Justin was asked to write equations based on the triangle below. So far he has come up with the following equations: Which of the following would be another correct equation?

Answer:

[tex]x=-3[/tex]

Step-by-step explanation:

Hi there!

Linear equations are typically organized in slope-intercept form: [tex]y=mx+b[/tex] where m is the slope and b is the y-intercept (the value of y when x is 0).

Typically, we would start with finding the slope of the line. However, notice how the two x-coordinates in the given points are both -3. This means that this is a vertical line, with an undefined slope.

Vertical lines have their equations organized differently: [tex]x=d[/tex] where d is the x-intercept, or the value of x when y is 0.

Because the x-coordinates in all the points a vertical lines passes through are the same, the x-intercept would therefore be -3. Plug this into the equation [tex]x=d[/tex]:

[tex]x=-3[/tex]

I hope this helps!

Answer:

a) The area of the triangle AQB is 43 square centimeters.

b) The length of the line segment AQ is approximately 14.866 centimeters.

Step-by-step explanation:

a) The procedure consist in subtracting the areas of triangles APQ, ASB and BRQ of the area the rectangle, that is to say:

[tex]A = (9\,cm)\cdot (14\,cm) - \frac{1}{2}\cdot (5\,cm)\cdot (14\,cm) - \frac{1}{2}\cdot (8\,cm)\cdot (9\,cm) -\frac{1}{2}\cdot (4\,cm) \cdot (6\,cm)[/tex]

[tex]A = 43\,cm^{2}[/tex]

The area of the triangle AQB is 43 square centimeters.

b) The length of the line segment AQ is determined by Pythagorean Theorem:

[tex]AQ = \sqrt{AP^{2}+PQ^{2}}[/tex] (1)

[tex]AQ = \sqrt{(5\,cm)^{2}+(14\,cm)^{2}}[/tex]

[tex]AQ \approx 14.866\,cm[/tex]

The length of the line segment AQ is approximately 14.866 centimeters.

Answer:

Percent * base = Amount

660 g = 660 g

3kg = 3000g

percent(3000) = 660

percent = 660/3000

percent = .22

.22 = 22%

Step-by-step explanation:

Answer:

25%

Step-by-step explanation:

increase by = 150 - 120

=30

increase percent = 30/120 * 100%

=3000/120

=25 %

Answer:

25%

Step-by-step explanation:

Percentage increase=(new value-original value)/(original value) x 100%

Percentage increase=(150-120)/120 x 100%

Percentage increase=30/120 x 100%

Percentage increase=1/4 x 100%

Percentage increase=25%

B neither perpendicular nor parallel

Answer:

B

Step-by-step explanation:

B. neither perpendicular nor parallel

because, the line are not crossing nor are they aside from each other.

Answer:

f(2) = 0 and g(2) = 0

f(2) = g(2) TRUE

b) f(0) = 2 and g(0) = -2

f(0) = g(0) FALSE

c) f(2) = 0 and g(0) = -2

f(2) = g(0) FALSE

d) f(0) = 2 and g(2) = 0

f(0) = g(2) FALSE

Answer:

Empty square = +

Empty Circle = ÷

Step-by-step explanation:

In order to eliminate the extra numbers from the equation you have to do the opposite of the problem. So...

-6x-1=5

-6x -1+1 = 5+1 (eliminating the 1 from the -6x side and adding it to the other side)

-6x = 6

-6x ÷ -6 = 6 ÷ -6 ( eliminating the-6 so that one side just has x)

so... x= -1

Answer: Option B is your correct answer.

Answer:

Step-by-step explanation:

angle 2 is also 60 degree (being vertically opposite angles)

angle 3 is also 60 degree (being corresponding angles)

angle 4 is also 60 degree (being corresponding angles ) . sice angle 2 is 60 degree and relation between  angle 2 and 4 is corresponding angle , angle 4 will also be 60 degree.

Answer:

5 pints of milk

Step-by-step explanation:

took the test

Answer:

i think its A but im not sure its correct

Step-by-step explanation:

Answer:

x=-9/10

Step-by-step explanation:

2x+8x+16=7

Step 1: Simplify both sides of the equation.

2x+8x+16=7

(2x+8x)+(16)=7(Combine Like Terms)

10x+16=7

10x+16=7

Step 2: Subtract 16 from both sides.

10x+16−16=7−16

10x=−9

Step 3: Divide both sides by 10.

10x/10

=

−9/10

x=-9/10

Answer:

x = - 4 ± [tex]\sqrt{7}[/tex]

Step-by-step explanation:

Given

x² + 8x + 16 = 7 ( subtract 16 from both sides )

x² + 8x = - 9

Using the method of completing the square

add ( half the coefficient of the x- term)² to both sides

x² + 2(4)x + 16 = - 9 + 16

(x + 4)² = 7 ( take the square root of both sides )

x + 4 = ± [tex]\sqrt{7}[/tex] ( subtract 4 from both sides )

x = - 4 ± [tex]\sqrt{7}[/tex]

Then

solutions are x = - 4 - [tex]\sqrt{7}[/tex] , x = - 4 + [tex]\sqrt{7}[/tex]

Answer:

D. - 3 ≤ x < 1

Step-by-step explanation:

The numerator cannot be the square root of a neg. no.

So, x + 3 ≥ 0 or x ≥ -3

The denominator cannot be a neg. no. or 0.

So, 1 - x > 0

1 > x or x < 1

So, altogether - 3 ≤ x < 1

Therefore, D is the correct answer.

HOPE IT MAY HELP YOU

PLEASE MARK AS BRAINLIST

Answer:

option 3 : (2x - 7 )

Step-by-step explanation:

ax + bx = x(a+ b)

a(x+ y) + b(x+y) = (x+y)(a+b)

[tex](3x - 8 ) ( 2x + 5) - (x + 1)(2x + 5)\\\\(2x+5)[ (3x - 8) - (x+1) ][/tex]      [ (2x + 5) is common is both terms ]

[tex](2x+ 5)(3x -8 -x + 1)\\\\(2x+ 5)(2x - 7)[/tex]

Therefore , the binomial is ( 2x - 7)

Answer:

[tex]\frac{3}{4}[/tex]

Step-by-step explanation:

[tex]\frac{1}{4} +\frac{1}{6} +\frac{1}{3}[/tex]

4 = 2 × 2 × 1

6 = 2 × 3 × 1

3 = 3 × 1

GCF = 1

4 × 6 × 3 = 72

[tex]\frac{18}{72} +\frac{12}{72} +\frac{24}{72}[/tex]

[tex]\frac{18+12+24}{72}[/tex]

[tex]\frac{54}{72}[/tex]

54 = 2 × 3 × 3 × 3

72 = 2 × 2 × 2 × 3 × 3

GCF = 2 × 3 × 3

GCF = 18

[tex]\frac{\frac{54}{18} }{\frac{72}{18} }=\frac{3}{4}[/tex]

[tex]\huge\textsf{Hey there!}[/tex]

[tex]\large\textsf{Looking for your LCD (Least Common Denominator) of each fraction}\downarrow\\\\\\\mathsf{\dfrac{1}{4}=\dfrac{3}{12}}\\\\\\\mathsf{\dfrac{1}{6}=\dfrac{2}{12}}\\\\\\\mathsf{\dfrac{1}{3}=\dfrac{4}{12}}\\\\\\\\\\\large\textsf{The LCD is \underline{12}}[/tex]

[tex]\mathsf{\dfrac{1}{4}+\dfrac{1}{6}+\dfrac{1}{3}}[/tex]

[tex]\mathsf{= \ \dfrac{1\times3}{4\times3}+\dfrac{1\times2}{6\times2}+\dfrac{1\times4}{3\times4}}[/tex]

[tex]\large\textsf{Solving for the numerators (TOP numbers)}\downarrow\\\\\mathsf{1\times3=\boxed{\bf 3}}\\\\\mathsf{1\times2=\boxed{\bf 2}}\\\\\mathsf{1\times4=\boxed{\bf 4}}[/tex]

[tex]\large\textsf{Solving for the denominators (BOTTOM numbers)}\downarrow\\\\\mathsf{4\times3=\boxed{\bf 12}}\\\\\mathsf{6\times2=\boxed{\bf 12}}\\\\\mathsf{3\times4=\boxed{\bf 12}}[/tex]

[tex]\mathsf{=\ \dfrac{3+2+4}{12}}[/tex]

[tex]\large\textsf{Solving for your numerator (TOP number) }\downarrow\\\\\\\mathsf{3+2+4}\\\\\mathsf{= 5+4}\\\\\mathsf{= \boxed{\large\textsf{\bf 9}}}[/tex]

[tex]\mathsf{=\ \dfrac{9}{12}}[/tex]

[tex]\mathsf{\dfrac{9\div3}{12\div3}}\\\\\\\\\mathsf{9\div3= \boxed{\large\textsf{\bf 3}}}\\\\\mathsf{12\div3=\boxed{\large\textsf{\bf 4}}}[/tex]

[tex]\mathsf{= \dfrac{3}{4}}[/tex]

[tex]\boxed{\boxed{\large\textsf{Answer: }\boxed{\mathsf{\bold{ \dfrac{9}{12}\ or\ \dfrac{3}{4}}\ either\ of\ those\ fractions\ should\ work\ because}}}}\\\boxed{\boxed{\large\textsf{they are equal to each other!}}}\huge\checkmark[/tex]

[tex]\large\textsf{Good luck on your assignment and enjoy your day!}[/tex]

~[tex]\frak{Amphitrite1040:)}[/tex]

Answer:

8 hours

Step-by-step explanation:

In 4 hours she earns 16 dollars

Since this is proportional ( goes through zero), we can multiply by 2

8 hours = 32 dollars

Jada needs to walk the dog for, 8 hours.

4x8 = 32

Answer:

{F, G, H, I, J, K, L, M, N, O, P}

are the points between segment EQ :)

Answer:

33.89

Step-by-step explanation:

the side lengths are the distances between the corner points of the triangle.

P and Q have the same x value, and they therefore create a side parallel to the y-axis. and it is easy to find the length of this side : it is just the difference of the y values.

PQ = 6 - (-6) = 6 + 6 = 12

QR and RP are trickier.

we need Pythagoras to calculate the length of the direct connection between these points as the Hypotenuse of the right triangles with the differences in x and in y values as the other sides.

QR :

QR² = (-3 - 6)² + (-6 - -2)² = (-9)² + (-4)² = 81 + 16 = 97

QR = sqrt(97) ≈ 9.848857802

RP :

RP² = (6 - -3)² + (-2 - 6)² = 9² + (-8)² = 81 + 64 = 145

RP = sqrt(145) ≈ 12.04159458

the perimeter/circumference of the triangle is the sum of all 3 sides

= 12 + sqrt(97) + sqrt(145) ≈ 33.89

Answer: (C) 308 cm^2

Step-by-step explanation: Flat surface area is the surface area that is not curved; in this case, it would be the two circular bases. The height is arbitrary as the height is not needed to calculate the area of the bases. The formula for the area of circular bases is πr^2. Let's plug the given values into the formula. (22/7)(7)^2=(22/7)(49)=154. 154 cm^2 is the area of one base. To find the area of both bases, simply multiply the area of one base by two. 154*2 is 308, therefore the answer is (C) 308 cm^2.

answer:

the answer is 40 because any expression divides itself is equals to 1

Step-by-step explanation:

Hi there!  

»»————-　★　————-««

I believe your answer is:  

[tex]\frac{1}{x^3}[/tex]

»»————-　★　————-««  

Here’s why:

⸻⸻⸻⸻

[tex]\boxed{\text{Calculating the Answer...}}\\\\x^5\div x^8\\---------\\\rightarrow \text{Rewrite as:} \frac{x^5}{x^8}\\\\\rightarrow \text{Recall the exponent rule: } \frac{x^a}{x^b}=x^{a-b}\\\\\rightarrow \frac{x^5}{x^8} = x^{-3}\\\\\rightarrow \text{Recall the exponent rule: }x^{-b}=\frac{1}{x^b}\\\\\rightarrow x^{-3}\\\\\rightarrow \boxed{\frac{1}{x^3}}[/tex]

⸻⸻⸻⸻

»»————-　★　————-««  

Hope this helps you. I apologize if it’s incorrect.  

Answer: is b

Step-by-step explanation:

Answer:

13

Step-by-step explanation:

-2x + 6 = -20

Step 1 subtract 6 from both sides

6 - 6 cancels out

-20 - 6 = -26

We now have -2x = -26

Step 2 divide both sides by -2

-2x/-2 = x

-26/-2 = 13

We're left with x = 13

Answer:

The probability is 32/81

Step-by-step explanation:

We know that:

The probability that the team wins is p = 2/3

Then the probability of not winning is q = 1 - p = 1 - 2/3 = 1/3

The team plays 4 matches.

We want to find the probability that the team wins 1 more than half of the number of matches played.

So if there are 4 matches, the half is 2 matches

one more than half is then 3 matches.

Let's assume that the team wins the first 3 matches, and does not win the last match.

match one, the team wins with prob: P₁ = 2/3

match two, the team wins with prob: P₂ = 2/3

match three, the team wins with prob: P₃ = 2/3

match four, the team wins with prob: P₄ = 1/3

The joint probability is the product of all the individual probabilities:

P = (2/3)*(2/3)*(2/3)*(1/3)

Now we must also considerate the permutations, we have the cases:

the team does not win the fourth match

the team does not win the third match

the team does not win the second match

the team does not win the first match

So we have just four permutations, then the total probability is:

probability = 4*P = 4*(2/3)*(2/3)*(2/3)*(1/3) = 4*(8/81) = (32/81)

Answer:

Draw the number line like in the picture.

Step-by-step explanation:

√5 is about 2.236, meaning it's kind of close to 2.25.

√7 is about 2.646, meaning it's very close to 2.625.

Answer:

10

Step-by-step explanation:

First, we know that the angles of a triangle add up to 180 degrees. We can then sum up our angles as 90 (since it's a right triangle, represented by the square in the bottom left angle) +27+6x+3=180

90+27+6x+3=180

Add up left side

120+6x=180

Subtract 120 from both sides

6x=60

Divide both sides by 6

x=10

Answer:

[tex]A \approx 1.488[/tex]

Step-by-step explanation:

Por definición de razones trigonométricas, tenemos las siguientes identidades:

[tex]\tan \theta = \frac{y}{x} = \sqrt{2}[/tex] (1)

[tex]\sin \theta = \frac{y}{\sqrt{x^{2}+y^{2}}}[/tex] (2)

[tex]\cos \theta = \frac{x}{\sqrt{x^{2}+y^{2}}}[/tex] (3)

Si [tex]\theta[/tex] es agudo, entonces [tex]x, y > 0[/tex].

De (1), suponemos [tex]x = 1[/tex] que [tex]y = \sqrt{2}[/tex], entonces los valores de las funciones seno y coseno:

[tex]\sin \theta = \frac{\sqrt{2}}{\sqrt{5}} = \sqrt{\frac{2}{5} }[/tex]

[tex]\sin \theta = \frac{\sqrt{10}}{5 }[/tex]

[tex]\cos \theta = \sqrt{\frac{1}{5} }[/tex]

[tex]\cos \theta = \frac{\sqrt{5}}{5}[/tex]

Por último, calculemos [tex]A[/tex]:

[tex]A = 3\cdot \left(\frac{\sqrt{10}}{5} + \frac{\sqrt{5}}{5} \right) - \sqrt{7}[/tex]

[tex]A \approx 1.488[/tex]

Answer:

0.77

Step-by-step explanation:

Given that:

P(A) = 0.64

P(B) = 0.25

P(AnB) = 0.12

Probability that customer buys either pet or baby supplies ; P(AuB)

P(AuB) = P(A) + p(B) - p(Ann)

P(AuB) = 0.64 + 0.25 - 0.12

P(AuB) = 0.77

Answer:

Step-by-step explanation:

[tex]\frac{1.107}{123} \times \frac{1.998}{333} = [/tex]

[tex] = > 9 \times 6[/tex]

[tex] = 45[/tex]

Answer:

Step-by-step explanation:

[tex]\frac{1.107}{123}*\frac{1.998}{333}= 0.009 * 0.006 = 0.000054[/tex]

1107÷ 123 = 9

The dividend has 3 decimal places. So, take 3 decimal places from the right towards left in the result  0.009

1.107 ÷ 123 = 0.0009

0.009 * 0.006

First multiply 9 * 6 = 54

Now, count the number of decimal place in the multiplicands. 0.009 has 3 decimal places and 0.006 has 3 decimal places. So totally, 3+ 3 = 6 decimal places in the result

0.009 * 0.006 = 0.000054

Answer:

TH is an element on the sample space for first rolling a die and then tossing a coin. A coin has both heads and tails.

The sample space for rolling a number cube and then tossing a coin is:

{(1, H), (1, T), (2, H), (2, T), (3, H), (3, T), (4, H), (4, T), (5, H), (5, T), (6, H), (6, T)}

The elements can be any of the elements in the sample space.

It is the total number of possible outcomes from a given set.

We have,

The sample space for rolling a number cube and then tossing a coin consists of all possible outcomes from rolling the number cube and tossing the coin.

Each outcome is a pair consisting of a number from 1 to 6 (the possible outcome from rolling the number cube) and a head or tail (the possible outcome from tossing the coin).

Therefore, an element in the sample space can be represented as an ordered pair (n, h/t), where n is the number rolled on the number cube and h/t is the outcome of the coin toss (either head or tail).

So,

The sample space for rolling a number cube and then tossing a coin is:

{(1, H), (1, T), (2, H), (2, T), (3, H), (3, T), (4, H), (4, T), (5, H), (5, T), (6, H), (6, T)}

For example, (3, H), (6, T), (1, H), and (4, T) are all elements in the sample space.

Thus,

The sample space for rolling a number cube and then tossing a coin is:

{(1, H), (1, T), (2, H), (2, T), (3, H), (3, T), (4, H), (4, T), (5, H), (5, T), (6, H), (6, T)}

Learn more about sample space here:

https://brainly.com/question/24273864

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