I'm assuming the integral is
[tex]\displaystyle \int \frac{\mathrm dx}{x+\sqrt{x^2-1}}[/tex]
Rationalize the denominator:
[tex]\dfrac1{x+\sqrt{x^2-1}} \times \dfrac{x-\sqrt{x^2-1}}{x-\sqrt{x^2-1}} = \dfrac{x-\sqrt{x^2-1}}{x^2-\left(\sqrt{x^2-1}\right)^2} = x-\sqrt{x^2-1}[/tex]
Then the integral is
[tex]\displaystyle \int\left(x-\sqrt{x^2-1}\right)\,\mathrm dx = \dfrac12x^2 - \int\sqrt{x^2-1}\,\mathrm dx[/tex]
For the remaining integral, substitute x = sec(t ) and dx = sec(t ) tan(t ) dt. Then over an appropriate domain, we have
[tex]\displaystyle\int\sqrt{x^2-1}\,\mathrm dx = \int\sec(t)\tan(t)\sqrt{\sec^2(t)-1}\,\mathrm dt = \int\sec(t)\tan^2(t)\,\mathrm dt[/tex]
Integrate by parts, taking
u = tan(t ) ==> du = sec²(t ) dt
dv = sec(t ) tan(t ) dt ==> v = sec(t )
Then
[tex]\displaystyle\int\sec(t)\tan^2(t)\,\mathrm dt = \sec(t)\tan(t) - \int\sec^3(t)\,\mathrm dt[/tex]
Now for *this* remaining integral, integrate by parts again, taking
u = sec(t ) ==> du = sec(t ) tan(t ) dt
dv = sec²(t ) dt ==> v = tan(t )
so that
[tex]\displaystyle\int\sec^3(t)\,\mathrm dt = \sec(t)\tan(t) - \int\sec(t)\tan^2(t)\,\mathrm dt \\\\ \int\sec^3(t)\,\mathrm dt = \sec(t)\tan(t) - \int\sec(t)(\sec^2(t)-1)\,\mathrm dt \\\\ \int\sec^3(t)\,\mathrm dt = \sec(t)\tan(t) - \int\sec^3(t)\,\mathrm dt + \int\sec(t)\,\mathrm dt \\\\ \int\sec^3(t)\,\mathrm dt = \frac12\sec(t)\tan(t)+\frac12\int\sec(t)\,\mathrm dt \\\\ \int\sec^3(t)\,\mathrm dt = \frac12\sec(t)\tan(t) + \frac12\ln\left|\sec(t)+\tan(t)\right| + C[/tex]
To summarize, if I denotes the original integral, we have
[tex]\displaystyle I = \frac12x^2 - \int\sqrt{x^2-1}\,\mathrm dx \\\\ I = \frac12x^2 - \int\sec(t)\tan^2(t)\,\mathrm dt \\\\ I = \frac12x^2 - \sec(t)\tan(t) + \int\sec^3(t)\,\mathrm dt \\\\ I = \frac12x^2 - \sec(t)\tan(t) + \frac12\sec(t)\tan(t) + \frac12\ln\left|\sec(t)+\tan(t)\right| + C \\\\ I = \frac12x^2 - \frac12\sec(t)\tan(t) + \frac12\ln\left|\sec(t)+\tan(t)\right| + C[/tex]
Putting everything back in terms of x, we have
sec(t ) = x
tan(t ) = √(x ² - 1)
so that
[tex]\displaystyle I = \boxed{\frac12x^2 - \frac12x\sqrt{x^2-1}+\frac12\ln\left|x+\sqrt{x^2-1}\right|+C}[/tex]
plz do this all plz
Answer:
I don't know search it up I picked B
okay it's 5 and I'm
if possible help me in this. I need to find the two odd numbers...
Part (a)
Consecutive odd integers are integers that odd and they follow one right after another. If x is odd, then x+2 is the next odd integer
For example, if x = 7, then x+2 = 9 is right after.
Answer: x+2========================================================
Part (b)
The consecutive odd integers we're dealing with are x and x+2.
Their squares are x^2 and (x+2)^2, and these squares add to 394.
Answer: x^2 + (x+2)^2 = 394========================================================
Part (c)
We'll solve the equation we just set up.
x^2 + (x+2)^2 = 394
x^2 + x^2 + 4x + 4 = 394
2x^2+4x+4-394 = 0
2x^2+4x-390 = 0
2(x^2 + 2x - 195) = 0
x^2 + 2x - 195 = 0
You could factor this, but the quadratic formula avoids trial and error.
Use a = 1, b = 2, c = -195 in the quadratic formula.
[tex]x = \frac{-b\pm\sqrt{b^2-4ac}}{2a}\\\\x = \frac{-(2)\pm\sqrt{(2)^2-4(1)(-195)}}{2(1)}\\\\x = \frac{-2\pm\sqrt{784}}{2}\\\\x = \frac{-2\pm28}{2}\\\\x = \frac{-2+28}{2} \ \text{ or } \ x = \frac{-2-28}{2}\\\\x = \frac{26}{2} \ \text{ or } \ x = \frac{-30}{2}\\\\x = 13 \ \text{ or } \ x = -15\\\\[/tex]
If x = 13, then x+2 = 13+2 = 15
Then note how x^2 + (x+2)^2 = 13^2 + 15^2 = 169 + 225 = 394
Or we could have x = -15 which leads to x+2 = -15+2 = -13
So, x^2 + (x+2)^2 = (-15)^2 + (-13)^2 = 225 + 169 = 394
We get the same thing either way.
Answer: Either 13, 15 or -15, -13A circle has a radius of 8cm. An angle of 1.4 radians is subtended at the center by an arc. Calculate the length of the arc
Answer:
11.2 cm
Step-by-step explanation:
Given that;
Arc Length Formula (if θ is in radians): l = ϴ × r
ϴ = angle subtended in radians
r= radius of the circle
l = 8cm × 1.4 radians
l= 11.2 cm
Rewrite in simplest terms (-9x-2y)+(4x-5y)
Answer:
-5x - 7y
Step-by-step explanation:
PLEASE HELP QWQ AsAp with these 4 questions
Answer:
Step-by-step explanation:
I can't believe I'm doing this for 5 points, but ok!
For the first 3, we are going to multiply to find the value of that 3 x 3 matrix by picking up the first 2 columns and plopping them down at the end and then multiplying through using the rules for multiplying matrices:
[tex]\left[\begin{array}{ccccc}7&4&6&7&4\\-4&8&9&-4&8\\1&8&7&1&8\end{array}\right][/tex] and from there find the sum of the products of the main axes minus the sum of the products of the minor axes, as follows (I'm not going to state the process in the next 2 problems, so make sure you follow it here. This is called the determinate. The determinate is what you get when you evaluate or find the value of a matrix. Just so you know):
[tex](7*8*7)+(4*9*1)+(6*-4*8)-[(1*8*6)+(8*9*7)+(7*-4*4)][/tex] which gives us:
392 + 36 - 192 - [48 + 504 - 112] which simplifies to
236 - 440 which is -204
On to the second one:
[tex]\left[\begin{array}{ccccc}-8&-4&-1&-8&-4\\1&7&-3&1&7\\8&9&9&8&9\end{array}\right][/tex] and multiplying gives us
[tex](-8*7*9)+(-4*-3*8)+(-1*1*9)-[(8*7*-1)+(9*-3*-8)+(9*1*-4)][/tex] which gives us:
-504 + 96 - 9 - [-56 + 216 - 36] which simplifies to
-417 - 124 which is -541, choice c.
Now for the third one:
[tex]\left[\begin{array}{ccccc}-2&-2&-5&-2&-2\\2&7&-3&2&7\\8&9&9&8&9\end{array}\right][/tex] and multiplying gives us
[tex](-2*7*9)+(-2*-3*8)+(-5*2*9)-[(8*7*-5)+(9*-3*-2)+(9*2*-2)][/tex] which gives us:
[tex]-126+48-90-[-280+54-36][/tex] which simplifies to
-168 - (-262) which is 94, choice c again.
Now for the last one. I'll show you the set up for the matrix equation; I solved it using the inverse matrix. So I'll also show you the inverse and how I found it.
[tex]\left[\begin{array}{cc}-4&-5&\\-6&-8\\\end{array}\right][/tex] [tex]\left[\begin{array}{c}x\\y\\\end{array}\right][/tex] = [tex]\left[\begin{array}{c}-5\\-2\\\end{array}\right][/tex] and I found the inverse of the 2 x 2 matrix on the left.
Find the inverse by:
* finding the determinate
* putting the determinate under a 1
* multiply that by the "mixed up matrix (you'll see...)
First things first, the determinate:
|A| = (-4*-8) - (-6*-5) which simplifies to
|A| = 32 - 30 so
|A| = 2; now put that under a 1 and multiply it by the mixed up matrix. The mixed up matrix is shown in the next step:
[tex]\frac{1}{2}\left[\begin{array}{cc}-8&5\\6&-4\end{array}\right][/tex] (to get the mixed up matrix, swap the positions of the numbers on the main axis and then change the signs of the numbers on the minor axis). Now we multiply in the 1/2 to get the inverse:
[tex]\left[\begin{array}{cc}-4&\frac{5}{2}\\3&-2\\\end{array}\right][/tex] Multiply that inverse by both sides of the equation. This inverse "undoes" the matrix that's already there (like dividing the matrix that's already there by itself) which leaves us with just the matrix of x and y. Multiply the inverse matrix by the solution matrix:
[tex]\left[\begin{array}{c}x&y\end{array}\right] =\left[\begin{array}{cc}-4&\frac{5}{2} \\3&-2\end{array}\right] *\left[\begin{array}{c}-5&-2\\\end{array}\right][/tex] and that right side multiplies out to
x = 20 - 5 which is
x = 15 and
y = -15 + 4 which is
y = -11
(It works, I checked it)
I need help with all the answers to 1 and 2
1a. 128
1b. 81
1c. 64
1d. 25
1e. 343
1f. 100000
1g. 64
1h. 0
1i. 13
1j. 1
2a. 243
2b. 64
2c. 36
2d. 625
2e. 1331
2f. 10000000
2g. 81
2h. 0
2i. 17
2j. 1
WILL GIVE BRAINLIEST PLS HELP
Answer:
Hello
Step-by-step explanation:
[tex]y=2x^2-12x+19\\=2(x^2-6x)+19\\=2(x^2-2*3*x+9)+19-18\\=2(x-3)^2+1\\\\Vertex\ is\ (3,1)\\\\Axis\ of\ symmetry\ is\ x=3\\\\y-intercept\ is \\\\y=2(0-3)^2+1=19\\[/tex]
3x + ky = 8
X – 2ky = 5
are simultaneous equations where k is a constant.
a) Show that x = 3.
b) Given that y = 1/2 determine the value of k.
Answer:
a) 3x + ky = 8
ky = 8 - 3x
x – 2ky = 5
x - 2(8 - 3x) = 5
x - 16 + 6x = 5
7x = 21
x = 3 (shown)
b) x-2ky = 5
sub x = 3, y = 1/2
3-2k(1/2) = 5
-2k = 2
k = -1
Suppose a triangle has two sides of length 32 and 35, and that the angle
between these two sides is 120°. Which equation should you solve to find the
length of the third side of the triangle?
A. C2 = 322 + 352 – 2(32)(35)sin120°
B. sin32
sin35
b
120
C. C= 32 + 35 - 2(32)(35)cos120°
D. 2 = 322 + 352 - 2(32)(35)cos120°
Answer:
D
Step-by-step explanation:
It is the law of cos
C^2= A^2+B^2-2*A*B*cosL where L is the angle between A and B
so C = 32^2 + 35^2 - 2(32)(35)cos120°
find the inequality represented by the graph
Answer:
4x+3y<15
This is the inequality represented by the graph
Need helppppp asappppppp
Answer:
162
Step-by-step explanation:
because this is a parallelogram :
m<2 = m<4 so
4x - 22 = 3x - 12
4x - 3x = 22 - 12
x = 10 replace x with 10 in the equation for m<4
3x - 12 is 30 - 12 = 18
m<4 and m<1 are supplementary and their sum is equal to 180
m<4 + m<1 = 180
m<1 = 180 - 18
m<1 = 162
A lemonade recipe calls for 1/4 cups of lemon juice for every cup of water.
Plot the pairs in the table in a coordinate plane
Answer:
they are in order cross x with the y across from it
Step-by-step explanation:
If V=πh²(r-h\3) make r subject of formula
Making r the subject of formula, we have; [tex]r = \frac{V}{\pi h^{2} } \; + \;\frac{h}{3}[/tex]
In Mathematics, making a variable the subject of formula simply means making the particular variable to be equal to all the other variable contained in an algebraic expression or mathematical equation. Thus, the subject of a formula is typically on the left-hand side of a mathematical equation while the other variables on the right-side.
Given the mathematical expression;
[tex]V = \pi h^{2}(r \; - \;\frac{h}{3} )[/tex]
To make "r" subject of formula;
First of all, we would divide both sides by [tex]\pi h^{2}[/tex]
[tex]\frac{V}{\pi h^{2} } = r \; - \;\frac{h}{3}[/tex]
Next, we would rearrange the equation;
[tex]r = \frac{V}{\pi h^{2} } \; + \;\frac{h}{3}[/tex]
For more on subject of formula visit: https://brainly.com/question/17148850
What are the domain and range of f(x) = |x + 6|? Domain: (negative infinity, infinity); range: f(x) > 0 domain: x < -6; range: (negative infinity, infinity) domain: x > -6; range: (negative infinity, infinity) domain: (negative infinity, infinity) ; range: f(x) < 0
Answer:
Domain: [tex](-\infty,\infty)[/tex]
Range: [tex]f(x) \ge 0[/tex]
Step-by-step explanation:
Given
[tex]f(x) = |x + 6|[/tex]
Required
The domain and the range
First, we calculate the domain
[tex]f(x) = |x + 6|[/tex]
The above function does not have roots or fraction, where x is the denominator. This means that the domain is all real numbers, i.e. [tex](-\infty,\infty)[/tex]
The range
The function is an absolute function; So, the minimum value is 0.
Hence, the range is:
[tex]f(x) \ge 0[/tex]
Answer:
A
Step-by-step explanation:
on edge
which one is the right answers
Answer:
B
Step-by-step explanation:
n is the number of litres.
if you substitute 1 for 'n' then you will get :
C = 8 + 1.5(1)
C = $9.5
$9.50 for every litre
Answer:
C is correct
Step-by-step explanation:
The $8 charge is only once regardless of how many liters are ordered, so only answer C works.
PLS HELP ME ON THIS QUESTION I WILL MARK YOU AS BRAINLIEST IF YOU KNOW THE ANSWER!!
Which of the following statements is correct about the data set 7, 10, 9, 100, 5, 12?
A. The data set has an outlier
B. The mean is the best and most accurate measure to describe this data set
C. The data set has two modes
D. The data set has a median of 10
Answer:
A. The data set has an outlier
Step-by-step explanation:
The data set has an outlier because 100 is the largest number of the set.
Answer:
option b
Step-by-step explanation:
Brady scored a total of 320 points last season for his basketball team. This season, the team
added 2 extra games to the schedule. Brady thinks this will allow him to increase the total
number of points he scores by 5%. How many points is Brady expecting to score this season?
a. 336
b. 325
c. 304
d. 16
Which expressions are equivalent to
3(6+b) + 2b+1?
Select 2 answers.
Step 1 - Use the distributive property and pick your first
answer
Step 2 - Combine like terms and pick your second
answer
Step-by-step explanation:
3(6+b)+2b+1
18+3b+2b+1
5b+19
A set of composite number less than 12.Express it in listing and set-builder methods
composite numbers less than 12={1,3,4,6,8,9,10}
Help is greatly appreciated:)
Can someone please help me with these 3 questions and help me check my work?
Answer:
18. [tex] x = 8 [/tex]
19. [tex] c = 9 [/tex]
20. [tex] d = \sqrt{10} [/tex]
21. 83 1/3 ft
22.
a. decay
b. growth
c. decay
Step-by-step explanation:
18.
[tex] \sqrt{x + 1} + 12 + 10 = 25 [/tex]
[tex[ \sqrt{x + 1} = 3 [/tex]
Square both sides.
[tex] x + 1 = 9 [/tex]
[tex] x = 8 [/tex]
19.
[tex] a^2 + b^2 = c^2 [/tex]
[tex] (\sqrt{75})^2 + (\sqrt{6})^2 = c^2 [/tex]
[tex] 75 + 6 = c^2 [/tex]
[tex] 81 = c^2 [/tex]
[tex] c = 9 [/tex]
20.
[tex] d = \sqrt{(x_2 - x_1)^2 + (y_2 - y_1)^2} [/tex]
[tex] d = \sqrt{(3 - 4)^2 + (-9 - (-6))^2} [/tex]
[tex] d = \sqrt{(-1)^2 + (-3)^2} [/tex]
[tex] d = \sqrt{1 + 9} [/tex]
[tex] d = \sqrt{10} [/tex]
21.
Max: 5 ft tall; 3 ft shadow
Building: x ft tall; 50 ft shadow
5 ft is to 3 ft as x ft is to 50 ft
5/3 = x/50
3x = 250
x = 250/3
x = 83 1/3
Answer: 83 1/3 ft
22.
Exponential function:
y = a(b)^x
b is the number in parentheses raised to exponent x.
If b > 1, it is growth.
If b is between 0 and 1, it is decay.
Look at each case.
a. 0.85 is between 0 and 1: decay
b. 1.025 > 1: growth
c. 0.682 is between 0 and 1: decay
Find the equation of the line:
through (5, -1) and (2, 2).
Answer:
y = -x + 4
Step-by-step explanation:
(x₁,y₁)= (5, - 1) & (x₂,y₂)= (2 , 2)
Slope = [tex]\frac{y_{2}-y_{1}}{x_{2}-x_{1}}[/tex]
[tex]\frac{2-[-1]}{2-5}\\\\=\frac{2+1}{-3}\\\\=\frac{3}{-3}\\\\= -1[/tex]
m = -1
Equation of the line y - y₁ = m(x - x₁)
y - [-1] = (-1)*(x - 5)
y + 1 = -x + 5 {-1 is distributed}
y = -x + 5 - 1
y = -x + 4
Given two consecutive integers whose sum is 92, find the larger of the two integers.
If f(x)=5x-3 find x=2
A.7
B.4
C.-4
D.-5
Answer: A. 7
Concept:
Here, we need to understand the idea of evaluation.
When encountering questions that gave you an expression with variables, then stated: "If x = a, y = b, z = c" (a, b, c are all constants), this means you should substitute the value given for each variable back to the expression.
Solve:
Given Information
f(x) = 5x - 3
x = 2
Substitute the value into the function
f(2) = 5 (2) - 3
f(2) = 10 - 3
f(2) = 7
Hope this helps!! :)
Please let me know if you have any questions
Christa needs to make a painting for art class.
She can only choose two of the eight colors listed
in the table above. What is the probability the two
colors she chooses are green and purple?
Please Help and thank you so much!!
what is the difference of the fractions?
-2 1/2 - (-1 3/4)
Answer:
-3/4
Step-by-step explanation:
First, let's convert the mixed numbers into improper fractions in an effort to make this problem easier to solve.
-2 1/2 as a mixed number is -5/2 and -1 3/4 as a mixed number is -7/4.
Our problem is now -5/2 - (-7/4).
We still can't solve this because the two fractions do not share a common denominator. 4 can serve as one, so -5/2 with a denominator of 4 would be -10/4.
The problem is now -10/4 - (-7/4).
Two negatives make a positive so the problem can be rewritten as -10/4 + 7/4. The final answer is -3/4.
Multiply the polynomial by distribution. Show your work and explain the steps you used to solve.
- 8x(x^2 – 8x + 3)
Answer:
-8x^3 + 64x^2 - 24x
Step-by-step explanation:
To distribute, we must multiple -8x to each term:
-8x(x^2) - 8x(-8x) - 8x(3)
-8x^3 + 64x^2 - 24x
Step-by-step explanation:
[tex] - 8x( {x}^{2} - 8x + 3) \\ = ( - 8x \times {x}^{2}) - ( - 8x \times 8x) + ( - 8x \times 3) \\ = - 8 {x}^{3} + 64 {x}^{2} - 24x[/tex]
distribute -8x to each term in the perenthesis i.e. multiply each term by -8x
What is the image of the point (-1,3) after a rotation of 270° counterclockwise
about the origin?
Answer:
3,-1
Step-by-step explanation:
The image of the point (-1,3) after a rotation of 270° counterclockwise about the origin is (3, -1).
The given coordinate point is (-1, 3).
What is a rotation of 270° counterclockwise about the origin?When rotating a point 270 degrees counterclockwise about the origin our point A(x, y) becomes A'(y,-x). This means, we switch x and y and make x negative.
The point (-1, 3) is rotated 270° counterclockwise about the origin becomes (3, -1).
Therefore, the image of the point (-1,3) after a rotation of 270° counterclockwise about the origin is (3, -1).
To learn more about the rotation of 270° counterclockwise visit:
brainly.com/question/9109065.
#SPJ2
What is the volume of this figure?
Step-by-step explanation:
3 x 3 x 3 = 27
2 x 2 x 2 = 8
6 x 10 x 2 = 120
27+8+120=155m³
