Joseph puts a piece of toast on a plate. The toast is hot from the toaster. When he puts the toast on the plate, the energy of the plate increases. What must be true of the energy of the toast?

Answer:

3.68 g/cm3

Explanation:

D = M / V

350 / 95

Answer:

2.41 * 10^24 atoms of carbon present in the products.

Explanation:

First, we need to find the moles of carbon in the products in order to find the number of atoms.

We see that in the chemical formula, carbon belongs to the compound known as glucose. To get the amount of moles of carbon, we need to divide my the amount of carbon within glucose (in grams) from the total amu ( or grams) of glucose to get the moles.

C6 = 72.066.

C6H12O6 = 180.156

72.066/180.156 = 0.4000199827 moles of Carbon within the Glucose compound

Now we will convert to atoms/molecules by multiplying the moles by avogadro's number..

0.4000199827 moles C * 6.022*[tex]10^{23}[/tex] = 2.408920336 *[tex]10^{24}[/tex] atoms of Carbon present in the products

*Note --> this can be estimated to 2.41 * [tex]10^{24}[/tex] atoms of Carbon

Answer:

35.453 amu.

Explanation:

From the question given above, the following data were obtained:

Isotope A (Cl–35):

Abundance (A%) = 75.77%

Mass of A = 34.969 amu

Isotope B (Cl–37):

Abundance (B%) = 24.23%

Mass of B = 36.966 amu

AVERAGE atomic mass of Cl =?

The average atomic mass of Cl can be obtained as follow:

Average = [(Mass of A × A%)/100] + [(Mass of B × B%)/100]

Average = [(34.969 × 75.77)/100] + [(36.966 × 24.23)/100]

Average = 26.496 + 8.957

Average atomic mass of Cl = 35.453 amu.

Answer:

P4O10

Explanation:

Answer:

i not sure but i searched it up and it said Q=104525J

Explanation:

Answer:

The answer is c, Clouds fill with moisture and get too hravy

The characteristic that could distinguish a crystalline solid from an amorphous solid is option b. The way it breaks.

Crystalline solids contained edges and faces, that should be diffracted x-rays, and have sharp melting points.

While on the other hand, amorphous solids should contain irregular does not provide well-resolved x-ray diffraction patterns.

hence, the option b is correct.

And, the rest of the options are wrong.

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thermal contact

When heat flows from one object or substance to another it is in contact with, the objects or substances are said to be in thermal contact. The state where objects in thermal contact with each other reach the same temperature, no heat flows between them.

Answer: In the case of water, we know that the O-H covalent bond is polar, due to the different electronegativities of hydrogen and oxygen. Since there are two O-H bonds in water, their bond dipoles will interact and may result in a molecular dipole which can be measured.

Explanation:

Answer:

dunno

Explanation:

Answer:

253.5mL of Ba(OH)₂ are required to neutralize the HCl solution

The pH at equivalence point is = 7

Explanation:

The reaction of Ba(OH)₂ with HCl is:

Ba(OH)₂ + 2HCl → BaCl₂ + 2H₂O

First, we need to find moles of HCl. With these moles and the chemical equation we can find the moles of Ba(OH)₂ and the volume required:

Moles HCl:

75.0mL = 0.075L * (0.845mol / 1L) = 0.063375moles HCl

Moles Ba(OH)₂:

0.06338moles HCl * (1mol Ba(OH)₂ / 2mol HCl) = 0.03169 moles Ba(OH)₂

Volume of the 0.125M Ba(OH)₂:

0.03169 moles Ba(OH)₂ * (1L / 0.125mol) = 0.2535L are required =

253.5mL of Ba(OH)₂ are required to neutralize the HCl solution

As the titration was of a strong acid, HCl, with a strong base, Ba(OH)₂, the pH at equivalence point is = 7

Answer: The empirical formula is [tex]NaBO_2[/tex]

Explanation:

If percentage are given then we are taking total mass is 100 grams.

So, the mass of each element is equal to the percentage given:

Mass of Na= 34.5 g

Mass of B= 16.4 g

Mass of O = 48.6 g

Step 1 : convert given masses into moles.

Moles of Na =[tex]\frac{\text{ given mass of Na}}{\text{ molar mass of Na}}= \frac{34.5g}{23g/mole}=1.5moles[/tex]

Moles of B =[tex]\frac{\text{ given mass of B}}{\text{ molar mass of B}}= \frac{16.4g}{11g/mole}=1.5moles[/tex]

Moles of O =[tex]\frac{\text{ given mass of O}}{\text{ molar mass of O}}= \frac{48.6g}{16g/mole}=3moles[/tex]

Step 2 : For the mole ratio, divide each value of moles by the smallest number of moles calculated.

For Na = [tex]\frac{1.5}{1.5}=1[/tex]

For B = [tex]\frac{1.5}{1.5}=1[/tex]

For O =[tex]\frac{3}{1.5}=2[/tex]

The ratio of Na: B: O= 1: 1: 2

Hence the empirical formula is [tex]NaBO_2[/tex]

Answer:

C. are found in the nucleus of an atom

Explanation:

Protons and Neutrons are always located at the center of the atom also called as the nuclei of the atom and constitute nearly all the mass of the atom, while the electrons revolve around them in orbits called shells. Only protons have a positive charge and electrons have negative charges, due to which only protons and electrons attract each other, while neutrons lack charges or have 'Neutral Charges'.

Answer:

the final temperature is 465.2k

Answer:

Molarity = 0.3 M

Explanation:

Given data:

Moles of NaOH = 0.720 mol

Volume of water = 2.40 L

Molarity = ?

Solution:

Molarity is used to describe the concentration of solution. It tells how many moles are dissolve in per litter of solution.

Formula:

Molarity = number of moles of solute / L of solution

Molarity = 0.720 mol / 2.40 L

Molarity = 0.3 mol/L

Molarity = 0.3 M

Answer:

PCl3 - trigonal pyramidal <109 degrees

SCl2 - bent<109 degrees

SiF4 - tetrahedral 109 degrees

Explanation:

The shape of all three molecules derive from a tetrahedral arrangement of electron pairs.

However, in PCl3 there is a lone pair of electrons on P and three bond pairs. This leads to the observance of a trigonal pyramidal geometry with bond angle <109 degrees.

In SCl2, there are four regions of electron density around S, two lone pairs and two bond pairs leading to a bent molecular geometry with bond angle <109 degrees.

In SiF4, there are four bond pairs and no lone pair. The molecular geometry is tetrahedral with a bond angle of 109 degrees.

Answer:

0.9612 g

Explanation:

First we calculate how many moles are there in 3.00 g of CCl₃F, using its molar mass:

Now, we need to calculate how many grams of N₂O would have that same number of molecules, or in other words, the same amount of moles.

Thus we calculate how many grams would 0.0218 moles of N₂O weigh, using the molar mass of N₂O :

The  mass of dinitrogen monoxide is 0.9612 g

The number of  moles are there in 3.00 g of CCl₃F, using its molar mass:

= 3.00 g CCl₃F ÷ 137.37 g/mol

= 0.0218 mol CCl₃F

Now the mass should be

=[ 0.0218 mol N₂O ×  44.013 g/mol

= 0.9612 g N₂O

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Answer:

carbon mono oxide CO

Explanation:

as both are in 1:1 ratio so CO is formed

The [H₃0⁺] of the solution : 1.778  x 10⁻¹² M

pH is the degree of acidity of a solution that depends on the concentration of H⁺ ions. The greater the value the more acidic the solution and the smaller the pH.  

pH = - log [H⁺]  

So that the two quantities between pH and [H⁺] are inversely proportional because they are associated with negative values.  

A solution whose value is different by n has a difference in the concentration of H⁺ ion of 10ⁿ.  

pH of solution = 11.75

the [H₃0⁺] of the solution :

[tex]\tt pH=-log[H_3O^+]\\\\11.75=-log[H_3O^+]\\\\(H_3O^+]=10^{-11.75}=1.778\times 10^{-12}[/tex]

Answer:

1. They will react.

2. 2HCI + Zn —> ZnCl2 + H2

Explanation:

1. From the question given above,

We can see that Zn is higher than H in the activity series.

NOTE: Elements higher (i.e at the top) in the activity series will displace those lower (i.e at the bottom) in the series. Thus, Zn is higher in the series than H. Therefore, Zn will displace H from solution. Hence, they will react.

2. The product obtained from the reaction can be seen as follow:

HCI + Zn —> ZnCl2 + H2

The above equation can be balance as follow:

There are 2 atoms of H on the right side and 1 atom on the left side. It can be balance by putting 2 in front of HCl as shown below:

2HCI + Zn —> ZnCl2 + H2

Answer:

377mL is the volume of the solution

Explanation:

A 0.140M solution of CuNO₃ contains 0.140 moles of CuNO₃ per liter of solution. Thus, we need to convert first the mass of CuNO₃ to moles using its molar mass and, with the moles available, we can find the volume of the solution, thus:

Moles CuNO₃ -Molar mass: 125.55g/mol:

6.63g * (1mol / 125.55g) = 0.0528 moles of CuNO₃.

Volume of solution:

0.0528 moles of CuNO₃ * (1L / 0.140 moles CuNO₃) = 0.377L

0.377L * (1000mL / 1L) =

Answer:

i think the answer is c

Explanation:

collission

Answer:

bottom right corner with arrows going up

Hi there! :)

[tex]\large\boxed{x = 2.49 L}[/tex]

Use the proportion for Charles' Law where:

[tex]\frac{v_{1}}{t_{1}}= \frac{v_{2}}{t_{2}}[/tex]

v1 = initial volume

t1 = initial temperature

v2 = final volume

v2 = final temperature

Substitute in the given values into the proportion:

v1 = 4.39 L

t1 = 44° C

t2 = 25°C

v2 = x L

Set up the proportion:

[tex]\frac{4.39}{44} = \frac{x}{25}[/tex]

Cross multiply:

[tex]25 * 4.39 = 44x\\\\109.75 = 44x\\\\x = 2.49 L[/tex]

Answer:

The new volume will be approximately 2.49 L.

Explanation:

We are given that a gas sample occupies 4.39 L at 44° C.

We are also given that we are going decrease the temperature to 25° C.

Charles' Law has a formula which shows the relationship between the volumes of a samples and the temperatures of the samples.

The proportion is shown as:

[tex]\displaystyle \bullet \ \ \ \frac{V_1}{T_1} = \frac{V_2}{T_2}[/tex],

where V₁ and V₂ are the initial and final volume respectively and T₁ and T₂ are the initial and final temperature respectively.

This proportion can be used to determine what our unknown is. We need to know the final volume.

[tex]\displaystyle \frac{4.39 \ \text{L}}{44 \ \text{C}} = \frac{\text{x}}{25 \ \text{C}}\\\\\\\frac{4.39}{44} = \frac{x}{25}\\\\\\4.39 \times 25 = 44 \times x\\\\\\44x = 109.75\\\\\\\frac{44x}{44}=\frac{109.75}{44}\\\\\\x = 2.49432 \approx \boxed{2.49 \ \text{L}}[/tex]

Therefore, if we reduce the temperature to 25 °C, we will be reducing the volume of the substance to 2.49 L.

Protons,neutrons,electrons