Line A passes through the point (-1,2). Which of the
following CANNOT be the equation of line A?
A y=1 - 2
B
y = x +1
C
X = -1
D y=x+3

Answer:

c

Step-by-step explanation

Answer:

1.)  [tex]\frac{1}{9^4}*9^3[/tex]

2.) [tex]\frac{1}{w^7}[/tex]

3.)

Step-by-step explanation:

When you have a negative exponent, rewrite:

[tex]x^{-a}=\frac{1}{x^a}[/tex]

Rewrite using this to change all negative exponents.

Answer:

Multiple Answers

Step-by-step explanation:

Note: When multiplying numbers with exponents, you add the exponents. When dividing numbers with exponents, you subtract exponents.When you have a negative exponent, flip the fraction and write it as a positive exponent.

1) -4 + 3= -1  

So we have  (9^-4) + (9^3)= (1/(9^1)

2) (1/w)^7

3) cannot read problem, but just apply the rules I wrote under "Note"

4) 14/y

5) cannot read problem,but just apply the rules I wrote under "Note"

6) 20d^4 n^? --Cannot read n exponents--.

7) cannot read problem

8) Cannot read problem

9) 90/z^4---only if exponents are 5,-3,and-6

10) 1/(9^5)

11) 54b^4

12) Cannot read problem

13) 16d^8c^8 ---if exponents are 5,3,6,2--

14) s^8

Hope this helps! Plz give brainly, I kinda need it.

Answer:

(a) Shown below.

(b) The probability that the first ball drawn is blue is 0.40.

(c) The probability that only white balls are drawn is 0.36.

Step-by-step explanation:

The balls in the urn are as follows:

Blue balls: B₁ and B₂

White balls: W₁, W₂ and W₃

It is provided that two balls are drawn from the urn, with replacement, and their color is recorded.

(a)

The possible outcomes of selecting two balls are as follows:

B₁B₁          B₂B₁          W₁B₁          W₂B₁          W₃B₁

B₁B₂         B₂B₂          W₁B₂         W₂B₂          W₃B₂

B₁W₁         B₂W₁         W₁W₁         W₂W₁         W₃W₁

B₁W₂        B₂W₂         W₁W₂        W₂W₂         W₃W₂

B₁W₃        B₂W₃         W₁W₃        W₂W₃         W₃W₃

There are a total of N = 25 possible outcomes.

(b)

The sample space for selecting a blue ball first is:

S = {B₁B₁, B₁B₂, B₁W₁, B₁W₂, B₁W₃, B₂B₁, B₂B₂, B₂W₁, B₂W₂, B₂W₃}

n (S) = 10

Compute the probability that the first ball drawn is blue as follows:

[tex]P(\text{First ball is Blue})=\frac{n(S)}{N}=\frac{10}{25}=0.40[/tex]

Thus, the probability that the first ball drawn is blue is 0.40.

(c)

The sample space for selecting only white balls is:

X = {W₁W₁, W₂W₁, W₃W₁, W₁W₂, W₂W₂, W₃W₂, W₁W₃, W₂W₃, W₃W₃}

n (X) = 9

Compute the probability that only white balls are drawn as follows:

[tex]P(\text{Only White balls})=\frac{n(X)}{N}=\frac{9}{25}=0.36[/tex]

Thus, the probability that only white balls are drawn is 0.36.

Step-by-step explanation:

(f+g)(x) = f(x) + g(x)

= x/2-3 + 4x²+x+4

= ..........

Answer: 200 ways

Step-by-step explanation:

From the given information:

Total number of roads leading from Bluffton to​ Hardeeville = 4

Total number of roads leading from Hardeeville to​ Savannah = 10

Total number of roads leading from Savannah to Macon = 5

We need to find the total number of ways to get from Bluffton to​ Macon.

Total number of ways to get from Bluffton to​ Macon = 4 * 10 * 5

= 200

Therefore, there are 200 required number of ways to get from Bluffton to​ Macon.

Answer:

ΔP = 567

Step-by-step explanation:

The increasing rate of the population is  13,51*t.

That rate by definition is:

dP/dt   where P is the population therefore

dP/dt = 13,51*t

dt  =  13,51*t*dt

Integrating on both sides of the equation  we get:

∫dp = ∫ 13,51*t*dt

P =  13,51*t²/2 + K         ( K is population for t = 0 )

Now the population in 10 years    P(₁₀)

P(₁₀) =  13,51* (10)² /2  + K

P(₁₀) =  675,5  + K      (1)

And   P(₄)     is    

P(₄)  = 13,51*(4)²/2  * K

P(₄)  = 108,08 + K        (2)

Then substracting

P(₁₀) - P(₄)  =  ( 675,5  + K ) -  ( 108,08 + K )

ΔP =  567,42

But we don´t have fraction of animal, then

ΔP = 567

Answer:

(9). Range; {8, 5, 2, -1, -4}

(10). Range; {-15, -7, 1, 9, 17}

Step-by-step explanation:

Domain of a function is (x-values) determined by the input values and Range of a function is determined by the (y-values) output values of the function.

(9). For the given function,

    f(x) = -3x + 2

    If the Domain of this function is a set of values,

    {-2, -1, 0, 1, 2}

    For Range,

    x       -2        -1         0        1       2

    f(x)     8         5        2       -1      -4

   Therefore, Range of the function 'f' will be; {8, 5, 2, -1, -4}

(11). f(x) = 4x + 1

    Domain is {-4, -2, 0, 2, 4}

    Table for input-output values will be,

    x      -4        -2         0        2        4

    f(x)  -15        -7          1        9        17

    Therefore, Range of the function will be {-15, -7, 1, 9, 17}

Answer:

2 * 3 + 4 * 5 = 26

5 * 7 + 1 * 8 = 43

Step-by-step explanation:

Given

_ * _ + _ * _ = _ _

Required

Fill in the boxes with digits 0 to 9

From the question we understand that the result must be two digits i.e. _ _

To solve this, we'll make use of trial by error method:

Fill the first two boxes wit 2 and 3: _ * _ becomes 2 * 3

Fill the next two boxes with 4 and 5: _ * _ becomes 4 * 5

So,we have

2 * 3 + 4 * 5

6 + 20

26

Hence, the first combination is 2 * 3 + 4 * 5 = 26

Another possible combination is:

Fill the first two boxes wit 5 and 7: _ * _ becomes 5 * 7

Fill the next two boxes with 1 and 8: _ * _ becomes 1 * 8

So,we have

5 * 7 + 1 * 8

35 + 8

43

Hence, another combination is 5 * 7 + 1 * 8 = 43

Note that; there are more possible combinations

Answer:

the probability that out of these 75 people, 14 or more drink coffee is 0.6133

Step-by-step explanation:

Given that:

sample size n = 75

proportion of high school students that drink coffee p = 20% = 0.20

The proportion of the students that did not drink coffee = 1 - p

Let X be the random variable that follows a normal distribution

X [tex]\sim[/tex] N (n, p)

X  [tex]\sim[/tex] N (75, 0.20)

[tex]\mu = np[/tex] = 75 × 0.20

[tex]\mu =[/tex] 15

[tex]\sigma = \sqrt{p (1-p) n}[/tex]

[tex]\sigma = \sqrt{0.20(1-0.20) 75}[/tex]

[tex]\sigma = \sqrt{0.20*0.80* 75}[/tex]

[tex]\sigma = \sqrt{12}[/tex]

[tex]\sigma = 3.464[/tex]

Now ; if 14 or more people drank coffee ; then

[tex]P(X \geq 14) = P(\dfrac{X-\mu }{\sigma} \leq \dfrac{X-\mu}{\sigma})[/tex]

[tex]P(X \geq 14) =P(\dfrac{14-\mu }{\sigma} \leq \dfrac{14-15}{3.464})[/tex]

[tex]P(X \geq 14) = P(Z \leq \dfrac{-1}{3.464})[/tex]

[tex]P(X \geq 14) = P(Z \leq -0.28868)[/tex]

From the standard normal z tables; (-0.288)

[tex]P(X \geq 14) = P(Z \leq 0.38667)[/tex]

[tex]P(X \geq 14) = 1 - 0.38667[/tex]

[tex]P(X \geq 14) = 0.61333[/tex]

the probability that out of these 75 people, 14 or more drink coffee is 0.6133

Answer:

Using a graphing calc.

Step-by-step explanation:

Answer:

[tex]\bold{10x^4\sqrt{6}+x^3\sqrt{30x}-10x^4\sqrt{3}-x^3\sqrt{15x}}[/tex]

Step-by-step explanation:

To find:

Simplified product of:

[tex](\sqrt{10x^4}-x\sqrt{5x^2})(2\sqrt{15x^4}+\sqrt{3x^3})[/tex]

Solution:

First of all, let us have a look at some of the formula:

1. [tex](a+b) (c+d) = ac+bc+ad+bd[/tex]

2. [tex]a^b\times a^c =a^{b+c }[/tex]

3. [tex]\sqrt{a^{2b}} = \sqrt{a^b.a^b}=a^b[/tex]

4. [tex]\sqrt a \times \sqrt b = \sqrt{a\times b}[/tex]

Now, let us apply the above formula to solve the given expression.

[tex](\sqrt{10x^4}-x\sqrt{5x^2})(2\sqrt{15x^4}+\sqrt{3x^3})\\\\\Rightarrow(\sqrt{10x^4})(2\sqrt{15x^4})+(\sqrt{10x^4})(\sqrt{3x^3})-(x\sqrt{5x^2})(2\sqrt{15x^4})-(x\sqrt{5x^2})(\sqrt{3x^3})\\\\\Rightarrow2\sqrt{150x^8}+\sqrt{30x^7}-2x\sqrt{75x^6}-x\sqrt{15x^5}\\\\\Rightarrow\bold{10x^4\sqrt{6}+x^3\sqrt{30x}-10x^4\sqrt{3}-x^3\sqrt{15x}}[/tex]

The answer is:

[tex]\bold{10x^4\sqrt{6}+x^3\sqrt{30x}-10x^4\sqrt{3}-x^3\sqrt{15x}}[/tex]

Answer:

Its D

Step-by-step explanation:

Answer:

45

Step-by-step explanation:

2 digit number starts from 10 ends at 99

between 10 and 19 there is only one number whose tens digit is more than ones digit.

that is 10

between 20 and 29 there are two numbers

20 and 21

like the same

between 30 and 39 there are 3 numbers

10–19. 1

20–29. 2

30–39. 3

40–49. 4

50–59. 5

60–69. 6

70–79. 7

80–89. 8

99–99. 9

sum of first n natural numbers is n(n+1)/2

9(9+1)/2=45

Three numbers between 10 and 99 have tens places that are precisely three times larger than their one's places.

The foundation of our whole number system is place value. In this approach, the value of a digit in a number is determined by where it appears in the number.

The tens digit must be three times larger than the units digit in order to meet the requirement. The units digit can have one of the following values: 0, 1, 2, 3, 4, 5, 6, 7, 8, or 9.

Since we are seeking two-digit integers, it is not possible if the unit digit is zero for the tens digit also be zero.

In the case when the unit digit is 1, the tens digit must be 3, resulting in the number 31. Similar to the previous example, if the unit digit is 2, the tens digit must be 6, resulting in the number 62.

As we proceed, we discover the following integers meet the condition:

31, 62, 93

Therefore, there are three numbers from 10 to 99 that have a tens place exactly 3 times greater than their one's place.

Learn more about place values here:

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Answer:

72

Step-by-step explanation:

The formula for surface area is SA = 2lw + 2wh + 2lh

W = width

L= length

H = height

A = 2(wl + hl + hw)

2·(6·3+2·3+2·6)

Simplify that down to get the answer 72

Greetings from Brasil...

In this problem we have 2 translations: 4 units horizontal to the left and 3 units vertical to the bottom.

The translations are established as follows:

→ Horizontal

F(X + k) ⇒ k units to the left

F(X - k) ⇒ k units to the right

→ Vertical

F(X) + k ⇒ k units up

F(X) - k ⇒ k units down

In our problem, the function shifted 4 units horizontal to the left and 3 units vertical to the bottom.

F(X) = X³

4 units horizontal to the left: F(X + 4)

3 units vertical to the bottom: F(X + 4) - 3

So,

F(X) = X³

The transformed function is f ( x ) = ( x + 4 )³ - 3 and the graph is plotted

Every modification may be a part of a function's transformation.

Typically, they can be stretched (by multiplying outputs or inputs) or moved horizontally (by converting inputs) or vertically (by altering output).

If the horizontal axis is the input axis and the vertical is for outputs, if the initial function is y = f(x), then:

Vertical shift, often known as phase shift:

Y=f(x+c) with a left shift of c units (same output, but c units earlier)

Y=f(x-c) with a right shift of c units (same output, but c units late)

Vertical movement:

Y = f(x) + d units higher, up

Y = f(x) - d units lower, d

Stretching:

Stretching vertically by a factor of k: y = k f (x)

Stretching horizontally by a factor of k: y = f(x/k)

Given data ,

Let the function be represented as g ( x )

Now , the value of g ( x ) = x³

And , the transformed function has coordinates as A ( -4 , -3 )

So , when function is shifted 4 units to the left , we get

g' ( x ) = ( x + 4 )³

And , when the function is shifted vertically by 3 units down , we get

f ( x ) = ( x + 4 )³ - 3

Hence , the transformed function is f ( x ) = ( x + 4 )³ - 3

To learn more about transformation of functions click :

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Answer:

Midpoint formula.

The midpoint formula is (x_1+x_2)/2 , (y_1+y_2)/2

Step-by-step explanation:

This is one method. A list wasn't provided.

Answer:

1. It would take the car to get from Tucson to Phoenix 12 hours.

2. for the car to go around the equator it would take 637 hours if it is still travelling at 10km/hr.

hope this helps

Step-by-step explanation:

1. 120 km divided by 10 = 12 hours

(a) Expand the given expression as

[tex]\dfrac{3s-10}{s^2+25}=3\cdot\dfrac s{s^2+25}-2\cdot\dfrac5{s^2+25}[/tex]

You should recognize the Laplace transform of sine and cosine:

[tex]L[\cos(at)]=\dfrac s{s^2+a^2}[/tex]

[tex]L[\sin(at)]=\dfrac a{s^2+a^2}[/tex]

So we have

[tex]L^{-1}\left[\dfrac{3s-10}{s^2+25}\right]=3\cos(5t)-2\sin(5t)[/tex]

(b) Take the Laplace transform of both sides:

[tex]y'(t)+3y(t)=e^{6t}\implies (sY(s)-y(0))+3Y(s)=\dfrac1{s-6}[/tex]

Solve for [tex]Y(s)[/tex]:

[tex](s+3)Y(s)-2=\dfrac1{s-6}\implies Y(s)=\dfrac{2s-11}{(s-6)(s+3)}[/tex]

Decompose the right side into partial fractions:

[tex]\dfrac{2s-11}{(s-6)(s+3)}=\dfrac{\theta_1}{s-6}+\dfrac{\theta_2}{s+3}[/tex]

[tex]2s-11=\theta_1(s+3)+\theta_2(s-6)[/tex]

[tex]2s-11=(\theta_1+\theta_2)s+(3\theta_1-6\theta_2)[/tex]

[tex]\begin{cases}\theta_1+\theta_2=2\\3\theta_1-6\theta_2=-11\end{cases}\implies\theta_1=\dfrac19,\theta_2=\dfrac{17}9[/tex]

So we have

[tex]Y(s)=\dfrac19\cdot\dfrac1{s-6}+\dfrac{17}9\cdot\dfrac1{s+3}[/tex]

and taking the inverse transforms of both sides gives

[tex]y(t)=\dfrac19e^{6t}+\dfrac{17}9e^{-3t}[/tex]

Answer:

Probabilty of both Black

= 1/6

Step-by-step explanation:

A bag contains five white balls and four black balls.

Total number of balls= 5+4

Total number of balls= 9

Probabilty of selecting a black ball first

= 4/9

Black ball remaining= 3

Total ball remaining= 8

Probabilty of selecting another black ball without replacement

= 3/8

Probabilty of both Black

=3/8 *4/9

Probabilty of both Black

= 12/72

Probabilty of both Black

= 1/6

Answer: p-value of the test  = 0.167

Step-by-step explanation:

Given that,

sample size n = 400

sample success X = 80

confidence = 95%

significance level = 1 - (95/100) = 0.05

This is the left tailed test .

The null and alternative hypothesis is

H₀ : p = 0.22

Hₐ : p < 0.22

P = x/n = 80/400 = 0.2

Standard deviation of proportion α = √{  (p ( 1 - p ) / n }

α = √ { ( 0.22 ( 1 - 0.22 ) / 400 }

α = √ { 0.1716 / 400 }

α = √0.000429

α = 0.0207

Test statistic

z = (p - p₀) / α

z = ( 0.2 - 0.22 ) / 0.0207

z = - 0.02 / 0.0207

z = - 0.9661

fail to reject null hypothesis.

P-value Approach

P-value = 0.167

As P-value >= 0.05, fail to reject null hypothesis.

Since test is left tailed so p-value of the test is 0.167. Since p-value is greater than 0.05 so we fail to reject the null hypothesis.

Answer:

f(-5) = 22

Step-by-step explanation:

f(x) =-3x+7

Let x = -5

f(-5) =-3*-5+7

      = 15 +7

       =22

Answer:

Here's one way:

4    9    2

3    5    7

8    1     6

Step-by-step explanation:

Answer:

  2.5

Step-by-step explanation:

Put the values in place of the corresponding variables and do the arithmetic:

  ab - 0.5b = (1)(5) -0.5(5) = 5 - 2.5 = 2.5

Answer:

D)  0.49

Step-by-step explanation:

0.85 * 0.58 = 0.49

The probability is:

D  0.49

Answer:

a

   [tex]P(X < 2500) = 0.02668[/tex]

b

   [tex]P(X < 1500) = 0.00001[/tex]

Step-by-step explanation:

From the question we are told that

     The  population mean  is  [tex]\mu = 3350[/tex]

      The standard deviation is  [tex]\sigma = 440[/tex]

We also told in the question that the birth weight is  approximately Normally distributed

    i.e      [tex]X \ \~ \ N(\mu , \sigma )[/tex]

Given that Low-birth-weight babies weighing less than 2500 grams,then the proportion of babies born full term are low-birth-weight babies is mathematically represented as

       [tex]P(X < 2500) = P(\frac{ X - \mu }{\sigma } < \frac{2500 - \mu}{\sigma } )[/tex]

Generally  

         [tex]\frac{X - \mu}{ \sigma } = Z (The \ standardized \ value \ of \ X )[/tex]

So

      [tex]P(X < 2500) = P(Z < \frac{2500 - \mu}{\sigma } )[/tex]

substituting values

      [tex]P(X < 2500) = P(Z < \frac{2500 - 3350}{440 } )[/tex]

       [tex]P(X < 2500) = P(Z <-1.932 )[/tex]

Now from the standardized normal distribution table(These value can also be obtained from Calculator dot com) the value of

     [tex]P(Z <-1.932 ) = 0.02668[/tex]

=>    [tex]P(X < 2500) = 0.02668[/tex]

Given that  very-low-birth-weight babies (weighing less than 1500 grams,then the  proportion of babies born full term are very-low-birth-weight babies is mathematically represented as

    [tex]P(X < 1500) = P(\frac{ X - \mu }{\sigma } < \frac{1500 - \mu}{\sigma } )[/tex]

    [tex]P(X < 1500) = P(Z < \frac{1500 - \mu}{\sigma } )[/tex]

substituting values

           [tex]P(X < 1500) = P(Z < \frac{1500 - 3350}{440 } )[/tex]

       [tex]P(X < 1500) = P(Z <-4.205 )[/tex]

Now from the standardized normal distribution table(These value can also be obtained from calculator dot com) the value of

     [tex]P(Z <-1.932 ) = 0.00001[/tex]

    [tex]P(X < 1500) = 0.00001[/tex]

Answer:

-35 and 37

Step-by-step explanation:

If you start with negative 35 and count up (including zero), you’ll cancel out when you get to positive 35 and have 71 numbers.  Then you continue on with 36 and 37 which equals 73, and you have 73 consecutive integers.

Answer:

There is a positive correlation between X and Y.

Step-by-step explanation:

The estimated regression equation is:

[tex]\hat Y=20X+200[/tex]

The general form of a regression equation is:

[tex]\hat Y=b_{yx}X+a[/tex]

Here, [tex]b_{yx}[/tex] is the slope of a line of Y on X.

The formula of slope is:

[tex]b_{yx}=r(X,Y)\cdot \frac{\sigma_{y}}{\sigma_{x}}[/tex]

Here r (X, Y) is the correlation coefficient between X and Y.

The correlation coefficient is directly related to the slope.

And since the standard deviations are always positive, the sign of the slope is dependent upon the sign of the correlation coefficient.

Here the slope is positive.

This implies that the correlation coefficient must have been a positive values.

Thus, it can be concluded that there is a positive correlation between X and Y.

Answer:

[tex]\large \boxed{\mathrm{B. \ \ \{-10, -6, 10\} }}[/tex]

Step-by-step explanation:

The domain is the x values.

D = {-1, 0, 4}

y = 4(-1) - 6 = -4 - 6 = -10

y = 4(0) - 6 = 0 - 6 = -6

y = 4(4) - 6 = 16 - 6 = 10

The range is the y values.

R = {-10, -6, 10}

Answer:

[tex]\large \boxed{\mathrm{4/5 \ cups}}[/tex]

Step-by-step explanation:

Subtract 1/10 from 9/10 to find out how much is left.

9/10 - 1/10

8/10 = 4/5

Answer:

Step-by-step explanation:

[tex]Volume\:of \: syrup \:in \:cup\:from\:jug = \frac{9}{10}\\\\ She \:took\: \frac{1}{10} from \:the\:cup\:into\:the \:jug \\\\Volume \:of syrup\:in\:cup=?\\\\\frac{9}{10} -\frac{1}{10} \\\\= \frac{4}{5} cups[/tex]