Answer:
what is the question? If the question is how much time Lydia practiced, then the answer would be 75 x 76% = 57 minutes
there are red blue and green ribbon on the tabel.there are a total of 36 ribbon.3/6 of the ribbon is red.how manny ribbon is red
Answer:
18
Step-by-step explanation:
3/6 =1/2
1/2 of 36 is 18
What is the value of x+y in this question and what’s the equation?
Answer:
Step-by-step explanation:x
Assignment
and graphs.
Which of the following properly describe "slope"? Select all that apply.
✓x
y2yi
x₂-x
x₂-x
2 -->
run / rise
rise / run
ratio of the change in y-values (rise) for a segment of the graph to the corresponding change in x-values (run)
Tutori
M
Answer:
the first option is for sureee
Help me plz i wanna make an an A
Write down an example to show that each of the following two siatements is not correct
a) The factors of an even number are always even
Answer:
a) 2 * 3 = 6.
b) 123 is odd but contains an even digit (2).
Step-by-step explanation:
In a certain chemical, the ratio of zinc to copper is 3 to 14. A jar of the chemical contains 630 grams of copper. How many grams of zinc does it contain?
Answer:
135 grams of Zinc
Step-by-step explanation:
zinc:copper
3:14
3/14=x/630
x=135
The corner section of a football stadium has 6 seats on the first row. Each row after that has an additional 3 seats. How many seats would be on the 20th row?
32
63
103
342
9514 1404 393
Answer:
63
Step-by-step explanation:
The number of seats in a row will give an arithmetic sequence:
6, 9, 12, 15, ...
The first term is 6; the common difference is 3. The general term is ...
an = a1 +d(n -1) . . . . . . n-th term of sequence with first term a1, difference d
The 20th term of the sequence is ...
a20 = 6 +3(20 -1) = 6 +57 = 63
There would be 63 seats on the 20th row.
3. A gym charges a fee of $15 per month plus an additional charge for every group class
attended. The total monthly gym cost T can be represented by this equation: T = 15+c*n,
where c is the additional charge for a group class, and n is the number of group classes
attended
Which equation can be used to find the number of group classes a customer attended if we
know c and T?
a. n = I - 15
N
b. n=1 – 150
c. n = (T - 15) - C.
(T-15)
d. n=
1
Answer:
Option D) [tex]\huge\sf{n\:=\:\frac{(T\:-\:15)}{c}}[/tex]
Step-by-step explanation:
Given the equation, T = 15 + c × n, where:
T = represents the total monthly gym cost
c = represents the additional charge for a group class, and
n = represents the number of group classes attended
Solution:In order to determine which equation can be used to find the number of group classes a customer attended, if there are given values for c and T, we must isolate the variable, n algebraically.
The first step is to subtract 15 from both sides:
T = 15 + c × n
T - 15 = 15 - 15 + c × n
T - 15 = c × n
Next, divide both sides by c to isolate n :
[tex]\huge\mathsf{\frac{({T\:-\:15})}{c}\:=\:\frac{{c\:\times\:n}}{c}}[/tex]
[tex]\huge\sf{n\:=\:\frac{(T\:-\:15)}{c}}[/tex]
Therefore, the correct answer is Option D) [tex]\huge\sf{n\:=\:\frac{(T\:-\:15)}{c}}[/tex].
Is 7164 divisible by 6?
yes?
no?
Answer:
yes
7164 is divisible bt 6
Answer:
Yes
Step-by-step explanation:
Any number will be divisible by 6 if they be divisible by 2 & 3
- we know 7164 is divisible by 2
- also any number which sum of their digits are divisible by 3, the number will be divisible by 3
in this case (7164) 7+1+6+4=18 & 18 is divisible by 3 so 7164 is divisible by 3 as well.
so 7164 is divisible by 6
Pinky had 3 ¼ metre of red ribbon. She used 2 ½ metre of ribbon to wrap gifts. How much ribbon is left with her ?
3/4
9/4
2/4
Answer:
3/4
Step-by-step explanation:
simply divide 3 1\4‐2 1/2
question ;
Pinky had 3 ¼ metre of red ribbon. She 2 ½ used metre of ribbon to wrap gifts. How much ribbon is left with her ?
answer ;
meter of ribbon pinky had : 3 ¼ meter of ribbon used to wraped in gifts : 2 ½ step 1 : covert this into a proper fraction ; 13/4 , 5/2 step 2 : now take Lcm from the denominator ( picture ) so Lcm = 4 [tex] \frac{13 \times1 }{4 \times 1} = \frac{13}{4} [/tex][tex] \frac{5 \times 2}{2 \times 2} = \frac{10}{4} [/tex]now add them ; 13/4 + 10/4 = 23/43/4 is your answer24. A triangle has side lengths of 6, 8, and 9. What type of triangle is it?
acute
equiangular
obtuse
right
•
what is the percentage discount when a stereo is reduced from $258 to $199?
Please help ASAP! 15 points!
(27/8)^1/3×[243/32)^1/5÷(2/3)^2]
Simplify this question sir pleasehelpme
Step-by-step explanation:
[tex] = {( \frac{27}{8} )}^{ \frac{1}{3} } \times ( \frac{243}{32} )^{ \frac{1}{5} } \div {( \frac{2}{3} )}^{2} [/tex]
[tex] = { ({ (\frac{3}{2} )}^{3}) }^{ \frac{1}{3} } \times {( {( \frac{3}{2}) }^{5} )}^{ \frac{1}{5} } \div {( \frac{2}{3} )}^{2} [/tex]
[tex] = {( \frac{3}{2} )}^{3 \times \frac{1}{3} } \times {( \frac{3}{2} )}^{5 \times \frac{1}{5} } \times {( \frac{3}{2} )}^{2} [/tex]
[tex] = \frac{3}{2} \times \frac{3}{2} \times {( \frac{3}{2} )}^{2} [/tex]
[tex] = {( \frac{3}{2} )}^{1 + 1 + 2} [/tex]
[tex] = {( \frac{3}{2} )}^{4} \: or \: \frac{81}{16} [/tex]
[tex]\large\underline{\sf{Solution-}}[/tex]
[tex]\sf{\longmapsto{\bigg( \dfrac{27}{8} \bigg)^{\frac{1}{3}} \times \Bigg[\bigg( \dfrac{243}{32} \bigg)^{\frac{1}{5}} \div \bigg(\dfrac{2}{3} \bigg)^{2}\Bigg]}} \\[/tex]
We can write as :
27 = 3 × 3 × 3 = 3³
8 = 2 × 2 × 2 = 2³
243 = 3 × 3 × 3 × 3 × 3 = 3⁵
32 = 2 × 2 × 2 ×2 × 2 = 2⁵
[tex]\sf{\longmapsto{\bigg( \dfrac{3 \times 3 \times 3}{2 \times 2 \times 2} \bigg)^{\frac{1}{3}} \times \Bigg[\bigg( \dfrac{3 \times 3 \times 3 \times 3 \times 3}{2 \times 2 \times 2 \times 2 \times 2} \bigg)^{\frac{1}{5}} \div \bigg(\dfrac{2}{3} \bigg)^{2}\Bigg]}} \\[/tex]
[tex]\sf{\longmapsto{\bigg( \dfrac{{(3)}^{3}}{{(2)}^{3}} \bigg)^{\frac{1}{3}} \times \Bigg[\bigg( \dfrac{({3}^{5})}{{(2)}^{5}} \bigg)^{\frac{1}{5}} \div \bigg(\dfrac{2}{3} \bigg)^{2}\Bigg]}} \\[/tex]
Now, we can write as :
(3³/2³) = (3/2)³
(3⁵/2⁵) = (3/2)⁵
[tex]\sf{\longmapsto{\left\{\bigg(\frac{3}{2} \bigg)^{3} \right\}^{\frac{1}{3}} \times \Bigg[\left\{\bigg(\frac{3}{2} \bigg)^{5} \right\}^{\frac{1}{5}} \div \bigg(\dfrac{2}{3} \bigg)^{2}\Bigg]}} \\[/tex]
Now using law of exponent :
[tex]{\sf{({a}^{m})^{n} = {a}^{mn}}}[/tex]
[tex]\sf{\longmapsto{\bigg( \frac{3}{2} \bigg)^{3 \times \frac{1}{3}} \times \Bigg[\bigg(\frac{3}{2} \bigg)^{5 \times \frac{1}{5}} \div \bigg(\dfrac{2}{3} \bigg)^{2}\Bigg]}} \\[/tex]
[tex] \sf{\longmapsto{\bigg( \frac{3}{2} \bigg)^{\frac{3}{3}} \times \Bigg[\bigg(\frac{3}{2} \bigg)^{\frac{5}{5}} \div \bigg(\dfrac{2}{3} \bigg)^{2}\Bigg]}} \\[/tex]
[tex]\sf{\longmapsto{\bigg( \frac{3}{2} \bigg)^{1} \times\Bigg[\bigg(\frac{3}{2} \bigg)^{1} \div \bigg(\dfrac{2}{3} \bigg)^{2}\Bigg]}} \\[/tex]
[tex]\sf{\longmapsto{\bigg( \frac{3}{2} \bigg)^{1} \times \Bigg[\bigg(\frac{3}{2} \bigg)^{1} \times \bigg(\dfrac{3}{2} \bigg)^{2}\Bigg]}} \\[/tex]
[tex]\sf{\longmapsto{\bigg( \frac{3}{2} \bigg)^{1} \times \Bigg[\bigg(\frac{3}{2} \bigg)^{1} \times \bigg(\dfrac{3}{2} \times \dfrac{3}{2} \bigg)\Bigg]}} \\[/tex]
[tex]\sf{\longmapsto{\bigg( \dfrac{3}{2} \bigg)^{1} \times \Bigg[\bigg(\dfrac{3}{2} \bigg)^{1} \times \bigg(\dfrac{3 \times 3}{2 \times 2}\bigg)\Bigg]}} \\[/tex]
[tex]\sf{\longmapsto{\bigg( \dfrac{3}{2} \bigg)^{1} \times \Bigg[\bigg(\dfrac{3}{2} \bigg)^{1} \times \bigg(\dfrac{9}{4}\bigg)\Bigg]}} \\[/tex]
[tex] \sf{\longmapsto{\bigg( \frac{3}{2} \bigg)\times \Bigg[\bigg(\frac{3}{2} \bigg)\times \bigg(\dfrac{9}{4}\bigg)\Bigg]}} \\[/tex]
[tex]\sf{\longmapsto{\bigg( \dfrac{3}{2} \bigg)\times \Bigg[ \: \: \dfrac{3}{2} \times \dfrac{9}{4} \: \: \Bigg]}}\\[/tex]
[tex]\sf{\longmapsto{\bigg( \dfrac{3}{2} \bigg)\times \Bigg[ \: \: \dfrac{3 \times 9}{2 \times 4} \: \: \Bigg]}} \\[/tex]
[tex]\sf{\longmapsto{\bigg(\dfrac{3}{2} \bigg)\times \Bigg[ \: \: \dfrac{27}{8} \: \: \Bigg]}} \\[/tex]
[tex]\sf{\longmapsto{\dfrac{3}{2} \times \dfrac{27}{8}}} \\[/tex]
[tex]\sf{\longmapsto{\dfrac{3 \times 27}{2 \times 8}}} \\[/tex]
[tex] \sf{\longmapsto{\dfrac{81}{16}}\: ≈ \:5.0625\:\red{Ans.}} \\[/tex]
Jayden's snow cone machine makes 3 snow cones from 0.5 pounds of ice. How many snow cones can be made with ice please show your work, not an explanation!!!!
Answer:
30
Step-by-step explanation:
3 snow cones per 0.5 pounds of ice
0.5 pounds of ice x 10 = 5 pounds of ice
3 snow cones X 10 = 30 snow cones.
Reduce answers to their lowest
terms and mixed forms.
2 4
5
2/
+
f
Answer:
10 + 28 / 35
= 38 / 35
= 1.0875
What is the common ratio of the sequence 3, 21, 147, … ?
7
Which formula can be used to find the nth term of the sequence 3, 21, 147, … ?
Use the given formula to find the indicated terms of the sequence.
a4 =
1029
a5 =
7203
Answer:
What is the common ratio of the sequence 3, 21, 147, …?
7
Which formula can be used to find the nth term of the sequence 3, 21, 147, …?
c)
Use the given formula to find the indicated terms of the sequence.
a4 = 1029
a5 = 7203
Step-by-step explanation:
Answers for all three questions<3
The perimeter of a rectangular field is 312m. If the width of the field is 61m,what is the length.
Answer:
95m
Step-by-step explanation:
312 - 61 - 61 = 190
190/2 = 95
Find the number.
Less than 100
Odd number
Multiple of 5
Divisible by 3
Whose digit sum is an odd number
Anyone knows the best learning websites for like secondary/elementary school?
khan academy
khan academy is a site used for students to learn
Which situations shows a constant rate of change?
Answer:
A constant rate of change is accomplished when the change in one situation constantly results in changing another. In the scenario of a booster club constantly selling raffle tickets, the more tickets they sold the more the club raises.
Have an amazing day friend! <3
PLEASE READ THIS!!! Don't answer my questions with a link. Someone already answered this question, but they gave me a link and it was blocked on my school Chromebook, so it was an entirely useless answer. Thank you. If you answer this question without using a link I will give you an easy to earn 100 points. I just need to know how to turn this shape into as many triangles as possible. Thank you for reading this message.
Answer: 9 triangles
Step-by-step explanation:
lennys lizard weighs 6 pound less than duble the laura's lizard lennys weighs 60 pounds find the weight of lauras lizard
(Me, going to answer the easy questions because hard ones give me headaches)
Alright, listen up.
Steps:
First step: 60 is Lenny's lizard weight. Since it said 6 pounds less than double the lizard weight, we are going to multiply 60 by 2, therefore it would be 120.
Next step: Now 6 pounds less, so we are going to subtract 6 from that 120. 120 - 6 = 114.
Last step...: Label/answer: Lenny's lizard weight is 114 pounds.
Answer:
Laura’s lizard weights 33 pounds
Step-by-step explanation:
Let 2x be Laura’s lizard and
Let 2x - 6 be Lenny’s lizard
We know Lenny’s lizard is 60 pounds. Now to find Laura’s , equate( 2x - 6 )to 60 and solve for x
60 = 2x - 6
x =33
Therefore 33 is the answer
C+X=G
what is X?
this is a literal equation.
Answer:
x=g-c
Step-by-step explanation:
(1 point
4. On a scale drawing of a park, the sand box is 2 inches wide. The actual sand box is 8 feet wide.
What is the scale of the drawing?
1 in. = 4 ft
O 1 in = 6 ft
O4 in = 1 ft
04 in = 6 ft
Finish Cancel
Answer:
1 inch = 4 feet
Step-by-step explanation:
[tex]\frac{2 inches}{8 feet} = \frac{1 inch}{4 feet}[/tex]
If we divide the given numbers by two (dividing on both sides keeps the equation true), we get 1 inch/4 feet. This tells us that on the scale, one inch is representative of four feet.
If the sum of a number and two is tripled, the result is one less than twice the number. Find the number.
Answer:
z
Step-by-step explanation:
hqvqhqvw karrar ras wallah a part
Two dogs are running in a fenced park. One dog is following a path that can be modeled by the equation y=4. Another dog is following a path that can be modeled by the equation y=-x^2 +3. Well the dogs paths cross? Explain your answer.
Answer:
im not sure
Step-by-step explanation:
Which equation, in slope-intercept form, matches the equation shown?
a line that goes through the points (0, -4) and (6, -9)
Question 4 options:
y=47x−4
y=56x+1
y=−56x−4
y=−47x+1
Please help!
Answer: i think it is y=−56x−4
Step-by-step explanation:
The equation in the slope intercept form which passes through the points ( 0, -4 ) and ( 6 , 9 ) is y = (-5 / 6)x - 4.
The correct answer is Option C.
Given data:
To find the equation of a line in slope-intercept form (y = mx + b) that passes through the points (0, -4) and (6, -9), we need to determine the slope (m) and the y-intercept (b).
First, calculate the slope (m):
m = (change in y) / (change in x)
m = (-9 - (-4)) / (6 - 0)
m = (-9 + 4) / 6
m = -5 / 6
Now that we have the slope, we can use one of the given points (let's use (0, -4)) to solve for the y-intercept (b):
-4 = (-5 / 6) * 0 + b
-4 = b
So, the y-intercept (b) is -4.
Now, we can write the equation of the line in slope-intercept form:
y = (-5 / 6)x - 4
Hence, the equation of the line is y = (-5 / 6)x - 4.
To learn more about equation of line, refer:
https://brainly.com/question/14200719
#SPJ3
The complete question is attached below:
Which equation, in slope-intercept form, matches the equation shown?
a line that goes through the points (0, -4) and (6, -9)
A) y = ( 4/7 )x - 4
B) y = ( 5/6 )x + 1
C) y = ( -5/6 )x - 4
D) y = ( -4/7 )x + 1
Using the appropriate Algebraic identity evaluate the following:(4a - 5b)²
[tex](4a - 5b)^{2} \\ by \: \: \: using \: \: \: (x - y)^{2} = {x}^{2} - 2xy + {y}^{2} \\ = {(4a)}^{2} - 2(4a)(5b) + {(5b)}^{2} \\ = {16a}^{2} - 40ab + 25 {b}^{2} [/tex]
Answer:[tex] {16a}^{2} - 40ab + {25b}^{2} [/tex]
Hope it helps.
Do comment if you have any query.
4- (-z/3) = 8 Solve for z
Answer:z=12
Step-by-step explanation:
