The position of a particle on a straight line is given by s(t) = 3 – cos(t).
A. Find velocity and acceleration at t = 4.3 s.
Round your answers to 2 decimal(s).
v(t) =
a(t) =
Given the position function
s(t) = 3 - cos(t )
differentiate once to get the velocity, and twice to get the acceleration:
v(t) = s'(t) = sin(t ) → v (4.3 s) ≈ -0.92
a(t) = s''(t) = v'(t) = cos(t ) → a (4.3 s) ≈ -0.40
The acceleration is negative, so the particle is slowing down.
I need the answer too all of these:
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6. 3x + 6 + 1x = ?
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8. 2x - 5 + 2 =
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