Make a conjecture about the diagram below. Is AC greater than, less than, or equal to BC? Explain your reasoning.

Answer:

a) 4 packages

b) 7000 g or 7 kg

Step-by-step explanation:

x is the number of 250g packages and y is the number of 750g packages.

2x = y

3(x + 2 x (750 : 250)) = 5(y - 2)

3(x + 6) = 5(y - 2)

3(x + 6) = 5(2x - 2)

3(x + 6) = 5(2(x - 1))

3(x + 6) = 5 * 2 * (x - 1)

3(x + 6) = 10(x - 1)

3x + 18 = 10x - 10

(3x + 18) + 10 = (10x - 10) + 10

3x + 28 = 10x

28 = 10x - 3x

28 = 7x

x = 28/7

x = 4

y = 2 * 4 = 8

(250 * 4) + (750 * 8) = 7000 g

Answer: [tex]\frac{4}{3}[/tex]

Step-by-step explanation:

tangent of ∠PLM = [tex]\frac{opposite}{adjacent} =\frac{4}{3}[/tex]

Answer:

PLM=4/3

Step-by-step explanation:

Answer:

E. 248

Step-by-step explanation:

1 to 500 in set A, 250 to 750 in set B

500 - 250 = 250

100 and 200 are divisible by 100.

250 - 2 = 248

Step-by-step explanation:

Hello!

In order to graph this, a point would have to go through (-6, 1). Then, since it says it needs a slope of 5 (or, to make things a bit easer, we could see it as 5/1) we'd need the next point to be 5 up and 1 across.

One possible solution:

(-6, 1) -> (-5, 6)

Answer:

23

Step-by-step explanation:

[tex]2 y + 7[/tex]

Replace y with 8

[tex]= 2 (8) + 7\\= 16+ 7\\= 23[/tex]

Therefore, the value of the expression when y=8 is 23.

I hope this helps!

Answer: D

Step-by-step explanation:

[tex]a=0,\ b=0,\ k=2\\equation\ of\ the\ parabola:\\\\y=\dfrac{(x-a)^2}{2(b-k)} +\dfrac{b+k}{2} \\\\\\y=-\dfrac{x^2}{4}+1 \\\\x^2=-4(y-1)\\\\Answer\ D[/tex]

Answer:

So, we need to find irrational numbers between the given pairs.

Remember that the sum between an irrational number and an rational number is irrational.

For example, for the first case, we want a irrational number between:

3.14 and pi:

pi = 3.14159265.... is irrational

pi - 0.0001 = 3.14159265... - 0.0001 = 3.14149265...

So this number:

3.14149265...

is an irrational number larger than 3.14 and smaller than pi.

Second cacse:

3.33 and 1/3

(here the range would be actually:

1/3 = 0.33 and 3.33

So we want an irrational number larger tan 0.33 and smaller than 3.33

here we can just use pi = 3.141592...

third case:

e^2 and √5

Firs let's write these numbers so we can see how they look.

e^2  =7.389...

√5 = 2.236

So we want a number larger than 2.236... and smaller than 7.389...

Again, here we can use pi = 3.141592...

2.236... < 3.141592... < 7.389...

final case:

√(64/2) and √16

we have:

√(64/2) = 5.65

√16 = 4

So we want an irrational number larger than 4 and smaller than 5.65

Again, let's use our beloved number pi.

we have that:

pi + 1  is an irrational number:

pi + 1 = 3.14159265... + 1.0 = 4.14159265....

This number, 4.14159265..., is irrational, is larger than 4 and is smaller than 5.65, so we found the irrational number between the given pair of numbers.

Answer:

3.33 and 1/3

Step-by-step explanation:

Answer:

Hello,

Step-by-step explanation:

slope of the line=3/7

slope of the perpendicular = -7/3

equation of the perpendicular:

y-3=(x-3)*(-7/3)

or

y=-7/3*x +7+3

or

y=-7/3*x+10

===========================================

Explanation:

The two equations given to us are

Divide the second equation over the first equation and that would lead to b = 6

Notice how the 'a' terms divide to 1 and go away, i.e. cancel out.

The b terms divide to (b^2)/b = b

The right hand side values divide to 18/3 = 6

So that's how we end up with b = 6

-------------------------

Now if b = 6, then we can say,

ab = 3

a*6 = 3

a = 3/6

a = 1/2

Or we could say

ab^2 = 18

a*6^2 = 18

a*36 = 18

a = 18/36

a = 1/2

3rd step

Solution:-

[tex]\\ \sf\longmapsto -2x+8-3x=7[/tex]

[tex]\\ \sf\longmapsto -2x-3x+8=7[/tex]

[tex]\\ \sf\longmapsto -5x+8=7[/tex]

[tex]\\ \sf\longmapsto -5x=7-8[/tex]

[tex]\\ \sf\longmapsto -5x=-1[/tex]

[tex]\\ \sf\longmapsto x=\dfrac{-1}{-5}[/tex]

[tex]\\ \sf\longmapsto x=\dfrac{1}{5}[/tex]

Answer:

Hello,

answer:  -2 < k < 8

Step-by-step explanation:

As there are 2 roots: Δ>0

As there is a mininum, k-6 <0 ==> k<6,

minimum :y'=0 ==> (k-6)*2x-8=0 ==> x=4/(k-6)

[tex]\Delta=8^2-4*k*(k-6)\\=64-4k^2+24k\\=-4(k^2-6k+9)+36+64\\=100-4(k-3)^2\\=4(8-k)(k+2)\\\\\Delta\ is\ positive\ for\ -2 < k < 8[/tex]

Answer:

25

Step-by-step explanation:

f(5)=5(5-1)+5

f(5)=5(4)+5

f(5)=20+5

f(5)=25

Answer:

f(5) = 24

Step-by-step explanation:

f(1) = 4

f(n) = f(n − 1) + 5

Let n = 2

f(2) = f(2 − 1) + 5 = 4+5 = 9

Let n = 3

f(3) = f(3 − 1) + 5 = f(2)+5 = 9+5 = 14

Let n = 4

f(4) = f(4 − 1) + 5 = f(3)+5 = 14+5 = 19

Let n = 5

f(5) = f(5 − 1) + 5 = f(4)+5 = 19+5 = 24

Answer:

x + y = -5

Step-by-step explanation:

2x - x - y + 2y = -1 - 4

x + y = -5

Solution:-10

As <AGQ and <EQG are corresponding interior angles

[tex]\\ \qquad\quad\sf{:}\twoheadrightarrow 60°+a=180[/tex]

[tex]\\ \qquad\quad\sf{:}\twoheadrightarrow a=180-60[/tex]

[tex]\\ \qquad\quad\boxed{\sf{:}\twoheadrightarrow a=120}[/tex]

[tex]\\ \qquad\quad\boxed{\sf{:}\twoheadrightarrow b=75°}[/tex]

According to angle sum property

[tex]\\ \qquad\quad\sf{:}\twoheadrightarrow b+c+<PQR=180[/tex]

[tex]\\ \qquad\quad\sf{:}\twoheadrightarrow c+75+60=180[/tex]

[tex]\\ \qquad\quad\sf{:}\twoheadrightarrow c+135=180[/tex]

[tex]\\ \qquad\quad\sf{:}\twoheadrightarrow c=180-135[/tex]

[tex]\\ \qquad\quad\boxed{\sf{:}\twoheadrightarrow c=45°}[/tex]

Answer: 5.5

Step-by-step explanation: It is basically already solved the only thing I did was isolate x by itself my moving the 2 over and doing 11 divided by 2 which equals 5.5. This means that x equals 5.5

y - 1/z = 1   ==>   y = 1 + 1/z

z - 1/x = 1   ==>   z = 1 + 1/x

==>   y = 1 + 1/(1 + 1/x) = 1 + x/(x + 1) = (2x + 1)/(x + 1)

x - 1/y = x - (x + 1)/(2x + 1) = (2x ² - 1)/(2x + 1) = 1

==>   2x ² - 1 = 2x + 1

==>   2x ² - 2x - 2 = 0

==>   x ² - x - 1 = 0

==>   x = (1 ± √5)/2

If you start solving for z, then for x, then for y, you would get the same equation as above (with y in place of x), and the same thing happens if you solve for x, then y, then z. So it turns out that x = y = z.

Step-by-step explanation:

sin and tan are the only ones with p positive valued

Here we want to find the expressions we need to use to see if the functions g(x) and h(x) are inverses of each other.

The correct option is the last one, counting from the top.

∛((x + 72)^3) - 72  and -(∛(-x) - 72 + 72)^3

Two functions f(x) and g(x) are inverses if:

f( g(x) ) = x

g( f(x) ) = x

In this case, we have the functions:

g(x) = ∛(-x) - 72

h(x) =  -(x + 72)^3

Then the expressions we need to check are:

g( h(x) ) = ∛(-h(x)) - 72 = ∛(+(x + 72)^3) - 72 = (x + 72) - 72 = x

h( g(x) ) = -(g(x) + 72)^3 = -(∛(-x) - 72 + 72)^3 = -(∛(-x) )^3 = x

So we found that the two expressions needed are:

∛((x + 72)^3) - 72  and -(∛(-x) - 72 + 72)^3

Then the correct option is the last one, counting from the top.

If you want to learn more, you can read:

https://brainly.com/question/10300045

Answer:

GUYS ITS C THAT IS THE ANSWER

Answer:

hope it helps

Step-by-step explanation:

Answer:

SEE THE IMAGE FOR SOLUTION..

Answer:

a =b = [tex]\frac{5\sqrt{5} }{5}[/tex]

Step-by-step explanation:

[tex]a^{2} +b^{2} = 5 ^{2}[/tex]

a = b

[tex]2a^{2} = 5 ^{2}[/tex]

[tex]2a^{2} = 25\\[/tex]

[tex]a^{2} = \frac{25}{5}[/tex]

a = [tex]\frac{5}{\sqrt{5} }[/tex]

must rationalize...

a =b = [tex]\frac{5\sqrt{5} }{5}[/tex]

Answer: 22,200 words per hour.

Step-by-step explanation:

You can set up a proportion for this: 370 words/per 1 min= x words/ per 60 mins. Cross multiply and you get 22,200=1x which basically equals to 22,200 words per hour or 60 mins.

Answer:

A' (0,20)

B' (30,-20)

C' (-10,-40)

Answered by GAUTHMATH

Answer:

Brainliestgive o020201000

The sum of the interior angles in a triangle is 180 degrees.

72 + 35 + <1 = 180

107 + <1 = 180

<1 = 73 degrees

Hope this helps!

Answer:

<1 = 73

Step-by-step explanation:

The sum of the angles of a triangle is 180 degrees

72+ 35+ <1 = 180

Combine like terms

107 + <1 =180

Subtract 107 from each side

<1 = 180-107

<1 = 73

Answer:

-6 and - 65

Step-by-step explanation:

X-12x-29, by completing the square we get (x-6)^2-65