Answer: f(x)=200•(0.85)^x
Step-by-step explanation:
C(t) is the actual value of the function at time t
Co is the initial value of C at t=0
r is the decaying rate, expressed in decimal
Depreciation is often modeled as an exponential decay function. Since Jim bought a skateboard for Co=$200, its value will depreciate by r=15% = 0.15 each year since buying it.
What is the value of x?
A. 6
B. 5
c. 4
D.3
Answer:
D
Step-by-step explanation:
CD is an angle bisector and divides the opposite side into segments which are proportional to the other 2 sides, that is
[tex]\frac{BC}{AC}[/tex] = [tex]\frac{BD}{AD}[/tex] , substitute values
[tex]\frac{4}{3}[/tex] = [tex]\frac{x}{2.25}[/tex] ( cross- multiply )
3x = 9 ( divide both sides by 3 )
x = 3 → D
ik you want the points
plzz
Answer:
Line 1: Undefined
Line 2: -4/3
Line 3: 4/3
Line 4: Undefined
Line 5: 7/3
Line 6: -7/3
Line 7: 0
Line 8: 0
Line 9: Undefined
Line 11: 0
Line 10 & 12: Undefined
Step-by-step explanation:
Use the slope formula (you can just search up the slope formula)
Also, always remember that a vertical line's slope will be undefined and a horizontal line's slope will be 0 (zero).
I hope this helps!
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Answer: Only j = 2
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Explanation:
Let's solve for j
[tex]\frac{96}{j} \ge 40\\\\96 \ge 40j\\\\\frac{96}{40} \ge j\\\\2.4 \ge j\\\\j \le 2.4[/tex]
In the second step, I multiplied both sides by j. If j is a positive number, then the inequality sign will not flip. All of the answer choices are positive numbers, so we don't have to worry about the inequality sign flipping.
The last step shows that j = 2.4 or j < 2.4
So j is 2.4 or smaller.
Of the list given to us, only j = 2 fits the description, since something like j = 8 is not 2.4 or smaller.
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If j = 2, then,
[tex]\frac{96}{j} \ge 40\\\\\frac{96}{2} \ge 40\\\\48 \ge 40\\\\[/tex]
which is a true statement since 48 is larger than 40. This shows that j = 2 is a solution.
Something like j = 8 does not work because
[tex]\frac{96}{j} \ge 40\\\\\frac{96}{8} \ge 40\\\\12 \ge 40\\\\[/tex]
which is false because 12 is not equal to 40 or larger than 40. This means j = 8 is not a solution. You should find that j = 12 and j = 3 lead to similar false statements.
Of the list given, j = 2 is the only solution.
______________________________
1.) Solve using j = 12:Plug in 12: [tex]\frac{96}{12}[/tex] ≥ [tex]40[/tex]Divide 96 by 12: [tex]=8[/tex] Compare: [tex]8[/tex] ≥ [tex]40[/tex]
So this is False.
2.) Solve using j = 8:Plug in 8: [tex]\frac{96}{8}[/tex] ≥ [tex]40[/tex]Divide 96 by 8: [tex]=12[/tex] Compare: [tex]12[/tex] ≥ [tex]40[/tex]
So this is False.
3.) Solve using j = 2:Plug in 2: [tex]\frac{96}{2}[/tex] ≥ [tex]40[/tex] Divide 96 by 2: [tex]=48[/tex]Compare: [tex]48[/tex] ≥ [tex]40[/tex]So this is True.
4.) Solve using j = 3:Plug in 3: [tex]\frac{96}{3}[/tex] ≥ [tex]40[/tex]Divide 96 by 3: [tex]=32[/tex] Compare: [tex]32[/tex] ≥ [tex]40[/tex]So this is False.
______________________________
You pay $11.20 to buy drink boxes for the football team. Each drink box cost $0.40. How many drink boxes did
you buy?
The cylinder shown here has a height of 7 centimeters and a radius of 4 centimeters. What is the area of the base of the cylinder? Express your answer in terms of 1. Do not include units (cm2) in your answer. Use pi to represent the n symbol. For example: 321 would be typed as 32pi
Answer: 16pi
Step-by-step explanation:
14 is 33 1/2% of what number?
Answer:
41.79
Step-by-step explanation:
c = 14 * 100/33.5 = 1400/33.5 = 2800/67
= 41.79104