Answer:
D = L/k
Step-by-step explanation:
Since A represents the amount of litter present in grams per square meter as a function of time in years, the net rate of litter present is
dA/dt = in flow - out flow
Since litter falls at a constant rate of L grams per square meter per year, in flow = L
Since litter decays at a constant proportional rate of k per year, the total amount of litter decay per square meter per year is A × k = Ak = out flow
So,
dA/dt = in flow - out flow
dA/dt = L - Ak
Separating the variables, we have
dA/(L - Ak) = dt
Integrating, we have
∫-kdA/-k(L - Ak) = ∫dt
1/k∫-kdA/(L - Ak) = ∫dt
1/k㏑(L - Ak) = t + C
㏑(L - Ak) = kt + kC
㏑(L - Ak) = kt + C' (C' = kC)
taking exponents of both sides, we have
[tex]L - Ak = e^{kt + C'} \\L - Ak = e^{kt}e^{C'}\\L - Ak = C"e^{kt} (C" = e^{C'} )\\Ak = L - C"e^{kt}\\A = \frac{L}{k} - \frac{C"}{k} e^{kt}[/tex]
When t = 0, A(0) = 0 (since the forest floor is initially clear)
[tex]A = \frac{L}{k} - \frac{C"}{k} e^{kt}\\0 = \frac{L}{k} - \frac{C"}{k} e^{k0}\\0 = \frac{L}{k} - \frac{C"}{k} e^{0}\\\frac{L}{k} = \frac{C"}{k} \\C" = L[/tex]
[tex]A = \frac{L}{k} - \frac{L}{k} e^{kt}[/tex]
So, D = R - A =
[tex]D = \frac{L}{k} - \frac{L}{k} - \frac{L}{k} e^{kt}\\D = \frac{L}{k} e^{kt}[/tex]
when t = 0(at initial time), the initial value of D =
[tex]D = \frac{L}{k} e^{kt}\\D = \frac{L}{k} e^{k0}\\D = \frac{L}{k} e^{0}\\D = \frac{L}{k}[/tex]
IF A FUNCTION f(x) is defined AS 5x^2-3x+3, what is the expression for
Answer: C. 10x-3
Step-by-step explanation: I got this question correct on Edmentum.
The value of the expression will be 10x – 3. Then the correct option is C.
What is the limit?The value that approaches the output for the given input value. Limits are a very important tool in calculus.
The function is defined as,
f(x) = 5x² – 3x + 2
Then the value of the expression will be
[tex]\rightarrow \displaystyle \lim_{h \to 0} \dfrac{f(x+h)-f(x)}{h}[/tex]
Substitute the value of the function, then the value of the expression will be
[tex]\rightarrow \displaystyle \lim_{h \to 0} \dfrac{5(x+h)^2 - 3(x + h) + 3- 5x^2 + 3x - 3}{h}\\\\\\\rightarrow \displaystyle \lim_{h \to 0} \dfrac{5x^2 + 5h^2 + 10xh - 3x - 3h + 3- 5x^2 + 3x - 3}{h}\\\\\\\rightarrow \displaystyle \lim_{h \to 0} \dfrac{ 5h^2 + 10xh - 3h }{h}\\[/tex]
Simplify the equation further, then we have
[tex]\rightarrow \displaystyle \lim_{h \to 0} 5h + 10x - 3 \\[/tex]
Substitute the value of the h = 0, then the value of the expression will be
⇒ 5(0) + 10x – 3
⇒ 10x – 3
Then the correct option is C.
More about the limit link is given below.
https://brainly.com/question/8533149
#SPJ2
The base and height of a triangle are 9 yards and 10 yards respectively. Find the area of the triangle.
Answer:
45
Step-by-step explanation:
1/2×9×10
since the formula says half base times height, so therefore
Area =45
Challenge:
Put these in order (least to greatest)
Answer:
1 1/4, -1, -1/4, 0, 1/4, 1
Step-by-step explanation:
Answer:
-1 1/4, -1, -1/4, 0, 1/4, 1,
Step-by-step explanation:
Which fraction is the product of 5/4 x 6?
Answer:
15 x /2
Step-by-step explanation:
Use the method of cylidrincal shells to find the volume of the solid generated by rotating the region bounded by the curves y=6x-2x^2 and y=x^2 about the y axis.
Find where the two curves intersect:
y = 6x - 2x ²
y = x ²
6x - 2x ² = x ² → 3x ² - 6x = 3x (x - 2) = 0 → x = 0 and x = 2
Now, for a shell of radius x units away from the axis of revolution, the height of the shell would be the vertical distance between the upper curve and the lower curve. For 0 ≤ x ≤ 2, we have 6x - x ² ≥ x ², so the height of any given shell is (6x - x ²) - x ² = 6x - 2x ².
Then volume of the solid is
[tex]\displaystyle 2\pi \int_0^2 x(6x-2x^2)\,\mathrm dx = 2\pi \left(2x^3-\frac{x^4}2\right)\bigg|_0^2 = \boxed{16\pi}[/tex]
When graphed on a coordinate plane Beth’s house is located at (4, 3) and the coffee shop is located at the point (–2, –1).
What is the distance from Beth’s house to the coffee shop? Each grid line on the coordinate plane represents 1 mile.
10 miles
square root of 8
square root of 52
52 miles
Answer:
the answer is c square root 52
Step-by-step explanation:
just got a 100
The distance from Beth’s house to the coffee shop, which are graphed on a coordinate plane is √(52) units.
What is a distance formula?The distance formula is used to measure the distance between the two points on a coordinate plane.
Let the two coordinate point on a coordinate plane is ([tex]x_1,y_1[/tex]) and ([tex]x_2,y_2[/tex]). Thus, the distance between these two can be given as,
[tex]d=\sqrt{(x_1-x_2)^2+(y_1-y_2)^2}[/tex]
When graphed on a coordinate plane Beth’s house is located at (4, 3) and the coffee shop is located at the point (–2, –1).
Here, each grid line on the coordinate plane represents 1 mile.
Using the distance formula for these point, the distance from Beth’s house to the coffee shop can be given as,
[tex]d=\sqrt{(4-(-2)^2)+(3-(-1))^2}\\d=\sqrt{6)^2+(4)^2}\\d=\sqrt{36+16}\\d=\sqrt{52}[/tex]
Hence, the distance from Beth’s house to the coffee shop, which are graphed on a coordinate plane is √(52) units.
Learn more about the distance formula here;
https://brainly.com/question/661229
Ethan purchased a new cell phone for $75.00. The costs of the phone is included in his first month's bill. His cell phone plan charges $0.06 for each minute used.
if Ethan has $90.00 to spend on his first month's bill, what is the maximum number of minutes he can use?
A. 80 minutes
B. 250 minutes
C. 1,250 minutes
D. 1,500 minutes
Answer:1,250
Step-by-step explanation:
The manager of a fleet of automobiles is testing two brands of radial tires and assigns one tire of each brand at random to the two rear wheels of eight cars and runs the cars until the tires wear out. The data (in kilometers) follow. Find a 99% confidence interval on the difference in the mean life.
Car Brand 1 Brand 2
1 36663 33866
2 43509 41829
3 36240 35500
4 32100 31950
5 37210 38015
6 48360 47800
7 38200 37810
8 33500 33215
a) Calculate SD =
b) Calculate a 99% two-sided confidence interval on the difference in mean life.
c) Which brand would you prefer? (brand 1/ no difference /brand 2)_____
Answer:
a) σ = 4933,64
b) CI 99% = ( - 5746 ; 7194 )
c) No difference in brands
Step-by-step explanation:
Brand 1:
n₁ = 8
x₁ = 38222
s₁ = 4974
Brand 2:
n₂ = 8
x₂ = 37498
s₂ = 4893
As n₁ = n₂ = 8 Small sample we work with t -student table
degree of freedom df = n₁ + n₂ - 2 df = 8 +8 -2 df = 14
CI = 99 % CI = 0,99
From t-student table we find t(c) = 2,624
CI = ( x₁ - x₂ ) ± t(c) * √σ²/n₁ + σ²/n₂
σ² = [( n₁ - 1 ) *s₁² + ( n₂ - 1 ) * s₂² ] / n₁ +n₂ -2
σ² = 7* (4974)² + 7*( 4893)² / 14
σ² = 24340783 σ = 4933,64
√ σ²/n₁ + σ²/n₂ = √ 24340783/8 + 24340783/8
√ σ²/n₁ + σ²/n₂ = 2466
CI 99% = ( x₁ - x₂ ) ± 2,624* 2466
CI 99% = 724 ± 6470
CI 99% = ( - 5746 ; 7194 )
As we can see CI 99% contains 0 and that means that there is not statistical difference between mean life of the two groups
Help please and thanks <33
Answer:
The 4th one (bottom)
Step-by-step explanation:
[tex]\frac{2}{3}x - 5 > 3\\\frac{2}{3}x > 3 + 5\\\frac{2}{3}x > 8\\x > 8 / \frac{2}{3} \\x > 12\\[/tex]
> sign means an open circle over 12, shaded/pointing to the right. The 4th option is your answer
find the asymptotes, domain, range and end behavior and sketch the parent graph with the translated graph
Answer:
27) x = 2^(y) – 5.
Asymptote: x = -5.
D: x > -5; (-5, infinity).
R: -infinity < f(x) < infinity; ARN;
(-infinity, infinity).
x → -infinity, f(x) → -infinity.
x → +infinity, f(x) → +infinity.
________________________
28) x = 2^-(y–3).
Asymptote: x = 0.
D: x > 0; (0, infinity).
R: -infinity < f(x) < infinity; ARN;
(-infinity, infinity).
x → -infinity, f(x) → +infinity.
x → +infinity, f(x) → -infinity.
________________________
29) x = 4^(y–2) + 1.
Asymptote: x = 1.
D: x > 1; (1, infinity).
R: -infinity < f(x) < infinity; ARN;
(-infinity, infinity).
x → -infinity, f(x) → -infinity.
x → +infinity, f(x) → +infinity.
________________________
How many faces does a triangular pyramid have?
A. 3
B. 6
C. 4
D. 5
[tex]\huge{\textbf{\textsf{{\color{navy}{An}}{\purple{sw}}{\pink{er}} {\color{pink}{:}}}}}[/tex]
C. 4.
thanks hope it helpsThrough extensive data collection, quality control experts have verified that the true mean weight of a wrapped Starburst candy is 5.1 grams, as advertised on the package. However, in a class activity where you selected and weighed 8 wrapped Starburst candies you obtained a p-value of 0.003 and concluded that the true mean weight of Starburst candies is not as advertised. What type of error was potentially made in this hypothesis test
Answer:
Type 1 error.
Step-by-step explanation:
H0 : μ = 5.1
H1 : μ ≠ 5.1
The Pvalue of the test = 0.003
Decision made by the researcher was conclude that mean weight is not as advertised, that is the researcher rejected the Null hypothesis.
However, when the Pvalue is < α - value , we reject the null ; The type of error the researcher could have made is that ; The mean weight may be truly as advertised, Hence, leading us to make a false positive error, thus is rejecting a true null. This is a TYPE 1 error.
(MATH) (6) ((PHOTO))
label is m
Multiply the length by the height:
6.5 x 2 = 13
The width is the volume divided by 13
Width = 52/13 = 4 m
de una bolsa donde hay veinte bolas numeradas del 1 al 20 extraemos una, A: obtener un número par , B: obtener número primo, C: obtener un número tal que su suma de cifras sea 5,
a) comprobar que cumplan con las propiedades asociativa y distributiva en los sucesos, b) comprobar que se cumplan con las propiedades de las leyes de morgan entre los sucesos AyC , ByC, AyB , c) efectúa las siguientes operaciones en los sucesos unión entre AB, BC, AB, intersección entre AB,BC, AB, diferenciación entre AB, BA, CA, AC,
A sweater costs $25. The store marks up the price by 85%. What is the selling price of the sweater?
The body temperatures of all mosquitoes in a county have a mean of 57∘F and a standard deviation of 10∘F. What is the probability that in a sample of 25 mosquitoes the mean body temperature is greater than 59∘F, assuming the underlying distribution is normal? Do not write probability in terms of percentage. Round your answer to two decimal places.
Answer:
0.16 probability that in a sample of 25 mosquitoes the mean body temperature is greater than 59∘F, assuming the underlying distribution is normal.
Step-by-step explanation:
To solve this question, we need to understand the normal probability distribution and the central limit theorem.
Normal Probability Distribution:
Problems of normal distributions can be solved using the z-score formula.
In a set with mean [tex]\mu[/tex] and standard deviation [tex]\sigma[/tex], the z-score of a measure X is given by:
[tex]Z = \frac{X - \mu}{\sigma}[/tex]
The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the p-value, we get the probability that the value of the measure is greater than X.
Central Limit Theorem
The Central Limit Theorem estabilishes that, for a normally distributed random variable X, with mean [tex]\mu[/tex] and standard deviation [tex]\sigma[/tex], the sampling distribution of the sample means with size n can be approximated to a normal distribution with mean [tex]\mu[/tex] and standard deviation [tex]s = \frac{\sigma}{\sqrt{n}}[/tex].
For a skewed variable, the Central Limit Theorem can also be applied, as long as n is at least 30.
The body temperatures of all mosquitoes in a county have a mean of 57∘F and a standard deviation of 10∘F.
This means that [tex]\mu = 57, \sigma = 10[/tex]
Sample of 25:
This means that [tex]n = 25, s = \frac{10}{\sqrt{25}} = 2[/tex]
of 25 mosquitoes the mean body temperature is greater than 59∘F, assuming the underlying distribution is normal?
This is 1 subtracted by the pvalue of Z when X = 59. So
[tex]Z = \frac{X - \mu}{\sigma}[/tex]
By the Central Limit Theorem
[tex]Z = \frac{X - \mu}{s}[/tex]
[tex]Z = \frac{59 - 57}{2}[/tex]
[tex]Z = 1[/tex]
[tex]Z = 1[/tex] has a pvalue of 0.84
1 - 0.84 = 0.16
0.16 probability that in a sample of 25 mosquitoes the mean body temperature is greater than 59∘F, assuming the underlying distribution is normal.
The standard gasoline engine for the 2017 Toyota Corolla includes the following data: Configuration: In-line four-stroke, four-cylinder engine Bore: 3.17 in Stroke: 3.48 in Compression ratio: 10.6:1 Assuming an ideal Otto cycle to describe this engine. Consider the working fluid to be air, modeled as an ideal gas with variable specific heat. Determine: (a) The total engine volume VBDC for all cylinders (cu.in). (b) The mass of air (lbm) contained in the engine assuming ambient conditions of 540 R and 14.7 psia. (c) The efficiency of the engine (%). The maximum temperature that occurs during the cycle is 3600 R.
Answer:
a) The total engine volume is 30.3265 in³
b) the mass of air contained in the engine is 0.00129 lbm
c) The efficiency of the engine is 55.6%
Step-by-step explanation:
Given the data in the question;
The configuration is in line with four-stroke, four-cylinder engine.
Bore ( d ) = 3.17 in
Stroke ( L ) = 3.48 in
compression ratio ( r ) = 10.6 : 1
First, we calculate the swept Volume V₁ = π/4 × d²L
we substitute
V₁ = π/4 × (3.17 )² × (3.48) = 27.4655 in³
Now, Compression Ration; r = Vs + Vc / Vc
r = (V₁ + V₂) / V₂
we substitute
10.6 = (27.4655 + V₂) / V₂
10.6V₂ = 27.4655 + V₂
10.6V₂ - V₂ = 27.4655
9.6V₂ = 27.4655
V₂ = 2.861 in³
So
a) total engine volume
[tex]V_{BDC[/tex] = V₁ + V₂
we substitute
[tex]V_{BDC[/tex] = 27.4655 in³ + 2.861 in³
[tex]V_{BDC[/tex] = 27.4655 in³ + 2.861 in³
[tex]V_{BDC[/tex] = 30.3265 in³
Therefore, The total engine volume is 30.3265 in³
b) The mass of air
given that; T = 540°R, P = 14.7 psia
we know that; PV = mRT { R is constant }
we solve for m
m = PV / RT
we substitute
m = (14.7 × 30.3265) / ( 0.3704 × 1728 )540
m = 445.79955 / 345627.648
m = 0.00129 lbm
Therefore, the mass of air contained in the engine is 0.00129 lbm
c) The efficiency
from table { properties of air}
At 540°R; u₁ = 92.04 BTu/lbm, u[tex]_r[/tex]₁ = 144.32
Now process 1 - 2 ( Isentropic ) u[tex]_r[/tex]₁ / u[tex]_r[/tex]₂ = V₁/V₁ = r
so, u[tex]_r[/tex]₁ / u[tex]_r[/tex]₂ = r
144.32 / u[tex]_r[/tex]₂ = 10.6
u[tex]_r[/tex]₂ = 144.32/10.6
u[tex]_r[/tex]₂ = 13.61
Thus, at u[tex]_r[/tex]₂ = 13.61, u₂ = 235 BTU/lbm, T₂ = 1340°R
Now, we know that;
P₁V₁/T₁ = P₂V₂/T₂ ⇒ (P₁/V₁)r = P₂/T₂
⇒ ( 14.7 / 540 )10.6 = P₂/1340
P₂ = 386.664 psia
process 2 - 3; constant volume heat addition;
Now, At T₃ = 3600°R, u₃ = 721.44 BTU/lbm, u[tex]_r[/tex]₃ = 0.6449
so, [tex]q_{in[/tex] = u₃ - u₂
we substitute
so, [tex]q_{in[/tex] = 721.44 - 235 = 486.44 BTU/lbm
Next, process 3 - 4; Isentropic
u[tex]_r[/tex]₄/u[tex]_r[/tex]₃ = V₄/V₃ = r
u[tex]_r[/tex]₄ / 0.6449 = 10.6
u[tex]_r[/tex]₄ = 6.8359
At u[tex]_r[/tex]₄ = 6.8359; u₄ = 308 BTU/lbm
∴
Heat Rejection [tex]q_{out[/tex] = u₄ - u₁ = 308 - 92.04 = 215.96 BTU/lbm
so, [tex]W_{net[/tex] = [tex]q_{in[/tex] - [tex]q_{out[/tex]
[tex]W_{net[/tex] = 486.44 - 215.96
[tex]W_{net[/tex] = 270.48 BTU/lbm
so the efficiency; η[tex]_{thermal[/tex] = ([tex]W_{net[/tex] / [tex]q_{in[/tex] ) × 100%
η[tex]_{thermal[/tex] = ( 270.48 / 486.44 ) × 100%
η[tex]_{thermal[/tex] = ( 0.55604 ) × 100%
η[tex]_{thermal[/tex] = 55.6%
Therefore, The efficiency of the engine is 55.6%
Can someone please help me
Answer: 120cm squared
Step-by-step explanation: To do this you can cut off one of the 'triangle ends' on the trapezoid and add it to the other side to make a rectangle. Since the top is 10cm, each triangle will have a base of 5cm, so the bases will be 15cm when you subtract 20-5. Then you just have 8 * 15 which is 120cm SQUARED. This may have been a little confusing so i attachecd a diagram.
Given a polynomial f(x), if (x + 7) is a factor, what else must be true
Answer:
Step-by-step explanation:
at x = -7, the polynomail function f(x) has a zero (x-intercept)
Define the following terms using your own words. (2-3 sentences only)
1. Frequency
2 Class size
3. Ogive
4. Variance
5. Range
Answer:
Frequency: the rate at which something occurs over a particular period of time or in a given sample.Class size :Class size is the average number of students per class, calculated by dividing the number of students enrolled by the number of classes..O give :Ogive is the curve which is constructed by plotting cumulative frequency data on the graph paper, in the form of a smooth curve.Variance: The term variance refers to a statistical measurement of the spread between numbers in a data set. Range: The range, the difference between the largest value and the smallest value.Which of the following points are solutions to the equation 3x - 4y - 8 = 12?
Select all that apply.
(0-5)
(82)
(-16-17)
(-1,-8)
(-40,-34)
Sorry I did it wrong.
Answer:
(0, -5) and (-16, -17)
Step-by-step explanation:
You can plug in the points into the function to test them.
(0, -5)
3(0) - 4(-5) - 8 = 12
20 - 8 = 12
12 = 12
(8, 2)
3(8) - 4(2) - 8 = 12
24 - 8 - 8 = 12
8 ≠ 12
(-16, -17)
3(-16) - 4(-17) - 8 = 12
-48 + 68 - 8 = 12
12 = 12
3(-1) - 4(-8) - 8 = 12
-3 + 32 - 8 = 12
21 ≠ 12
3(-40) - 4(-34) - 8 = 12
-120 + 136 - 8 = 12
8 ≠ 12
(4x-1)2=11
whats the solution
Answer:
x = 13/8
Step-by-step explanation:
(4x−1)(2)=11
Simplify both sides of the equation.
(4x−1)(2)=11
(4x)(2)+(−1)(2)=11 (Distribute)
8x+−2=118x+−2=11
8x−2=11
Add 2 to both sides.
8x−2+2=11+2
8x=13
Divide both sides by 8.
8x/8 = 13/8
which brings you to the answer of
x = 13/8
(Note:If this was a little confusing,feel free to ask me any questions revolving around this topic)
Can someone help me with this question plz show work.
Answer:
d
Step-by-step explanation:
V=whl=3·4·6=72
D. 6*4*6≠72
Answer:
D 6x6x4
Step-by-step explanation:
the dimensions are 3x6x4 so 6x6x4 is not the volume of this rectangular prism
A store pay $120 for a bicycle. The store has a 60% markup policy. What is the selling price of the bicycle?
Answer:
$192
Step-by-step explanation:
A piecewise function is given.
Find f(-4)
Answer:
3
Step-by-step explanation:
For x<=0, f is constant: f(x) =3
-4<0, so f(-4)=3
Does anybody know the answer to this question
Answer:
A
Step-by-step explanation:
What are some of the applications for exponential functions?
Designing identification tags
Conversion of measurements
Assigning phone numbers
Finding perimeter
Determining the number of subsets in a given set
Answer:
Option B and D are correct
Step-by-step explanation:
Exponential functions are really useful in the real world situation. They can be used to solve following
a) Population Models
b) Determination of area and perimeters
c) Determine time related things such as half life, time of happening of an event etc.
d) Useful for solving financial problems such as computing investments etc.
Hence, option B and D
Abigail ordered a 32 oz steak that cost $60.
(cost to weight)
A tour helicopter travels at a constant rate of 80 mph. If the tour takes 2 hours, how far does the helicopter travel?
A. 40 mi.
B. 80 mi.
C. 120 mi.
D. 160 mi.
Answer:
D
Step-by-step explanation:
80 miles per hour, each hour it will travel 80 miles so for two hours tou do
80 x 2 = 160
Answer:
D
Step-by-step explanation:
80x2=40
it's just simple multiplecation but then again I cant spell multiplication so I mean
what is the midpoint of a segment with endpoints at (-4,-8) and (8,10)
Answer: Midpoint: (2, 1)
Step-by-step explanation:
Midpoint formula: ((x1 + x2)/2 , (y1 + y2)/2)
(-4 + 8)/2 = 2
(-8 + 10)/2 = 1
Answer: (2, 1)
