Last question of this. Please help.

Answer:

Omg why are you soo beautiful? I love it

Use the law of cosines, which says

189² = 215² + 123² - 2×215×123 cos(∠P)

==>   cos(∠P) = 25,633/52,890

==>   ∠P ≈ 61.06°

Answer:

25

Step-by-step explanation:

product of 18 and -3=18*-3= -54

positive difference=52-29=23

(18x-3)+56+(52-29)

= -54 + 56 + 23

=25

Answer:

37500

Step-by-step explanation:

pattern is multiplying by -5.

-7,500*-5 = 37,500

Have a nice day! :-)

Answer:

Ty = √k  * Tx

The orbital period of Y has to be be multiplied by √k .   or . k∧1/2

Step-by-step explanation:

The general equation:

T² = A³

is for the case of planet X

Tₓ² = Aₓ³

In the case of planet Y

Ty² = k * Aₓ³ .     and   Aₓ³ = Tₓ²

By substitution:

Ty² =  k *Tₓ²

Ty = √k  * Tx

Answer:

D: K^3/2

Step-by-step explanation:

Just took the test and this is right

Answer:

2ax(y-2ay^2+3a^2x)

Step-by-step explanation:

2axy-4a^2xy^2+6a^3x^2

Given data

we have the following expression

2axy-4a^2xy^2+6a^3x^2

let us factor this expression

we have

2ax(y-2ay^2+3a^2x)

The common factor is 2ax

And the factorized expression is 2ax(y-2ay^2+3a^2x)

Answer:

[tex] {x}^{2} - 36 \\ = (x + 6)(x - 6)[/tex]

Step-by-step explanation:

x^2-36

(x+6) ( x-6)

it's helpful to you

Answer:

[tex](x-6)(x+6)[/tex]

Step-by-step explanation:

In order to simplify this equation, one must use the quadratic factoring patterns. These patterns are as follows:

[tex]a^2-b^2=(a-b)(a+b)[/tex]

This pattern works because, if one is to distribute the terms in the parenthesis by multiplying each term in one of the parenthesis by every term in the other, the result is the original equation:

[tex](a-b)(a+b)\\\\=(a)(a)+(a)(-b)+(a)(b)+(b)(-b)\\\\=a^2-ab+ab-b^2\\\\=a^2-b^2[/tex]

One can apply this pattern to the given equation, remember (6) times itself equals (36). Therefore, one can state the following: ([tex]36=6^2[/tex]), thus one can apply it to the given equation:

[tex]x^2-36\\\\=x^2-6^2\\\\=(x-6)(x+6)[/tex]

Answer:

19

Step-by-step explanation:

Add 7 onto 12 to find answer.

Answer:

b = 19

Step-by-step explanation:

b = 12 + 7

Simplify 12+7 to 19.

Answer:

x=4

Step-by-step explanation:

(x-1+5)×5=(2+x+4)×4

or, 5×(x+4)=4×(x+6)

or, 5x+20=4x+24

or, 5x-4x=24-20

or, x=4

Answer:

-60 and -28

Step-by-step explanation:

-60 + 42= -18

CHECK:

-42-18=-60

-56+-28=-84

CHECK:

-84+28=-56

Hope this helps <3 Need thanks? Comment /hearthelp

Answer:

-60

-28

Step-by-step explanation:

x +42 = -18

Subtract 42 from each side

x+42-42 = -18-42

x = -60

-56 +y = -84

Add 56 to each side

y = -84+56

y = -28

Answer:

Step-by-step explanation:

15x-6y=48

-6y=48-15x

y=-8+(15/6)x

y=(5/2)x-8

Answer:

130

Step-by-step explanation:

65/50*100= 130

Answer:

30 quarts

Step-by-step explanation:

4 quarts = 1 gallon

7.5 gallons * 4 quarts/ 1 gallon = 30 quarts

Answer:

0.36

Step-by-step explanation:

Answer:

the cost of the tire=341.4$

Answer:

3√13

Step-by-step explanation:

3√13

This expression cannot be simplified because you cannot take any common factor outside the root.

Answer:

12/17

Step-by-step explanation:

Let

Numerator of the fraction = x

Denominator of the fraction = x + 5

The fraction is

x / (x + 5)

if both the numerator and denominator are increased by 3, the the resulting fraction becomes 3/4.

x + 3 / (x + 5) + 3 = 3/4

x + 3 / x + 8 = 3/4

Cross multiply

(x + 3)4 = (x + 8)3

4x + 12 = 3x + 24

4x - 3x = 24 - 12

x = 12

Recall,

x / (x + 5)

= 12 / (12 + 5)

= 12/17

The original equation = 12/17

Answer:

either 5 or 6

Step-by-step explanation:

I can't have a direct answer because you didn't get all of the histogram in there, but from what I can conclude from just this there's definitely either 5 or 6.

Answer:

5.30

Step-by-step explanation:

Total cost = flat fee + cost per mile * number of miles

              c(m)  = 3.50 + .60m

Let m=3

c(3)  = 3.50 + .60(3)

    = 3.50 + 1.80

    =5.30

Answer:

B: $5.30

Step-by-step explanation:

Each mile is $0.6, to get the result for 3 miles we would need to multiply $0.6 by 3. $0.60 * 3 = $1.8. Finally we would need to add the 3.50 to $1.8 resulting in $5.30

Answer:

3/12 as a decimal is 0.25

2/9 as a decimal is 0.2 reapeted

Answer:

Answer written below

Step-by-step explanation:

Divide 3 by 12 and 2 by 9 using long division solve like normal long division if your divisor is bigger than your dividend add a zero on top and add a zero to the dividend.

Decimal form of  3/12:0.25

Decimal form of  2/9:0.22223

Answer:

the answer will be

184.31

Answer:

100km

Step-by-step explanation:

Time taken to travel to Bangi:

x/80 hours

15min = 1/4hrs

Time taken to travel back:

x/80 - 1/4

x= x/(x/80-1/4)

x^2-100x=0

x(x-100)=0

x=0 (rejected) or x=100

Answer:

B. 100km

Step-by-step explanation:

Brainliest please

Answer:

[tex]36 + 35 = 71[/tex]

Step-by-step explanation:

[tex]3 + 5 + 4 = 12 \\ \\ 3 \times 3 = 9 \\ 5 \times 3 = 15 \\ 4 \times 3 = 12 \\ 9 + 15 + 12 = 36[/tex]

Answer:71 is correct

Step-by-step explanation:

3+5+4=12

3*3=9

5*3=15

4*3=12

9+5+12=36

36+35=71

Answer:

1 : 5

Step-by-step explanation:

3 students zoo

15 students aquarium

zoo : not zoo

3: 15

Divide each side by 3

3/3 : 15/3

1 : 5

Answer:

A

Step-by-step explanation:

The area (A) of a rectangle is calculated as

A = length × breadth

   = (2x - 5)(x + 4) ← expand using FOIL

   = 2x² + 8x - 5x - 20

  = 2x² + 3x - 20 → A

Let y = √x, so the limit can be rewritten as

[tex]\displaystyle \lim_{y\to\infty}\left(\frac{\sqrt{y^6+y^2}}{y^2+3} - \frac{\sqrt{y^4+1}}{y+4}\right)[/tex]

Now,

[tex]\sqrt{y^6+y^2} = \sqrt{y^2\left(y^4+1\right)} = y\sqrt{y^4+1}[/tex]

so we can rewrite the limit further as

[tex]\displaystyle \lim_{y\to\infty}\left(\frac{y}{y^2+3} - \frac1{y+4}\right)\sqrt{y^4+1}[/tex]

Combine the rational terms:

[tex]\dfrac y{y^2+3} - \dfrac1{y+4} = \dfrac{y(y+4)-(y^2+3)}{(y^2+3)(y+4)} = \dfrac{4y-3}{(y^2+3)(y+4)}[/tex]

Then in the limit, we get

[tex]\displaystyle \lim_{y\to\infty}\frac{(4y-3)\sqrt{y^4+1}}{(y^2+3)(y+4)} = \lim_{y\to\infty}\frac{(4y^3-3y^2)\sqrt{1+\dfrac1{y^4}}}{y^3+4y^2+3y+12} \\\\ = \lim_{y\to\infty}\frac{\left(4-\dfrac3y\right)\sqrt{1+\dfrac1{y^4}}}{1+\dfrac4y+\dfrac3{y^2}+\dfrac{12}{y^3}} = \boxed{4}[/tex]

Answer:

1) 6а-9b=3(2a-3b)

2)8a-12b=4(2a-3b)

3) 5ab-5ac=5a(b-c)

4) 6ax+6ay=6a(x+y)

[tex]6 \sqrt{7} (1 - x)[/tex]