Answers
C. 1,500 hope this helps
Related Questions
PLEASE READ THIS!!! Don't answer my questions with a link. Someone already answered this question, but they gave me a link and it was blocked on my school Chromebook, so it was an entirely useless answer. Thank you. If you answer this question without using a link I will give you an easy to earn 100 points. I just need to know how to turn this shape into as many triangles as possible. Thank you for reading this message.
Answers
Answer: 9 triangles
Step-by-step explanation:
Use the information given to find the equation of the line using the point-slope formula (y-y_1)=m(x-x_1)). Then convert your answer to slope-intercept form (y=mx+b).
y-intercept of 2 and (4,-1)
If it's possible please a explanation on how you solved it.
Answers
Answer:
y=[tex]-\frac{3}{4}[/tex]x+2
Step-by-step explanation:
y=sx+2;
-1=4s+2;
s=-3/4;
y=[tex]-\frac{3}{4}[/tex]x+2
If the sum of a number and two is tripled, the result is one less than twice the number. Find the number.
Answers
Answer:
z
Step-by-step explanation:
hqvqhqvw karrar ras wallah a part
Jayden's snow cone machine makes 3 snow cones from 0.5 pounds of ice. How many snow cones can be made with ice please show your work, not an explanation!!!!
Answers
Answer:
30
Step-by-step explanation:
3 snow cones per 0.5 pounds of ice
0.5 pounds of ice x 10 = 5 pounds of ice
3 snow cones X 10 = 30 snow cones.
-x = 3
HELP ASAP MATHEMATICS
Answers
Answer:
x = -3
Step-by-step explanation:
Answer:
x=-3
Step-by-step explanation:
You can just do +x on both sides so: 0=3+x and then -3 on both sides: -3=x.
3. A gym charges a fee of $15 per month plus an additional charge for every group class
attended. The total monthly gym cost T can be represented by this equation: T = 15+c*n,
where c is the additional charge for a group class, and n is the number of group classes
attended
Which equation can be used to find the number of group classes a customer attended if we
know c and T?
a. n = I - 15
N
b. n=1 – 150
c. n = (T - 15) - C.
(T-15)
d. n=
1
Answers
Answer:
Option D) [tex]\huge\sf{n\:=\:\frac{(T\:-\:15)}{c}}[/tex]
Step-by-step explanation:
Given the equation, T = 15 + c × n, where:
T = represents the total monthly gym cost
c = represents the additional charge for a group class, and
n = represents the number of group classes attended
Solution:In order to determine which equation can be used to find the number of group classes a customer attended, if there are given values for c and T, we must isolate the variable, n algebraically.
The first step is to subtract 15 from both sides:
T = 15 + c × n
T - 15 = 15 - 15 + c × n
T - 15 = c × n
Next, divide both sides by c to isolate n :
[tex]\huge\mathsf{\frac{({T\:-\:15})}{c}\:=\:\frac{{c\:\times\:n}}{c}}[/tex]
[tex]\huge\sf{n\:=\:\frac{(T\:-\:15)}{c}}[/tex]
Therefore, the correct answer is Option D) [tex]\huge\sf{n\:=\:\frac{(T\:-\:15)}{c}}[/tex].
In a certain chemical, the ratio of zinc to copper is 3 to 14. A jar of the chemical contains 630 grams of copper. How many grams of zinc does it contain?
Answers
Answer:
135 grams of Zinc
Step-by-step explanation:
zinc:copper
3:14
3/14=x/630
x=135
The corner section of a football stadium has 6 seats on the first row. Each row after that has an additional 3 seats. How many seats would be on the 20th row?
32
63
103
342
Answers
9514 1404 393
Answer:
63
Step-by-step explanation:
The number of seats in a row will give an arithmetic sequence:
6, 9, 12, 15, ...
The first term is 6; the common difference is 3. The general term is ...
an = a1 +d(n -1) . . . . . . n-th term of sequence with first term a1, difference d
The 20th term of the sequence is ...
a20 = 6 +3(20 -1) = 6 +57 = 63
There would be 63 seats on the 20th row.
Write down an example to show that each of the following two siatements is not correct
a) The factors of an even number are always even
Answers
Answer:
a) 2 * 3 = 6.
b) 123 is odd but contains an even digit (2).
Step-by-step explanation:
-2.3z = -13.8
I need to show work lol
Answers
Here are your answers.
it's made by computer.
- BRAINLIEST answerer
Answer:
z = 6
Step-by-step explanation:
- 2.3z = - 13.8 ( divide both sides by - 2.3 )
z = [tex]\frac{-13.8}{-2.3}[/tex] = 6
(27/8)^1/3×[243/32)^1/5÷(2/3)^2]
Simplify this question sir pleasehelpme
Answers
Step-by-step explanation:
[tex] = {( \frac{27}{8} )}^{ \frac{1}{3} } \times ( \frac{243}{32} )^{ \frac{1}{5} } \div {( \frac{2}{3} )}^{2} [/tex]
[tex] = { ({ (\frac{3}{2} )}^{3}) }^{ \frac{1}{3} } \times {( {( \frac{3}{2}) }^{5} )}^{ \frac{1}{5} } \div {( \frac{2}{3} )}^{2} [/tex]
[tex] = {( \frac{3}{2} )}^{3 \times \frac{1}{3} } \times {( \frac{3}{2} )}^{5 \times \frac{1}{5} } \times {( \frac{3}{2} )}^{2} [/tex]
[tex] = \frac{3}{2} \times \frac{3}{2} \times {( \frac{3}{2} )}^{2} [/tex]
[tex] = {( \frac{3}{2} )}^{1 + 1 + 2} [/tex]
[tex] = {( \frac{3}{2} )}^{4} \: or \: \frac{81}{16} [/tex]
[tex]\large\underline{\sf{Solution-}}[/tex]
[tex]\sf{\longmapsto{\bigg( \dfrac{27}{8} \bigg)^{\frac{1}{3}} \times \Bigg[\bigg( \dfrac{243}{32} \bigg)^{\frac{1}{5}} \div \bigg(\dfrac{2}{3} \bigg)^{2}\Bigg]}} \\[/tex]
We can write as :
27 = 3 × 3 × 3 = 3³
8 = 2 × 2 × 2 = 2³
243 = 3 × 3 × 3 × 3 × 3 = 3⁵
32 = 2 × 2 × 2 ×2 × 2 = 2⁵
[tex]\sf{\longmapsto{\bigg( \dfrac{3 \times 3 \times 3}{2 \times 2 \times 2} \bigg)^{\frac{1}{3}} \times \Bigg[\bigg( \dfrac{3 \times 3 \times 3 \times 3 \times 3}{2 \times 2 \times 2 \times 2 \times 2} \bigg)^{\frac{1}{5}} \div \bigg(\dfrac{2}{3} \bigg)^{2}\Bigg]}} \\[/tex]
[tex]\sf{\longmapsto{\bigg( \dfrac{{(3)}^{3}}{{(2)}^{3}} \bigg)^{\frac{1}{3}} \times \Bigg[\bigg( \dfrac{({3}^{5})}{{(2)}^{5}} \bigg)^{\frac{1}{5}} \div \bigg(\dfrac{2}{3} \bigg)^{2}\Bigg]}} \\[/tex]
Now, we can write as :
(3³/2³) = (3/2)³
(3⁵/2⁵) = (3/2)⁵
[tex]\sf{\longmapsto{\left\{\bigg(\frac{3}{2} \bigg)^{3} \right\}^{\frac{1}{3}} \times \Bigg[\left\{\bigg(\frac{3}{2} \bigg)^{5} \right\}^{\frac{1}{5}} \div \bigg(\dfrac{2}{3} \bigg)^{2}\Bigg]}} \\[/tex]
Now using law of exponent :
[tex]{\sf{({a}^{m})^{n} = {a}^{mn}}}[/tex]
[tex]\sf{\longmapsto{\bigg( \frac{3}{2} \bigg)^{3 \times \frac{1}{3}} \times \Bigg[\bigg(\frac{3}{2} \bigg)^{5 \times \frac{1}{5}} \div \bigg(\dfrac{2}{3} \bigg)^{2}\Bigg]}} \\[/tex]
[tex] \sf{\longmapsto{\bigg( \frac{3}{2} \bigg)^{\frac{3}{3}} \times \Bigg[\bigg(\frac{3}{2} \bigg)^{\frac{5}{5}} \div \bigg(\dfrac{2}{3} \bigg)^{2}\Bigg]}} \\[/tex]
[tex]\sf{\longmapsto{\bigg( \frac{3}{2} \bigg)^{1} \times\Bigg[\bigg(\frac{3}{2} \bigg)^{1} \div \bigg(\dfrac{2}{3} \bigg)^{2}\Bigg]}} \\[/tex]
[tex]\sf{\longmapsto{\bigg( \frac{3}{2} \bigg)^{1} \times \Bigg[\bigg(\frac{3}{2} \bigg)^{1} \times \bigg(\dfrac{3}{2} \bigg)^{2}\Bigg]}} \\[/tex]
[tex]\sf{\longmapsto{\bigg( \frac{3}{2} \bigg)^{1} \times \Bigg[\bigg(\frac{3}{2} \bigg)^{1} \times \bigg(\dfrac{3}{2} \times \dfrac{3}{2} \bigg)\Bigg]}} \\[/tex]
[tex]\sf{\longmapsto{\bigg( \dfrac{3}{2} \bigg)^{1} \times \Bigg[\bigg(\dfrac{3}{2} \bigg)^{1} \times \bigg(\dfrac{3 \times 3}{2 \times 2}\bigg)\Bigg]}} \\[/tex]
[tex]\sf{\longmapsto{\bigg( \dfrac{3}{2} \bigg)^{1} \times \Bigg[\bigg(\dfrac{3}{2} \bigg)^{1} \times \bigg(\dfrac{9}{4}\bigg)\Bigg]}} \\[/tex]
[tex] \sf{\longmapsto{\bigg( \frac{3}{2} \bigg)\times \Bigg[\bigg(\frac{3}{2} \bigg)\times \bigg(\dfrac{9}{4}\bigg)\Bigg]}} \\[/tex]
[tex]\sf{\longmapsto{\bigg( \dfrac{3}{2} \bigg)\times \Bigg[ \: \: \dfrac{3}{2} \times \dfrac{9}{4} \: \: \Bigg]}}\\[/tex]
[tex]\sf{\longmapsto{\bigg( \dfrac{3}{2} \bigg)\times \Bigg[ \: \: \dfrac{3 \times 9}{2 \times 4} \: \: \Bigg]}} \\[/tex]
[tex]\sf{\longmapsto{\bigg(\dfrac{3}{2} \bigg)\times \Bigg[ \: \: \dfrac{27}{8} \: \: \Bigg]}} \\[/tex]
[tex]\sf{\longmapsto{\dfrac{3}{2} \times \dfrac{27}{8}}} \\[/tex]
[tex]\sf{\longmapsto{\dfrac{3 \times 27}{2 \times 8}}} \\[/tex]
[tex] \sf{\longmapsto{\dfrac{81}{16}}\: ≈ \:5.0625\:\red{Ans.}} \\[/tex]
What is the common ratio of the sequence 3, 21, 147, … ?
7
Which formula can be used to find the nth term of the sequence 3, 21, 147, … ?
Use the given formula to find the indicated terms of the sequence.
a4 =
1029
a5 =
7203
Answers
A= 1029
B=7203
Answer:
What is the common ratio of the sequence 3, 21, 147, …?
7
Which formula can be used to find the nth term of the sequence 3, 21, 147, …?
c)
Use the given formula to find the indicated terms of the sequence.
a4 = 1029
a5 = 7203
Step-by-step explanation:
Answers for all three questions<3
HELP ME PLEASE RNNN FASTTT
Answers
Answer:
The first three are functions
Step-by-step explanation:
4th one fails the Vertical line test.
Which equation, in slope-intercept form, matches the equation shown?
a line that goes through the points (0, -4) and (6, -9)
Question 4 options:
y=47x−4
y=56x+1
y=−56x−4
y=−47x+1
Please help!
Answers
Answer: i think it is y=−56x−4
Step-by-step explanation:
The equation in the slope intercept form which passes through the points ( 0, -4 ) and ( 6 , 9 ) is y = (-5 / 6)x - 4.
The correct answer is Option C.
Given data:
To find the equation of a line in slope-intercept form (y = mx + b) that passes through the points (0, -4) and (6, -9), we need to determine the slope (m) and the y-intercept (b).
First, calculate the slope (m):
m = (change in y) / (change in x)
m = (-9 - (-4)) / (6 - 0)
m = (-9 + 4) / 6
m = -5 / 6
Now that we have the slope, we can use one of the given points (let's use (0, -4)) to solve for the y-intercept (b):
-4 = (-5 / 6) * 0 + b
-4 = b
So, the y-intercept (b) is -4.
Now, we can write the equation of the line in slope-intercept form:
y = (-5 / 6)x - 4
Hence, the equation of the line is y = (-5 / 6)x - 4.
To learn more about equation of line, refer:
https://brainly.com/question/14200719
#SPJ3
The complete question is attached below:
Which equation, in slope-intercept form, matches the equation shown?
a line that goes through the points (0, -4) and (6, -9)
A) y = ( 4/7 )x - 4
B) y = ( 5/6 )x + 1
C) y = ( -5/6 )x - 4
D) y = ( -4/7 )x + 1
C+X=G
what is X?
this is a literal equation.
Answers
Answer:
x=g-c
Step-by-step explanation:
hope this helps!
24. A triangle has side lengths of 6, 8, and 9. What type of triangle is it?
acute
equiangular
obtuse
right
•
Answers
It a acute
Hope this help you :)
Help me plz i wanna make an an A
Answers
2 . 3² - 1 = blank please hurry up and help
Answers
Is 7164 divisible by 6?
yes?
no?
Answers
Answer:
yes
7164 is divisible bt 6
Answer:
Yes
Step-by-step explanation:
Any number will be divisible by 6 if they be divisible by 2 & 3
- we know 7164 is divisible by 2
- also any number which sum of their digits are divisible by 3, the number will be divisible by 3
in this case (7164) 7+1+6+4=18 & 18 is divisible by 3 so 7164 is divisible by 3 as well.
so 7164 is divisible by 6
The length of a rectangle is 5 more than twice the width. Which equation could represent the area of the rectangle in terms of the width?
Answers
Answer:
l=5+2w
Step-by-step explanation:
Since the length is twice the width plus 5, the equation would look like :
l=5+2w
A=lw
w=width
2w+5=length
42=w(2w+5)
42=2w2+5w
2w2+5w-42=0
use the quadratic equation
(-5+√25+336)/4
(-5+√361)/4
(-5+19)/4
14/4=3.5
w=3.5 m
2w+5=12 m
3.5 by 12 rectangle
what is the percentage discount when a stereo is reduced from $258 to $199?
Answers
Using the appropriate Algebraic identity evaluate the following:(4a - 5b)²
Answers
[tex](4a - 5b)^{2} \\ by \: \: \: using \: \: \: (x - y)^{2} = {x}^{2} - 2xy + {y}^{2} \\ = {(4a)}^{2} - 2(4a)(5b) + {(5b)}^{2} \\ = {16a}^{2} - 40ab + 25 {b}^{2} [/tex]
Answer:[tex] {16a}^{2} - 40ab + {25b}^{2} [/tex]
Hope it helps.
Do comment if you have any query.
At Crescent High School, 108 students plan on going to an in-state college and 63 students plan on going to an out-of-state college. What is the ratio of students planning on going to an in-state college to students planning on going to an out-of-state college?
A.
12:7
B.
108:1
C.
7:12
D.
1:108
Answers
Explanation:
The ratio we want to find can be thought of in the form in:out
We list the number of "in-state" people first followed by the "out-of-state" people next. A colon separates the two values. So we have the initial ratio of 108:63
Divide both parts by the GCF 9
108/9 = 1263/9 = 7The ratio 108:63 fully reduces to 12:7 meaning there are 12 in-state students for every 7 out-of-state students. The order is important because 7:12 would be incorrect and imply we had 7 in-state vs 12 out-of-state.
The perimeter of a rectangular field is 312m. If the width of the field is 61m,what is the length.
Answers
Answer:
95m
Step-by-step explanation:
312 - 61 - 61 = 190
190/2 = 95
Y-2=-3(x-7) written in standard form
Answers
You just add +2 to each side and the positive and negative cancel out and it switches it over
4- (-z/3) = 8 Solve for z
Answers
Answer:z=12
Step-by-step explanation:
(2x+y)2-y2 if x=-3 y=4 and z=-5
Answers
-12
Hope this helps!
combine like the like terms
34w - 4g + 4g - 36w
Answers
the answer is -2w (i have the write at least 20 words to dont worry about this)
Answer:
-2w
Step-by-step explanation:
Like terms have same variable.
34w - 4g + 4g - 36w = 34w - 36w - 4g + 4g
= - 2w + 0 = -2w
help please
f − –7/3 = 3
Answers
Answer:
f=2/3
Step-by-step explanation:
3x - 5 = 7x + 11
x =
Answers
Answer:
[tex]3x - 5 = 7x + 11 \\ 7x - 3x = - 11 - 5 \\ 4x = - 16 \\x = - \frac{16}{4} \\ \color{yellow} \boxed{x =-4}[/tex]
Answer:
x= -4
Step-by-step explanation:
3x-5=7x+11
3x-5+5=7x+11+5
3x=7x+11+5
3x=7x+16
3x-7x=7x+16-7x
-4=7x+16-7x
-4x=16
divided each side by -4
x= 16 over -4
divide them and you get -4.
