Answer:
f(t) = 28,7 [N]
Explanation: IMPORTANT NOTE: IN PROBLEM STATEMENT CHARGES ARE IN C (COULOMBS) AND IN THE DIAGRAM IN μC. WE ASSUME CHARGES ARE IN μC.
The net force on +q₂ is the sum of the force of +q₁ on +q₂ ( is a repulsion force since charges of equal sign repel each other ) and the force of -q₃ on +q₂ ( is an attraction force, opposite sign charges attract each other)
The two forces have the same direction to the right of charge q₂, we have to add them
Then
f(t) = f₁₂ + f₃₂
f₁₂ = K * ( q₁*q₂ ) / (0,1)²
q₁ = + 8 μC then q₁ = 8*10⁻⁶ C
q₂ = + 3,5 μC then q₂ = 3,5 *10⁻⁶ C
K = 9*10⁹ [ N*m² /C²]
f₁₂ = 9*10⁹ * 8*3,5*10⁻¹²/ 1*10⁻² [ N*m² /C²]* C*C/m²
f₁₂ = 252*10⁻¹ [N]
f₁₂ = 25,2 [N]
f₃₂ = 9*10⁹*3,5*10⁻⁶*2,5*10⁻⁶ /(0,15)²
f₃₂ = 78,75*10⁻³/ 2,25*10⁻²
f₃₂ = 35 *10⁻¹
f₃₂ = 3,5 [N]
f(t) = 28,7 [N]
Answer:
facts
Explanation:
3. There are twice as many people in the household, but your income has also doubled. Is your new
tax liability about twice as much as when you were single, more than twice as much, or less than
twice as much? Tell whether you think this difference-or the lack of one-seems fair.
Answer:
The answer is less than twice as much.
Explanation:
When the income doubles, the personal tax liability also doubles. However, because I have more dependents on my household, I'm able to get tax reductions to take care of the dependents.
What did Thomson’s and Rutherford’s experiments have in common? They both used charged particles in their experiments. They both used emission spectra to discover electron clouds. They both compared the atom to an indivisible sphere. They both discovered electron clouds.
Answer:
Both Thomson and Rutherford used charged particles in their experiments.
Explanation:
Find the x-component of this vector: 47.3 m 39.4 ° Remember, angles are measured from the + x axis. x-component (m)
The x-component of the vector is 36.55 m.
Components of vectorsThe components of a vector include both x and y components. The x-component is determined along x-axis, while y-component is determined along y-axis.
Vx = Vcosθ
Vy = Vsinθ
where;
Vx is the x-component of the vectorVy is the y-component of the vectorX-components of the vectorThe x-component of the vector is calculated as follows;
x = 47.3 x cos(39.4)
x = 36.55 m
Thus, the x-component of the vector is 36.55 m.
Learn more about x-component of vector here: https://brainly.com/question/13416288
used to measure mass
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▹ Answer
Kg is the unit used to measure mass.
▹ Step-by-Step Explanation
Kg stands for kilogram, and is the SI unit used to measure mass.
Hope this helps!
CloutAnswers ❁
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fill in the term to complete each sentence
a wave carries___ from one place to another.
mechanical waves carry energy through___.
Energy
A material medium
A wave carries energy from one place to another. Mechanical waves carry energy through a material medium.
What is a wave?A wave is a phenomenon that flows across a material medium without leaving any lasting mark.
Mechanical or electromagnetic waves can be used to classify them. Transverse and longitudinal are the two main forms.
A wave carries energy from one place to another. Mechanical waves carry energy through a material medium.
Hence the correct options for the fill-in-the-blanks are energy and a material medium.
To learn more about the wave refer to the link;
brainly.com/question/3004869
What is the average velocity of atoms in 2.00 mol of neon (a monatomic gas)
at 308 K? Use the equation: -mv2
2
For m, use 0.02000 kg. Remember that R = 8.31 J/(mol-K).
= ER
3
2
nRT
A. 1540 m/s
B. 876 m/s
C. 87.6 m/s
O D. 15,400 m/s
Answer:
v = 876 m/s
Explanation:
It is given that,
Number of mol of Neon is 2 mol
Temperature, T = 308 K
Mass, m = 0.02 kg
Value of R - 8.31 J/mol-K
We need to find the average velocity of atoms in 2.00 mol of neon. Neon is a monoatomic gas. Let v is the velocity. So,
[tex]\dfrac{1}{2}mv^2=\dfrac{3}{2}nRT\\\\v=\sqrt{\dfrac{3nRT}{m}} \\\\v=\sqrt{\dfrac{3\times 2\times 8.314\times 308}{0.02}} \\\\v=876.47\ m/s[/tex]
So, the correct option is (B).
An alarm clock has a resistance of 14,000 ohms and is plugged into a 120-volt outlet. How much power does the clock use?
ОА.
0.0086 watts
OB.
0.96 watts
O C.
120 watts
OD
1.0 watts
Answer:
D . 1.0 watts!!!
A researcher is studying traffic patterns at an intersection before an upcoming construction project. As part of this investigation, the researcher writes a scientific question, develops a procedure to observe traffic specifically at this intersection, and draws a conclusion. Which type of investigation is the researcher conducting? descriptive comparative experimental procedural
Answer:
Procedural is the answer
hope this helps
If the cross-sectional area of a wire is decreased while all other factors remain the same, how will the resistance change?
OA
It will increase
OB.
It will decrease.
OC. It will go to zero.
OD
The cross-sectional area does not affect the resistance.
Answer:
The answer is OA it will increase.
Explanation: