Martin had 60kgs of sugar. He put the sugar weighing 3/4 kg. How many packets did he fill ??

Answer:

DBH

Step-by-step explanation:

#1

Initial Price = 100% = 18

Discount = 15% = x

0.15 ( 18 ) = 0.15 * 18 = 2.7

Discount = $2.7 or $2.70

Letter = D

#2

Initial Price = 100% = 450

Markup = 20% = x

0.20 ( 450 ) = 1/5 of 450 = 90

Markup = $90

Letter = B

#3

Initial Payment = 100% = 37.60

Tip = 15% = x

0.15 ( 37.60 ) = 0.15 * 37.60 = 5.64

Tip = $5.64

Letter = H

Your Code = DBH

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Step-by-step explanation:

Hope it helps you.^_^

Answer:

The LCM of 306 and 657 is 22338

Step-by-step explanation:

We know that

HCF (a, b) × LCM (a, b) = a × b

⇒ HCF (306, 657) x LCM (306, 657) = 306 × 657

⇒ 9 × LCM = 306 × 657

⇒ LCM (306, 657) = 306 × 657 / 9

                              =  201042 / 9

∴ LCM = 22338

Thus, the LCM of 306 and 657 is 22338.

Answer:

3.02 is the answer for this question if the answer is correct plz mark me as brainliest

Answer:

3.02

Step-by-step explanation:

51.34 ÷ 17 = 3.02

Answer:

x = -7       y = 35

Step-by-step explanation:

-5x = -7x - 14

2x = -14

x = -7

y = -5(-7)

y = 35

Answer:

Step-by-step explanation:

Step-by-step explanation:

call the height of the tower x

we have tan30°=x:200 so we can find x

Answer:

The probability is 32/81

Step-by-step explanation:

We know that:

The probability that the team wins is p = 2/3

Then the probability of not winning is q = 1 - p = 1 - 2/3 = 1/3

The team plays 4 matches.

We want to find the probability that the team wins 1 more than half of the number of matches played.

So if there are 4 matches, the half is 2 matches

one more than half is then 3 matches.

Let's assume that the team wins the first 3 matches, and does not win the last match.

match one, the team wins with prob: P₁ = 2/3

match two, the team wins with prob: P₂ = 2/3

match three, the team wins with prob: P₃ = 2/3

match four, the team wins with prob: P₄ = 1/3

The joint probability is the product of all the individual probabilities:

P = (2/3)*(2/3)*(2/3)*(1/3)

Now we must also considerate the permutations, we have the cases:

the team does not win the fourth match

the team does not win the third match

the team does not win the second match

the team does not win the first match

So we have just four permutations, then the total probability is:

probability = 4*P = 4*(2/3)*(2/3)*(2/3)*(1/3) = 4*(8/81) = (32/81)

Answer:

7 thousand because in word it is 0me hundred and seventy six thousand three hundred and fifty four

Answer:

tens of thousands

Step-by-step explanation:

Answer:

The answer is E.

Step-by-step explanation:

A quadrilateral that has only one pair of parallel sides is called a Trapezoid.

Answer:

Step-by-step explanation:

[tex]\frac{1.107}{123} \times \frac{1.998}{333} = [/tex]

[tex] = > 9 \times 6[/tex]

[tex] = 45[/tex]

Answer:

Step-by-step explanation:

[tex]\frac{1.107}{123}*\frac{1.998}{333}= 0.009 * 0.006 = 0.000054[/tex]

1107÷ 123 = 9

The dividend has 3 decimal places. So, take 3 decimal places from the right towards left in the result  0.009

1.107 ÷ 123 = 0.0009

0.009 * 0.006

First multiply 9 * 6 = 54

Now, count the number of decimal place in the multiplicands. 0.009 has 3 decimal places and 0.006 has 3 decimal places. So totally, 3+ 3 = 6 decimal places in the result

0.009 * 0.006 = 0.000054

Step-by-step explanation:

x-14y=0

x=0/14y

x=14y

14y

Answer:

Empty square = +

Empty Circle = ÷

Step-by-step explanation:

In order to eliminate the extra numbers from the equation you have to do the opposite of the problem. So...

-6x-1=5

-6x -1+1 = 5+1 (eliminating the 1 from the -6x side and adding it to the other side)

-6x = 6

-6x ÷ -6 = 6 ÷ -6 ( eliminating the-6 so that one side just has x)

so... x= -1

Answer: Option B is your correct answer.

Answer:

5. 80%

6.1.05 kilograms

Step-by-step explanation:

5. Plugging in the values into the formula, we get:

% difference = |60000 - 140000(60000 + 140000)/2| × 100% =

|60000-140000200000 / 2| × 100% =

|-80000100000| × 100% =

80000100000 × 100% =

0.8 × 100% =

80%

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Answer:

{F, G, H, I, J, K, L, M, N, O, P}

are the points between segment EQ :)

[tex] \: \: \: \: \: \: \huge \rm{answer :} \: { \boxed{ \rm\frac{x}{2} }}[/tex]

[tex] \huge \blue{ \boxed{ \pink{\boxed{ \blue{\rm{armed} \: \pink{account}}}}}}[/tex]

[tex] \huge \rm\frac{x} {4} + \frac{x}{4} \\ \\ \huge \rm\frac{x + x}{4} \\ \\ \huge \rm \frac{2x}{4} \\ \\ \huge \blue{ \boxed{ \pink{ \rm \: \frac{x}{2} \: }}}[/tex]

➖➖➖➖➖➖➖➖➖➖➖➖➖➖➖

I hope you understood!✏

➖➖➖➖➖➖➖➖➖➖➖➖➖➖➖

[tex] \huge\boxed{ \boxed{ \rm{Hope \: this \: helps }}}[/tex]

Answer:

The fuel efficiency of Lily's car in kilometers per liter is 12.5 km/litre.

Step-by-step explanation:

Answer:

x=-9/10

Step-by-step explanation:

2x+8x+16=7

Step 1: Simplify both sides of the equation.

2x+8x+16=7

(2x+8x)+(16)=7(Combine Like Terms)

10x+16=7

10x+16=7

Step 2: Subtract 16 from both sides.

10x+16−16=7−16

10x=−9

Step 3: Divide both sides by 10.

10x/10

=

−9/10

x=-9/10

Answer:

x = - 4 ± [tex]\sqrt{7}[/tex]

Step-by-step explanation:

Given

x² + 8x + 16 = 7 ( subtract 16 from both sides )

x² + 8x = - 9

Using the method of completing the square

add ( half the coefficient of the x- term)² to both sides

x² + 2(4)x + 16 = - 9 + 16

(x + 4)² = 7 ( take the square root of both sides )

x + 4 = ± [tex]\sqrt{7}[/tex] ( subtract 4 from both sides )

x = - 4 ± [tex]\sqrt{7}[/tex]

Then

solutions are x = - 4 - [tex]\sqrt{7}[/tex] , x = - 4 + [tex]\sqrt{7}[/tex]

Answer:

i think it would be y=x+3

Step-by-step explanation:

Answer:

Percent * base = Amount

660 g = 660 g

3kg = 3000g

percent(3000) = 660

percent = 660/3000

percent = .22

.22 = 22%

Step-by-step explanation:

Answer:

0.77

Step-by-step explanation:

Given that:

P(A) = 0.64

P(B) = 0.25

P(AnB) = 0.12

Probability that customer buys either pet or baby supplies ; P(AuB)

P(AuB) = P(A) + p(B) - p(Ann)

P(AuB) = 0.64 + 0.25 - 0.12

P(AuB) = 0.77

Answer:

sinB = [tex]\frac{12}{13}[/tex]

Step-by-step explanation:

sinB = [tex]\frac{opposite}{hypotenuse}[/tex] = [tex]\frac{AC}{AB}[/tex] = [tex]\frac{12}{13}[/tex]

The Trigonometric ratios is 12/13

The branch of mathematics concerned with specific functions of angles and their application to calculations.

We have,

H= 13, B= 5 and P=12

So,

sin B= Perpendicular/ Hypotenuse

        = 12/13

hence, sin B=  12/13

Learn more about trigonometry here:

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Answer:

Number of small boxes shipped = 7

Number of large boxes shipped = 15

Step-by-step explanation:

Let the number of small boxes = s

And the number of large boxes = l

Weight of small box = 25 pound

Weight of the large box = 50 pounds

Total weight of the shipment = 925 pounds

Therefore, equation for the weight of shipment will be,

25s + 50l = 925

s + 2l = 37 ----- (1)

Total number of boxes shipped = 22 boxes

Therefore, equation will be,

s + l = 22 ------(2)

Subtract equation (2) from equation (1)

(s + 2l) - (s + l) = 37 -22

l = 15

From equation (2)

s + 15 = 22

s = 7

Therefore, number of small boxes shipped = 7

Number of large boxes shipped = 15

Answer:

x = 3/2

The axis of symmetry is located at the vertex,

which is the also the highest point in this problem...

the x component of the vertex can be calculated as -b/2a = -48/-32 = 24/16 = 6/4 = 3/2

x = 3/2

Step-by-step explanation:

Answer:

B and D

Step-by-step explanation:

Answer:

1500 because if you mutiply by 35 u will get it

Step-by-step explanation:

Answer:

ratio of required answer

also given

5

now putting the value of × in another give

Required mum

7x+5x

12x

Step-by-step explanation:

HOPE IT'S HELP

Answer:

[tex]A \approx 1.488[/tex]

Step-by-step explanation:

Por definición de razones trigonométricas, tenemos las siguientes identidades:

[tex]\tan \theta = \frac{y}{x} = \sqrt{2}[/tex] (1)

[tex]\sin \theta = \frac{y}{\sqrt{x^{2}+y^{2}}}[/tex] (2)

[tex]\cos \theta = \frac{x}{\sqrt{x^{2}+y^{2}}}[/tex] (3)

Si [tex]\theta[/tex] es agudo, entonces [tex]x, y > 0[/tex].

De (1), suponemos [tex]x = 1[/tex] que [tex]y = \sqrt{2}[/tex], entonces los valores de las funciones seno y coseno:

[tex]\sin \theta = \frac{\sqrt{2}}{\sqrt{5}} = \sqrt{\frac{2}{5} }[/tex]

[tex]\sin \theta = \frac{\sqrt{10}}{5 }[/tex]

[tex]\cos \theta = \sqrt{\frac{1}{5} }[/tex]

[tex]\cos \theta = \frac{\sqrt{5}}{5}[/tex]

Por último, calculemos [tex]A[/tex]:

[tex]A = 3\cdot \left(\frac{\sqrt{10}}{5} + \frac{\sqrt{5}}{5} \right) - \sqrt{7}[/tex]

[tex]A \approx 1.488[/tex]

in a sale, normal prices are reduced by 10%

nathalie bought a pair of shoes in the sale for £54

what was the original price of the shoes

[tex]x = 60[/tex]

Explanation

[tex] \sf based \: on \: the \: given \: conditions \: write : x = \frac{54}{ 1 - 01} [/tex]

[tex] \sf calculate \: the \: sum \: difference: x = \frac{54}{0.9} [/tex]

convert decimal to fraction: x= 54 / 9 / 10

[tex] \sf \: divide \: a \: fraction \: by \: multiplying \: its \: reciprosal : x = 54 \times \frac{10}{9} [/tex]

[tex] \sf \: write \: as \: a \: single \: fraction : x = \frac{54 \times 10}{9} [/tex]

[tex] \sf \: reduce \: fraction \: to \: the \: lowest \: term \: by \: cancelling \: the \: greatest \: [/tex]

[tex] \sf \: common \: factor : x = 6 \times 10[/tex]

[tex] \sf \: calculate \: the \: product \: or \: quotient : x = 60 [/tex]

[tex] \sf{ \boxed{answer : x = 60}}[/tex]