In the reaction of aluminum with iron III oxide, if you start with 54.2 grams of aluminum, how many grams of iron III oxide are needed for the reaction to occur? ​

Answers

Answer 1

Answer:

[tex]m_{Fe_2O_3}=160.41gFe_2O_3[/tex]

Explanation:

Hello!

In this case, since the reaction between aluminum and iron (III) oxide is:

[tex]2Al+Fe_2O_3\rightarrow Al_2O_3+2Fe[/tex]

In such way, since there is 2:1 mole ratio between aluminum (atomic mass = 26.98 g/mol) and iron (III) oxide (molar mass = 159.70 g/mol), we'll be able to compute the mass of the required reactant as shown below:

[tex]m_{Fe_2O_3}=54.2gAl*\frac{1molAl}{26.98gAl}* \frac{1molFe_2O_3}{2molAl}*\frac{159.70gFe_2O_3}{1molFe_2O_3}\\\\m_{Fe_2O_3}=160.41gFe_2O_3[/tex]

Best regards!


Related Questions

A 25 cm sample of dilute sulfuric acid contains 0.025 moles of the acid.
What is the hydrogen ion concentration in the solution?
A. 0.2 mol/dm3
B. 0.05 mol/dm3
C. 1.00 mol/dm3
D. 2.00 mol/dm3

Answers

Answer:B. 0.05 mol/dm3

Explanation:

The hydrogen ion concentration in the solution is 2 mol/dm³

The correct answer to the question is Option D. 2 mol/dm³

We'll begin by calculating the molarity of the solution.

Volume = 25 cm³ = 25 / 1000 = 0.025 dm3

Mole of H₂SO₄ = 0.025 mol

Molarity of H₂SO₄ =?

Molarity = mole / Volume

Molarity of H₂SO₄ = 0.025 / 0.025

Molarity of H₂SO₄ = 1 mol/dm³

Finally, we shall determine the concentration of Hydrogen ion in the solution.

H₂SO₄(aq) —> 2H⁺(aq) + SO₄²¯(aq)

From the balanced equation above,

1 mole of H₂SO₄ contains 2 moles of H⁺.

Therefore,

1 mol/dm³ H₂SO₄ will also contain 2 mol/dm³ H⁺.

Thus, the concentration of Hydrogen ion in the solution is 2 mol/dm³

The correct answer to the question is Option D. 2 mol/dm³

Learn more: https://brainly.com/question/3655413

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