\lim_(x->0)(cos2x)^((3)/(x^(2)))

[tex]\huge\text{Hey there!}[/tex]

[tex]\huge\boxed{\rm{LCM\ (aka\ Lowest\ Common\ Multiple)\ is\ the}}\\\huge\boxed{\rm{lowest\ positive \ number\ has \ a \ multiple}}}\\\huge\boxed{\rm{of\ more\ than\ one\ number.}}[/tex]

[tex]\huge\boxed{\rm{The\ multiples\ of\ 42\ are: 42, 84, 126, 168, \& \ 210}}[/tex][tex]\huge\boxed{\rm{The \ multiples \ of \ 63\ are: 63, 126, 189, \& \ 252}}[/tex]

[tex]\huge\boxed{\rm{Therefore, your\ answer\ is: 126}}}[/tex]

[tex]\huge\boxed{\text{Good luck on your assignment \& enjoy your day,}}[/tex]

Answer:

1360

Step-by-step explanation:

there are 1200 seconds in 20 minutes. if Ella can do 17 jumps in 15 seconds, you would divide 1200 by 15 (which equals 80) because that would be the number of 15 seconds in 20 minutes. then you would divide 80 by 17, which gives you your final answer of 1360 jumps in 20 minutes.

-7/10 + (-5/6) = -(7/10 + 5/6) =

= -(21/30 + 25/30) = -46/30 =

= -1 16/30 = -1 8/15 ← the end

Answer:

13

Step-by-step explanation:

Since the angles form 180 degrees, it will be what the equation is equal to.

Make the equation:

8r + 5 + 5r + 6 = 180

Combine like terms:

8r + 5 + 5r + 6 = 180

13r + 5 + 6 = 180

13r + 11 = 180

Solve:

13r + 11 = 180

       -11     -11

---------------------

     13r = 169

    ------   ------

      13      13

        r = 13

Hope this helped.

Answer:

[tex]38[/tex] and [tex]68[/tex].

Step-by-step explanation:

Let [tex]x[/tex] be the smaller one of the two number.

[tex]x[/tex] must be a positive integer. The other number would be [tex](x + 30)[/tex].

The question states that the product of the two numbers is [tex]2584[/tex]. In other words:

[tex]x\, (x + 30) = 2584[/tex].

Rearrange this equation and solve for [tex]x[/tex]:

[tex]x^{2} + 30\, x - 2584 = 0[/tex].

The first root of this quadratic equation would be:

[tex]\begin{aligned}x_{1} &= \frac{(-30) + \sqrt{30^{2} - 4 \times (-2584)}}{2} \\ &= \frac{(-30) + \sqrt{900 + 10336}}{2} \\ &= \frac{(-30) + \sqrt{11236}}{2} \\ &= \frac{(-30)}{2} + \sqrt{\frac{11236}{2^{2}}} \\ &= (-15) + \sqrt{2809} \\ &= (-15) + 53 \\ &= 38 \end{aligned}[/tex].

Similarly, the second root of this quadratic equation would be:

[tex]\begin{aligned}x_{1} &= \frac{(-30) - \sqrt{30^{2} - 4 \times (-2584)}}{2} \\ &= (-15) - 53 \\ &= -68\end{aligned}[/tex].

Since the question requires that both numbers should be positive, [tex]x > 0[/tex]. Therefore, only [tex]x = 38[/tex] is valid.

Hence, the two numbers would be [tex]38[/tex] and [tex](38 + 30)[/tex], which is [tex]68[/tex].

9514 1404 393

Answer:

  38 and 68

Step-by-step explanation:

Let x represent the average of the two numbers. Then their product is ...

  (x -15)(x +15) = 2584

  x^2 = 2584 +225 = 2809 . . . . . . use relation (x -a)(x +a) = x^2 -a^2; add a^2

  x = √2809 = 53

Then the two numbers are ...

  53 +15 = 68

and

  68 -30 = 38

The two numbers are 38 and 68.

_____

Additional comment

Solving the problem in this way is equivalent to writing the quadratic equation for the smallest (or largest) number and solving that by completing the square. The "solution" x = -53 is not relevant in this problem.

Answer:

5 more matches was won by yu-na kim

Answer:

7.5

Step-by-step explanation:

168.75 divided by 22.5 = 7.5

$7.50 dollars an hour.

7.50 x 22.5 = 168.75