Let A = 0, 1 , B = 2, 3, 4 and C = 3, 5 verity that A x (BUC) = (AXB) U (AXC)
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Answer:

C: 1/4x + 4 = 3

Step-by-step explanation:

1/4x + 4 = 3

1/4x = 3 - 4

x = - 4

Thus, option c gives out the solution x = - 4.

Answer:  Choice B

Work Shown:

[tex]-2 \le 2x-4 < 4\\\\-2+4 \le 2x-4+4 < 4+4\ \text{ ... add 4 to all sides}\\\\2 \le 2x < 8\\\\2/2 \le 2x/2 < 8/2\ \text{ ... divide all sides by 2}\\\\1 \le x < 4\\\\[/tex]

This says that x is between 1 and 4; it can equal 1, but it can't equal 4.

To visually represent this, we'll have a closed circle at 1, an open circle at 4, with shading in between these circles. This is represented by graph B.

Answer:

no soultion

Step-by-step explanation:

did on paper

Answer:

exactly one solution

Step-by-step explanation:

got it right on khan lol

Answer:

5n+3

Step-by-step explanation:

:)

Answer:

[tex]\alpha n=5n+3[/tex]

Step-by-step explanation:

Answer:

81[tex]y^{8}[/tex][tex]z^{4}[/tex]

Step-by-step explanation:

Answer:

6.72

Step-by-step explanation:

I multiplied both numbers by 10 to make it easier in my opinion. That made the equation 994.66 x 148

Then, I divided it until i got to the thousandths place. Lastly, i just rounded making it 6.72

Answer:

30x + 28

Step-by-step explanation:

To evaluate (f ￮ g)(x), substitute x = g(x) into f(x) , that is

f(g(x))

= f(- 6x - 6)

= - 5(- 6x - 6) - 2 ← distribute parenthesis and simplify

= 30x + 30 - 2

= 30x + 28

Answer:

Yes

Step-by-step explanation:

6 × 18.75 = 112.50

8 × 18.75 = 150.00

11 × 18.75 = 206.25

Answer:

False

Step-by-step explanation:

If the graph represented y = 2x + 1, then the y-intercept would be 1. The slope is correct(-ish), the y-intercept is not.

Answer:

y- intercept, x=0

8(0)-4y=12

y=-3

Answer:

17) 19

19) 8

Step-by-step explanation:

17)

(6 +6² -4)÷2

(6 +36 -4)÷2

(38)÷2

19

19)

3³ ÷3 - 1

27 ÷3 -1

9 -1

8

To graph an exponential,

d. T-chart using random values for x and y.

The set of ordered pairings (x, y) where f(x) = y makes up the graph of a function.

These pairs are Cartesian coordinates of points in two-dimensional space and so constitute a subset of this plane in the general case when f(x) are real values.

Now,

We know an exponential function is a function in which the independent variable is the exponent.

One such function is y = eˣ

Now, To graph an exponential function you come up with values to use in the graph should be a T-chart using random values for x and y.

As it would result in graphing the complete nature of the function.

Learn more about graphs here :

brainly.com/question/2288321

#SPJ7

Answer:

It is 7x + 12

Step-by-step explanation:

[tex]5(3x + 2) - 2(4x - 1)[/tex]

open brackets:

[tex] = 15x + 10 - 8x + 2[/tex]

group like terms together:

[tex] = (15x - 8x) + (10 + 2)[/tex]

factorise out x :

[tex] = x(15 - 8) + 12 \\ = 7x + 12[/tex]

Answer:

[tex]4y + 6y = 90 \\ 10y = 90 \\ y = 9 \\ thank \: you[/tex]

SORRYYYYYYYYYYYYYYY I DONT KNOWWWWW

Answer:

7, 8, 9

Step-by-step explanation:

1/5 = 6/30

1/3 = 10/30

Answer:

[tex]2(3m + 6n) + 3(5m - 2n) + 5( - 6m + n) \\ [/tex]

open the brackets:

[tex] = (6m + 12n) + (15m - 6n) + ( - 30m + 5n) \\ [/tex]

group the coefficients of m and n in their brackets:

[tex] = (6 + 15 - 30)m + (12 - 6 + 5)n \\ [/tex]

then operate the brackets:

[tex] = - 9m + 11n[/tex]

A. is the correct answer

Answer:

A

Step-by-step explanation:

(x-3)(2x+1)= (due to FOIL(First Outer Inner Last)) (First)2x^2-(Outer+Inner)5x-(Last)3. 2x^2-5x-3 is what A says, so A is the answer.

Answer:

11

Step-by-step explanation:

2^10 + 2^10 = 2^x

1024 + 1024 = 2^x

2,048 = 2^x

x = 11

If my answer is incorrect, pls correct me!

If you like my answer and explanation, mark me as brainliest!

-Chetan K

Hi there!  

»»————-　★　————-««

I believe your answer is:  

[tex]x = 11[/tex]

»»————-　★　————-««  

Here’s why:  

⸻⸻⸻⸻

[tex]\boxed{\text{Solving for 'x'...}}\\\\2^{10}+2^{10} = 2^x\\--------------\\\rightarrow 2^{10} = 1024\\\\\rightarrow 1024 + 1024 = 2^x\\\\\rightarrow 2048 = 2 ^x\\\\\rightarrow log(2^x)=log(2048)\\\\\rightarrow xlog(2)=log(2048)\\\\\rightarrow \frac{log(2)}{log(2)} =\frac{log(2048)}{log(2)}\\\\\rightarrow x = \frac{log(2048)}{log(2)}\\\\\rightarrow \boxed{x = 11}[/tex]

⸻⸻⸻⸻

»»————-　★　————-««  

Hope this helps you. I apologize if it’s incorrect.  

15:-

[tex]\\ \qquad\quad\sf\longmapsto \dfrac{x^5y^6}{xy^2}[/tex]

[tex]\\ \qquad\quad\sf\longmapsto x^{5-1}y^{6-2}[/tex]

[tex]\\ \qquad\quad\sf\longmapsto x^4y^4[/tex]

16:-

[tex]\\ \qquad\quad\sf\longmapsto \dfrac{x^2y^5}{xy^4}[/tex]

[tex]\\ \qquad\quad\sf\longmapsto x^{2-1}y^{5-4}[/tex]

[tex]\\ \qquad\quad\sf\longmapsto xy[/tex]

17;-

[tex]\\ \qquad\quad\sf\longmapsto \left(\dfrac{4x^5y}{16xy^4}\right)^3[/tex]

[tex]\\ \qquad\quad\sf\longmapsto (4^{1-2}x^{5-1}y^{1-4})^3[/tex]

[tex]\\ \qquad\quad\sf\longmapsto (4^{-1}x^4y^{-3})^3[/tex]

[tex]\\ \qquad\quad\sf\longmapsto 4^{-3}x^{12}y^{-9}[/tex]

18:-

[tex]\\ \qquad\quad\sf\longmapsto \left(\dfrac{5x^3y}{20xy^5}\right)^4[/tex]

[tex]\\ \qquad\quad\sf\longmapsto (4^{-1}x^{2}y^{-4})^4[/tex]

[tex]\\ \qquad\quad\sf\longmapsto 4^{-4}x^8y^{-16}[/tex]

19:-

[tex]\\ \qquad\quad\sf\longmapsto y^{-7}[/tex]

[tex]\\ \qquad\quad\sf\longmapsto \dfrac{1}{y^7}[/tex]

20:-

[tex]\\ \qquad\quad\sf\longmapsto 7^{-2}[/tex]

[tex]\\ \qquad\quad\sf\longmapsto \dfrac{1}{7^2}[/tex]

[tex]\\ \qquad\quad\sf\longmapsto \dfrac{1}{49}[/tex]

21:-

[tex]\\ \qquad\quad\sf\longmapsto \dfrac{1}{x^{-5}}[/tex]

[tex]\\ \qquad\quad\sf\longmapsto x^5[/tex]

22:-

[tex]\\ \qquad\quad\sf\longmapsto \dfrac{1}{2^{-4}}[/tex]

[tex]\\ \qquad\quad\sf\longmapsto 2^4[/tex]

[tex]\\ \qquad\quad\sf\longmapsto 16[/tex]

23:-

[tex]\\ \qquad\quad\sf\longmapsto x^5\times x^{-1}[/tex]

[tex]\\ \qquad\quad\sf\longmapsto x^{5-1}[/tex]

[tex]\\ \qquad\quad\sf\longmapsto x^4[/tex]

24:-.

[tex]\\ \qquad\quad\sf\longmapsto x^{-6}[/tex]

[tex]\\ \qquad\quad\sf\longmapsto \dfrac{1}{x^6}[/tex]

25:-

[tex]\\ \qquad\quad\sf\longmapsto x^9(x^{-7})[/tex]

[tex]\\ \qquad\quad\sf\longmapsto x^{9-7}[/tex]

[tex]\\ \qquad\quad\sf\longmapsto x^2[/tex]

Step-by-step explanation:

ABCD is a quadrilateral triangle,where AD=BC and <DAB =<CBA.

In ∆ABD and ∆BAC

•AD=BC. (given)

•<DAB=<CBA (given)

•AB=BA. (common side)

Therefore, ∆ABD ≌ ΔBAC. {SAS congruence rule}

Answer:

0.0300300030000...

Step-by-step explanation:

An irrational number has endless non-repeating digits to the right of the decimal point. They can be written as decimals, but not as fractions.

1632 can be written as 3264/2

0.25 can be written as 1/4

0 could be written as 0/0

but 0.0300300030000 cannot be written as a fraction, and it satisfies the condition of an irrational number having endless non-repeating digits to the right of the decimal point.

Answer: 8 hours

Step-by-step explanation:

Given information

Admission fee = $7.00

Hour rent fee = $1.50

Number of hours = h

Total fee = $19

Set equation according to the given information

Total fee = admission fee + (hours) × (hour rend fee)

Substitute values into the equation

19 = 7 + 1.5h

Subtract 7 on both sides

19 - 7 = 7 + 1.5h - 7

12 = 1.5h

Divide 1.5 on both sides

12 / 1.5 = 1.5h / 1.5

[tex]\boxed{h=8}[/tex]

Hope this helps!! :)

Please let me know if you have any questions

Answer:

48 children went to the big picnic

Step-by-step explanation:

hope that helps>3

Answer:

48 children

Step-by-step explanation:

Answer:

Parallel lines

Step-by-step explanation:

Answer:

angle 1 + angle 2 = ∠DEB

angle 7 + angle 8 = ∠NEG

angle 1 + angle 6 = ∠NEA

Answer:

[tex]x = \frac{5}{13} [/tex]

Step-by-step explanation:

[tex] \frac{3}{4} x + \frac{5}{4} = 4x[/tex]

[tex]3x + 5 = 16x[/tex]

[tex]3x - 16x = - 5[/tex]

[tex] - 13x = - 5[/tex]

[tex]x = \frac{5}{13} [/tex]

Answer:

True

Step-by-step explanation:

[tex]f(x)=y=-8x+5: exchanging\ x\ and\ y\\\\x=-8y+5\\\\8y=-x+5\\\\f^{-1}(x)=y=\dfrac{-x}{8}+\dfrac{5}{8} =g(x)\\\\\\[/tex]

The two functions are inverses.

Answer:

In algebra, like terms are terms that have the same variables and powers. ... Unlike terms are two or more terms that are not like terms, i.e. they do not have the same variables or powers. The order of the variables does not matter unless there is a power.

Answer:

These are not like terms.

Step-by-step explanation:

Although their variables are the same, the exponents are different.  LIke terms must have the same variables AND same exponents.  The first term's variables are: x raised to the second power times y, while the other term's variables are:  y times x times 2

2x ≠ x²