Keith has $500 in a saving account at the beginning of the summer. He wants to have at least $200 in the account by the end of the summer. He withdraws $25 (that means he takes $25 out of) from his account each week for food, clothes, and movie tickets.

Answer:

A is a function

Step-by-step explanation:

Hope the image helps.

Answer:

d = - 1

Step-by-step explanation:

The common difference d between consecutive terms is

6 - 7 = 5 - 6 = 4 - 5 = - 1

Answer:

Step-by-step explanation:

Answer:

$18.40

Step-by-step explanation:

480/30= 16

$16 is the amount earned per hour

16×.15= 2.40

$2.40 is 15% increase in the amount she earns per hour

16+2.40=18.40

$18.40 is hourly rate in dollars after the increase

Answer:

the answer is the second choice

Step-by-step explanation:

hopefully this helps :)

Answer:

8 visits

Step-by-step explanation:

26+8 visits (1 dollar a visit)= 34

Answer:

8

Step-by-step explanation:

Answer:

p = −7

Step-by-step explanation:

96=−8(p−5)

96=(−8)(p)+(−8)(−5)(Distribute)

96=−8p+40

Step 2: Flip the equation.

−8p+40=96

Step 3: Subtract 40 from both sides.

−8p+40−40=96−40

−8p=56

Step 4: Divide both sides by -8.

−8p /−8 = 56 /−8

Answer: look up alaskan pipeline

Step-by-step explanation:

Answer: n+(n+6)=24,where n is the number of blue marbles. 3. n+6n=24,where n is the number of blue marbles.

Step-by-step explanation:

Answer:

Total you have to pay: $47.55

Tax amt: $6.20

Step-by-step explanation:

Multiply $41.35 by 1.15

How this works, when your increasing an amount you first change the percentage to a decimal number. Afterwards you add the decimal number

Ex: 1 + .15= 1.15

Or the opposite: 1 - .15= .85

Then multiply your original number by the number you got from the previous step.

Ex: $41.35 x 1.15=47.55

And to find how much you increase just do (Final amount-Initial Amount)

Answer:

A rational expression that has the nonpermissible values [tex]x = 0[/tex] and [tex]x = 17[/tex] is [tex]f(x) = \frac{4}{x\cdot (x-17)}[/tex].

Step-by-step explanation:

A rational expression has a nonpermissible value when for a given value of [tex]x[/tex], the denominator is equal to zero. In addition, we assume that both numerator and denominator are represented by polynomials, such that:

[tex]f(x) = \frac{p(x)}{q(x)}[/tex] (1)

Then, the factorized form of [tex]q(x)[/tex] must be:

[tex]q(x) = x\cdot (x-17)[/tex] (2)

If we know that [tex]p(x) = 4[/tex], then the rational expression is:

[tex]f(x) = \frac{4}{x\cdot (x-17)}[/tex] (3)

A rational expression that has the nonpermissible values [tex]x = 0[/tex] and [tex]x = 17[/tex] is [tex]f(x) = \frac{4}{x\cdot (x-17)}[/tex].

Answer:

[tex]2\sqrt[3]{2}[/tex]

Step-by-step explanation:

This is equal to [tex]\sqrt[3]{8} * \sqrt[3]{2} = 2\sqrt[3]{2}[/tex]

Answer:

The rate of change of the height is 0.021 meters per minute

Step-by-step explanation:

From the formula

[tex]V = \frac{1}{3}\pi r^{2}h[/tex]

Differentiate the equation with respect to time t, such that

[tex]\frac{d}{dt} (V) = \frac{d}{dt} (\frac{1}{3}\pi r^{2}h)[/tex]

[tex]\frac{dV}{dt} = \frac{1}{3}\pi \frac{d}{dt} (r^{2}h)[/tex]

To differentiate the product,

Let r² = u, so that

[tex]\frac{dV}{dt} = \frac{1}{3}\pi \frac{d}{dt} (uh)[/tex]

Then, using product rule

[tex]\frac{dV}{dt} = \frac{1}{3}\pi [u\frac{dh}{dt} + h\frac{du}{dt}][/tex]

Since [tex]u = r^{2}[/tex]

Then, [tex]\frac{du}{dr} = 2r[/tex]

Using the Chain's rule

[tex]\frac{du}{dt} = \frac{du}{dr} \times \frac{dr}{dt}[/tex]

∴ [tex]\frac{dV}{dt} = \frac{1}{3}\pi [u\frac{dh}{dt} + h(\frac{du}{dr} \times \frac{dr}{dt})][/tex]

Then,

[tex]\frac{dV}{dt} = \frac{1}{3}\pi [r^{2} \frac{dh}{dt} + h(2r) \frac{dr}{dt}][/tex]

Now,

From the question

[tex]\frac{dr}{dt} = 7 m/min[/tex]

[tex]\frac{dV}{dt} = 236 m^{3}/min[/tex]

At the instant when [tex]r = 99 m[/tex]

and [tex]V = 180 m^{3}[/tex]

We will determine the value of h, using

[tex]V = \frac{1}{3}\pi r^{2}h[/tex]

[tex]180 = \frac{1}{3}\pi (99)^{2}h[/tex]

[tex]180 \times 3 = 9801\pi h[/tex]

[tex]h =\frac{540}{9801\pi }[/tex]

[tex]h =\frac{20}{363\pi }[/tex]

Now, Putting the parameters into the equation

[tex]\frac{dV}{dt} = \frac{1}{3}\pi [r^{2} \frac{dh}{dt} + h(2r) \frac{dr}{dt}][/tex]

[tex]236 = \frac{1}{3}\pi [(99)^{2} \frac{dh}{dt} + (\frac{20}{363\pi }) (2(99)) (7)][/tex]

[tex]236 \times 3 = \pi [9801 \frac{dh}{dt} + (\frac{20}{363\pi }) 1386][/tex]

[tex]708 = 9801\pi \frac{dh}{dt} + \frac{27720}{363}[/tex]

[tex]708 = 30790.75 \frac{dh}{dt} + 76.36[/tex]

[tex]708 - 76.36 = 30790.75\frac{dh}{dt}[/tex]

[tex]631.64 = 30790.75\frac{dh}{dt}[/tex]

[tex]\frac{dh}{dt}= \frac{631.64}{30790.75}[/tex]

[tex]\frac{dh}{dt} = 0.021 m/min[/tex]

Hence, the rate of change of the height is 0.021 meters per minute.

Answer:

parallel

Step-by-step explanation:

The answer is parallel because Since parallel lines never cross, then there can be no intersection; that is, for a system of equations that graphs as parallel lines

Answer:

35

Step-by-step explanation:

if GFL = 34 and GEL = 36 FLG would be 35

♥️♥️♥️♥️♥️♥️♥️♥️♥️♥️♥️♥️♥️♥️

[tex] (x + 5)(x - 4)(x + 2) = [/tex]

[tex](x + 5) ({x}^{2} - 2x - 8) = [/tex]

[tex] {x}^{3} - 2 {x}^{2} - 8x + 5 {x}^{2} - 10x - 40 = \\ [/tex]

[tex] {x}^{3} + 3 {x}^{2} - 18x - 40[/tex]

_________________________________

Compare :

[tex] {x}^{3} + 3 {x}^{2} - 18x - 40[/tex]

[tex] {x}^{3} + a {x}^{2} - 18x + b[/tex]

Thus :

[tex]a = 3[/tex]

and

[tex]b = - 40[/tex]

♥️♥️♥️♥️♥️♥️♥️♥️♥️♥️♥️♥️♥️♥️

Answer:

a

The sale was for a 43% decrease.

Step-by-step explanation:

The computation of the percent off of the coat during the sale is shown below:

Regular price is $35.25

And, in the sale the price is $19.99

So, the percent off would be

= ($35.25 - $19.99) ÷ ($19.99)

= 43% decrease

hence, the percent off of the coat during the sale is 43% decrease

Therefore the correct option is a.

And, all the other options are incorrect

Answer:  [tex](-\infty, -4][/tex]

Curved parenthesis at negative infinity

Square bracket at -4

====================================================

Work Shown:

[tex]5(x+4) \le 0 \\\\x+4 \le \frac{0}{5} \\\\x+4 \le 0 \\\\x \le 0-4 \\\\x \le -4 \\\\[/tex]

The last inequality shown above is the same as saying [tex]-\infty < x \le -4[/tex]

Converting this to interval notation leads to the final answer of [tex](-\infty , -4][/tex]

Note the use of a square bracket at -4 to include this endpoint. We can never include either infinity, so we always use a parenthesis for either infinity.

Answer: ight bet

i/yes

ii/no

iii/no

iv/no

v/no

vi/no

Step-by-step explanation:

Answer

Charlie paid $5.94

Step-by-step explanation:

0.76x2 3/4=2.09

1.40x2.75=3.85

3.85+2.09=$5.94

Answer:

5 feet away

Step-by-step explanation:

i am not sure but did mental math

Answer:

228

Step-by-step explanation:

22*10-220

220+8=228

Answer:

I believe the answer is 34 cm (I may be wrong but I'm 98% that my answer is correct)

Step-by-step explanation:

(excuse my handwriting on the ss its hard to write on a computer lol)

hope this helps :)

Answer:

g

Step-by-step explanation:

Answer:

They have to drive 182, 2820 miles more.

Step-by-step explanation:

... ;)

Answer:

no :)

Step-by-step explanation:

Answer:

Sometimes

Step-by-step explanation:

I’ll give you an example so you can understand:

Let’s say x is 4. So plug 4 into the problem:

|4|=4  →  This is a very true statement, where the absolute value of 4 is equal to 4.

Now, let’s say x is -7. So plug -7 into the problem:

|-7|=-7  →  This is a false statement because it’s saying that the absolute value of -7 is -7 which is very untrue.

So |x|=x only works for positive numbers, but not negative numbers. Therefore, |x|=x is the absolute value of x sometimes.

Hope this helps and answers your question! :)

Answer:

yes becasue their sides have the same length and angles

Step-by-step explanation:

Answer: -2.2

Step-by-step explanation:

Answer:

-3/5 which is the third line between 0 and -1 if you're going back from 0.