is sublimation exothermic or endothermic

Answer:

Follows are the solution to this question:

Explanation:

Methane inlet humidity content of [tex]=7.00\%[/tex]

Methane moisture outlet content [tex]=0.05\%[/tex]

Zeolite absorption humidity [tex]= 6.95\%[/tex]

Dry zeolite 1 kg will accommodate water[tex]= 0.1000 \ kg[/tex]

One kilogram of Dry Zeolite will carry water from [tex]=0.1000\ kg[/tex]

The water can contain 1000 kg of zeolite [tex]= 100 \ kg[/tex]

Methane which would be made [tex]=\frac{100}{6.95\%}= 1,439 \ kg[/tex]

That's why it will be producing 1439 kg of methane.

The amount of methane that can be produced before the regeneration of zeolite is 1,439 kg.

What is zeolite?

Zeolite belongs from the family of hydrated aluminosilicate minerals, in which alkali and alkaline earth metals are present.

In the question, it is given that:

Capacity of 1kg of zeolite to hold water = 0.100kg

Capacity of 1000kg of zeolite to hold water = 100kg

Inlet moisture content of the methane = 7.00 % (by mass)

Outlet moisture content of the methane = 0.05% (by mass)

Capacity of zeolite to absorb methane content = 6.95 %

Amount of methane before the regeneration of zeolite = 100kg / 6.95% = 14.39% of kg = 1,439 kg

Hence, 1,439 kg methane will be produced before the zeolite must be regenerated.

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Answer:

peace of vassals

Explanation:

I think i spelled it worng

Answer:

The wavelength for the transition from n = 4 to n = 2 is 486nm and the name  name given to the spectroscopic series belongs to The Balmer series.

Explanation

lets calculate -

Rydberg equation-   [tex]\frac{1}{\pi } =R(\frac{1}{n_1^2} -\frac{1}{n_2^2})[/tex]

where ,[tex]\pi[/tex] is wavelength , R is Rydberg constant ( [tex]1.097\times10^7[/tex]), [tex]n_1[/tex] and [tex]n_2[/tex]are the quantum numbers of the energy levels. (where [tex]n_1=2 , n_2=4[/tex])

Now putting the given values in the equation,

                [tex]\frac{1}{\pi }=1.097\times10^7\times(\frac{1}{2^2} -\frac{1}{4^2} )[/tex][tex]=2056875m^-^1[/tex]

    Wavelength [tex]\pi =\frac{1}{2056875}[/tex]

             =[tex]4.86\times10^-^7[/tex] = 486nm

   Therefore , the wavelength is 486nm and it belongs to The Balmer series.

Answer:

_c+_so2-_cs2+_co= Toxic

Answer:

pH = 7.08

Explanation:

We can solve this problem using Henderson-Hasselbach's equation:

With the given concentrations and volumes, we can calculate the new values for [ClO⁻] and [HClO] when the solutions are mixed:

Now we calculate pKa:

Finally we calculate the pH:

Answer: Physical Weathering

Explanation: It is physical weathering because it is caused by natural elements causing the rock to break. It is not chemical weathering because it is not using any chemical reaction to break the rock. It is not erosion or deposition because it is still not finished with the process with breaking the rock. Think of it this way:

Step 1: Weathering - Breaks rock/stone

Step 2: Erosion - Taking the small bits of rock

Step 3: Deposition - Dropping the rock

Answer:

i don't know but I just want to have coins

Answer:

Fractional distillation of crude oil in laboratory

Explanation:

In general, we can sort them according to their boiling point.

We should first place a ball of mineral wool soaked with petroleum into a boiling tube and heat it with a Bunsen flame. At the beginning of the experiment, heat the mineral with a gentle flame, and then more strongly later. The fraction with a lower boiling range will distil out first. Since petrol is quite volatile, it should be condensed by cooling with water or an ice-water bath.

Petrol will be collected first, as it has a lower boiling point than kerosene. It will turn into vapour and condense again in the receive tub in the beaker.

Answer:

The responses to the given points can be defined as follows:

Explanation:

In point 1:

The answer is "No".

In point 2:

The mass of solute = The mass of precipitate [tex]= 0.56\ kg =0.56\ \times 1000 = 560 \ g[/tex]

Calculating the solubility:

[tex]= \frac{\text{mass of solute in g}}{\text{volume of solution in ml}}\\\\ = \frac{560}{ 4000} \\\\ = 0.14 \ \frac{g}{ml}[/tex]

Answer:

[tex]\huge\boxed{\sf Q = 13.7\ Joules}[/tex]

Explanation:

Given Data:

Mass = m = 96 g = 0.096 kg

[tex]T_1[/tex] = 124 °C

[tex]T_2[/tex] = 158 °C

Change in Temp. = ΔT = 158 - 124 = 34 °C

Specific Heat Constant = c = 4.186 J/g °C

Required:

Specific Heat Capacity = Q = ?

Formula:

Q = mcΔT

Solution:

Q = (0.096)(4.186)(34)

Q = 13.7 Joules

[tex]\rule[225]{225}{2}[/tex]

Hope this helped!

Answer:

[tex]\Large \boxed{\sf 13600 \ J}[/tex]

Explanation:

Use formula

[tex]\displaystyle \sf Heat \ (J)=mass \ (g) \times specific \ heat \ capacity \ (Jg^{-1}\°C^{-1}) \times change \ in \ temperature \ (\°C)[/tex]

Specific heat capacity of water is 4.18 J/(g °C)

Substitute the values in formula and evaluate

[tex]\displaystyle \sf Heat \ (J)=96 \ g \times 4.18 \ Jg^{-1}\°C^{-1} \times (158\°C-124 \°C)[/tex]

[tex]\displaystyle Q=96 \times 4.18 \times (158-124 )=13643.52[/tex]

Answer:

The readings of equilibrium constant is incorrect.

Explanation:

There is a mistake in the value of equilibrium constant if the burette contains traces of distilled water because the water will be present in the solution from which equilibrium constant is calculated. The spectrophotometer did not give the correct reading because its calibration is incorrect. If we want to gain correct readings from the spectrophotometer, we must have to calibrate the instrument correctly.

Incorrect value of equilibrium constant is obtained.

Equilibrium constant of any reaction tells about the relative ration of the concentration of products to the reactants.

Value of equilibrium constant can be calculated in the aqueous medium where concentration of water also present. If we don't rinse the burette with the reaction solution then the already present traces of water affect the concentration of water during the calculation of equilibrium constant.

As the absorbance of any solution is also directly proportional to the concentration, so if the spectrometer is not calibrated accurately then incorrect value of absorbance also affects the value of equilibrium constant.

Hence, we get incorrect value of equilibrium constant for each of the given mistakes.

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Answer:

When there is a conflict and if a friend responding to conflict with confrontation it may affect positively or negatively both ways depend how he responds or confront the other person he has a conflict with. But normally people alienate with the person being confrontational. A friend should try to resolve the conflict by making an amicable solution.

if it is used correctly it could help in making the relationship strong, however, confronting by attacking them verbally, insult them, or talking loudly among the group of people can escalate the conflict.

I will advise him to be cautious of the approach as it may positively or negatively affect the situation.

This is the process which involves directly engaging one another in the course of a dispute between them.

This method however could either resolve the conflict or worsen it which is why special approach should be taken by being calm and being respectful to the other party involved.

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Answer:

C) Mercury based thermometer

Explanation:

Answer:

Mercury based thermometer

Explanation:

When you touch a lightbulb it is warm. Hairdryer produces heat to dry your hair. Stove heats up to warm food and liquids up.

Answer:

Approximately [tex]279\; \rm mg[/tex] of fluorine would be produced.

Explanation:

Look up the relative atomic mass of these calcium and fluorine on a modern periodic table:

In other words, the mass of each mole of calcium atoms is (approximately) [tex]40.078\; \rm g[/tex]. Similarly, the mass of each mole of fluorine atoms is (approximately) [tex]18.998\; \rm g[/tex].

Calculate the number of moles of calcium atom that were produced:

[tex]\begin{aligned} &n({\rm Ca}) \\ &= \frac{m({\rm Ca})}{M({\rm Ca})} \\ &= \frac{294\; \rm mg}{40.078\; \rm g \cdot mol^{-1}} \\ &= \frac{0.294\; \rm mg}{40.08 \; \rm g \cdot mol^{-1}}\\ & \approx 7.3357 \times 10^{-3}\; \rm mol\end{aligned}[/tex].

Every formula unit of calcium fluoride, [tex]\rm CaF_2[/tex], contains twice as many fluorine atoms as calcium atoms.

Hence, if the sample contained approximately [tex]7.33570 \times 10^{-3}\; \rm mol[/tex] calcium atoms, it would contain twice as many fluorine atoms:

[tex]\begin{aligned}n({\rm F}) &= 2\, n({\rm Ca}) \\ &\approx 2 \times 7.33570\times 10^{-3}\; \rm mol \\ &\approx 1.4671 \times 10^{-2}\; \rm mol\end{aligned}[/tex].

Calculate the mass of that many fluorine atoms:

[tex]\begin{aligned}& m({\rm F}) \\ &= n({\rm F}) \cdot M({\rm F}) \\ &\approx 1.4671 \times 10^{-2}\; \rm mol \times 18.998\; \rm g \cdot mol^{-1} \\ &\approx 278.72 \times 10^{-3}\; \rm g \\&\approx 279\; \rm mg\end{aligned}[/tex].

279 mg of Fluorine was formed in the decomposition reaction

The equation of the reaction is;

CaF2 -----> Ca + 2F

Mass of calcium formed = 294 mg

Number of moles of Ca in 294 mg = 294 × [tex]10^-3[/tex] g/40 g/mol = 0.00735 moles

From the equation, the products are in ration 1 : 2

Since 1 mole of Ca is to 2 moles of F

0.00735 moles of Ca is to 0.00735 moles × 2 moles/1 mole

= 0.0147 moles of F

Mass of F = 0.0147 moles × 19 g/mol

= 0.279g or 279 mg of F

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Answer:

0.75mol/LNaOH

Explanation:

Data: Soln:

M= ? M= n/ V(l)

n= 3moles. M= 3mol/ 4L

V= 4L. M = 0.75 mol/LNaOH

Hey love! <3

Answer:

C. Resource use by humans has gone up and down over the years is a false statement

Explanation:

In the graph you can make an observation on how the increase of human population is directly positive.

The resource use either has a positive or negative correlation, making it impossible for the usage to fluctuate over the years.

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Answer: The formula of the hydrate is [tex]MnSO_4.2H_2O[/tex]

Explanation:

Decomposition of hydrated manganese sulphate is given by:

[tex]MnSO_4.xH_2O\rightarrow MnSO_4+xH_2O[/tex]

Molar mass of [tex]MnSO_4[/tex] = 151.0 g/mol

According to stoichiometry:

(151.0+18x) g of [tex]MnSO_4.xH_2O[/tex] decomposes to give 151.0 g of [tex]MnSO_4[/tex]

Thus 45.91 g of [tex]MnSO_4.xH_2O[/tex] decomposes to give= [tex]\frac{ 151.0}{151.0+18x}\times 45.91g[/tex]  of [tex]MnSO_4[/tex]

Also we are given : 37.07 g of  [tex]MnSO_4[/tex] is produced

Thus we can equate the two equations:

[tex]\frac{ 151.0}{151.0+18x}\times 45.91=37.07[/tex]

[tex]x=2[/tex]  

Thus the formula of the hydrate is [tex]MnSO_4.2H_2O[/tex]

Answer:

a Binomial Naming System

Explanation:

Answer:

Splits into

Explanation:

Because fission reaction is divided into two or more pieces.

Answer: F. Electrons

Explanation: hope it helped    .u.

Answer:

294.87 gm  CaCl_2

Explanation:

The computation of the  mass of calcium chloride is shown below:

But before that following calculations need to be done

Number of moles of chlorine atom is

= 3.20 × 10^24 ÷ 6.022 × 10^23

= 5.314 moles

As we know that

1 mole CaCl_2 have the 2 moles of chlorine atoms

Now 5.341 mole chloride atoms would be

= 1 ÷ 2 × 5.314

= 2.657 moles

Now

Mass of CaCl_2 = Number of moles × molar mass of  CaCl_2

= 2.657 moles × 110.98 g/mol

= 294.87 gm  CaCl_2

Answer:

P4O10

Explanation:

(P2O5)n=283.89

62+80=283.89

142n=283.89

n=2

P2O10

The empirical and molecular formula are related by the formula, molecular formula=2×empirical formula ,meaning double the atoms present in empirical formula,hence molecular formula is P₄O₁₀.

Empirical formula of a compound is defined as the simplest whole number ratio of atoms which are present in a compound.It does not make any mention of the arrangement of atoms or the number of atoms. The empirical formula gives information about the ratio of number of atoms which are present in a compound.

Molecular formula is determined from the empirical formula by dividing the molar mass of a compound by the empirical formula mass. The resultant which should be a whole number or very close to the whole number , then the subscripts are multiplied by the whole number to get the molecular formula.

For the compound P₂O₅ the subscripts of phosphorous and oxygen are multiplied by 2 and hence the molecular formula P₄O₁₀.

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Answer: The molarity of [tex]Na_2S_2O_3[/tex] is 0.108 M

Explanation:

[tex]KIO_3+5KI+3H_2SO_4\rightarrow 3K_2SO_4+3H_2O+3I_2[/tex]

[tex]2Na_2S_2O_3+I_2\rightarrow Na_2S_4O_6+2NaI[/tex]

To calculate the number of moles for given molarity, we use the equation:

[tex]\text{Molarity of the solution}=\frac{\text{Moles of solute}}{\text{Volume of solution (in L)}}[/tex]    

[tex]\text{Moles of }KIO_3=\frac{0.0131mol/L\times 21.55}{1000}=2.8\times 10^{-4}mol[/tex]

1 mole of [tex]KIO_3[/tex]  produces = 3 moles of   [tex]I_2[/tex]

[tex]2.8\times 10^{-4}[/tex] moles of [tex]KIO_3[/tex] produces = [tex]\frac{3}{1}\times 2.8\times 10^{-4}=8.4\times 10^{-4}[/tex] moles of [tex]I_2[/tex]  

Now 1 mole of [tex]I_2[/tex] uses = 2 moles of [tex]Na_2S_2O_3[/tex]

[tex]8.4\times 10^{-4}[/tex] moles of [tex]I_2[/tex] uses =  [tex]\frac{2}{1}\times 8.4\times 10^{-4}=1.69\times 10^{-3}[/tex]  moles of [tex]Na_2S_2O_3[/tex]

[tex]\text{Molarity of the solution}=\frac{\text{Moles of solute}}{\text{Volume of solution in L}}=\frac{1.69\times 10^{-3}\times 1000}{15.65}=0.108M[/tex]

The molarity of [tex]Na_2S_2O_3[/tex] is 0.108 M  

Answer:

4.80×10³ years

Explanation:

Let the original amount (N₀) of ²²⁶Rn = 1 g

Therefore,

12.5% of the original amount = 12.5% × 1 = 12.5/100 × 1 = 0.125 g

Next, we shall determine the number of half-lives that has elapse. This can be obtained as follow:

Original amount (N₀) = 1

Amount remaining (N) = 0.125 g

Number of half-lives (n) =?

N = 1/2ⁿ × N₀

0.125 = 1/2ⁿ × 1

0.125 = 1/2ⁿ

Cross multiply

0.125 × 2ⁿ = 1

Divide both side by 0.125

2ⁿ = 1/0.125

2ⁿ = 8

Express 8 in index form with 2 as the base

2ⁿ = 2³

n = 3

Thus, 3 half-lives has elapsed.

Finally, we shall determine the time taken for only 12.5% of the original sample of ²²⁶Rn to remain.

This can be obtained as follow:

Half-life (t½) = 1.60×10³ years

Number of half-lives (n) = 3

Time (t) =?

t = n × t½

t = 3 × 1.60×10³

t = 4.80×10³ years.

Thus, it will take 4.80×10³ years for 12.5% of the original sample of ²²⁶Rn to remain.

With few exceptions, cellular membranes — including plasma membranes and internal membranes — are made of glycerophospholipids, molecules composed of glycerol, a phosphate group, and two fatty acid chains. Glycerol is a three-carbon molecule that functions as the backbone of these membrane lipids.

Explanation:

the principal components of plasma membrane are lipids phospholipid and cholesterol proteins and carbohydrates