Answer:
The correct answer is - 242 ft^2
Step-by-step explanation:
Given:
one door : 3*6.5 => 19.5 ft^2
other door: 3*6.5 => 19.5 ft^2
a window: 2*3.5 => 7 ft^2
total = 46 ft^2
area of all four walls: 2h (l+b)
= 2(8) (10+8)
= 16 (18)
= 288 ft^2
paint required excluding doors and window:
=> area of your wall - (area of doors and window)
=> 288 - 46
= 242 ft^2
PLS HELP
The holding tanks are congruent in size, and both are in the shape of a cylinder that has been cut in half vertically. The bottom of the tank is a curved surface. What is the volume of both tanks if the radius of tank #1 is 15 feet and the height of tank #2 is 120 feet? You must explain your answer using words, and you must show all work and calculations.
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Answer:
42,412 ft³ each tank
84,823 ft³ both tanks added together
Step-by-step explanation:
"Congruent in size" means both tanks have the same dimensions. Each has a radius of 15 ft and a length of 120 ft. Each has half the volume of a cylinder with those dimensions.
The formula for the volume of a cylinder is ...
V = πr²h
where r is the cylinder radius, and h is the length of its axis.
We want the volume of half a cylinder with r=15 and h=120 (dimensions in ft). We can compute that using ...
V = 1/2π(15 ft)²(120 ft) = π(225 ft²)(60 ft)= 13500π ft³
If we want the volume to the nearest cubic foot, we need a value of pi that is at least 7 significant digits (3.14 isn't appropriate). Then the volume is about ...
(13,500)(3.141593) ft³ ≈ 42,411.5 ft³ ≈ 42,412 ft³
Both tanks have a volume of 42,412 ft³ each.
_____
Additional comment
The question, "What is the volume of both tanks?" is ambiguous. We're not sure if the combined volume is intended, or if the volume of each of the two tanks is intended. Both numbers are provided, so you can sort it out as you see fit.
Ralph bought a computer monitor with an area of 384 square inches. The length of the monitor is six times the quantity of five less than half its width.
Complete the equation that can be used to determine the dimensions of the monitor in terms of its width, w.
Answer:
w= 103.5 inches
Step-by-step explanation:
384=w+3w-30
414=4w
w=414/4=103.5 inches
Answer:
first drop box 384
second drop box 3
third drop boc 30
384 = 3 [tex]w^{2}[/tex] – 30 w
Step-by-step explanation:
Correct answer on Plato/Edmentum test
remove bracket and simplify 6x-(3x+2)
Answer: 3x - 2
Step-by-step explanation:
First to solve this, we need to know some basic information such as:
1. (-) × (-) = +
2. (+) × (-) = -
3. (+) × (+) = +
Therefore, 6x-(3x+2)
= 6x - 3x - 2
= 3x - 2
The answer to the question after removing the bracket will be 3x - 2.
A cookie recipe that yields 24 cookies requires 1 3/4 cups of butter. When the ingredients in this recipe are increased proportionally, how many cups of butter are required for the recipe to yield 72 cookies?
Answer:
5 1/4
Step-by-step explanation:
* is multiplication
1 3/4 is 1.75
so
24/1.75 = 72/×
1.75 * 72 = 24 * x
126 = 24x
24x = 126
x = 5.25 or 5 1/4
Total [tex]5\frac{1}{4}[/tex] cups of butter required to make 72 cookies.
What is unitary method?The unitary method is a process of finding the value of a single unit, and based on this value; we can find the value of the required number of .
According to the given question.
Number of cups or butter required for making 24 cookies = [tex]1\frac{3}{4} =\frac{7}{4}[/tex]
⇒ Number of cups of butter required to make 1 cookie = [tex]\frac{\frac{7}{4} }{24} =\frac{7}{(24)(4)}[/tex]
Therefore,
The number of cups of butter required to make 72 cookies
= [tex]72[/tex] × [tex]\frac{7}{(24)(4)}[/tex]
= [tex]\frac{21}{4}[/tex]
= [tex]5\frac{1}{4}[/tex]
Hence, total [tex]5\frac{1}{4}[/tex] cups of butter required to make 72 cookies.
Find out more information about unitary method here:
https://brainly.com/question/22056199
#SPJ3
Which operation will solve the following word problem? Andrea's class has 20 students and half of the students are studying math, half of these are studying word problems. How many are studying word problems?
Addition
Subtraction
Division
Multiplication
divide .2÷20 =10 10 students are Studing word problems
Can I get the answer for those
Answer:
1) 5.64
2) 17.321
1) [tex]\frac{21}{28}[/tex]
2) [tex]\frac{16}{34}[/tex]
3) [tex]\frac{28}{35}[/tex]
4) [tex]\frac{32}{24}[/tex]
Step-by-step explanation:
SOH - CAH - TOA
Sin = [tex]\frac{O}{H}[/tex] Cos = [tex]\frac{A}{H}[/tex] Tan = [tex]\frac{O}{A}[/tex]
O = opposite, A = adjacent, H = hypotenuse
First two, use Pythagorean Theorem
If you want to calculate the angle on the last 4, use inverse of function and put in the ratio.
For example :
1) Tan Z = [tex]\frac{21}{28}[/tex]
[tex]Tan^{-1}[/tex] ( [tex]\frac{21}{28}[/tex])
Z = 36.9°
Please answer!<333 xx
12. X= 6
14. B= -11
16. N= 15
Answer:
q12. [tex]x=6[/tex]
q14. [tex]b=-11[/tex]
q16. [tex]n=15[/tex]
Step-by-step explanation:
Q12.
[tex]-1=\frac{x}{-6}[/tex]
Flip the equation:
[tex]\frac{x}{-6} =-1[/tex]
Multiply both sides by 6/(-1)
[tex](\frac{6}{-1} )[/tex] × [tex](\frac{-1}{6}x )[/tex] = [tex](\frac{6}{-1} )[/tex] × [tex](-1)[/tex]
[tex]x=6[/tex]
Q14.
[tex]5b=-55[/tex]
[tex]b=\frac{-55}{5}[/tex]
[tex]b=-11[/tex]
Q16.
[tex]-3n=-45[/tex]
[tex]n=\frac{-45}{-3}[/tex]
[tex]n=15[/tex]
hope this helps.....
Olivia rides her scooter 3/4 mile in
1/3 hour. How fast, in miles per hour,
does she ride her scooter?
Answer:
2.25 miles per hr
Answer:
2.25 miles per hour
Step-by-step explanation:
speed = distance / time
speed = [tex]\frac{3}{4} / \frac{1}{3}[/tex] (take the reciprocal of [tex]\frac{1}{3}[/tex])
= [tex]\frac{3}{4} * 3[/tex]
= [tex]\frac{9}{4}[/tex] = 2.25 miles per hour
The graph of y=x^3 is transformed as shown in the graph below. Which equation represents the transformed function?
y = x cubed minus 4
y = (x minus 4) cubed
y = (negative x minus 4) cubed
y = (negative x) cubed minus 4
Answer:
y = (-x)^3 - 4
Step-by-step explanation:
Ok, for the function:
y = x^3
When x = 0, we have:
y = 0^3 = 0
So the original graph passes through the point (0, 0)
If we look at the given graph, we can see that the y-intercept (the value of y when x = 0) is:
y = -4
So, this is the graph of y = x^3 moved down 4 units.
You can also see that the graph goes downward as x increases (and up as x decreases) while for the function:
y = x^3
as x increases, we should see that y also increases.
Then we have a reflection across the x-axis.
Ok, now let's describe a vertical shift.
For a general function f(x), a vertical shift of N units is written as:
g(x) = f(x) + N
if N is positive, the shift is upwards
if N is negative, the shift is downwards.
And for a function f(x), a reflection across the x-axis is written as:
g(x) = - f(x)
Here we first apply the reflection across the x-axis, so we get:
g(x) = -f(x)
now we apply the shift 4 units downwards
g(x) = - f(x) - 4
replacing f(x) by our function, x^3
we get:
g(x) = -x^3 - 4
And because of the odd power, we can write:
-x^3 = (-x)^3
Then the function is:
g(x) = (-x)^3 - 4
The correct option is the last one.
y = (-x)^3 - 4
Brian, the gorilla, was planning a party for his zoo friends. He sent his elves Jamie and Nancy into the North Pole exhibit to count the penguins and reindeer. Jamie said there were 40 legs and Nancy said there were 14 heads. How many penguins and reindeer were in the exhibit?
Answer:
There are 8 penguins and 6 reindeers.
Step-by-step explanation:
Since Brian, the gorilla, was planning a party for his zoo friends, and he sent his elves Jamie and Nancy into the North Pole exhibit to count the penguins and reindeer, and Jamie said there were 40 legs and Nancy said there were 14 heads To determine how many penguins and reindeer were in the exhibit, the following calculation must be performed:
Penguins: 1 head and 2 legs
Reindeers: 1 head and 4 legs
40 - (14 x 2) = X
40 - 28 = X
12 = X
12/2 = 6
14 - 6 = 8
8 x 2 + 6 x 4 = X
16 + 24 = X
40 = X
Therefore, there are 8 penguins and 6 reindeers.
Read the following scenario, and then answer the question.
Juan assumes that the temperature of the hot tea cooling on his desk can be modeled with an exponential function like this one: T(t)=179(0.92)t. He bases his assumption on the following: The tea cools about 8% every minute. The tea's current temperature is around 179 degrees Fahrenheit.
Which explanation correctly addresses Juan's assumption?
He is incorrect. The tea will cool linearly since it cools at the same number of degrees every minute.
He is correct. The tea will cool exponentially since it cools at a percentage rate every minute.
He is incorrect. The tea will cool along the curve of a parabola since it cools at an increasing percentage rate every minute.
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Answer:
(b) He is correct. The tea will cool exponentially since it cools at a percentage rate every minute.
Step-by-step explanation:
Newton's Law of Cooling says the change in temperature is proportional to the temperature. This relation gives rise to an exponential function describing the temperature.
In this description, the temperature referred to is the difference between the temperature of the object and the temperature of the environment to/from which heat is being transferred.
Juan is only partially correct. The function is exponential, but the temperature that should be used in his equation is not the temperature of the tea, but the temperature difference between the tea and his desk.
__
The curve is not linear and not parabolic, excluding the other answer choices.
Which of the following numbers is rational? Assume that the decimal patterns continue.
Answer:
[tex]\sqrt{49}[/tex]
Step-by-step explanation:
Define a rational number by a number able to expressed a fraction where the denominator is not 0 or 1.
Non-terminating (never-ending) decimals cannot be expressed as a fraction and therefore are irrational. However, recall that [tex]\sqrt{49}=7[/tex], which can be expressed as a fraction (e.g. [tex]\frac{14}{2}[/tex], etc). Thus, the answer is [tex]\boxed{\sqrt{49}}[/tex].
A polynomial function has a root of -6 with multiplicity 1, a root of -2 with multiplicity 3, a root of 0 with multiplicity 2, and a
root of 4 with multiplicity 3. If the function has a positive leading coefficient and is of odd degree, which statement about
the graph is true?
O The graph of the function is positive on (-6, -2).
O The graph of the function is negative on (-0, 0).
O The graph of the function is positive on (-2, 4).
O The graph of the function is negative on (4.co).
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Answer:
(a) the graph is positive on (-6, -2)
Step-by-step explanation:
The roots, left to right, are ...
-6, -2, 0, 4
The odd-multiplicity roots, where the sign changes, are ...
-6, -2, 4
The function is negative to the left of -6, and positive to the right of +4. It is positive on the interval (-6, -2) and negative on the intervals (-2, 0) and (0, 4).
Answer:it’s a!!!
edge please stop deleted my answer ;)
Step-by-step explanation:
Question 3
A 70kg patient has approximately 8 pints of blood. The patient donates 470mL of blood.
Approximately what fraction of his body's blood is this? (one pint = 568mL)
Step-by-step explanation:
Given that,
The mass of a patient = 70 kg
A 70kg patient has approximately 8 pints of blood.
The patient donates 470mL of blood.
We know that,
1 pint = 568 mL
8 pints = 4544 mL
Required fraction,
[tex]\dfrac{470}{4544}=0.1\\\\=\dfrac{1}{10}[/tex]
So, the required fraction is approximately [tex]\dfrac{1}{10}[/tex].
Round 0.485 to the nearest hundredth
Decimals start at tenths, then hundredths, then thousandths, and so on. When we round, we look at the place value that is one smaller than the one we want to round to.
So, let's take a look at the thousandths place in 0.485. The value in the thousandths place is 5. When rounding, if the value is 5 or over we round up and if the value is 4 or lower we round down. Since the value in the thousandths place is 5, we will round the hundredths place up one.
0.485 rounded to the nearest hundredth is 0.49
Hope this helps!
Answer:
0.49
Step-by-step explanation:
[tex]0<x<5=[/tex] Round down
[tex]x\geq5=[/tex] Round up
In this case, it's a round up, so the answer would be...
0.49
Hope this helped! Please mark brainliest!
Which statements below represent the situation? Select three options.
Answer:
where is the statement
Step-by-step explanation:
its incomplete po
______are used to represent an unknown quantity in a mathematical expression.
Answer:
Variables are used to represent an unknown quantity in a mathematical expression.
Step-by-step explanation:
Variables are used to represent an unknown quantity in a mathematical expression.For example : x + 2 = 4, here x is the variable.We can denote variable by any alphabet i.e, a,b,c,d etc.Jonas builds a snow fort. He tells his friends it is 0.8 meters tall inside, but he rounded the height to the nearest tenth.
Which could be the height of the snow fort before Jonas rounded it?
2 answers
A. 0.85
B. 0.82
C. 077
Answer:
B. 0.82
C. 077
Step-by-step explanation:
Given
[tex]Number = 0.8[/tex] -- approximated
Required
The possible value of Number
Since [tex]Number = 0.8[/tex] is approximated, then the possible values of Number that can be gotten from the preparation
The approximated value 0.8 has the following range: 0.75 to 0.84
Options B and C are in this category.
In a survey, 24 people were asked how much they spent on their child's last birthday gift. The results were roughly bell-shaped with a mean of $42 and standard deviation of $2. Construct a confidence interval at a 98% confidence level.
Answer:
The 98% confidence interval for the mean amount spent on their child's last birthday gift is between $40.98 and $43.02.
Step-by-step explanation:
We have the standard deviation for the sample, which means that the t-distribution is used to solve this question.
The first step to solve this problem is finding how many degrees of freedom, we have. This is the sample size subtracted by 1. So
df = 24 - 1 = 23
98% confidence interval
Now, we have to find a value of T, which is found looking at the t table, with 23 degrees of freedom(y-axis) and a confidence level of [tex]1 - \frac{1 - 0.98}{2} = 0.99[/tex]. So we have T = 2.5
The margin of error is:
[tex]M = T\frac{s}{\sqrt{n}} = 2.5\frac{2}{\sqrt{24}} = 1.02[/tex]
In which s is the standard deviation of the sample and n is the size of the sample.
The lower end of the interval is the sample mean subtracted by M. So it is 42 - 1.02 = $40.98.
The upper end of the interval is the sample mean added to M. So it is 42 + 1.02 = $43.02.
The 98% confidence interval for the mean amount spent on their child's last birthday gift is between $40.98 and $43.02.
A simple random sample of students could be achieved by stopping every other student who enters the library.
a. True
b. False
A teacher has a 2-gallon (52 cup) container of juice. She gives each student z cup of juice. Which equation represents the amount of juice that remains, y, after x students are served?
Answer:
[tex]y = 32 - \frac{1}{2}x[/tex]
Step-by-step explanation:
Given
[tex]Cups = 32[/tex] ---- not 52
[tex]Students = x[/tex]
[tex]Remainder = y[/tex]
[tex]Each = \frac{1}{2}[/tex] --- not z
Required
The equation for y
The remainder y is calculated as:
[tex]y = Cups - Students * Each\\[/tex]
[tex]y = 32 - \frac{1}{2}x[/tex]
The function f is defined by the following rule. f(x) = 5x+1 Complete the function table.
Answer:
[tex]-5 \to -24[/tex]
[tex]-1 \to -4[/tex]
[tex]2 \to 11[/tex]
[tex]3 \to 16[/tex]
[tex]4 \to 21[/tex]
Step-by-step explanation:
Given
[tex]f(x) = 5x + 1[/tex]
Required
Complete the table (see attachment)
When x = -5
[tex]f(-5) = 5 * -5 + 1 = -24[/tex]
When x = -1
[tex]f(-1) = 5 * -1 + 1 = -4[/tex]
When x = 2
[tex]f(2) = 5 * 2 + 1 = 11[/tex]
When x = 3
[tex]f(3) = 5 * 3 + 1 = 16[/tex]
When x = 4
[tex]f(4) = 5 * 4 + 1 = 21[/tex]
So, the table is:
[tex]-5 \to -24[/tex]
[tex]-1 \to -4[/tex]
[tex]2 \to 11[/tex]
[tex]3 \to 16[/tex]
[tex]4 \to 21[/tex]
A scientist claims that 4% of viruses are airborne. If the scientist is accurate, what is the probability that the proportion of airborne viruses in a sample of 662 viruses would be greater than 6%
Answer:
The probability that the proportion of airborne viruses in a sample of 662 viruses would be greater than 6%=0.00427
Step-by-step explanation:
We are given that
[tex]\mu_{\hat{p}}=p=4%=0.04[/tex]
n=662
We have to find the probability that the proportion of airborne viruses in a sample of 662 viruses would be greater than 6%.
q=1-p=1-0.04=0.96
[tex]\sigma_{\hat{p}}=\sqrt{p(1-p)/n}[/tex]
[tex]\sigma_{\hat{p}}=\sqrt{\frac{0.04(1-0.04)}{662}}[/tex]
[tex]\sigma_{\hat{p}}=0.0076[/tex]
Now,
[tex]P(\hat{p}>0.06)=1-P(\hat{p}<0.06)[/tex]
[tex]=1-P(\frac{\hat{p}-\mu_{\hat{p}}}{\sigma_{\hat{p}}}<\frac{0.06-0.04}{0.0076})[/tex]
[tex]=1-P(Z<2.63)[/tex]
[tex]=1-0.99573[/tex]
[tex]P(\hat{p}>0.06)=0.00427[/tex]
Hence, the probability that the proportion of airborne viruses in a sample of 662 viruses would be greater than 6%=0.00427
જ્યારે જહાંગીરની ઉંમર 18 વર્ષ થશે ત્યારે અકબરની ઉંમર 50 વર્ષ થર્શ.
જ્યારે અકબરની ઉંમર જહાંગીરની ઉંમર કરતા 5 ઘણી હશે ત્યારે
અકબરની ઉમર કેટલી હશે?
A) 36
B) 40
C) 44
D) 48
Answer:
C: 44
Step-by-step explanation:
Help differentiate this
Answer:
[tex]\displaystyle y' = 20x^3 + 6x^2 + 70x + 9[/tex]
General Formulas and Concepts:
Pre-Algebra
Distributive PropertyAlgebra I
Terms/CoefficientsExpand by FOILFunctionsFunction NotationCalculus
Derivatives
Derivative Notation
Derivative Property [Multiplied Constant]: [tex]\displaystyle \frac{d}{dx} [cf(x)] = c \cdot f'(x)[/tex]
Derivative Property [Addition/Subtraction]: [tex]\displaystyle \frac{d}{dx}[f(x) + g(x)] = \frac{d}{dx}[f(x)] + \frac{d}{dx}[g(x)][/tex]
Basic Power Rule:
f(x) = cxⁿ f’(x) = c·nxⁿ⁻¹Derivative Rule [Product Rule]: [tex]\displaystyle \frac{d}{dx} [f(x)g(x)]=f'(x)g(x) + g'(x)f(x)[/tex]
Step-by-step explanation:
Step 1: Define
Identify
[tex]\displaystyle y = (x^3 + 7x - 1)(5x + 2)[/tex]
Step 2: Differentiate
Product Rule: [tex]\displaystyle y' = \frac{d}{dx}[(x^3 + 7x - 1)](5x + 2) + (x^3 + 7x - 1)\frac{d}{dx}[(5x + 2)][/tex]Basic Power Rule [Derivative Property - Addition/Subtraction]: [tex]\displaystyle y' = (3x^{3 - 1}+ 7x^{1 - 1} - 0)(5x + 2) + (x^3 + 7x - 1)(5x^{1 - 1} + 0)[/tex]Simplify: [tex]\displaystyle y' = (3x^2+ 7)(5x + 2) + 5(x^3 + 7x - 1)[/tex]Expand: [tex]\displaystyle y' = 15x^3 + 6x^2 + 35x + 14 + 5(x^3 + 7x - 1)[/tex][Distributive Property] Distribute 5: [tex]\displaystyle y' = 15x^3 + 6x^2 + 35x + 14 + 5x^3 + 35x - 5[/tex]Combine like terms: [tex]\displaystyle y' = 20x^3 + 6x^2 + 70x + 9[/tex]Topic: AP Calculus AB/BC (Calculus I/I + II)
Unit: Derivatives
Book: College Calculus 10e
HELP FAST PLEASEEEEEE
Which of the tables represents a function?
Table AInput
Output
3
1
3
4
2
3
Table BInput
Output
2
7
5
6
2
9
Table CInput
Output
1
5
7
2
7
3
Table DInput
Output
3
4
1
5
8
5
Select one:
a. Table A
b. Table B
c. Table C
d. Table D
Answer:
d.......................
The difference between seven times a number and 9 is equal to five times
the sum of the number and 2. Find the number. Hint: There will be
parenthesis in your equation.
Answer:
The number is 9.5
Step-by-step explanation:
Look at the picture above, it explains everything
1^2 +2^2+••••+n^2=1/6n(n+1)(2n+1)
using maths induction
Hello,
[tex]if\ n=1\ then\ 1^2=1\ and\ \dfrac{1}{6}*1*2*3=1:\ true\ for\ n=1\\[/tex]
We suppose the property true for n:
1²+2²+...+n²=n(n+1)(2n+1) / 6
and we are going to demonstrate that the property is true for n+1:
1²+2²+..+(n+1)²=(n+1)*(n+2)*(2n+3)/6
[tex]1^2+2^2+...+n^2+(n+1)^2\\\\=n*(n+1)*(2n+1)/6+(n+1)^2\\\\=(n+1)/6*[n(2n+1)+6n+6]\\\\=(n+1)/6*(2n^2+7n+6)\\\\=(n+1)(n+2)(2n+3)/6\\[/tex]
09:30 am - 4:30 pm minus 30 minutes?
How many hours is that ?
0.9.30 am to 4.30 p.m. is 7 hours.
If we minus 30 minutes from it then it is 6 hours 30 minutes.
I am having trouble with this problem. If anyone could help that would be great.
Let M be the capped cylindrical surface which is the union of two surfaces, a cylinder given by x^2+y^2=16, 0≤z≤1, and a hemispherical cap defined by x^2+y^2+(z−1)^2=16, z≥1. For the vector field F=(zx+z^2y+4y, z^3yx+3x, z^4x^2), compute ∬M(∇×F)⋅dS in any way you like.
Answer:
Ok... I hope this is correct
Step-by-step explanation:
Let M be the capped cylindrical surface which is the union of two surfaces, a cylinder given by x^(2)+y^(2)=16
Center: ( 0 , 0 )
Vertices: ( 4 , 0 ) , ( − 4 , 0 )
Foci: ( 4 √ 2 , 0 ) , ( − 4 √ 2 , 0 )
Eccentricity: √ 2
Focal Parameter: 2 √ 2
Asymptotes: y = x , y = − x
Then 0≤z≤1, and a hemispherical cap defined by x^2+y^2+(z−1)^2=16, z≥1.
Simplified
0 ≤ z ≤ 1 , x ^2 + y ^2 + z ^2 − 2 ^z + 1 = 16 , z ≥ 1
For the vector field F=(zx+z^2y+4y, z^3yx+3x, z^4x^2), compute ∬M(∇×F)⋅dS in any way you like.
Vector:
csc ( x ) , x = π
cot ( 3 x ) , x = 2 π 3
cos ( x 2 ) , x = 2 π
Since
( z x + z ^2 y + 4 y , z ^3 y x + 3 x , z ^4 x ^2 ) is constant with respect to F , the derivative of ( z x + z ^2 y + 4 y , z ^3 y x + 3 x , z ^4 x 2 ) with respect to F is 0 .
