Answer:
[tex]UCL = 0.078[/tex]
[tex]LCL = 0[/tex]
Step-by-step explanation:
Poorly formatted question (see attachment)
From the attachment, we have:
[tex]n = 135[/tex] --- the sample size
[tex]Samples = 20[/tex] --- The number of samples
[tex]\sum np = 87[/tex] --- Number of leaking tubes
First, we calculate the number of observations
[tex]\sum n = n * Samples[/tex]
[tex]\sum n= 135 * 20[/tex]
[tex]\sum n= 2700[/tex]
Using 3 sigma control limit, we have:
[tex]z = 3[/tex]
Calculate [tex]\bar p[/tex]
[tex]\bar p = \frac{\sum np}{\sum n}[/tex]
So, we have:
[tex]\bar p = \frac{87}{2700}[/tex]
[tex]\bar p = 0.0322[/tex]
Next, calculate the standard deviation
[tex]s_p = \sqrt{\frac{\bar p* (1-\bar p)}{n}}[/tex]
So, we have:
[tex]s_p = \sqrt{\frac{0.0322* (1-0.0322)}{135}}[/tex]
[tex]s_p = \sqrt{\frac{0.03116}{135}}[/tex]
[tex]s_p = \sqrt{0.0002308}[/tex]
[tex]s_p = 0.0152[/tex]
The control limits is then calculated as:
[tex]UCL = \bar p + z * s_p[/tex] --- upper control limit
[tex]LCL = \bar p - z * s_p[/tex] --- lower control limits
So, we have:
[tex]UCL = \bar p + z * s_p[/tex]
[tex]UCL = 0.0322 +3 * 0.0152[/tex]
[tex]UCL = 0.078[/tex]
[tex]LCL = \bar p - z * s_p[/tex]
[tex]LCL = 0.0322 - 3 * 0.0152[/tex]
[tex]LCL = -0.013[/tex]
Since the calculated LCL is less than 0, we simply set it to 0
[tex]LCL = 0[/tex]
So, the p chart control limits are:
[tex]UCL = 0.078[/tex]
[tex]LCL = 0[/tex]
If 8 x - 4 = 6 - 3 x then x =
Answer:
x = 10/11
Step-by-step explanation:
Your welcome! :)
In the diagram, Find the value of w
Answer:
-13
Step-by-step explanation:
the angle of ACD is 180-72 = 108 degrees.
simply because every side of a line represents 180 degrees of turning potential (to flip something around on a flat ground is a 180 degree turn). and we know 72 degrees are already "taken" at the other side of the angle.
BC bisects the angle. that means it divided the angle into 2 equal parts.
so the angle between BC and k is 108/2 = 54 degrees.
because j is parallel to k, this angle is the same as the angle between BC and j.
so,
54 = 2w + 80
-26 = 2w
w = -13
NO LINKS OR ELSE YOU'LL BE REPORTED! Only answer if you're very good at Math.No guessing please.
Keisha's teacher gives her the following information:
• m,n,p,and q are all integers and p= 0 and q=0
•A= m/q and B= n/p
What conclusion can Keisha make?
A: A +B = mp+nq/PQ,so the sum of a rational number and an irrational number is an irrational number.
B: A•B= mp+nq/PQ,so the product of two irrational numbers is an irrational number.
C: A+B= mp + nq/PQ,so the sum of two rational numbers is a rational number.
D: A•B= mp + nq/PQ,so the product of two rational numbers is a rational number.
Answer:
C.
Step-by-step explanation:
Integers are rational numbers.
A + B = m/q + n/p = (mp + nq)/pq
Find the measurement of the numbered angles
Answer:
m<1 = 60
m<2 = 30
m<3 = 80
Step-by-step explanation:
1. Solve for angle (1)
The sum of angles in any triangle is (180) degrees. As one can see, there is a (30) degree angle in this triangle, and a (90) degree angle. Bear in mind that the box around an angle indicates that it is a (90) degree angle. One can form an equation and solve for the unknown angle using this given information;
(30) + (m<1) + (90) = 180
Simplify,
120 + m<1 = 180
Inverse operations,
m<1 = 60
2. Solve for angle (2)
The vertical angles theorem states that when two lines intersect, the angles opposite each other are congruent. One can apply this theorem here by stating the following,
m<2 = 30
Thus one gets their answer, the measure of angle (2) must be (30) degrees by the vertical angles theorem.
3. Solve for angle (3)
As states above, the sum of angles in a triangle is (180) degrees. Since one has found the measure of angle (2), one can form an equation and solve for the measure of angle (3) using the given information, combined with the information found.
(m<2) + (70) + (m<3) = 180
Susbtitute,
30 + 70 + (m<3) = 180
Simplify,
100 + m<3 = 180
Invers eoperations,
m<3 = 80
Please awnser
Please help
Answer:
I believe the answer would be 11/30 longer but you might want to simplify it
Do they take your phones and watch you take the cumulative test on edginuity?
Answer:
I don't know what your school is doing but what happened to me was that I just waited for the test to be unlocked and I was working from home so I was able to keep my phone and I didn't need to be in a meeting
Los principales accionistas de la empresa global zafiro S.A. están interesado en una empresa que representa una importante competencia. Entre los datos de la empresa tiene los siguientes: la planta opera a nivel que oscila entre 80 y 100% de su capacidad. Cuando su nivel de actividad es de 80% los costos variables de fabricación totalizan $180,000,000. A su nivel normal de 90% de la empresa utiliza 40,500 horas de mano de obra directa y tiene costos de fabricación totales de $371,500,000. Determina los costos de fabricación finos y variables al 80 y 100% de su capacidad
Answer:
Los costos de fabricación fijo y variables al 80 y 100% de su capacidad son:
80%: Fijos = $169,000,000.00 Variables = $180,000,000.00
100%: Fijos = $169,000,000.00 Variables = $225,000,000.00
Explicación:
Los costos totales de fabricación (CT) vienen dados por la suma de los costos fijos (CF) y los costos variables (CV), recordando que los costos fijos son aquellos en los que se incurre independientemente de que se esté operando o no; mientras que los costos variables son aquellos que dependen del nivel de actividad pues corresponden a consumibles en el proceso productivo.
En el caso estudio, se sabe que los costos variables de fabricación totalizan $180,000,000.00 al nivel de actividad de 80%. Ya que estos costos incrementan o disminuyen en relación con el nivel de actividad, planteamos una regla de tres simple para calcular los costos variables en los niveles de actividad 90% y 100%
Si al 80% de actividad ---------------- los CV son $180,000,000.00
al 90% de actividad ---------------- los CV serán x
x = [(90)(180,000,000.00)]/(80) = 202,500,000.00
Los costos variables de fabricación al nivel de actividad de 90% son $202,500,000.00
Si al 80% de actividad ---------------- los CV son $180,000,000.00
al 100% de actividad ---------------- los CV serán x
x = [(100)(180,000,000.00)]/(80) = 225,000,000.00
Los costos variables de fabricación al nivel de actividad de 100% son $225,000,000.00
Para conocer los costos fijos basta recordar que al nivel de actividad de 90% lo costos de fabricación totales son $371,500,000.00. Este monto es la suma de los costos fijos y los costos variables; así que:
CT = CV + CF ⇒ CV = CT - CF ⇒
CV = 371,500,000.00 - 202,500,000.00 = 169,000,000.00
Los costos fijos de fabricación son de $169,000,000.00
Conclusión:
Los costos de fabricación fijo y variables al 80 y 100% de su capacidad son:
80%: Fijos = $169,000,000.00 Variables = $180,000,000.00
100%: Fijos = $169,000,000.00 Variables = $225,000,000.00
A puppy named Dusty started out at 2 pounds and gained 1 pound every month. At
how many months did Dusty weigh 6 pounds?
Answer:
4 months
Step-by-step explanation:
Let x be the number of months
Dusty started at 2 lbs, and gains 1 lb every month
So we can make the equation
2+x=6
x=4
At 4 months, Dusty was 6 lbs
The following are the Pulse Rates of the 12 students in a Math Class
76 60 59 60
81 72 91 80
80 68 73 77
If we create Classes for a relative frequency distribution.
For the Class 50-59 , find the frequency
Answer:
1
Step-by-step explanation:
Given the pulse rate for 12 students :
76 60 59 60 81 72 91 80 80 68 73 77
Creating class intervals ::
Width = 10
59, 60, 60, 68, 72, 73, 76, 77, 80, 80, 81, 91
Interval ____ Frequency
50 - 59 ______ 1
60 - 69 ______ 3
70 - 79 ______ 4
80 - 89 ______ 3
90 - 99 ______ 1
Frequebcy if the 50 - 59 class interval is 1
what is the derivative of y=(x^2√(1+x))/((1+x^2)^3/2))
Step-by-step explanation:
Maple calculator used.........................
Answer:
Step-by-step explanation:
[tex]f(x)={x^2\sqrt{1+x}\over{(1+x^2)^{3\over{2}}}}\\\\f^\prime (x)=\frac{{{(x^2\sqrt{1+x})^\prime (1+x^2)^{\frac{3}{2}}+ (x^2\sqrt{1+x})}((1+x^2)^{\frac{3}{2}}})^\prime}{((1+x^2)^\frac{3}{2})^2}}}[/tex]
[tex](x^2 \sqrt{1+x})^\prime=2x\sqrt{1+x}+ \frac{x^2}{2\sqrt{1+x}}[/tex]
[tex]((1+x^2)^{\frac{3}{2}})^\prime=\frac{3}{2}(1+x^2)^{\frac{1}{2}} (2x)=3x(1+x^2)^{\frac{1}{2}}[/tex]
[tex]f^\prime(x)=\frac{\{(1+x^2)^{\frac{3}{2}}\}(2x\sqrt{1+x}+\frac{x^2}{2\sqrt{1+x}})+(x^2 \sqrt{1+x})(3x\sqrt{1+x^2})}{(1+x^2)^{3}}}[/tex]
[tex]\sqrt{1+x^2}=\sqrt{(1+x)(1-x)}[/tex]
[tex]f^\prime (x)=x\sqrt{1+x}~\frac{(1+x^2)^{\frac{3}{2}}(2+\frac{x^2}{2(1+x)})+3x^2\sqrt{1-x}}{(1+x^2)^3}[/tex]
x^ 3 + 3 x ^ 2 - 9 x - 27 draw the graph of the first derivative and the second derivative on the same set
Answer:
The graph is in the second attached image.
Step-by-step explanation:
In the first attached image, you have three equation graphed, the first is in red color, it's the original equation:
x^3 + 3x^2 - 9x - 27I graphed this to obtain a clear relation between the equation and its derivatives, the second graphed equation is in blue color and it's the first derivative:
First derivative = 3x^2 + 6x - 9 (It's a parabola)And at last, we have in green color the second derivative:
Second derivative = 6x + 6 (It's a line)As you can see, you only need the first and the second derivatives in the exercise, by this reason, in the second attached image you have the graph as you need to show in this exercise.
calculate 5/10÷9 please
Answer:
1/2 times 1/9
which equals 1/18
Step-by-step explanation:
5/10 equals 1/2 and /9 equals *1/9
Answer: i think its 1/9
PLEASE ANSWER ASAP FOR BRAINLEST!!!!!!!!!!!!!!!!!!!!!!!!!!!!
Answer:
I say number 2 idrk so I hope I helped >-<
Find the Value of X (in this picture)
9514 1404 393
Answer:
x = 64
Step-by-step explanation:
The two base angles in the isosceles obtuse triangle are equal, so are both 29°. The sum of these angles is 58°, which is the measure of the external acute angle at the upper left of the acute triangle.
The two base angles of the acute isosceles triangle are equal, so are both 58°. The angle marked x° has a measure that makes the sum of angles in that triangle be 180°.
x° = 180° -2(58°)
x° = 64°
Question 6. * The number of likes a social media post has generated has been tracked as a function of the number of min since it was posted. The data is shown in the table below, where t is the number of minutes and I is the number of likes. If an exponential model was used to fit this data, which of the following would be closest to its prediction for the number of likes after one hour
Answer:
Step-by-step explanation:
yes
Graph the image of rectangle BCDE after a translation 8 units left and 5 units up.
3. Find the value of:
a) 9²
b) 15²
c) (0.2)²
d) (0.7)
Answer:
Step-by-step explanation:
9^2
=9*9
=81
15^2
=15*15
=225
(0.2)^2
=0.2 * 0.2
=0.04
(0.7)
=0.7
Please help solve this using L.C.M and explain the steps plz ty.
9514 1404 393
Answer:
(x, y) = (2, 3)
Step-by-step explanation:
The first step is to find the least common multiple of the denominators of each of the equations. If the denominators have no common factors, a reasonable choice is their product. Here, it works to start with the fractions that must be added, then compare the LCM found to the denominator on the right to see if any further factors must be included.
First equation:
LCM = 3×4 = 12
12(2x/3 -y/4) = 12(7/12) . . . . . multiply the equation by 12
8x -3y = 7 . . . . . . . . . simplify
Second equation:
LCM = 4×5 =20
20(3x/4 -2y/5) = 20(3/10) . . . . multiply equation by 20
15x -8y = 6 . . . . . . simplify
Solve by elimination
We can eliminate the y-variable by subtracting 3 times the second equation from 8 times the first:
8(8x -3y) -3(15x -8y) = 8(7) -3(6)
19x = 38 . . . . . simplify
x = 2 . . . . . . . divide by 19
Substituting into the first equation gives ...
8(2) -3y = 7
3y = 9 . . . . . . add 3y-7
y = 3 . . . . . divide by 3
The solution is ...
(x, y) = (2, 3)
_____
There are many ways to solve such a system of equations. Using the LCM to eliminate fractions is one way to start. You can also do the arithmetic with the fractions intact, though most folks don't care to. In addition to the elimination method used here, you can use matrix or graphical methods, substitution, or any of the variations of Cramer's Rule.
Which angle is an obtuse angle?
A. 310°
B. 80°
O c. 260°
O D. 170°
Step-by-step explanation:
obtuse angle is an angle whose measure is more than 90 degree but less than 180 degree..
So,
170°
Which statements are correct? Check all that apply.
Answer:
E is the subset of I
S is the subset of T
R ⊂ P
Step-by-step explanation:
Which of the following are true statements using the Associative Property of Multiplication?
(a – b) – c = a – (b – c)
a(b + c) = ab + ac
a(bc) = (ab)c
(a + b) + c = c + (a + b)
9514 1404 393
Answer:
a(bc) = (ab)c
Step-by-step explanation:
The associative property of multiplication says the product is the same regardless of how the factors are grouped. That is demonstrated by the equality ...
a(bc) = (ab)c
Solve this equation 2n-9<25
Answer:
n < 17
Step-by-step explanation:
2n-9<25
Add 9 to each side
2n-9+9<25+9
2n < 34
Divide each side by 2
2n/2 < 34/2
n < 17
Answer:
n < 17
Step-by-step explanation:
Move the constant to the right -hand side and change its sign
2n<25+9
Then add the numbers
2n < 34
Divide both sides of the inequality by 2
so that would be n<17
Find the value of the polynomial 3x
3 – 4x
2+ 7x + 5, when x = 3 and also when
x = –3.
Answer:
71
-133
Step-by-step explanation:
Given the polynomial :
3x³– 4x² + 7x + 5, when x = 3 and also when
x = –3.
Put x = 3
3(3)³– 4(3)² + 7(3) + 5
3(27) - 4(9) + 21 + 5
81 - 36 + 21 + 5
= 71
Put x = - 3
3(-3)³– 4(-3)² + 7(-3) + 5
3(-27) - 4(9) - 21 + 5
-81 - 36 - 21 + 5
= - 133
Mathematical Literacy Assignment no 2021
Find the simple interest on a loan of ₱65,000.00 if the loan is given at a rate of 2% and is
due in 5 years and 3 months?
Answer:
6,825
Step-by-step explanation:
The principlal is #65,000
Rate, = 2%
= 2/100
= 0.02
Time= 5+0.25
= 5.25
Simple interest= 65,000×0.02×5.25
= 6,825
Please help don't get it.
Answer:
Part A: B is the answer since if you move the triangle they would be differently rotated
Part B: the answer is C since if you translate both over the y-axis and then the x-axis you will get the other pair
the product of -3 and m increased by 7 is -20. what is the value of m?
Answer:
The value of m is 9.
Step-by-step explanation:
We need to set up an algebraic equation, then solve.
(-3 * m) + 7 = -20
-3m + 7 = -20
Subtract 7 from both sides so we can get -3m by itself. We are isolating it.
-3m + 7 - 7 = -20 - 7
-3m = -27
Divide by -3 on both sides.
m = 9
The value of m is 9.
QUESTION AT THE BOTTOM MAKE SURE YOU KNOW THE ANSWER FIRST PLAESE
Answer:
V=πr2h /3
so we just substate and we get
V≈130.9
Answer: 130.83 units cubed
Step-by-step explanation:
The formula for finding the volume of a cone is [tex]\pi r^2\frac{h}{3}[/tex]
We will use 3.14 for pi.
[tex]3.14r^2\frac{h}{3}[/tex]
Now let's sub in our variables and solve
[tex]3.14(5^2)(\frac{5}{3})\\3.14(25)(\frac{5}{3})\\78.5(\frac{5}{3})\\130 \frac{5}{6}[/tex]
5/6 is about .83
130.83
3.(8 points)Consider the following experiment:Experiment: A bag contains 3 red balls, 4 blue balls, 4 green balls and 3yellow balls. Two balls are drawn from the bag without replacing the ballafter the first draw.(a)(2 points)Specify the sample space (set of outcomes) and probability distributionof the outcomes.(b)(3 points)If you draw two balls from the bag without replacing them, what isthe probability of drawing two red balls
Answer:
3 / 91
Step-by-step explanation:
Given :
Red balls = 3
Blue balls = 4
Green balls = 4
Yellow balls = 3
Total number of balls = (3+4+4+3) = 14
Sample space :
RR, BB, GG, YY, RB, BR, BG, GB, YG, GY, YR, RY, BY, YB, GR, RG
Probability of drawing two red balls without replacement :
1st draw :
P(red) = number of red balls / total number of balls
P(red) = 3/14
2nd draw :
P(red) = 2 / 13
Hence,
P(RR) = 3/14 * 2/13 = 6 / 182 = 3 / 91
Russell deposited $200 to open a new bank account before he paid $250 for his portion of the rent. His bank charged him a $50 overdraft fee. Then he deposited his paycheck of $400. How much money is in Russell’s account now?
The answers isssssssss
$300
:)