Answer:
Sample because it's only the first ten games of the season not of all the games in the season
Step-by-step explanation:
Answer:
Sample but the power of a study is its ability to detect an effect when there is one to be detected. ... A sample size that is too small increases the likelihood of a Type II error skewing the results, which decreases the power of the study.
Within accompaniment order to be a population then it would need to be justifiable to be comparable to a larger cross section same teams different players that could be at the end of the season, and a population that shows cross section of change, such as the inevitable and include distractions that occur in sports as season starts and progresses till end. Examples of this would include ie) playing with man down etc. or against a team with man down or during penalties etc..
It only becomes a population when it defines all home games only being used as a population as this would show less distraction for each team. Which would be unlikely event in first 10 games, just like it would be unfair to not show the differences for away games within a population.
The higher proportion showing the whole season, thereafter would show population as things change too fast in seasonal events.
please help :) Respecting and understanding different opinions promotes fill in the blank . answer choices : (value/tolerance)
Answer:
Tolerance
Step-by-step explanation:
Value in this situation doesn't make sense and you can search up the definition of tolerance on the web to verify.
Also, this doesn't seem like a math related question so you should have answered this in English or something.
Kapil deposited Rs. 1600 in a bank on 1st January 2005. Find the amount in his bank account on 1st January 2006, if the bank pays interest at 8% per annum and the interest is calculated every year on 30th June and 31st December.
Answer:
SI=PRT/100
=10000*5*42/12*100
=1750
SI=1750
TOTAL AMOUNT=PRINCIPLE+SI
=10000+1750
=101750
Your mother has left you in charge of the annual family yard sale. Before she leaves you to your entrepreneurial abilities, she explains that she has made the job easy for you: everything costs either $1.50 or $3.50. She asks you to keep track of how many of each type of item is sold, and you make a list, but it gets lost sometime throughout the day. Just before she’s supposed to get home, you realize that all you know is that there were 150 items to start with (your mom counted) and you have 41 items left. Also, you know that you made $227.50. Write a system of equations that you could solve to figure out how many of each type of item you sold.
A) x + y = 109
(1.5)x + 227.50 = (3.5)y
B) x + y = 109
(3.5)x + 227.50 = (1.5)y
C) x + y = 41
(1.5)x + 227.50 = (3.5)y
D) x + y = 109
(1.5)x + (3.5)y = 227.50
E) x + y = 150
(1.5)x + (3.5)y = 227.50
F) x + y = $3.50
(1.5)x + (3.5)y = 227.50
Answer:
[tex]D)\ x + y = 109\\(1.5)x + (3.5)y = 227.50[/tex]
Step-by-step explanation:
Let the items sold with price $1.5 = [tex]x[/tex]
Let the items sold with price $3.5 = [tex]y[/tex]
Initially, total number of items = 150
Items left at the end of the day = 41
So, number of items sold throughout the day = Total number of items - Number of items left
Number of Items sold = 150 - 41 = 109
So, the first equation can be written as:
[tex]\bold{x+y = 109} ....... (1)[/tex]
Now, let us calculate the sales done by each item.
Sales from item with price $1.5 = Number of items sold [tex]\times[/tex] price of each item
= (1.5)[tex]x[/tex]
Sales from item with price $3.5 = Number of items sold [tex]\times[/tex] price of each item
= (3.5)[tex]y[/tex]
Total sales = [tex]\bold{(1.5)x+(3.5)y = 227.50} ....... (2)[/tex]
So, the correct answer is:
[tex]D)\ x + y = 109\\(1.5)x + (3.5)y = 227.50[/tex]
3. E, F and G are collinear points. E is between F and G.
If FE = 3 in., and FG = 7 in., what is the length of EG?
a. 4
c. 3
I
b. 10
d. 21
Answer:
A. 4 inStep-by-step explanation:
Collinear points are points that lies on the same straight line. If the points E, F and G are collinear points, then the three points lies on the same straight line.
If E is between F and G, the FE+EG = FG
EG = FG - FE
Given FE = 3 in and FG = 7 in
On substituting into the expression above to get EG;
EG = 7in - 3in
EG = 4in
Hence the length of EG is 4in
represent 1/3 and 5/2 on the same number line
Answer:
Picture below
Step-by-step explanation:
● 5/2 is 2.5 so just divide the space between 3 by 2
● for 1/3 divide the space between 0 and by 3
QUICK IT IS FOR, NOW!!! I WILL GIVE BRAINLIESTS AND 10 POINTS
When p2 – 4p is subtracted from p2 + p – 6, the result is: -3p-6, 5p-6 or 4p+6. To get p – 9, subtract: 4p+3, 4p-15 or 4p+12 from this result.
Step-by-step explanation:
p² - 4p is subtracted from p² + p - 6 is written as
p² + p - 6 - (p² - 4p)
Remove the bracket and simplify
That's
p² + p - 6 - p² + 4p
p² - p² + 4p + p - 6
We have the answer as
5p - 6Let the unknown expression be x
Subtract x from the expression to get p - 9
That's
5p - 6 - x = p - 9
x = 5p - p - 6 + 9
x = 4p + 3
The expression is
4p + 3Hope this helps you
Order the expressions from least to greatest.
2^3 - 2^1 , 2^1 + 3^1 , 3^2
Answer:
2¹ + 3¹, 2³ - 2¹, 3²
Step-by-step explanation:
2³ - 2¹ = 8 - 2 = 6
2¹ + 3¹ = 2 + 3 = 5
3² = 9
Which products result in a difference of squares? Select three options. A. (x minus y)(y minus x) B. (6 minus y)(6 minus y) C. (3 + x z)(negative 3 + x z) D. (y squared minus x y)(y squared + x y) E. (64 y squared + x squared)(negative x squared + 64 y squared)
Answer:
C D E
Step-by-step explanation:
Edg
Out of the given options, options C, D and E are a difference of squares.
What is the difference of squares?Difference of Squares, two terms that are squared and separated by a subtraction sign.
Given are, options,
D) (y squared minus x y)(y squared + x y) = (y²-xy)(y²+xy) = y⁴-(xy)²
E) (64 y squared + x squared)(negative x squared + 64 y squared) = (64y²+x²)(64y²-x²) = (64y)⁴-x⁴
C) (3 + x z)(negative 3 + x z) = (3+xz)(3-xz) = 3²-(xz)²
Hence, out of the given options, options C, D and E are a difference of squares.
For more references on difference of squares, click;
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A study of long-distance phone calls made from General Electric Corporate Headquarters in Fairfield, Connecticut, revealed the length of the calls, in minutes, follows the normal probability distribution. The mean length of time per call was 3.5 minutes and the standard deviation was 0.70 minutes. What is the probability that calls last between 3.5 and 4.0 minutes? (Round your z value to 2 decimal places and final answer to 4 decimal places.)
Answer:
0.2611
Step-by-step explanation:
Given the following information :
Normal distribution:
Mean (m) length of time per call = 3.5 minutes
Standard deviation (sd) = 0.7 minutes
Probability that length of calls last between 3.5 and 4.0 minutes :
P(3.5 < x < 4):
Find z- score of 3.5:
z = (x - m) / sd
x = 3.5
z = (3.5 - 3.5) / 0.7 = 0
x = 4
z = (4.0 - 3.5) / 0.7 = 0.5 / 0.7 = 0.71
P(3.5 < x < 4) = P( 0 < z < 0.714)
From the z - distribution table :
0 = 0.500
0.71 = very close to 0.7611
(0.7611 - 0.5000) = 0.2611
P(3.5 < x < 4) = P( 0 < z < 0.714) = 0.2611
Oliver completed his project in no more than twice the amount of time it took Karissa to complete her project. Oliver spent 4 and one-fourth hours on his project. If k represents the amount of time that it took Karissa to complete her project, which inequality can be used to represent the situation?
Answer:
4 1/4 <_ 2K
Step-by-step explanation:
The inequality that represents the situation is k ≥ 2.125 hours.
What is Inequality ?Inequality is the statement where two algebraic expressions are equated using an inequality operator, <, >, <> etc.
Karissa takes k time to complete the project.
Oliver takes ≤ 2k
The time spent by Oliver is 4 1/4 = 17/4 = 4.25 hours
2k ≥ 4.25
k ≥ 2.125 hours
Therefore, the inequality that represents the situation is k ≥ 2.125 hours.
To know more about Inequality
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Find the median of the following frequency distribution
Answer:
3
Step-by-step explanation:
First right out all the data in numerical order from left to right.
2, 2, 2, 3, 4, 5, 7
The median is the middle number in the set. If there is an even amount of data points, find the average of the two middle numbers. If there is an odd number of data points, like in this data set, just take the middle number as you median.
There are 7 data points in this set so the fourth number in the set written in numerical order would be your median.
When writing this set out in numerical order, repeated numbers must be repeated, we find that the fourth, or middle, number is 3. Therefore, 3 is the median of this data set.
2500 feet is to how many meters
Answer: is 762 meters
Step-by-step explanation:
One foot is equal to 0.3048 meters so multiply 2500 by 0.3048 to find how many meters there are.
2500 * 0.3048 = 762
Answer:762.5 meters
Step-by-step explanation:
1 foot =0.305 m
Hence,0.305×2500=762.5 metres as the answer.
Use the first four terms of the binomial theorem to approximate 2.2^7
A. 248.96
B. 248.4688
C. 23.424
D. 249.4357888
please explain the steps to how you got your answer thank you!!
Answer:
248.96.
Step-by-step explanation:
We write it as:
(2 + 0.2)^7 = 2^7 + 7*2^6*0.2 + 7C2*2^5*(0.2)^2 + 7C3*2^4(*(0.2)^3
= 128 + 89.6 + 26.88 + 4.48
= 248.96.
what is the method or solution to this question (3)x-1=81x
[tex]3x-1=81x\\78x=-1\\x=-\dfrac{1}{78}[/tex]
Answer:
[tex]\large \boxed{\displaystyle x=- \frac{1}{78}}[/tex]
Step-by-step explanation:
[tex]3x-1=81x[/tex]
Subtract 3x from both sides of the equation.
[tex]-1=78x[/tex]
Divide both sides of the equation by 78.
[tex]\displaystyle \frac{-1}{78} =x[/tex]
At the beginning of the day the stock market goes up 60 1/2 points and stays at this level for most of the day. At the end of the day the stock market goes down 100 1/4 points from the high at the beginning of the day. What is the total change in the stock market from the beginning of the day to the end of the day?
Answer: it would be 40/2 or 20, but im not sure.
Step-by-step explanation: so what I did was: 100 1/4 - 60 1/2: 100 - 60 = 40 and then I subtracted 1-1 which is 0 then 4-2 which is 2, and got 40/2 or just simplify which will be equal to 20
Answer ASAP, Will give brainliest!!
Answer:
First. 115°
Second. 65°
Third. 65°
Fourth. 7
Fifth. 425.25
First
angle DAB = angle ADC (since this is an isosceles trapezoid)
Second
In a trapezoid adjacent angle are supplmentary (that is their sum is 180°)
180-115 is 65°
Third
(Same reason as second)
Fourth
The side 3x+4 is same as the opposite side
So 3x + 4 = 25
on solving you get x = 7 in
Fifth
[tex]area \: = \frac{1}{2} \times length \: of \: the \: perpendicular \: (b1 + b2)[/tex]
area = 1/2 × 13.5 (20+43)
area = 1/2 × 13.5 × 63
Thus area is 425.25
Answer:
Step-by-step explanation:
1)As ABCD is isosceles trapezium,
∠ADC= ∠DAB
∠ADC = 115°
2) AD //BC
∠ADC + ∠DCB = 180° {co interior angles}
115 + ∠DCB = 180
∠DCB = 180 - 115
∠DCB = 65°
3) As ABCD is isosceles trapezium,
∠CBA = ∠DCB
∠CBA = 65°
4) As ABCD is isosceles trapezium, non parallel sides are congruent.
AB = DC
3x + 4 = 25 in
3x = 25 - 4
3x = 21
x = 21/3
x = 7 in
5) height = 13.5 in
a= 43 in
b= 20 in
Area of trapezium = [tex]\frac{(a+b)*h}{2}\\[/tex]
[tex]= \frac{(43 +20)*13.5}{2}\\\\=\frac{63*13.5}{2}\\\\\\= 425.25 in^{2}[/tex]
Two shaded identical rectangular decorative tiles are first placed (one each) at the top and at the base of a door frame for a hobbit's house, as shown in Figure 1. The distance from W to H is 45 inches. Then the same two tiles are rearranged at the top and at the base of the door frame, as shown in Figure 2. The distance from Y to Z is 37 inches. What is the height of the door frame, in inches?
Answer:
41 inches
Step-by-step explanation:
Let the point at the top of the door on the left be x
Wx + xH = 45
Let the point at the top of the door on the right be c
Yc + cZ = 37
We know the door is
xH + plus the width of the tile
The width of the tile is Yc
xH + Yc
On the right door
cZ + the height of the tile
cZ + Wx
Add the two doors together
xH + Yc + cZ + Wx = 2 times the height of the door
Rewriting
xH + Wx + Yc + cZ = 2 times the height of the door
45+ 37 = 2 times the door height
82 = 2 times the door height
Divide by 2
41 = door height
Someone pls HELP MEEEE i’m giving the rest of my points away . i have like 20 mins to turn this in
Answer:
1) 27.89
2) 20
Step-by-step explanation:
#1)
9.5x + 75 --> 340
340 - 75 --> 265
265 / 9.5 = 27.89
#2)
120 / 6 =
20 minutes
Of the students at Milton Middle School, 120 are girls. If 50% of the students are girls, how many total students are there at Milton Middle school
It costs $0.0015 to leave a lightbulb on for an hour. How much would it cost
to have a lightbulb on for a month? (Helpful conversions: There are 24 hours
in a day, and there are 30 days in a month).
Will give brainliest
Jillian’s school is selling tickets for a play. The tickets cost $10.50 for adults and $3.75 for students. The ticket sales for opening night totaled $2071.50. The equation 10.50 a plus 3.75 b equals 2071.50, where a is the number of adult tickets sold and b is the number of student tickets sold, can be used to find the number of adult and student tickets. If 82 students attended, how may adult tickets were sold? ___adult tickets
Answer: The number of the adult tickets is 168
Step-by-step explanation: * Lets explain how to solve the problem
- The adults ticket costs $10.50
- The students ticket costs $3.75
- The total money of the opening night is $2071.50
- The equation of the total money earned in the opening night is:
10.50 a + 3.75 b = 2071.50, where a is the number of the adult ticket
and b is the number of the student ticket
- There were 82 students attended
* Lets solve the problem
∵ 10.50 a + 3.75 b = 2071.50
∵ The number of the students attended is 82
∵ b is the number of the students
∴ b = 82
- Substitute the value of b in the equation
∴ 10.50 a + 3.75(82) = 2071.50
∴ 10.50 a + 307.5 = 2071.50
- Subtract 307.5 from both sides
∴ 10.50 a = 1764
- Divide both sides by 10.50
∴ a = 168
∵ a is the number of the adult tickets
∴ The number of the adult tickets is 168
Give credit to ashraf 82
Answer:
The answer is 168
Step-by-step explanation:
Which of these is a ratio table?
A 2-column table has 3 rows. Column 1 is labeled A with entries 1, 2, 3. Column 2 is labeled B with entries 5, 6, 7.
A 2-column table has 3 rows. Column 1 is labeled A with entries 1, 2, 3. Column 2 is labeled B with entries 4, 5, 7.
A 2-column table has 3 rows. Column 1 is labeled A with entries 1, 2, 3. Column 2 is labeled B with entries 1, 4, 9.
A 2-column table has 3 rows. Column 1 is labeled A with entries 1, 2, 3. Column 2 is labeled B with entries 2, 4, 6.
Answer:
A 2-column table has 3 rows. Column 1 is labeled A with entries 1, 2, 3. Column 2 is labeled B with entries 2, 4, 6.
Step-by-step explanation:
The table with a constant ratio between A and B is the one with entries ...
B/A = 2/1 = 4/2 = 6/3
The ratio is 2. The table is the last one described here.
Answer:
b
Step-by-step explanation:
hope this helps
Evaluate the expression when c = 4 and x = -2.
-C+ 6x
Answer:
-16
Step-by-step explanation:
We are given the expression:
-c+6x
and asked to evaluate when c=4 and x=-2. Therefore, we must substitute 4 in for c and -2 in for x.
-(4)+6(-2)
Solve according to PEMDAS: Parentheses, Exponents, Multiplication, Addition, Subtraction.
First, multiply 6 and -2.
6 * -2= -12
-(4)+ -12
-(4) -12
Distribute the negative sign.
-4 -12
Subtract 12 from -4.
-16
The expression -c+6x when c=4 and x= -2 is -16.
Answer:
-16
Step-by-step explanation:
Start with -C+ 6x. Replace C with '4' and x with '-2'
This comes out to -(4) + 6(-2) = -4 - 12 = - 16
Please help.. very confused
Answer:
D { -1,0,3,5}
R { -3,-1,1,7}
Step-by-step explanation:
The domain is the input values
3,-1,5,0
We normally put them from smallest to largest
D { -1,0,3,5}
The range is the output values
1,-3,7, -1
We normally put them from smallest to largest
R { -3,-1,1,7}
Find the area of a circle with a diameter of 4.
Either enter an exact answer in terms of it or use 3.14 for 7 and enter your answer as a decimal.
units?
area of circle =22/7×4=12.56
Chuck goes to a community college there is an enrollment fee of 207.55 plus 223.07 per credit hour which eqaution shows C the total cost of attending the community college for x credit hour
Answer:
C = 207.55 + 223.07x
Step-by-step explanation:
Given the following :
Cost of community college:
Enrollment fee = 207.55
Fee per credit hour = 223.07
Attending the community College for 'x' credit hours can be represented by:
Total cost = C
[Enrollment fee + (fee per credit hour * number of credit hours)]
Number of credit hours = x
C = [207.55 + (223.07 * x)]
C = 207.55 + 223.07x
Therefore, the total cost 'C' of attending the community college for 'x' credit hour:
C = 207.55 + 223.07x
(-6x)(½y)(-⅓z) what is the product?
Answer:
xyz
Step-by-step explanation:
[tex](-6x)(\frac{1}{2}y)(-\frac{1}{3}z) = (-6)*\frac{1}{2}*(-\frac{1}{3}) * xyz = \frac{6}{6} xyz = xyz[/tex]
I need help fast please
Answer:
Difference : 4th option
Step-by-step explanation:
The first thing we want to do here is to factor the expression x² + 3x + 2. This will help us if it is similar to the factored expression " ( x + 2 )( x + 1 ). " The denominators will be the same, and hence we can combine the fractions.
x² + 3x + 2 - Break the expression into groups,
( x² + x ) + ( 2x + 2 ) - Factor x from x² + x and 2 from 2x + 2,
x( x + 1 ) + 2( x + 2 ) - Group,
( x + 2 )( x + 1 )
This is the same as the denominator of the other fraction, and therefore we can combine the fractions.
x - 1 / ( x + 2 )( x + 1 )
As you can see this is not any of the options present, as we have not expanded ( x + 2 )( x + 1 ). Remember previously that ( x + 2 )( x + 1 ) = x² + 3x + 2. Hence our solution is x - 1 / x² + 3x + 2, or option d.
0.21212121 as a fraction
Answer:
21212121/100000000
Step-by-step explanation:
21212121/100000000 cannot be simplified
Hope this helps!
Answer:
0.21212121 Cannot be converted into a fraction
sinθ/(1-〖cos〗^2 θ)=cosecθ
Answer:
see explanation
Step-by-step explanation:
Using the trigonometric identities
sin²x + cos²x = 1 ⇒ sin²x = 1 - cos²x
cosec x = [tex]\frac{1}{sinx}[/tex]
Consider the left side
[tex]\frac{sin0}{1-cos^20}[/tex]
= [tex]\frac{sin0}{sin^20}[/tex] ← cancel sinΘ on numerator/denominator
= [tex]\frac{1}{sin0}[/tex]
= cosecΘ = right side
