In the reaction of: ????2O4 (g) ⇌ 2????O2(g) If the equilibrium constant is Kc = 0.513 and the initial concentration of ????2O4 = 0.0500 ????. What are the equilibrium concentrations of ????2O4 and ????O2 under these conditions?

Answers

Answer 1

Answer:

[N₂O₄] = 0.00411 M

[NO₂] = 0.0918 M

Explanation:

In the reaction of: N₂O₄(g) ⇌ 2 NO₂(g) If the equilibrium constant is Kc = 0.513 and the initial concentration of N₂O₄ = 0.0500 M. What are the equilibrium concentrations of N₂O₄ and NO₂ under these conditions?

Step 1: Given data

Initial concentration of N₂O₄: 0.0500 M

Equilibrium constant (Kc): 0.513

Step 2: Make an ICE chart

        N₂O₄(g) ⇌ 2 NO₂(g)

I        0.0500           0

C           -x              +2x

E      0.0500-x        2x

Step 3: Find the value of "x"

The equilibrium constant is:

Kc = [NO₂]² / [N₂O₄]

0.513 = (2x)² / (0.0500-x)

4x² + 0.513 x -0.02565

We solve for x and we get x₁ = 0.0458942 and x₂ = −0.558894 (neglected).

Step 4: Calculate the concentrations at equilibrium

[N₂O₄] = 0.0500-x = 0.00411 M

[NO₂] = 2x = 0.0918 M


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Explanation:

2. c

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1 is A number two is C

Why do gases diffuse more quickly than liquids?

Choose the correct answer.

A) Liquids can be compressed easily.

B)The particles in gases are not mobile.

C)Liquids are always at lower temperatures than gases.

D)Gas particles move rapidly and have space between them.

Answers

Answer:

D)Gas particles move rapidly and have space between them.

Explanation:

Matter exists in three states namely: solids, liquids and gases. The particles contained in these three states are different from one another. In the gaseous state, the particles are FAR APART from one another i.e. space exists and they move at a very fast rate in contrast to the particles of a liquid, which have less space and move slower.

This rapid movement of gas particles within a less restricted space accounts for the reason why gaseous substances DIFFUSE more quickly than liquids.

Two moles of acetyl chloride was mixed with two moles of dimethylamine. After the reaction is complete, what species can be found in the mixture

Answers

Answer:

See explanation

Explanation:

The reaction is shown in the image attached. This reaction occurs by a carbocation (ionic) mechanism.

The lone pair on the nitrogen atom attacks the carbocation leading to the formation of the product as shown in the image attached.

Since the reaction occurs in a 1:1 ratio, two moles of reactants yields two moles of product.

Whenever the same two elements form more than one
compound, the different masses of one element that combine
with the same mass of the other element are in the ratio of
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TRUE
FALSE

Answers

Answer:

The answer is true

Explanation: Because The law of multiple proportions states that when two elements react to form more than one compound, a fixed mass of one element will react with masses of the other element in a ratio of small, whole numbers.

every spring has an equilibrium position which statement describe a spring at it equilibruim position?

Answers

The elastic potential energy is zero. The net force acting on the spring is zero. Explanation: The equilibrium position of a spring is the position that the spring has when its neither compressed nor stretched - it is also called natural length of the spring.Mar

predict how many moles of nh3 would be made if 6.00 moles of h2 were used N2

Answers

Answer:

4 moles

Explanation:

The equation is 3H2 + N2 → 2NH3

so the ratio of moles would be

2:3 or 2/3

so 6*2/3 which is 4

hope this helped.

Answer:

4moles

Explanation:

Given parameters:

Number of moles of H₂ used  = 6moles

   Equation of the reaction:

           N₂  + 3H₂  →   2NH₃

       3 mole of H₂  was used to produce 2 mole of NH₃;

       6 mole of H₂ will produce [tex]\frac{6x2}{3}[/tex]   = 4 moles of NH₃

The number of moles of NH₃ produced is 4moles

Which of the following conclusions about the two intermolecular forces is correct? X represents London dispersion forces, and Y represents ion-dipole forces. X represents dipole-dipole forces, and Y represents ion-dipole forces. X represents hydrogen bonding, and Y represents dipole-dipole forces. X represents London dispersion forces, and Y represents dipole-dipole forces.

Answers

Answer:

X represents London dispersion forces, and Y represents dipole-dipole forces.

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