line j passes through the coordinate points (4,1) and (-3,_6).what is the y-intercept of the equation that is parallel; to line j and passes through the point,(7,1)

Answers

Answer 1

Answer: y-intercept is -6

Step-by-step explanation: Calculate the slope of the line between the two given points:

Rise/Run = slope, m in the standard form of a straight line: y=mx+b, with b the y-intercept (the value of y when x=0).

Rise = 1 - (-6) = 7

Run = 4 - (-3) = 7

Slope = Rise/Run, 7/7, or 1

y=mx+b

y = 1x+ b

Find b by entering one of the two given points. I'll pick (4,1).

y = 1x+ b

What's important now is the next step. The equation "that is parallel" must have the same slope as the reference equation, 1 in this case.

[If, out of curiosity, you want the full equation of the reference line, we can find b in this way:

Enter one of the two given points and solve for b. I'll pick (4,1):

y = 1x+ b

1 = 1*(4)+ b

b = -3

y = 1x - 3 is the first equation.]

All we really needed from the first, or reference, equation is the slope, 1 in this case. Parallel lines have the same slope, so we want an equation in the form:

y=1x+b

This equation will be parallel, regardless of the value of b. But we want it to go through a specific point, (7,1). So use that point and solve for b:

y=1x+b

1=1*7+b

b=-6

The equation is y=1x-6

Line J Passes Through The Coordinate Points (4,1) And (-3,_6).what Is The Y-intercept Of The Equation

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Given that r varies directly as t^3, and r=54 when t=3. Find t when r=250

Answers

Answer:

t = 5

Step-by-step explanation:

Given r varies directly as t³ then the equation relating them is

r = kt³ ← k is the constant of variation

To find k use the condition r = 54 when t = 3 , then

54 = k × 3³ = 27k ( divide both sides by 27 )

2 = k

r = 2t³ ← equation of variation

When r = 250 , then

250 = 2t³ ( divide both sides by 2 )

125 = t³ ( take cube root of both sides )

[tex]\sqrt[3]{125}[/tex] = t , that is

t = 5

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A. 1

B. 9

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D. 81√2

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Answer:

h = 18 units

Step-by-step explanation:

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If the mean score is 55% and the s.d. is 15%, then a test score of at least

55% + 1.5 × 15% = 77.5%

falls in the A range.

The next cutoff score is 0.5 s.d. from the mean, which is

55% + 0.5 × 15% = 62.5%

so any test score between 62.5% and 77.5% is in the B range.

The next cutoff is

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Answer:

your answer is 4+3

Step-by-step explanation:

What is the missing side length of a right triangle with legs 4 and 6 centimeters

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Answer:

7.21 cm.

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4² + 6² = x²

16 + 36 = x²

52 = x²

[tex]\sqrt{52} = x[/tex]

7.21 cm.

Check

The third side of a triangle is greater than the difference and less than the sum of the lengths of the two given sides. 6 - 4 = 2 and 6 + 4 = 10

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solve for y:

24=4x+6y

Answers

Answer:

let x = 0

therefore

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you can take different value of x and the value of y will change automatically

Rahmat wants to meet Ah Chong at his house. He has two options, whether via the road by walking 195 m to west and 28 m to north or he can pass through a field directly to Ah Chong's house. Which option is faster to Ah Chong's house? Then, find the difference between the distance via the road and through the field.

Answers

Answer:

197 m26 m

Step-by-step explanation:

Use Pythagorean to find the distance through the field:

[tex]d = \sqrt{195^2+28^2} =\sqrt{38809} =197[/tex]

Difference between two options:

(195 + 28) - 197 = 26 m

Answer:

It is faster to walk through the field and directly to Ah Chong's house.

The difference between the distance via the road and through the field is 26 m.

Step-by-step explanation:

The scenario can be modeled as a right triangle (see attached diagram).

Option 1Walk 195 m west and 28 m north.

⇒ Total distance = 195 + 28 = 223 m

Option 2Walk directly to Ah Chong's house through the field.

To calculate this distance (hypotenuse of the right triangle), use Pythagoras Theorem.

Pythagoras Theorem

[tex]a^2+b^2=c^2[/tex]

where:

a and b are the legs of the right triangle.c is the hypotenuse (longest side) of the right triangle.

[tex]\implies 195^2+28^2=c^2[/tex]

[tex]\implies c^2=38025+784[/tex]

[tex]\implies c^2=38809[/tex]

[tex]\implies c=\sqrt{38809}[/tex]

[tex]\implies c=197[/tex]

Therefore, the distance for option 2 is 197 m.

Difference

Option 1 - Option 2 = 223 - 197 = 26 m

Conclusion

As 197 < 223, it is faster for Rahmat to walk through the field and directly to Ah Chong's house (option 2).

Learn more about Pythagoras Theorem here:

https://brainly.com/question/27648540

https://brainly.com/question/27988757

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Tom walks 1 mile in
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Answers

Answer:

460 feet

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#Help plz
#No spam -_-||
#Quality answer needed

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Please find attached photograph for your answer.

Hope it helps.

Do comment if you have any query.

All changes saved
D
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↑

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Answer:

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Answers

Answer:

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Sorry if its wrong ^.^

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