match electrons answer help

Explanation:

here's the answer to your question

Answer:

I'm not really sure. Sorry dude.

Explanation:

Sorry.

Answer:

Mass of each weight = 56.7 gram per piece

Explanation:

Given:

Lead’s density = 11.34 g/mL

Number of weights = 50

Volume of box = 250 mL

Find:

Mass of each weight

Computation:

Mass = volume x density

Mass = 250 x 11.34

Mass = 2,835 gram

Mass of each weight = Total Mass / Number of weights

Mass of each weight = 2,835 / 50

Mass of each weight = 56.7 gram per piece

Answer:2.26

Explanation:

Answer:

Pottasium

Explanation:

because it is the nineteenth element

Answer:

The answer is B. Potassium.

Explanation: Potassium has 19 electrons that are organized like the image if you count the electrons on each obital. This answer is correct on edge 2020. Hope this helps!

Answer:

Follows are the solution to the given question:

Explanation:

Following are the balanced redox equation:

[tex]Cr_2O_7^{2-} + 6 Fe^{2+} + 14H^{+} \to 2Cr^{3+} + 6 Fe^{3+} + 7H_2O[/tex]

Calculating the average volume of the dichromate:

[tex](i)\ 13.8 - 2.3 = 11.5 \ ml\\\\(ii)\ 24.4 - 13.8 = 10.6\ ml\\\\(ii)\ 35.2 - 24.4 = 10.8 \ ml\\\\(iv)\ 45.9 - 35.2 = 10.7\ ml[/tex]

[tex]Mean\ volume = 10.9\ ml = 0.0109\ L\\\\moles\ Fe^{2+} \ titrated = 0.01500 \ L \times 0.07\ \frac{mol}{L} = 0.00105 \\\\moles\ Cr_2O_7^{2-}\ required = 0.00105\ mol\ Fe^{2+} \times 1 \ mol\ \frac{Cr_2O_7^{2-}}{6 \mol\ Fe^{2+} } = 0.000175 \ moles\ Cr_2O_7^{2-}\\\\Concentration \ of\ Cr_2O_7^{2-} = \frac{0.000175\ moles}{0.0109\ L} = 0.01606\ M\\\\[/tex]

Answer:

see explanations

Explanation:

4NH₃(g) + 5O₂(g) => 4NO(g) + 6H₂O(g)

Ci(NH₃) = 3.5mole/4L = 0.875M

Cf(NH₃) = 1.6mole/4L = 0.400M

Rate-1 => Δ[NH₃]/Δt = |(0.400M - 0.875M)/3min| = 0.158M/s

Rate-2 => 6(Δ[NH₃]/Δt) =  4(Δ[H₂O]/Δt) => 6/4(0.158M/s) = 0.237M/s

Rate-3 => 5(Δ[NH₃]/Δt) =  4(Δ[O₂]/Δt) => 5/4(0.158M/s) = 0.237M/s

_________________________________________________________

NOTE: When setting up comparative rate expressions for a given reaction, set the rates expressions as equal then swap coefficient values.  Then solve for rate of interest and substitute givens.      

example: for NH₃ and H₂O

              4NH₃(g) + 5O₂(g) => 4NO(g) + 6H₂O(g)

              =>  6(Δ[NH₃]/Δt) =  4(Δ[H₂O]/Δt)

              =>  Δ[H₂O]/Δt = 6/4(Δ[NH₃]/Δt) = 6/4(0.237M/s) = 0.237M/s

Answer:

A water molecule consists of two atoms of hydrogen linked by covalent bonds to the same atom of oxygen. Atoms of oxygen are electronegative and attract the shared electrons in their covalent bonds.

Answer:

b is the answr

Explanation:

The correct answer is Option (B) Enrichment of Uranium-235 is done.

Hence Option (B) is correct because enrichment of uranium-235 is achieved by the process of conversion So , It does not facilitate containment

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Answer:

the answer is c)inches

Explanation:

inches is best for showing length

Answer:

Benzaldehyde (C6H5CHO) is an organic compound consisting of a benzene ring with a formyl substituent. It is the simplest aromatic aldehyde and one of the most industrially useful.

Answer:

The SI base unit for amount of substance is the mole. 1 mole is equal to 1 moles KMnO4, or 158.033949 grams.

Explanation:

I belive that is correct,hope it helps:)

Explanation:

here's the answer to your question

13.41 moles are present in 2.20 kg of sodium phosphate.

A mole is defined as 6.02214076 × [tex]10^{23}[/tex]of some chemical unit, be it atoms, molecules, ions, or others. The mole is a convenient unit to use because of the great number of atoms, molecules, or others in any substance.

The molar mass of sodium phosphate is 163.94 g/mol.

2.20 kg = 2200g

[tex]Moles = \frac{2200g}{163.94 g/mol.}[/tex]

Moles = 13.41954374 = 13.41 moles

Hence, 13.41 moles are present in 2.20 kg of sodium phosphate.

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Answer:

c. the reactants

Explanation:

the reactants are specifically the substances consumed in the course of chemical reaction

[tex]okay \: bro[/tex]

Answer is [tex]32[/tex]

Explanation:

There are mainly four shells in an atom namely K, L, M, and N.

By using 2n², we can find the maximum number of electrons present in M shell.

Let, K = 1st shell, L = 2nd shell, M = 3rd shell, and N = 4th shell.

K = 1, L = 2, M = 3 and N = 4.

K = 2n² = 2(1)² = 2(1) = 2.

L = 2n² = 2(2)² = 2(4) = 8.

M = 2n² = 2(3)² = 2(9) = 18.

N = 2n² = 2(4)² = 2(16) = 32.

So, The maximum number of electrons present in the M shell is [tex]32.[/tex]

Answer:

1

Explanation:

in my opinion,The answer would be organism

please mark me as brainliest

Answer:

Answer: 9.35 moles Li contains 2.08 × 10 (to the power of)24 atoms .

Explanation:

Answer:

B. Ester

Explanation:

"Esters have the general formula RCOOR′, where R may be a hydrogen atom, an alkyl group, or an aryl group, and R′ may be an alkyl group or an aryl group but not a hydrogen atom."

The type of molecule is ester.

A molecule is a collection of  more than one atom bound together by chemical bonds; based on the circumstances, the phrase will not include ions that meet this requirement.

Esters were chemical molecules formed by mixing an oxoacid and a hydroxyl substance like alcohol as well as phenol.

It can be seen that molecule have -COO group which represent ester group. Hence, given molecule have ester group.

Therefore, the correct answer will be option (B).

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Explanation:

The Gas Law Apparatus is a high-quality demonstrator of the relationship between pressure, volume and temperature of a gas. The pressure gauge shows how pressure affects volume and vice versa. A digital thermometer displays the temperature.

Answer:

When an atom has an equal number of electrons and protons, it has an equal number of negative electric charges (the electrons) and positive electric charges (the protons). The total electric charge of the atom is therefore zero and the atom is said to be neutral.

I HOPE THIS HELPS !!!!!!!!!!!

Answer:

E

Explanation:

kinetic energy of linear motion

[tex]k.e = \frac{1}{2} m {v}^{2} [/tex]

kinetic energy, K.e= 100joules

mass, m = 2kg

velocity, v =?

substituting the values into the formula :

[tex]100joules = \frac{1}{2} \times 2kg \times {v}^{2} [/tex]

[tex] {v }^{2} = 100[/tex]

[tex]v = \sqrt{100 } [/tex]

[tex]v = 10m { \sec }^{ - 1} [/tex]

Explanation:

The given chemical equation is:

[tex]2A + 4B -> 2C + 2D[/tex]

The rate of the reaction is 0.0352 M/s.

During the course of the reaction, the rate of reactants decreases, and the rate of products increases.

The rate of disappearance of B is shown below:

[tex]rate=-\frac{1}{4} \frac{d[B]}{dt}[/tex]

So, rate of change of B is :

[tex]rate of change of B =- rate * 4\\=-0.0352 M/s * 4\\=-0.1408M/s\\\\=-0.141M/s[/tex]

Option C.

In the given reaction, rate of change of reactant B is equal to -0.141 M/s.

Rate of any chemical reaction defines the speed of the completion of that reaction.

In the question given reaction is:

2A + 4B ----> 2C + 2D

Rate of reaction = 0.0352 M/s.

Rate of the reaction with respect to the reactant B is written as:

Rate = [tex]${\rm{ - }}\frac{{\rm{1}}}{{\rm{4}}}\frac{{\left[ {{\rm{dB}}} \right]}}{{{\rm{dT}}}}$[/tex], where negative sign shows the disappearance of reactant B.

Rate of change of B i.e. [tex]$\frac{{{\rm{dB}}}}{{{\rm{dT}}}}$[/tex] =  4 × (-rate)

[tex]$\frac{{{\rm{dB}}}}{{{\rm{dT}}}}$[/tex] =  4 × (-0.0352) = -0.1408 = -0.141 M/s

Hence, -0.141 M/s is the rate of change of B.

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Answer:

Metallic

Explanation:

Iron is a metal

de Broglie's wave equation describes that particles have wave properties. The equation is  

   λ = h/mv

Where λ  is the wave length of the particle (m), h is the Planck's constant (6.62607 x 10⁻³⁴J s), m is the mass of a particle (kg) and v is the velocity (m/s).

λ = ?

h =  6.62607 x 10⁻³⁴ J s

m =200 g = 0.2 kg

v = 20 m/s

By substitution,

   λ  = 6.62607 x 10⁻³⁴ J s / (0.2 kg x 20 m/s)

   λ  = 1.66 x 10⁻³⁴ m

Hence, the wavelength of the 200 g ball 1.66 x 10⁻³⁴ m.

Answer: first of all an ionic bonds is the electrostatic force of attraction between opposite ions and and covalent bonds is the bond between different elements mostly non metals or the sharing of electrons between elements which are mostly non metals.

Explanation:  metals and non metals react to form ionic compounds

and non metals react to form covalent bonds

HOW TO DIFFERENTIATE

ionic solids the particles are charged and the forces between them are strong

covalent solids the particles are not charged and the forces between them are weak

now i would differentiate using their  properties

ionic bonds  / compounds

have high melting point

have low melting point

They are soluble in water

and they conduct electricity even when melted or dissolved in water

covalent bonds /compounds

they have low melting point

they have low melting point

They are insoluble

they do not conduct electricity

HOPE THIS HELPS!!!

Answer:

could occur at any temperature.

Explanation:

The spontaneity of a reaction is what determines whether the reaction will occur or not. A spontaneous reaction occurs easily.

The spontaneity of a reaction is predicted by the sign of ∆G.

When ∆G is positive, the reaction is not spontaneous. When ∆G is negative, the reaction is spontaneous.

Note that;

∆G= ∆H - T∆S

Where;

∆H = Change in enthalpy

∆S = Change in entropy

T= temperature

If ∆H is unfavourable and ∆S is favourable, the reaction can proceed at all temperatures because ∆G will always be negative.

It should be noted that a process that is unfavorable as regards to enthalpy, but favorable with respect to entropy could occur at any temperature.

Enthalpy(∆H) serves as amount of internal energy that a compound has, entropy( ∆S)  on the other hand serves as intrinsic disorder within the system.

However, spontaneity of a reaction determines likely hood of occurrence of a reaction, when the process is spontaneous, it makes the reaction to occurs easily.

We can conclude that whenever enthalpy is unfavourable and entropy of a system is favourable, then the spontaneity will be negative and the reaction will occur at any temperature.

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Answer:

The limiting Reactant would be KI

Explanation:

Answer:

eşnatto

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Answer:

Q.no 8 = at the at the bottom of the first hill.