Kids's Kingdom, a retail toy chain, placed a seasonal order for stuffed animals from Stuffed Stuff, a distributor. Large animals cost $20, and small ones cost $14.
If the total cost of the order was $7,320 for 450 pieces, how many of each size were ordered? What was the dollar amount of each size ordered?

When the minimum volume of a clown is 60,000 cm³ and the volume of a car is 3 million cm³, 55 is an upper bound on the maximum number of clowns that can fit in a car. The correct answer is Option A.

Bounds are the maximum and minimum limits that are permitted, within which something can or must be performed. Bounds are used to refer to an acceptable range of values that provide safe operation or performance. In mathematics, a set of bounds can define the limits of the amount of things or objects.

The minimum volume of a clown is 60,000 cm³, so to fit 55 clowns in a car we need:

55 clowns × 60,000 cm³/clown = 3,300,000 cm³

This is lower than the volume of the car. Therefore, 55 is an upper bound on the maximum number of clowns that can fit in the car.

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both containers have the same surface area and neither has a smaller surface area than the other.

Container 1:

Surface area of a single ball = π x (54/2)^2 = 3,092.62 mm^2

Total surface area of 4 balls = 12,370.48 mm^2

Container 2:

Surface area of a single ball = π x (54/2)^2 = 3,092.62 mm^2

Total surface area of 4 balls = 12,370.48 mm^2

Both containers have the same surface area.

To calculate the surface area of the two containers, I first calculated the surface area of one ball by using the formula π x (diameter/2)^2. I then multiplied this by 4 to get the total surface area of 4 balls. I repeated this process for both containers and found that both containers had the same surface area of 12,370.48 mm^2. both containers have the same surface area and neither has a smaller surface area than the other.

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In Bitcoin, when a merchant waits for n confirmation of a payment transaction before providing the product, there is a risk of a double-spend attack. In this situation, the network is aware of a branch crediting the merchant, which has n blocks on top of the one in which the fork started.

      By simulating m as a negative binomial variable, P(m) = (m + n - 1m)pnqm can be used to more precisely compute this probability for a given value of m.

           The attacker, on the other hand, has a branch with only m additional blocks. If we assume the honest network and the attacker have a proportion of p and q of the total network hash power, respectively, the probability of the attacker catching up when he is currently z blocks behind is given by az = paz+1 + qaz−1, where a is a constant.

          To calculate the probability more accurately, we can model m as a negative binomial variable.

          This is the number of successes (blocks found by the attacker) before n failures (blocks found by the honest network), with a probability q of success.

          The probability for a given value m is then given by P(m) = (m + n - 1m)pnqm.

         Thus, when dealing with a double-spend attack in Bitcoin, the probability that the attacker will be able to catch up is given by az = paz+1 + qaz−1, where a is a constant.

              This probability can be more accurately calculated by modeling m as a negative binomial variable, with the probability for a given value m given by P(m) = (m + n - 1m)pnqm.

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The correct answer is option (C).

Sine (sin), cosine (cos), tangent (tan), cosecant (csc), secant (sec), and cotangent are the six functions (cot).

The equation t = Q - P, where Q and P are the specified locations, can be used to determine the components of the vector t. Therefore:

t = (–18, 2) – (–13, 11) = (–18 + 13, 2 – 11) = (–5, –9) (–5, –9)

The vector's magnitude is given by:

|t| = √(–5)^2 + (–9)^2 = √106 ≈ 10.296

The formula = tan1 (y/x), where x and y are the vector's components, can be used to determine the direction of the vector t. The direction must be expressed in terms of sine and cosine functions because we are required to represent the vector in trigonometric form.

θ = tan⁻¹ (–9/–5) ≈ 60.945°

In trigonometric form, the vector t is thus represented as follows:

t = [t|cos|i] + [t|sin|j]

We get the following by altering the values of |t| and:

t = 10.296 cos I + 10.296 sin j of angle 60.945

As a result, the following is the proper trigonometric representation of the vector t:

t = 10.296 cos I + 10.296 sin j of angle 60.945

Thus, alternative is the right response (C).

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Answer:

5 cm

Step-by-step explanation:

Opposite sides are equal in a rectangle.

So, Area of missing length = 16-11 = 5 cm

Daniel's pay for the week was $504.00, which includes his hourly pay and his commission on direct phone sales.

To calculate Daniel's pay for the week, we need to find his total earnings, which include his hourly wage and his commission on direct phone sales.

First, let's calculate his commission on direct phone sales. We know that he received $72.00 in commissions, and we also know that his commission is six percent of his sales. So, we can use the formula:

Commission = Sales x Commission Rate

To find his sales, we can rearrange the formula to:

Sales = Commission / Commission Rate

Plugging in the given values, we get:

Sales = $72.00 / 0.06 = $1200.00

So, Daniel's direct phone sales for the week were $1200.00.

Now, let's calculate his hourly pay. He worked for 48 hours at a rate of $9.00 per hour, so his hourly earnings were:

Hourly Pay = Hours Worked x Hourly Rate

Hourly Pay = 48 x $9.00 = $432.00

Finally, we can add his commission and his hourly pay to find his total earnings for the week:

Total Pay = Hourly Pay + Commission

Total Pay = $432.00 + $72.00

Total Pay = $504.00

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Answer:

To find the point that partitions the line segment AB in a ratio of 1:3, we can use the following formula:

P = (3B + 1A) / 4

where P is the point that partitions the line segment in a ratio of 1:3, A and B are the endpoints of the line segment, and the coefficients 3 and 1 represent the ratio of the segment we are dividing.

Substituting the values, we get:

P = (3*(-1, -5) + 1*(-5, 3)) / 4

P = (-3, -7)

Therefore, the point that partitions the line segment AB in a ratio of 1:3 is (-3, -7).

Step-by-step explanation:

Answer:

A. x = -2 or x = 8

Good luck!!

Step-by-step explanation:

(x - 3) - 10 = -5

x - 3 = - 5 + 10

x - 3 = 5

x = 5 + 3

x = 8

The correctness of the student's solution, we need to have the equations of the system.

A system of equations is graphed on the coordinate plane. A student concludes that the solution of the system is (-0.5, 1.5). Is this correct? Justify your response.To conclude that a system of equations has a solution in the coordinate plane, a set of ordered pairs (x, y) should satisfy both equations in the system of equations. That is, the system of equations should have a point (x, y) that is a solution of both equations.Only by testing the solution in the given system of equations can we know if the student's conclusion is correct. If the solution is satisfied by the system of equations, then the answer is true. Otherwise, it is false. However, since no system of equations is provided in the question, we cannot test the student's solution.To justify the correctness of the student's solution, we need to have the equations of the system.

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The cat population in Catonsville in 2007 was 200. The answer is option B.

Population refers to the total number of people, animals, or objects in a particular group or area. It is the entire group or collection of individuals, things, or events that we are interested in studying or describing.

We can use the given equation to find the cat population at any given time in years since the beginning of 2010. However, to find the population in 2007, we need to make a conversion from years since the beginning of 2010 to years since the beginning of 2007.

From the beginning of 2007 to the beginning of 2010, there are 3 years, so if we subtract 3 from the number of years since the beginning of 2010, we will get the number of years since the beginning of 2007. Therefore, we need to substitute t = -3 into the given equation and solve for p:

[tex]p = 1600(2)^t\\p = 1600(2)^(-3)\\p = 1600(1/8)\\p = 200[/tex]

Therefore, the cat population in Catonsville in 2007 was 200. The answer is option B.

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the triangles are similar, corresponding parts of the triangles are equal in measure. Thus, it is reasonable to conclude that [tex]AB ≅ DE.[/tex]

It is reasonable to conclude that [tex]AB ≅ DE[/tex]because triangles ABC and DEF are similar.

This means that corresponding parts of the two triangles are equal in measure. Specifically, ∠A and ∠D are equal in measure, as are ∠B and ∠E.

Therefore, the corresponding sides AB and DE are equal in measure.

A way to show that the two triangles are similar is by using the AA Similarity Postulate.

This postulate states that if two angles of one triangle are equal in measure to two angles of a second triangle, then the two triangles are similar. In this case, [tex]∠A ≅ ∠D and B ≅ ∠E[/tex], which means the two triangles are similar.

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The probability is a fraction of 43/205 which is approximately 0.2098.

To calculate the probability of the next person who leaves the lecture having gray hair, we need to know the total number of people who left the lecture, as well as the number of people who have gray hair.

From the given data, we can see that there were a total of 50+40+39+33+43 = 205 people who left the lecture. We also know that there were 43 people who had gray hair.

Therefore, the probability of the next person who leaves the lecture having gray hair is:

P(gray hair) = (number of people with gray hair) / (total number of people who left the lecture)

P(gray hair) = 43/205

P(gray hair) ≈ 0.2098

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Answer:

To find the function of n(p(x)), we substitute p(x) for x in the function n(x):

n(p(x)) = p(x) + 4

n(p(x)) = x^2 + 6x + 4

The domain of p(x) is all real numbers. Therefore, we need to find the domain of n(p(x))

To find the domain of n(p(x)), we need to consider the domain of p(x) that makes n(p(x)) a real number. Since the coefficient of the x^2 term is positive, the graph of the function p(x) is a parabola that opens upwards, which means that it has a minimum value. The minimum value of p(x) occurs at x = -3, where p(-3) = 9 - 18 = -9

Therefore, the range of p(x) is [ -9, ∞ ). To ensure that n(p(x)) is a real number, we need to have p(x) ≥ -4. Therefore, the domain of n(p(x)) is [ -3 - 2√5, -3 + 2√5 ] or ( -∞, -3 - 2√5 ] ∪ [ -3 + 2√5, ∞)

Answer:

circumference=43.96 yd

Area=153.86 yd^2

Step-by-step explanation:

c=2pi r

c=2x3.14x7

c=43.96 yd

area=pi r^2

Area=3.14x7^2

Area=153.86 yd^2

If the two removed squares have the same color, then it is possible to cover the truncated checkerboard with non-overlapping dominoes. If they have different colors, then it will be impossible to cover the truncated checkerboard with non-overlapping dominoes.

To prove that the chess board can be completely covered by non-overlapping dominoes, where each domino covers exactly two squares, we can color the board alternatively in black and white. The two colors will make the board have 32 black squares and 32 white squares. Each domino will cover one white and one black square. Since there are the same number of black and white squares, there is an equal number of squares that each domino can cover so it is possible to cover the entire board with dominoes without overlap.

To determine whether the cut checkerboard can be covered by non-overlapping dominoes, note that we have 62 squares, 31 of which are black, and 31 white. This means that one color will have one extra square, in this case black. Therefore, if the two removed squares are of different colors, it will be impossible to cover the cut checkerboard with non-overlapping dominoes.However, if the two removed squares have the same color, then it will be possible to cover the checkerboard with non-overlapping dominoes. This is because we will still have an equal number of black and white squares even after the removal of the two squares.The same logic applies to the truncated checkerboard.

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Answer: it is b

Step-by-step explanation:

it is b bec if you do that by 10x9 90=a a x x =1 90/s

Answer:

C

Step-by-step explanation:

To determine the number of distinct triangles that can be made with the given measurements, we can use the Law of Sines, which states:

a/sin(A) = b/sin(B) = c/sin(C)

where a, b, c are the lengths of the sides opposite to the angles A, B, and C, respectively.

Using this formula, we can solve for sin(B) as follows:

sin(B) = b*sin(A)/a

sin(B) = 8*sin(42°)/3

sin(B) ≈ 0.896

Since sin(B) is a positive value, we know that there are two possible angles B that satisfy this equation: one acute angle and one obtuse angle. To find the acute angle B, we take the inverse sine of sin(B):

B = sin^(-1)(0.896)

B ≈ 63.8°

To find the obtuse angle, we subtract the acute angle from 180°:

B' = 180° - 63.8°

B' ≈ 116.2°

Now, we can use the fact that the sum of the angles in a triangle is 180° to find the possible values for angle C. For the acute triangle, we have:

C = 180° - A - B

C = 180° - 42° - 63.8°

C ≈ 74.2°

For the obtuse triangle, we have:

C' = 180° - A - B'

C' = 180° - 42° - 116.2°

C' ≈ 21.8°

Therefore, we have found two distinct triangles that can be made with the given measurements: one acute triangle with angles A = 42°, B ≈ 63.8°, and C ≈ 74.2°, and one obtuse triangle with angles A = 42°, B' ≈ 116.2°, and C' ≈ 21.8°. Thus, the answer is C. 2.

Answer:

To find out how much Gary's backpack will weigh with the math and science textbooks in it, we need to add the weight of the textbooks to the weight of the backpack:

Total weight = backpack weight + math textbook weight + science textbook weight

Total weight = 1.2 + 3.75 + 2.85

Total weight = 7.8 pounds

Therefore, Gary's backpack will weigh 7.8 pounds with the math and science textbooks in it.

Answer: His backpack will weigh 7.8 pounds

Step-by-step explanation:

Gary's backpack already weights 1.2 pounds without the science and math textbook, now we add the weights of both the math and science textbook.

1.2 + 3.75 = 4.95

4.95 is the weight with only his math textbook in his bag

now we add the science textbooks weight to 4.95

4.95 + 2.85 = 7.8

7.8 is the weight of his backpack with both his science and math textbook in his bag

The given expression is

[tex]15 + c = 17.50[/tex]

We can use this expression to model the cost for a service.

Let's say that your gardener charges an initial amount of $15, and an additional per hour. If the gardener worked only for one hour, and the total cost charged was $17.50, how much was the additional cost?

So, the given expression models this real life situation, we can answer the problem by just solving the equation for [tex]c[/tex]

[tex]15 + c = 17.50[/tex]

[tex]c=17.50-15[/tex]

[tex]c=2.50[/tex]

Answer: Well C equals 2.5. You could use...

You have 3 sticks. one stick is 15 inches long and the other is 17.50. You want to get a small stick to add to the first one so that the first and last stick is equal to the 2nd stick.  C is the third stick.  15+C = 17.50. What is the length of C?

Step-by-step explanation:

EASY

Move all terms not containing C to the right side of the equation. C = 2.5

For the fourth-year forward rate: The forward rate is equaI to [(770.89/835.62)(1/(4-3)] - 1 = 0.0289 or 2.89% .

An equation in mathematics is a cIaim that two mathematicaI expressions are equivaIent. The Ieft-hand side (LHS) and the right-hand side (RHS), which are separated by the equaI sign ("="), make up an equation. Equations are a common tooI for probIem-soIving and determining the vaIue of an unknowabIe variabIe since they are used to describe mathematicaI reIationships.

given

I For a bond having a one-year maturity:

[tex]YTM = [(1000/945.90)^{(1/1)}] - 1 = 0.0572 or 5.72%[/tex]

(ii) For a bond having a two-year maturity:

[tex]YTM = [(1000/911.47)^{(1/2)}] - 1 = 0.0474 or 4.74%[/tex]

(iii) For a bond having a three-year maturity:

[tex]YTM = [(1000/835.62)^{(1/3)}] - 1 = 0.0617 or 6.17%[/tex]

(iv) For a bond with a four-year maturity:

[tex]YTM = [(1000/770.89)^{(1/4)}] - 1 = 0.0672 or 6.72%[/tex]

We can use the foIIowing formuIa to determine the forward rates:

Forward rate is equaI to [((Bond Price 1/Bond Price 2)(1/(n2-n1))]]. - 1

where n₂-n₁ is the time period between the maturities, Price of Bond 1 is the price of the bond with maturity n₁, and Price of Bond 2 is the price of the bond with maturity n₂.

We may determine the forward rates using the bonds' current prices by foIIowing these steps:

I For the second-year forward rate:

((911.47/945.90)(1/(2-1))) is the forward rate. - 1 = 0.0379 or 3.79%

(ii) For the third-year forward rate:

The forward rate is equaI to [((835.62/911.47)(1/(3-2))] - 1 = 0.0360 or 3.60%

For the fourth-year forward rate: The forward rate is equaI to [(770.89/835.62)(1/(4-3)] - 1 = 0.0289 or 2.89% .

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Keenan's z-score is 0.71, rounded to the nearest hundredth.

The z-score measures how many standard deviations an individual's score is from the mean, and can be calculated using the formula:

z = (x - μ) / σ

where x is the individual's score, μ is the mean score, and σ is the standard deviation.

For Keenan's exam:

z = (80 - 77) / 4.2

z = 0.71

Therefore, Keenan's z-score is 0.71, rounded to the nearest hundredth.

Rounding to the nearest hundredth means the rounding of any decimal number to its nearest hundredth value. In decimal, hundredth means 1/100 or 0.01. For example, the rounding of 2.167 to its nearest hundredth is 2.17.

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(a) The eigenvalues of the coefficient matrix is  [-1,3]  and for λ=42, we get the eigenvector [1,5].

Itcan be found by solving the characteristic equation |A-λI|=0, where A is the coefficient matrix and λ is the eigenvalue. Solving for λ, we get λ=0 and λ=42.

o find the eigenvectors, we substitute each eigenvalue into the equation (A-λI)x=0 and solve for x. For λ=0, we get the eigenvector [-1,3]. For λ=42, we get the eigenvector [1,5].

(b) The solution is y(t) = c1e^(0t)[-1,3] + c2e^(42t)[1,5].

To find the real-valued solution to the initial value problem, we can use the eigenvectors and eigenvalues to diagonalize the coefficient matrix. We have A = PDP^-1, where P is the matrix whose columns are the eigenvectors and D is the diagonal matrix with the eigenvalues on the diagonal.

Using the initial condition y2(0) = 15, we can solve for the constants c1 and c2.

The solution is y(t) = c1e^(0t)[-1,3] + c2e^(42t)[1,5]. Solving for c1 and c2 using the initial condition, we get

y(t) = [-15e^(42t) + 3e^(0t), 15e^(42t) + 5e^(0t)].

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Answer: $22.50

Step-by-step explanation:

Let x be the cost per pound of the secret-formula coffee beans.

The total cost of the secret-formula beans is 12x dollars.

The total cost of the other beans is 15 × 18 = 270 dollars.

The total cost of the mix is (12 + 15) × 20 = 540 dollars.

Since the barista mixed 12 pounds of the secret-formula beans with 15 pounds of the other beans, the total weight of the mix is 12 + 15 = 27 pounds.

We can set up an equation based on the total cost of the mix:

12x + 270 = 540

Subtracting 270 from both sides:

12x = 270

Dividing both sides by 12:

x = 22.5

Therefore, the barista's secret-formula coffee beans cost $22.50 per pound.

The Length of AB in square ABCD is 30 feet.

Since the squares ABCD and EFGH are similar, their corresponding sides are proportional, so we can set up the following relation:

AB/EF = 1/4

We can also use the fact that the ratio of the areas of two similar figures is equal to the square of the ratio of their corresponding sides. Therefore,

AB²/EF² = (Area of square ABCD)/(Area of square EFGH)

Substituting the given values:

AB²/EF² = (Area of square ABCD)/(14400)

Since the areas of squares are proportional to the square of their sides, we can write,

Area of square ABCD/Area of square EFGH = (AB/EF)²

Substituting this into the above equation and solving for AB, we get,

AB²/EF² = (AB/EF)²

AB² = (AB/EF)² * EF²

AB² = (1/4)² * 14400

AB² = 900

AB = 30 feet

Therefore, the length of the side AB of square ABCD is 30 feet.

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The three examples of contracts are:

Contracts are legal agreements between two or more parties that involve the exchange of goods, services, or money. They can be classified as unilateral or bilateral, express or implied, executed or executory.

Here are three examples of contracts that a person can be a part of:

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To perform matrix multiplication in MIPS, we can use nested loops to iterate over the rows and columns of the matrices.

The outer loop iterates over the rows of the first matrix, while the inner loop iterates over the columns of the second matrix. We then perform the dot product of the corresponding row and column, which involves multiplying the elements and summing the products.

To perform multiplication efficiently, we can use MIPS registers to store intermediate values and avoid accessing memory unnecessarily. We can also use assembly instructions like "lw" and "sw" to load and store values from memory, and "add" and "mul" to perform arithmetic operations.

In summary, matrix multiplication in MIPS involves nested loops, efficient use of registers and assembly instructions, and arithmetic operations.

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The answer to the question is 334 kittens.

Given that a cat gave birth to 333 kittens who each had a different mass between 147 g and 159 g. Then the cat gave birth to a 4th kitten with a mass of 57 g.

First of all, we will find out the range of the mass of kittens. The range is given as follows;Range = Maximum Value - Minimum Value Range = 159 g - 147 g Range = 12 g

Now, the cat gave birth to a 4th kitten with a mass of 57 g, we can say that the minimum value of kitten's mass is 57 g.So, the maximum value of kitten's mass can be calculated as follows;Maximum Value = 57 g + Range Maximum Value = 57 g + 12 g Maximum Value = 69 g Now, we can say that all kittens with a mass of 69 g or less would be born because the minimum value of kitten's mass is 57 g and the range of mass is 12 g.

Therefore, the answer to the question is 334 kittens.

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Answer:

  10.309 in²/s

Step-by-step explanation:

Given A³ = 36πV² and V' = 18 in³/s, you want to know A' when A=153.24 in² and V=178.37 in³.

Using implicit differentiation, we have ...

  3A²·A' = 36π·2V·V'

  A' = (36π·2)/3·V/A²·V' = 24πV/A²·V'

  A' = 24π·(178.37 in²/(153.24 in²)²·18 in³/s

  A' ≈ 10.309 in²/s

The surface area is increasing at about 10.309 square inches per second.

__

Additional comment

There are at least a couple of ways a calculator can be used to find the rate of change. The first attachment shows evaluation of the expression we derived above. The second attachment shows the rate of change when the area is expressed as a function of the volume.

The result rounded to 5 significant figures is the same for both approaches.

The option in the question that is equivalent to 3/8 is 2/5.

We can simplify 3/8 and 2/5 so that they have a common denominator:

3/8 = 3*(5/5)/(85/5) = 15/40

2/5 = 2(8/8)/(5*8/8) = 16/40

Since 15/40 and 16/40 have the same denominator, we can compare their numerators to see which is larger:

15/40 < 16/40

Since 16/40 is larger, we can conclude that 2/5 is greater than 3/8.

Therefore, the option that is equivalent to 3/8 is 2/5.

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Answer:

Correct choices

[tex]\csc (\theta) = - \dfrac{5}{3} \quad \quad \text{2nd option}\\\\\cot(\theta) = \dfrac{4}{3} \quad \quad \text{3rd option}\\\\\cos(\theta) = -\dfrac{4}{5} \quad \quad \text{4th option}\\\\[/tex]

Step-by-step explanation:

[tex]\text{If \;$ \tan\theta = \dfrac{3}{4} $}} \\\\\text{then }\\\theta = \tan^{-1} \left(\dfrac{3}{4}\right)\\\\= 36.87^\circ \text{ in Q1}\\[/tex]

But since tan θ is periodic it will also be 3/4 in Q3 which is 180° + 36.87 = 216.87°