = x/2

x = z-30 or z = x+30

3.8 m = 380 cm

x+y+z = 380

x + x/2 + x+30 = 380

multiply by 2

2x +x + 2x +60 = 760

5x = 700

x = 140 cm

y = x/2

 = 140 /2 = 70 cm

z = x+30

 = 140 + 30 = 170 cm

There  

x (Boy)             = 140 cm

y (His Sister)  = 70 cm

z (Father)        = 170 cm

Using an appropriate equation, the boy's height is 140  cm.​

What is a system of equations?

A system of equations is two or more equations that can be solved to get a unique solution. the power of the equation must be in one degree.

Let Boy = x and His Sister = y

Father = z

So, x = 2*y  

y = x/2

x = z-30 or z = x+30

Now, substitute

3.8 m = 380 cm

Equation form;

x+y+z = 380

x + x/2 + x+30 = 380

then multiply by 2

2x +x + 2x +60 = 760

5x = 700

x = 140 cm

Thus,

y = x/2 = 140 /2 = 70 cm

z = x+30 = 140 + 30 = 170 cm

There  are x (Boy) = 140 cm

y (His Sister)  = 70 cm

z (Father)   = 170 cm

Hence, Using an appropriate equation, the boy's height is 140  cm.​

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A circle is circumscribed around a square and another circle is inscribed in the square. If the area of the square is 9 in2, what is the ratio of the circumference of the circumscribed circle to the one of the inscribed?

Answers

Answer:

√2:1

Step-by-step explanation:

First we need to know that the length of the side of the square is equal to the diameter of the inscribed circle i.e

L = di

Given the area of the square to be 9in², we can get the length of the square.

Area of a square = L²

L is the length of the square.

9 = L²

L = √9

L = 3in

Hence the length of one side of the square is 3in

This means that the diameter of the inscribed circle di is also 3in.

Circumference of a circle = π×diameter of the circle(di)

Circumference of inscribed circle = π×3

= 3π in

For the circumscribed circumscribed circle, diameter of the outer circle will be equivalent to the diagonal of the square.

To get the diagonal d0, we will apply the Pythagoras theorem.

d0² = L²+L²

d0² = 3²+3²

d0² = 9+9

d0² = 18

d0 = √18

d0 = √9×√2

d0 = 3√2 in

Hence the diameter of the circumscribed circle (d0) is 3√2 in

Circumference of the circumscribed circle = πd0

= π(3√2)

= 3√2 π in

Hence, ratio of the circumference of the circumscribed circle to the one of the inscribed will be 3√2 π/3π = √2:1

The city soccer club has thirteen new members and fifty-two returning members. If they break up into teams of eleven players, how many complete teams would there be?

Answers

Answer:

5

Step-by-step explanation:

The easiest way to do this is to add the new members to the old and then divide by 11. Ignore the remainder.

13 + 52 = 65

65 / 11 = 5 with 10 left over. Ignore the 10. That's not a complete team.

The answer is 5

What are the domain and range of the real-valued function f(x)=2/(x+5)?

Answers

Answer:

Domain is all real numbers, x ≠ -5

Range is all real numbers, y ≠ 0

Step-by-step explanation:

Domain: all real numbers except x=-5
(-infinity, -5)U(-5, infinity)

Range: all real numbers except y=0
(-infinity, 0)U(0, infinity)

A square of side 40 cm and a rectangle of length 50 cm has the same perimeter. Which has greater area? Please write the answer with steps.

Answers

Answer: The square has greater area

Explanation:

P(square) = 40 x 4 = 160

Find width of rectangle:

2(50 + W) = 160 (P(square) = P(rectangle)
100 + 2W = 160
2W = 60
W = 30

Find area of square:

A = 40 x 40 = 1600cm^2

Find area of rectangle:

A = 50 x 30 = 1500cm^2

Therefore, the area of square is greater than rectangle.

Answer:

[tex]\huge\boxed{The\ area\ of\ square\ is\ greater.}[/tex]

Step-by-step explanation:

Perimeter of Square:

P = 4(Length)

P = 4(40)

P = 160 cm

This means that the rectangle also has a perimeter of 160 cm

So, Finding the width of rectangle by Perimeter formula:

2L + 2W = Perimeter

2(50) + 2W = 160

100 + 2W = 160

Subtracting 100 to both sides

2W = 60

Dividing both sides by 2

W = 30

Now, Area of Square:

Area = Length * Length

Area = 40 * 40

Area = 1600 cm²

Area of Rectangle:

Area = Length * Width

Area = 50 * 30

Area = 1500 cm²

When we compare both of the area of the figure, we come to know that the area of square is greater.

| Find the quadratic polynomial whose
Sum and products of zeros are 21/8 and 5/16

Answers

Answer:

[tex]16x^{2} -42x+5[/tex]

Step-by-step explanation:

Sum of its zeroes=[tex]\alpha +\beta =\frac{21}{8} \\[/tex]

Product of its zeroes=[tex]\alpha \beta[/tex]=[tex]\frac{5}{16}[/tex]

Formula to form a quadratic polynomial:

[tex]p(x)=k[x^{2} -(\alpha +\beta )x+\alpha \beta ][/tex]

p(x)=[tex]k[x^{2} -(\frac{21}{8} )x+\frac{5}{16}][/tex]

p(x)=[tex]16[x^{2} -(\frac{21}{8} )x+\frac{5}{16}][/tex]

p(x)=[tex][16x^{2} -42x+5][/tex]

The quadratic polyniomial is [tex]16x^{2}-42x+5[/tex]

Newly planted seedlings approximately double their weight every week. If a seedling weighing 5 grams is planted at time t=0 weeks, which equation best describes its weight, W, during the first few weeks of its life?

Answers

Answer:

[tex]W(t)=5(2^t)[/tex]

Step-by-step explanation:

Given that the Newly planted seedlings approximately double their weight every week and a seedling weighing 5 grams is planted at time t = 0 weeks. This represent an exponential function with an equation in the form:

[tex]W(t)=ab^t[/tex].

W(t) is the weight in t weeks, t is the weeks and a is the weight when t = 0. At t = 0, W = 5 g:

[tex]W(t)=ab^t\\W(0)=ab^0\\5=ab^0\\a=5[/tex]

Since the weight double every week, b = 2. The exponential function is given as:

[tex]W(t)=ab^t\\\\W(t)=5(2^t)[/tex]

Complex numbers
[ = square root symbol

-[-64
How would I find this?

Answers

[tex]-\sqrt{-64}=-\sqrt{8^2\cdot (-1)}-8\sqrt{-1}=-8i[/tex]

The body paint, an automobile body paint shop, has determined that the painting time of automobiles is uniformly distributed and that the required time ranges between 45 minutes to 11/2hours.


What is the probability that the painting time will be less than or equal to an hour?

What is the probability that the painting time will be more than 50 minutes?

Determine the expected painting time and its standard deviation.

Answers

Answer:

a. [tex]\mathbf{P(Y \leq 60) = 0.3333}[/tex]

b. P(Y>50) = 0.8889

c. E(y) = 67.5 and  Standard deviation [tex]\sigma[/tex] = 12.99

Step-by-step explanation:

From the information given :

an automobile body paint shop, has determined that the painting time of automobiles is uniformly distributed and that the required time ranges between 45 minutes to [tex]1\frac{1}{2}[/tex]hours.

The objective is to determine  the probability that the painting time will be less than or equal to an hour?

since 60 minutes make an hour;

[tex]1\frac{1}{2}[/tex]hours = 60 +30 minutes = 90 minutes

Let Y be the painting time of the automobile; then,

the probability that  the painting time will be less than or equal to an hour ca be  computed as :

[tex]P(Y \leq 60) = \int ^{60}_{45} f(y) dy \\ \\ \\ P(Y \leq 60) = \int ^{60}_{45} \dfrac{1}{45} dy \\ \\ \\ P(Y \leq 60) = \dfrac{1}{45} \begin {pmatrix} x\end {pmatrix}^{60}_{45} \\ \\ \\ P(Y \leq 60) = \dfrac{60-45}{45 } \\ \\ \\ P(Y \leq 60) = \dfrac{15}{45} \\ \\ \\ P(Y \leq 60) = \dfrac{1}{3} \\ \\ \\ P(Y \leq 60) = 0.3333[/tex]

What is the probability that the painting time will be more than 50 minutes?

The probability that the painting will be more than 50 minutes is P(Y>50)

So;

[tex]P(Y>50) = \int \limits ^{90}_{50} f(y) dy[/tex]

[tex]P(Y>50) = \int \limits ^{90}_{50} \dfrac {1}{45} dy[/tex]

[tex]P(Y>50) = \dfrac{1}{45}[x]^{90}_{50}[/tex]

[tex]P(Y>50) = (\dfrac{90-50}{45})[/tex]

[tex]P(Y>50) = \dfrac{40}{45}[/tex]

P(Y>50) = 0.8889

Determine the expected painting time and its standard deviation.

Let consider E to be the expected painting time

Then :

[tex]E(y) = \int \limits ^{90}_{45} y f(y) dy \\ \\ \\ E(y) = \int \limits ^{90}_{45} y \dfrac{1}{45} dy \\ \\ \\ E(y) = \dfrac{1}{45} [\dfrac{y^2}{2}]^{90}_{45} \\ \\ \\ E(y) = \dfrac{1}{45}[\dfrac{(90^2-45^2)}{2}] \\ \\ \\ E(y) = \dfrac{1}{45} (\dfrac{6075}{2}) \\ \\ \\ E(y) = \dfrac{1}{45} \times 3037.8 \\ \\ \\ \mathbf{E(y) = 67.5}[/tex]

[tex]E(y^2) = \int \limits ^{90}_{45} y^2 f(y) dy \\ \\ \\ E(y^2) = \int \limits ^{90}_{45} y^2 \dfrac{1}{45} dy \\ \\ \\ E(y^2) = \dfrac{1}{45} [\dfrac{y^3}{3}]^{90}_{45} \\ \\ \\ E(y^2) = \dfrac{1}{45}[\dfrac{(90^3-45^3)}{3}] \\ \\ \\ E(y^2) = \dfrac{1}{45} (\dfrac{637875}{3}) \\ \\ \\ E(y^2) = \dfrac{1}{45} \times 2126.25 \\ \\ \\ \mathbf{E(y^2) = 4725}[/tex]

To determine the standard deviation, we need to first know what is the value of our variance,

So:

Variance [tex]\sigma^2[/tex] = E(x²) - [E(x)]²

Variance [tex]\sigma^2[/tex] = 4725 - (67.5)²

Variance [tex]\sigma^2[/tex] = 4725 - 4556.25

Variance [tex]\sigma^2[/tex] = 168.75

Standard deviation [tex]\sigma[/tex] = [tex]\sqrt{variance}[/tex]

Standard deviation [tex]\sigma[/tex] = [tex]\sqrt{168.75}[/tex]

Standard deviation [tex]\sigma[/tex] = 12.99

1 liter of ink can print 5000 pages of text. If you had 100 gallons of ink then how many pages could you print?

Answers

Answer:

500,000 pages

Step-by-step explanation:

1 / 5000 = 100 / x

x = 5000(100)

x = 500,000

Answer:

1892705 pages of text.

Step-by-step explanation:

g=Gallon

L=Liters

P=Pages

1L=5000p

1g=3.78541L

100g·3.78541L=378.541L

378.541L·5000=1892705

-8+4x-12=-4(2x-8) help me plz

Answers

Answer:

x = 13/3

Step-by-step explanation:

[tex]-8+4x-12=-4\left(2x-8\right)\\\\\mathrm{Group\:like\:terms}\\\\\mathrm{Subtract\:the\:numbers:}\:-8-12=-20\\\\4x-20=-4\left(2x-8\right)\\\\\mathrm{Expand\:}-4\left(2x-8\right):\quad -8x+32\\4x-20=-8x+32\\\\\mathrm{Add\:}20\mathrm{\:to\:both\:sides}\\4x-20+20=-8x+32+20\\\\Simplify\\\\4x=-8x+52\\\\\mathrm{Add\:}8x\mathrm{\:to\:both\:sides}\\\\4x+8x=-8x+52+8x\\\\\mathrm{Simplify}\\\\12x=52\\\\\mathrm{Divide\:both\:sides\:by\:}12\\\\\frac{12x}{12}=\frac{52}{12}\\\\x=\frac{13}{3}[/tex]

Answer:

Step-by-step explanation:

-8+4x-12 =-8x+32

4x+8x=32+8+12

12x=52

x=52\12

x=41.3

Katherine's class is selling raffle tickets for $3 to raise money for charity. Katherine's class raised $504. Which equation would you use to find the number of tickets sold?


Answers

Answer:

3T=504

Step-by-step explanation:

HOPE I HELPED

PLS MARK BRAINLIEST

DESPERATELY TRYING TO LEVEL UP

        ✌ -ZYLYNN JADE ARDENNE

JUST A RANDOM GIRL WANTING TO HELP PEOPLE!

                                       PEACE!

what is the expression of 28 19/100

Answers

Answer:

the mixed form is 28 [tex]19/100[/tex]

the improper form is ( 28 x 100) = 19 / 100

2819 / 00

Rearrange the equation so x is the independent variable. y+6=5(x-4)

Answers

Answer:

x = (y + 26)/5

Step-by-step explanation:

Order of Operations: BPEMDAS

Step 1: Write out equation

y + 6 = 5(x - 4)

Step 2: Distribute

y + 6 = 5x - 20

Step 3: Isolate x

y + 26 = 5x

Step 4: Isolate variable x

(y + 26)/5 = x

Step 5: Rewrite

x = (y + 26)/5

Answer:

y = 5x - 26

Step-by-step explanation:

Since x is the independent variable, you have to solve for y.

y + 6 = 5(x-4)

Now distribute:

y + 6 = 5x - 20

subtract the 6 from both sides

y + 6 - 6 = 5x - 20 - 6

y = 5x - 26

Father's age is 3 times the sum of ages of his two children. After 5 years his age will be twice the sum of ages of two children. Find the age of father.​

Answers

Answer:

45 is the father's age

Step-by-step explanation:

4:3=x:6, find the value of x please help me

Answers

Answer:

x=8

Step-by-step explanation:

4:3=x:6

Multiply the first set by 2

4*2 : 3*2

8:6

That means x =8

Will has 2 quarters, 6 dimes, some nickels, and 4 pennies. If the ratio of pennies to the total number of coins he has is 1:5, how many nickels are there?

Answers

Answer:

8 nickels

Step-by-step explanation:

Let n be the number of nickels.

4: (2+ 6 + 4 + n) = 1:5

4÷(12 + n) = 1÷5

4 x 5 = 1 x (12 + n)

20 = 12 + n

n = 8

on a map, the distance between jacksonville FL and tallahasse FL is about 5 inches. According to the scale, 1 inch represents 25 miles. About how far apart are these two cities?

Answers

Jacksonville Fl and Tallahassee FL will be about 125 miles apart in real life.

A model of a wedge of cheese is used in a display for a deli. All the sides of the model are covered in yellow construction paper. A rectangular prism has a rectangular base with length of 15 centimeters and height of 5 centimeters. Another rectangle has length of 15 centimeters and height of 13 centimeters. Another rectangle has length of 15 centimeters, and height of 12 centimeters. The triangular sides have a base of 5 centimeters and heights of 12 centimeters. How much construction paper is needed for the model? 45 square cm 330 square cm 510 square cm 570 square cm

Answers

Answer:

510 cm²

Step-by-step explanation:

To find how much construction paper is needed for the model, we calculate the total areas of each of its sides.

The area of the first triangular sides is A₁ = 15 cm × 5 cm = 75 cm²

The area of the second triangular sides is A₂ = 15 cm × 13 cm = 195 cm²

The area of the third triangular sides is A₃ = 15 cm × 12 cm = 180 cm²

The area of each triangular side is A₄ = 1/2 × 5 cm × 12 cm = 30 cm²

The area of the two triangular sides is A₅ = 2A₄ = 2 × 30 cm² = 60 cm²

The total surface area of a wedge of cheese is A = A₁ + A₂ + A₃ + A₅ = 75 cm² + 195 cm² + 180 cm² + 60 cm² = 510 cm²

So the amount of construction paper needed equals the total surface area of the wedge of cheese = 510 cm²

Answer:

510

Step-by-step explanation:

The polygons in each pair are similar. find the scale factor of the smallest figure to larger figure.

Answers

Greetings from Brasil...

It is said that polygons are similar, so we can use the expression of similarity.

BIG/small = BIG/small

35/14 = 25/X

X = 10

But the scale factor is questioned. Just use one of the expressions. We conclude that the largest is 2.5 times the value of the smallest

35/14 OR 40/16 OR 25/10

We get 2.5x

-----------------------------------------------------------

BIG/small = BIG/small

25/5 = 40/Y

Y = 8

25/5 OR 25/5 OR 40/8

We get 5x

times the value of the smallest

what's the square footage of 12'3" * 18'4"

Answers

Answer:

multiply length time width  

Simplify 6.920
A.-1
B.0
C.1
D.6.92

Answers

I'm pretty sure the answer is 6.92 cause when you simplify it you'll get that exact answer

Answer:

D 6.92

Step-by-step explanation:

6.920 and 6.92 are equal

PLEASE ANSWER QUICKLY ASAP

Answers

Answer:

67°

Step-by-step explanation:

● cos<PQR = adjacent/hypotenus

● cos<PQR = 5/13

● cos< PQR = 0.384

Using a calculator:

● cos^-1(0.384) = 67°

● <PQR = 67°

What is the 6th row of Pascal's triangle?

Answers

Answer:

1, 6, 15, 20, 15, 6, 1

Mia’s average driving speed is 6 kilometers per hour faster than Kirk’s. In the same length of time it takes Mia to drive 558 kilometers, Kirk drives only 522 kilometers. What is Mia’s average speed?

Answers

Answer:

93km/hr

Step-by-step explanation:

Using the formula Speed = Distance/Time. From the formula we can substitute for time as shown;

Time = Distance/Speed

Let the distance and speed  travelled by Mia be Dm ans Ds respectively

Distance travelled by Kirk be Km and and Ks respective.

Time taken be Mia to travel Tm = Dm/Sm

Time taken be Kirk to travel Tk = Dk/Sk

Since it takes the same length of time for both of them to travel, then Tm = Tk. Hence Dm/Sm = Dk/Sk

Given parameters

Dm = 558 kilometers

Dk = 522 kilometres

If Mia’s average driving speed is 6 kilometers per hour faster than Kirk’s, then Mia's driving speed Sm = 6 + Sk

Required

Mia’s average speed (Sm)

Since Dm/Sm = Dk/Sk

Substituting the given values to get Sk first we have;

558/6+Sk = 522/Sk

Cross multiply

558Sk = 522(6+Sk)

open the parenthesis

558Sk = 3132 + 522SK

558Sk-522Sk = 3312

36Sk =3132

Sk = 3132/36

Sk =87km/hr

SInce Sm = 6+Sk

Sm = 6+87

Sm = 93km/hr

Hence Mia's average speed is 93km/hr

20 POINTS AND BRAINLIEST!! Which of the following statements can be supported by the evidence shown in the graph?

A. The line best fit shows a positive correlation between month number and minutes

B. The line of best fits shows a negative correlation between the number of months and the number of minutes

C. The line of best fits shows no correlation between the month number and the number of minutes

Answers

Answer:

B. The line of best fits shows a negative correlation between the number of months and the number of minutes

Step-by-step explanation:

In a scatter plot, when the data points are clustered along the line of best fit, it shows a trend, and it implies there's a correlation between the x-variable and the y-varisble.

Also, when the line of best fit slopes upward, from your left to your far right, it shows a positive correlation between the variables on the x-axis and y-axis.

On the other hand, if the line of best fit slopes downwards, from your left down to your right, this shows a negative correlation.

Thus, considering the line of best fit in the question, the line of best fit shows a negative correlation between the number of months and the number of minutes. The line of best fit slopes downwards, from your left to your right.

This shows that, as month number increases, number of minutes decreases.

The Fairy Tale Spectacular is coming to town. Admission to the fair costs $32.50 and each ride costs $0.80. You have $50 to spend at the Fairy Tale Spectacular including admission. Write and solve an inequality to determine the maximum number of rides you can enjoy at the Fairy Tale Spectacular?

Answers

Answer:21

Step-by-step explanation:

50-32.5=17.5

17.5/0.8=21.875

Ernesto solves the equation below by first squaring both sides of the equation. \sqrt{\dfrac{1}{2}w+8}=-2 2 1 ​ w+8 ​ =−2square root of, start fraction, 1, divided by, 2, end fraction, w, plus, 8, end square root, equals, minus, 2 What extraneous solution does Ernesto obtain?

Answers

Answer:

w = -8

Step-by-step explanation:

Given the equation solved by Ernesto expressed as [tex]\sqrt{\dfrac{1}{2}w+8}=-2[/tex], the extraneous solution obtained by Ernesto is shown below;

[tex]\sqrt{\dfrac{1}{2}w+8}=-2\\\\square\ both \ sides \ of \ the \ equation\\(\sqrt{\dfrac{1}{2}w+8})^2=(-2)^2\\\\\dfrac{1}{2}w+8 = 4\\\\Subtract \ 8 \ from \ both \ sides\\\\\dfrac{1}{2}w+8 - 8= 4- 8\\\\\dfrac{1}{2}w= -4\\\\multiply \ both \ sides \ by \ 2\\\\\dfrac{1}{2}w*2= -4*2\\\\w = -8[/tex]

Hence, the extraneous solution that Ernesto obtained is w = -8

Other Questions
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