Of the three Intermolecular forces, the type with the largest dissociation energy is ________.
A. Dipole-dipole interactions
B. Dispersion forces
C. Hydrogen bonds
Answer:
C. Hydrogen bonds
Explanation:
Strongest intermolecular force
Hydrogen Bonding (H-Bonding)
Hydrogen bonds are caused by highly electronegative atoms. They only occur between hydrogen and oxygen, fluorine or nitrogen, and are the strongest intermolecular force.
Answer: C hydrogen bonds
Explanation:
The answer for this
what makes up the cell menbrane
With few exceptions, cellular membranes — including plasma membranes and internal membranes — are made of glycerophospholipids, molecules composed of glycerol, a phosphate group, and two fatty acid chains. Glycerol is a three-carbon molecule that functions as the backbone of these membrane lipids.
Explanation:
the principal components of plasma membrane are lipids phospholipid and cholesterol proteins and carbohydrates
Calculate the wavelength for the transition from n = 4 to n = 2, and state the name given to the spectroscopic series to which this transition belongs?
Answer:
The wavelength for the transition from n = 4 to n = 2 is 486nm and the name name given to the spectroscopic series belongs to The Balmer series.
Explanation
lets calculate -
Rydberg equation- [tex]\frac{1}{\pi } =R(\frac{1}{n_1^2} -\frac{1}{n_2^2})[/tex]
where ,[tex]\pi[/tex] is wavelength , R is Rydberg constant ( [tex]1.097\times10^7[/tex]), [tex]n_1[/tex] and [tex]n_2[/tex]are the quantum numbers of the energy levels. (where [tex]n_1=2 , n_2=4[/tex])
Now putting the given values in the equation,
[tex]\frac{1}{\pi }=1.097\times10^7\times(\frac{1}{2^2} -\frac{1}{4^2} )[/tex][tex]=2056875m^-^1[/tex]
Wavelength [tex]\pi =\frac{1}{2056875}[/tex]
=[tex]4.86\times10^-^7[/tex] = 486nm
Therefore , the wavelength is 486nm and it belongs to The Balmer series.
It is often possible to change a hydrate into an anhydrous compound by heating it to drive off the water (dehydration). A 45.91 gram sample of a hydrate of MnSO4 was heated thoroughly in a porcelain crucible, until its weight remained constant. After heating, 37.07 grams of the anhydrous compound remained. What is the formula of the hydrate
Answer: The formula of the hydrate is [tex]MnSO_4.2H_2O[/tex]
Explanation:
Decomposition of hydrated manganese sulphate is given by:
[tex]MnSO_4.xH_2O\rightarrow MnSO_4+xH_2O[/tex]
Molar mass of [tex]MnSO_4[/tex] = 151.0 g/mol
According to stoichiometry:
(151.0+18x) g of [tex]MnSO_4.xH_2O[/tex] decomposes to give 151.0 g of [tex]MnSO_4[/tex]
Thus 45.91 g of [tex]MnSO_4.xH_2O[/tex] decomposes to give= [tex]\frac{ 151.0}{151.0+18x}\times 45.91g[/tex] of [tex]MnSO_4[/tex]
Also we are given : 37.07 g of [tex]MnSO_4[/tex] is produced
Thus we can equate the two equations:
[tex]\frac{ 151.0}{151.0+18x}\times 45.91=37.07[/tex]
[tex]x=2[/tex]
Thus the formula of the hydrate is [tex]MnSO_4.2H_2O[/tex]
If 3 moles of NaOH is dissolved in 4L of water, what is the
molarity of the solution?
Answer:
0.75mol/LNaOH
Explanation:
Data: Soln:
M= ? M= n/ V(l)
n= 3moles. M= 3mol/ 4L
V= 4L. M = 0.75 mol/LNaOH
When a lead acid car battery is recharged by the alternator, it acts essentially as an electrolytic cell in which solid lead(II) sulfate PbSO4 is reduced to lead at the cathode and oxidized to solid lead(II) oxide PbO at the anode. Suppose a current of 96.0A is fed into a car battery for 37.0 seconds. Calculate the mass of lead deposited on the cathode of the battery.
Answer: 3.73 grams
Explanation:
[tex]Q=I\times t[/tex]
where Q= quantity of electricity in coloumbs
I = current in amperes = 96.0 A
t= time in seconds = 37.0 sec
[tex]Q=96.0A\times 37.0s=3552C[/tex]
The reaction at cathode is:
[tex]Pb^{2+}+2e^-\rightarrow Pb[/tex]
[tex]96500\times 2=193000Coloumb[/tex] of electricity deposits 1 mole of
3552 C of electricity deposits =[tex]\frac{1}{193000}\times 3552=0.018moles[/tex] of Pb
[tex]\text {mass of Pb}={\text{moles}\times {\text{Molar mass}}[/tex]
[tex]\text {mass of Pb}={0.018}\times {207.2g/mol}=3.73g[/tex]
Thus mass of lead deposited is 3.73 g
HELP FAST 75 PTS Calculate the amount of heat needed to melt 35.0 g of ice at 0 ºC. must show work
Answer:
It takes 12,000 Joules of energy to melt 35 grams of ice at 0 °C
Explanation:
Good Luck!
What is the enthalpy in KJ of reaction for the initial combustion if the delta H for vaporization is 75.75 KJ and the net delta H is -700 kJ?
Write your answer to hundredths, including a negative sign if needed. Do not write the unit.
Answer:
-775.75
Explanation:
Advise a friend who responds to conflict by using the strategies below on why
each (strategy) is not healthy for sustaining positive relationships.
a. Confrontation
Answer:
When there is a conflict and if a friend responding to conflict with confrontation it may affect positively or negatively both ways depend how he responds or confront the other person he has a conflict with. But normally people alienate with the person being confrontational. A friend should try to resolve the conflict by making an amicable solution.
if it is used correctly it could help in making the relationship strong, however, confronting by attacking them verbally, insult them, or talking loudly among the group of people can escalate the conflict.
I will advise him to be cautious of the approach as it may positively or negatively affect the situation.
What is Confrontation?This is the process which involves directly engaging one another in the course of a dispute between them.
This method however could either resolve the conflict or worsen it which is why special approach should be taken by being calm and being respectful to the other party involved.
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which element is shown in the picture here?
A sample of calcium fluoride was decomposed into the constituent elements. If the sample produced 294 mg of calcium, how many g of fluorine were formed?
Answer:
Approximately [tex]279\; \rm mg[/tex] of fluorine would be produced.
Explanation:
Look up the relative atomic mass of these calcium and fluorine on a modern periodic table:
[tex]\rm Ca[/tex]: [tex]40.078[/tex].[tex]\rm F[/tex]: [tex]18.998[/tex].In other words, the mass of each mole of calcium atoms is (approximately) [tex]40.078\; \rm g[/tex]. Similarly, the mass of each mole of fluorine atoms is (approximately) [tex]18.998\; \rm g[/tex].
Calculate the number of moles of calcium atom that were produced:
[tex]\begin{aligned} &n({\rm Ca}) \\ &= \frac{m({\rm Ca})}{M({\rm Ca})} \\ &= \frac{294\; \rm mg}{40.078\; \rm g \cdot mol^{-1}} \\ &= \frac{0.294\; \rm mg}{40.08 \; \rm g \cdot mol^{-1}}\\ & \approx 7.3357 \times 10^{-3}\; \rm mol\end{aligned}[/tex].
Every formula unit of calcium fluoride, [tex]\rm CaF_2[/tex], contains twice as many fluorine atoms as calcium atoms.
Hence, if the sample contained approximately [tex]7.33570 \times 10^{-3}\; \rm mol[/tex] calcium atoms, it would contain twice as many fluorine atoms:
[tex]\begin{aligned}n({\rm F}) &= 2\, n({\rm Ca}) \\ &\approx 2 \times 7.33570\times 10^{-3}\; \rm mol \\ &\approx 1.4671 \times 10^{-2}\; \rm mol\end{aligned}[/tex].
Calculate the mass of that many fluorine atoms:
[tex]\begin{aligned}& m({\rm F}) \\ &= n({\rm F}) \cdot M({\rm F}) \\ &\approx 1.4671 \times 10^{-2}\; \rm mol \times 18.998\; \rm g \cdot mol^{-1} \\ &\approx 278.72 \times 10^{-3}\; \rm g \\&\approx 279\; \rm mg\end{aligned}[/tex].
279 mg of Fluorine was formed in the decomposition reaction
The equation of the reaction is;
CaF2 -----> Ca + 2F
Mass of calcium formed = 294 mg
Number of moles of Ca in 294 mg = 294 × [tex]10^-3[/tex] g/40 g/mol = 0.00735 moles
From the equation, the products are in ration 1 : 2
Since 1 mole of Ca is to 2 moles of F
0.00735 moles of Ca is to 0.00735 moles × 2 moles/1 mole
= 0.0147 moles of F
Mass of F = 0.0147 moles × 19 g/mol
= 0.279g or 279 mg of F
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32 g of a metal, M, reacts with 8 g of oxygen to form an oxide. The formula of the oxide is MO. What is the atomic mass of M in g mol-?
Answer: M= 128 g/mol (Te is quite close)
Explanation: number of Oxygen moles is n = 8 g / 32 g/mol = 0,25 mol.
Because formula of oxide is MO, thus amount of metal is also 0,25 mol.
Because n = m/M , Molar mass of the metal M = m/n = 32 g /0.25 mol = 128 g/ mol
The action of a tree stump splitting bedrock depicts what type of process?
А. chemical weathering
B. physical weathering
С. deposition
D. erosion
Answer: Physical Weathering
Explanation: It is physical weathering because it is caused by natural elements causing the rock to break. It is not chemical weathering because it is not using any chemical reaction to break the rock. It is not erosion or deposition because it is still not finished with the process with breaking the rock. Think of it this way:
Step 1: Weathering - Breaks rock/stone
Step 2: Erosion - Taking the small bits of rock
Step 3: Deposition - Dropping the rock
PLEASE HELP!!
A scientist places a pH meter in a sample of concentrated potassium hydroxide (KOH). The scientist slowly adds nitric acid (HNO3) to the KOH and monitors the pH. Describe how the pH and hydronium ion concentration will change in the solution as the acid is added.
Answer:
pH of the solution will decrease & hydronium ion concentration will increase in the solution as the acid is added.
Explanation:
Calculate the pH of a solution formed by mixing 550.0 mL of 0.30 M HClO with 275.0 mL of 0.20 M CsClO. The Ka for HClO is 2.9 × 10-8.
Answer:
pH = 7.08
Explanation:
We can solve this problem using Henderson-Hasselbach's equation:
pH = pKa + log[tex]\frac{[ClO^-]}{[HClO]}[/tex]With the given concentrations and volumes, we can calculate the new values for [ClO⁻] and [HClO] when the solutions are mixed:
Total volume = 550.0 mL + 275.0 mL = 825.0 mL[HClO] = 550 mL * 0.30 M / 825 mL = 0.20 M[ClO⁻] = 275 mL * 0.20 M / 825 mL = 0.07 MNow we calculate pKa:
pKa = -log(Ka) = 7.54Finally we calculate the pH:
pH = 7.54 + log[tex]\frac{0.07}{0.2}[/tex] = 7.08__C+_SO2—_CS2 + __CO
Answer:
_c+_so2-_cs2+_co= Toxic
Explain what method you would use to obtain
Petrol (boiling point 20
60 C) from a mature of petrol and kerosene (boiling point 180 220 C)
Answer:
Fractional distillation of crude oil in laboratory
Explanation:
In general, we can sort them according to their boiling point.
We should first place a ball of mineral wool soaked with petroleum into a boiling tube and heat it with a Bunsen flame. At the beginning of the experiment, heat the mineral with a gentle flame, and then more strongly later. The fraction with a lower boiling range will distil out first. Since petrol is quite volatile, it should be condensed by cooling with water or an ice-water bath.
Petrol will be collected first, as it has a lower boiling point than kerosene. It will turn into vapour and condense again in the receive tub in the beaker.
Do molecules move faster or slower when energy is transferred in?
Answer:
In conduction, faster-moving molecules contact slower-moving molecules and transfer energy to them. During conduction the slower-moving molecules speed up and the faster-moving molecules slow down.
Explanation:
1. a) Define the term electricity ?
Answer:
a form of energy resulting from the existence of charged particles (such as electrons or protons), either statically as an accumulation of charge or dynamically as a current.
Explanation:
Best answer gets brainliest
Answer:
C) Mercury based thermometer
Explanation:
Answer:
Mercury based thermometer
Explanation:
When you touch a lightbulb it is warm. Hairdryer produces heat to dry your hair. Stove heats up to warm food and liquids up.
Solution Mass of NaCl (9) Volume of water (mL)
A
5.0
50.0
B
5.0
75.0
с
5.0
100.0
D
5.0
125.0
Which of the solutions has the highest salt concentration?
O A Solution B
B. Solution A
O
C. Solution C
D. Solution D
Divide the volume of water with mass of salt and multiply with 100 you'll get the concentration percentage
answer is B, because solution A's percentage is 10%
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An unknown concentration of sodium thiosulfate, Na2S2O3, is used to titrate a standardized solution of KIO3 with excess KI present. Suppose 15.65 mL of the Na2S2O3 solution is required to titrate the iodine formed from 21.55 mL of 0.0131 M KIO3. What is the molarity of the Na2S2O3 solution
Answer: The molarity of [tex]Na_2S_2O_3[/tex] is 0.108 M
Explanation:
[tex]KIO_3+5KI+3H_2SO_4\rightarrow 3K_2SO_4+3H_2O+3I_2[/tex]
[tex]2Na_2S_2O_3+I_2\rightarrow Na_2S_4O_6+2NaI[/tex]
To calculate the number of moles for given molarity, we use the equation:
[tex]\text{Molarity of the solution}=\frac{\text{Moles of solute}}{\text{Volume of solution (in L)}}[/tex]
[tex]\text{Moles of }KIO_3=\frac{0.0131mol/L\times 21.55}{1000}=2.8\times 10^{-4}mol[/tex]
1 mole of [tex]KIO_3[/tex] produces = 3 moles of [tex]I_2[/tex]
[tex]2.8\times 10^{-4}[/tex] moles of [tex]KIO_3[/tex] produces = [tex]\frac{3}{1}\times 2.8\times 10^{-4}=8.4\times 10^{-4}[/tex] moles of [tex]I_2[/tex]
Now 1 mole of [tex]I_2[/tex] uses = 2 moles of [tex]Na_2S_2O_3[/tex]
[tex]8.4\times 10^{-4}[/tex] moles of [tex]I_2[/tex] uses = [tex]\frac{2}{1}\times 8.4\times 10^{-4}=1.69\times 10^{-3}[/tex] moles of [tex]Na_2S_2O_3[/tex]
[tex]\text{Molarity of the solution}=\frac{\text{Moles of solute}}{\text{Volume of solution in L}}=\frac{1.69\times 10^{-3}\times 1000}{15.65}=0.108M[/tex]
The molarity of [tex]Na_2S_2O_3[/tex] is 0.108 M
The heat of a reaction may be found with the equation q=mc triangle T. A 951 g sample of carbon steel with a specific heat capacity of 0.49 J/(g*K) is heated to 673K and quenched in oil. The steel cools to 523K. Assuming there is no heat lost to the surroundings, calculate the heat absorbed by the oil. A) -69.9kj B) -31.5kj C) 69.9 kJ D) 71.2 kj
Answer:b
Explanation:
Answer:
C.
Explanation:
I took the quiz and made a 100
A 20 mL sample of human urine was found to have 10 mg of
urea during analysis. The molar mass of urea is 60.1 g/mol.
Calculate the molarity of urea in the given sample.
1. Chlorofluorocarbons (CFCs) are of interest because of their ability to destroy ozone molecules. A carbon-chlorine bon din the CFC molecule can be broken by sunlight, leaving a highly reactive free radical which then goes on to destroy the surrounding ozone molecules. The energy of a C-Cl bond is 328 kJ/mole. Calculate the wavelength of light needed to break a bond in a single molecule. In which region of the spectrum (infrared, visible, UV) does this wavelength fall
Answer:
See explanation
Explanation:
Energy of the photon (E) = 328 * 10^3/6.02 * 10^23 = 5.45 * 10^-19 J
Recall that E = hc/λ
h = Plank's constant = 6.36 * 10^-34 Js
c = speed of light = 3 * 10^8 m/s
λ = ??
λ = hc/E
λ = 6.36 * 10^-34 * 3 * 10^8/5.45 * 10^-19
λ = 3.5 * 10^-7 m
This falls into the UV region of the spectrum
When we report the concentration of a solution we are using the moles of the entire compound.
a. True
b. False
Answer:
b. False
Explanation:
The formula to find the concentration of a solution is we simply divide the number of moles of the solute with total solution volume in liters. This gives the molar concentration of a solution. Clearly we do not use the number of moles of the entire compound but only that of solute.
Hence, we can conclude that the given statement is false.
Which if the following numbers in your personal life are exact numbers?
A. Your cell phone number
B. Your weight
C. Your IQ
D. Your driver's license number
E. The distance you walked yesterday
Answer:
I think D
Explanation:
Your cell phone number and your driver's license number are the numbers of your personal life that are exact.
In this context, an exact number refers to a number that if it undergoes any modification will not refer to the same thing that it referred to before that modification.
For example, my phone number is 12345. This number is exact because it cannot be changed because or else it would cease to be my phone number, that is, if someone wants to call me and writes the number 12346 it is no longer my number.
Addicionally, if my driver's license number is 112233 it is an exact number because if it is modified it would be the number of another driver.
According to the above, options B, C, and E are incorrect because they are inaccurate numbers because if they are modified they all refer to me and they would not change their meaning.
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Show your reasoning in describing what would be the effect on the calculated equilibrium constant for each of the following mistakes.
1. Your buret was not rinsed with NaNCS solution before use and still contained traces of distilled water.
2. The spectrophotometer was set well-past infinite absorbance upon calibration with the sample holder empty.
Answer:
The readings of equilibrium constant is incorrect.
Explanation:
There is a mistake in the value of equilibrium constant if the burette contains traces of distilled water because the water will be present in the solution from which equilibrium constant is calculated. The spectrophotometer did not give the correct reading because its calibration is incorrect. If we want to gain correct readings from the spectrophotometer, we must have to calibrate the instrument correctly.
Incorrect value of equilibrium constant is obtained.
What is equilibrium constant?Equilibrium constant of any reaction tells about the relative ration of the concentration of products to the reactants.
Value of equilibrium constant can be calculated in the aqueous medium where concentration of water also present. If we don't rinse the burette with the reaction solution then the already present traces of water affect the concentration of water during the calculation of equilibrium constant.
As the absorbance of any solution is also directly proportional to the concentration, so if the spectrometer is not calibrated accurately then incorrect value of absorbance also affects the value of equilibrium constant.
Hence, we get incorrect value of equilibrium constant for each of the given mistakes.
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5. A grouping of organisms based on shared characteristics is called
A. binomial nomenclature
B. scientific name
C. classification
D. genus
Answer:
peace of vassals
Explanation:
I think i spelled it worng
