Leo is running in a 5-kilometer race along a straight path. If he is at the midpoint of the path, how many kilometers does he have left to run?

Answer:

The sample proportion of students who prefer vanilla ice cream is 0.56.

Step-by-step explanation:

Sample proportion of students who prefer vanilla ice cream:

Sample of 375 students.

Of those, 210 said they prefer vanilla ice cream.

The proportion is:

[tex]p = \frac{210}{375} = 0.56[/tex]

The sample proportion of students who prefer vanilla ice cream is 0.56.

Answer:

8x-21

----------------------

(2x-7)(2x+7)

Step-by-step explanation:

7                       4

-----------   + ------------

4x^2 -49    2x+7

Factor  ( notice that it is the difference of squares)

7                       4

-----------   + ------------

(2x)^2 - 7^2    2x+7

7                       4

-----------       + ------------

(2x-7)(2x+7)    2x+7

Get a common denominator

7                       4(2x-7)

-----------       + ------------

(2x-7)(2x+7)    (2x-7)(2x+7)

Combine

7 +4(2x-7)

----------------------

(2x-7)(2x+7)  

7 +8x-28

----------------------

(2x-7)(2x+7)  

8x-21

----------------------

(2x-7)(2x+7)  

Answer:

(8x - 21) / (2x + 7)(2x - 7)

Step-by-step explanation:

7 / (4x^2 - 49)+ 4 / (2x + 7)

= 7 / (2x + 7)(2x - 7) + 4 / (2x + 7)

LCM = (2x + 7)(2x - 7)   so we have

(7 + 4(2x - 7) / (2x + 7)(2x - 7)

=   (8x - 21) / (2x + 7)(2x - 7).

The vertex can be written as:

(-b/2a, b^2/(4*a) - b^2/2a + c)

For a general parabola:

y = a*x^2 + b*x + c

We can write the vertex as:

(h, k)

The x-value of the vertex is the value of the axis of symmetry.

Then we have:

h = x = -b/2a

Now we need to find the y-value of the vertex.

To do that, we just replace the variable "x" by the x-value of the vertex in our equation, so we get:

k = y = a*(-b/2a)^2 + b*(-b/2a) + c

k = b^2/(4*a) - b^2/2a + c

Then the coordinates of the vertex are:

(h, k) = (-b/2a, b^2/(4*a) - b^2/2a + c)

If you want to read more:

https://brainly.com/question/24302770

Answer:

7/18

Step-by-step explanation:

1/6 x 3 = 3/18

3/18 + 4/18 = 7/18

Answer:

7/18

Step-by-step explanation:

Make the denominators the same!

You can turn 1/6 into 3/18 by multiplying the numerator and denominator by 3. Then you add the numerators of 3/18 and 4/18 together to get 7/18.

It can't be simplified any further :)

Answer:

C

Step-by-step explanation:

in my point of view, my choice is C (asking the customer how the shirt was damaged) because when he finds out the reason why the shirt was damaged, he will explain whether or not that fault is in the store's return policy

another reason:

A) stopping the customers when they are talking, it's impolite behavior and i ensure that that customer will feel disatified.

B) i guess that customer doesnt waste of time because it

D) a full refund without finding the reason, i dont think it's a good idea

Answer: I think the correct answer is 40 but I am not sure.

Step-by-step explanation:

Answer: 40

The angle measure of BCD is m∠BCD = 140°.

Angles inside a polygon are referred to as interior angles. A triangle, for instance, has three internal angles. Interior angles are sometimes defined as "angles confined in the interior area of two parallel lines when they are crossed by a transversal."

Given that a quadrilateral ABCD.

To find the angle measure of BCD,

first, we find the other interior angle with supplementary angles.

m∠DAB = 180 - 25 = 155°

m∠ABC = 180 - 146 = 34°

m∠ADC = 180 - 149 = 31°

And the total sum of the interior angles of a quadrilateral is 360°

So, m∠BCD = 360 - (34 + 31 + 155)

m∠BCD = 140°

Therefore, m∠BCD = 140°.

To learn more about the interior angles;

brainly.com/question/10638383

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Answer:

See below

Step-by-step explanation:

we want to prove that A.M, G.M. and H.M between any two unequal positive numbers satisfy the following relations.

well, to do so let the two unequal positive numbers be [tex]\text{$x_1$ and $x_2$}[/tex] where:

the AM,GM and HM of [tex]x_1[/tex] and[tex] x_2[/tex] is given by the following table:

[tex]\begin{array}{ |c |c|c | } \hline AM& GM& HM\\ \hline \dfrac{x_{1} + x_{2}}{2} & \sqrt{x_{1} x_{2}} & \dfrac{2}{ \frac{1}{x_{1} } + \frac{1}{x_{2}} } \\ \hline\end{array}[/tex]

[tex] \displaystyle \rm AM \times HM = \frac{x_{1} + x_{2}}{2} \times \frac{2}{ \frac{1}{x_{1} } + \frac{1}{x_{2}} } [/tex]

simplify addition:

[tex] \displaystyle \frac{x_{1} + x_{2}}{2} \times \frac{2}{ \dfrac{x_{1} + x_{2}}{x_{1} x_{2}} } [/tex]

reduce fraction:

[tex] \displaystyle x_{1} + x_{2} \times \frac{1}{ \dfrac{x_{1} + x_{2}}{x_{1} x_{2}} } [/tex]

simplify complex fraction:

[tex] \displaystyle x_{1} + x_{2} \times \frac{x_{1} x_{2}}{x_{1} + x_{2}} [/tex]

reduce fraction:

[tex] \displaystyle x_{1} x_{2}[/tex]

rewrite:

[tex] \displaystyle (\sqrt{x_{1} x_{2}} {)}^{2} [/tex]

[tex] \displaystyle AM \times HM = (GM{)}^{2} [/tex]

hence, PROVEN

[tex] \displaystyle x_{1} > x_{2}[/tex]

square root both sides:

[tex] \displaystyle \sqrt{x_{1} }> \sqrt{ x_{2}}[/tex]

isolate right hand side expression to left hand side and change its sign:

[tex]\displaystyle\sqrt{x_{1} } - \sqrt{ x_{2}} > 0[/tex]

square both sides:

[tex]\displaystyle(\sqrt{x_{1} } - \sqrt{ x_{2}} {)}^{2} > 0[/tex]

expand using (a-b)²=a²-2ab+b²:

[tex]\displaystyle x_{1} -2\sqrt{x_{1} }\sqrt{ x_{2}} + x_{2} > 0[/tex]

move -2√x_1√x_2 to right hand side and change its sign:

[tex]\displaystyle x_{1} + x_{2} > 2 \sqrt{x_{1} } \sqrt{ x_{2}}[/tex]

divide both sides by 2:

[tex]\displaystyle \frac{x_{1} + x_{2}}{2} > \sqrt{x_{1} x_{2}}[/tex]

[tex]\displaystyle \boxed{ AM>GM}[/tex]

again,

[tex]\displaystyle \bigg( \frac{1}{\sqrt{x_{1} }} - \frac{1}{\sqrt{ x_{2}}} { \bigg)}^{2} > 0[/tex]

expand:

[tex]\displaystyle \frac{1}{x_{1}} - \frac{2}{\sqrt{x_{1} x_{2}} } + \frac{1}{x_{2} }> 0[/tex]

move the middle expression to right hand side and change its sign:

[tex]\displaystyle \frac{1}{x_{1}} + \frac{1}{x_{2} }> \frac{2}{\sqrt{x_{1} x_{2}} }[/tex]

[tex]\displaystyle \frac{\frac{1}{x_{1}} + \frac{1}{x_{2} }}{2}> \frac{1}{\sqrt{x_{1} x_{2}} }[/tex]

[tex]\displaystyle \rm \frac{1}{ HM} > \frac{1}{GM} [/tex]

cross multiplication:

[tex]\displaystyle \rm \boxed{ GM >HM}[/tex]

hence,

[tex]\displaystyle \rm A.M>G.M>H.M[/tex]

PROVEN

9514 1404 393

Answer:

  false

Step-by-step explanation:

The statement is nonsense (false). Regardless of the sign of a product, subtraction plays no part in anything related to it.

Answer:

The answer would be D. DE

Step-by-step explanation:

same prob

Congruent triangles are exact same triangles, but they might be placed at different positions. The correct option is D.

Suppose it is given that two triangles ΔABC ≅ ΔDEF

Then that means ΔABC and ΔDEF are congruent. Congruent triangles are exact same triangles, but they might be placed at different positions.

The order in which the congruency is written matters.

For ΔABC ≅ ΔDEF, we have all of their corresponding elements like angle and sides congruent.

Thus, we get:

[tex]\rm m\angle A = m\angle D \: or \: \: \angle A \cong \angle D \angle B = \angle E\\\\\rm m\angle B = m\angle E \: or \: \: \angle B \cong \angle E \\\\\rm m\angle C = m\angle F \: or \: \: \angle C \cong \angle F \\\\\rm |AB| = |DE| \: \: or \: \: AB \cong DE\\\\\rm |AC| = |DF| \: \: or \: \: AC \cong DF\\\\\rm |BC| = |EF| \: \: or \: \: BC \cong EF[/tex]

(|AB| denotes the length of line segment AB, and so on for others).

Given that ΔABC ≅ ΔDEF. Therefore, the given sentence can be completed as AB ≅ ΔDE.

Hence, the side AB ≅ ΔDE

Learn more about Congruent Triangles:

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Answer:

378 and 380

Step-by-step explanation:

The two even consecutive numbers that add up to 758 are going to be very close to half of 758. This is because two half of 758 are going to be the most similar addends of 758. This is important because the answers will be consecutive and therefore, must also be very similar. To solve, first, divide 758 by 2. This is 379, which is not an even number. So, to find the needed addends subtract and add 1 to 379. Both of these will be even and consecutive. These two numbers are 378 and 380. Then, to check you, can add them and see that they do sum 758.

Answer:

Step-by-step explanation:

Let the first number = x

Let the second number = x + 2

x + x + 2 = 758                      Collect like terms

2x + 2 = 758                         Subtract 2

2x = 758 - 2                          Combine

2x = 756                                Divide by 2

2x/2 = 756/2

x = 378

The first number is 378

The second number 380

If your teacher is really fussy, you can do it this way.

Let the first number = 2x

Let the second number = 2x + 2

The reason for this is to guarantee that both numbers were even to start with.

2x + 2x+2 = 758                    Combine like terms

4x + 2 = 758                          Subtract 2

4x = 756                                Divide by 4

x = 756/4

x = 189

Therefore 2x = 378

2x + 2 = 380                 Just as before.

Answer:

C

Step-by-step explanation:

Answer:

15m+12m+15m+13m=54m

2m×12m=24m

Answer:

y"= 2 wich is positive

Step-by-step explanation:

Step-by-step explanation:

Our equation is: y=(x-3)²

x should be replaced by x-4

y=(x-3)²

y=[(x-4)-3]²

y=(x-4-3)²

y=(x-7)²

The graph is still a parabola but with a different vertex

The vertex here is :

y= (x-7)²

y= x²-14x-49

y'= 2x-14

solve y'=0

2x-14=0

2x=14

x=7

You can easily find it without derivating by dividing -14 by -2

since: x²-14x-49

a=1 b= -14  c=-49

-b/2a = 14/2 = 7

the image of 7 is:

y=(7-7)² = 0

so the coordinates of the new vertex are (7,0) and it's a maximum

since y">0

y'= 2x-14

y"= 2 wich is positive

Using function concepts, it is found that the correct options are:

I and III only

--------------------------------

The function is:

[tex]y = \frac{4}{x^2 - 4}[/tex]

--------------------------------

Statement 1:

A function is even if: [tex]f(x) = f(-x)[/tex]

We have that:

[tex]f(x) = \frac{4}{x^2 - 4}[/tex]

[tex]f(-x) = \frac{4}{(-x)^2 - 4} = \frac{4}{x^2 - 4} = f(x)[/tex]

Since [tex]f(x) = f(-x)[/tex], the function is even, and the statement is true.

--------------------------------

Statement 2:

The function increases when: [tex]f^{\prime}(x) > 0[/tex]

The derivative is:

[tex]f^{\prime}(x) = \frac{-8x}{(x^2-4)^2}[/tex]

The denominator is always positive, but the numerator can be both positive/negative, which means that when the numerator is negative(x > 0), the derivative will be negative, thus the function will decrease and the statement is false.

--------------------------------

Statement 3:

A horizontal asymptote is given by:

[tex]y = \lim_{x \rightarrow \infty} f(x)[/tex]

In this question:

[tex]y = \lim_{x \rightarrow \infty} \frac{4}{x^2 - 4} = \frac{4}{\infty - 4} = \frac{4}{\infty} = 0[/tex]

y = 0 is the x-axis, thus, the statement is true, and the correct option is:

I and III only

A similar problem is given at https://brainly.com/question/23535769

Answer:

I and III

Step-by-step explanation:

Answer:

Answer:f(2)=-3(2)^2+2*2+11

Answer:f(2)=-3(2)^2+2*2+11 =-3*4+4+11

Answer:f(2)=-3(2)^2+2*2+11 =-3*4+4+11 =-12+4+11

Answer:f(2)=-3(2)^2+2*2+11 =-3*4+4+11 =-12+4+11 =3

hence, f(2)=3

9514 1404 393

Answer:

  a. 5/10

  b. 2.5/10

  c. 1/10

  d. 4/10

Step-by-step explanation:

To find the numerator, multiply each fraction by 10.

  a. (1/2)(10) = 5, so 1/2 = 5/10

  b. (1/4)(10) = 2.5, so 1/4 = (2.5)/10 or (5/2)/10

  c. (3/30)(10) = 1, so 3/30 = 1/10

  d. (12/30)(10) = 4, so 12/30 = 4/10

Answer:

A

Step-by-step explanation:

horizontal component=18cos 36.9°≈14.39 m/s≈14.4 m/s

Vertical component=18 sin 36.9°≈10.81 m/s≈10.8 m/s

Answer:

990/23

Step-by-step explanation:

Step 1

Multiply the denominator by the whole number

23 × 43 = 989

Step 2

Add the answer from Step 1 to the numerator

989 + 1 = 990

Step 3

Write answer from Step 2 over the denominator

990/23

Answer: -2

Step-by-step explanation:

g(-4) + f(1) = 7 + (-9) = 7 - 9 = -2

Answer:

Option C

Angle C has the largest measure

Answer:

gang nem

Step-by-step explanation:

Answer:

1. What is 0.252525 as a fraction?

0.252525 as a fraction equals 252525/1000000

2. 2.454545 as a fraction equals 2454545/1000000

Step-by-step explanation:

To write 0.252525 as a fraction you have to write 0.252525 as numerator and put 1 as the denominator. Now you multiply numerator and denominator by 10 as long as you get in numerator the whole number.

0.252525 = 0.252525/1 = 2.52525/10 = 25.2525/100 = 252.525/1000 = 2525.25/10000 = 25252.5/100000 = 252525/1000000

And finally we have:

0.252525 as a fraction equals 252525/1000000

2. What is 2.454545 as a fraction?

To write 2.454545 as a fraction you have to write 2.454545 as numerator and put 1 as the denominator. Now you multiply numerator and denominator by 10 as long as you get in numerator the whole number.

2.454545 = 2.454545/1 = 24.54545/10 = 245.4545/100 = 2454.545/1000 = 24545.45/10000 = 245454.5/100000 = 2454545/1000000

And finally we have:

2.454545 as a fraction equals 2454545/1000000

Thanks

Answer:

"Type II error" is the right answer.

Step-by-step explanation:

Thus the above is the right answer.

Answer:

B. The mean is less than the median.

Step-by-step explanation:

Say there was 20 kids: 10 kids(half) scored 86's, 3 kids(a few) scored 45's, and 7 kids(the remaining) scored 77's.

The median would be- 81.5 (chronological order, find the middle number)

The mean would be- 76.85 (sum of all the scores divided by the number of scores)

The mode would be- 86 (most frequent number)

The mean(76.85) is less than(<) the median(81.5)

Answer:

The value of the test statistic is 59.75.

Step-by-step explanation:

The test statistic for the population standard deviation is:

[tex]\chi^2 = \frac{n-1}{\sigma_0^2}s^2[/tex]

In which n is the sample size, [tex]\sigma_0[/tex] is the value tested and s is the sample standard deviation.

A sample of 45 bottles of soft drink showed a variance of 1.1 in their contents.

This means that [tex]n = 45, s^2 = 1.1[/tex]

The process engineer wants to determine whether or not the standard deviation of the population is significantly different from 0.9 ounces.

0.9 is the value tested, so [tex]\sigma_0 = 0.9, \sigma_0^2 = 0.81[/tex]

What is the value of the test statistic

[tex]\chi^2 = \frac{n-1}{\sigma_0^2}s^2[/tex]

[tex]\chi^2 = \frac{44}{0.81}1.1 = 59.75[/tex]

The value of the test statistic is 59.75.

Answer:

SA = 153.9m^2

Step-by-step explanation:

SA = 4[tex]\pi[/tex][tex]r^{2}[/tex]

r = 3.5

SA = 4[tex]\pi[/tex][tex](3.5)^{2}[/tex]

SA = 4[tex]\pi[/tex](12.25)

SA = 49[tex]\pi[/tex]

SA = 153.9m^2

Answer:

perimeter = 50

Step-by-step explanation:

Tangents to a circle from an external point are congruent , then

perimeter = (8 + 8) + (10 + 10) + (7 + 7) = 16 + 20 + 14 = 50