May anyone help me with this please

Answer:

Below,...

Step-by-step explanation:

They are saying that if you add a odd number + a odd number than you'd get a even number,... odd + even = odd,... odd x even = even,... and so on,...

Hope it helps,... Chow!

Answer:

[tex]{ \tt{1 \: mg = 1 \times {10}^{ - 3} \: g}} \\ { \tt{75 \: mg = (75 \times 1 \times {10}^{ - 3} ) \: g}} \\ { \bf{ = 75 \times 10 {}^{ - 3} \: grams}} \\ { \bf{ = 0.075 \: grams}}[/tex]

Answer:

fourth time ...

same problem...

the red line crosses a corner of a box at (4,20) and (2,10)

20/4 = 5

and

10/2 = 5

the slope , constant, gradient for this relationship is "5"

Step-by-step explanation:

Answer:

Hello

Step-by-step explanation:

Axis of symmetry is vertical:

x=-7 (since (-7,-3) is the vertex)

Answer:

x = -7

Step-by-step explanation:

y = (x+7)^2 -3

This is in vertex form

y =a(x-h)^2+k  where (h,k) is the vertex and the line of symmetry for a vertical parabola is x=h

y = (x- -7)^2 -3

x = -7

Answer:

r=-11

Step-by-step explanation:

7r+2=5(r-4)

7r+2=5r-20

2r=-22

r=-11

Answer:

Option A, 86°

Step-by-step explanation:

each diagonals of a rhombus divides the angles at half, so a+b+c+d = 360°/2 = 180°

now, a+b+c+d-94° = 180°-94° = 86°

Answer:

D 266°

Step-by-step explanation:

a+b+c+d-94°

90°+ 90°+ 90°+ 90° -94°

360°-94°

266°

9514 1404 393

Answer:

  g(x) = 7x -1

Step-by-step explanation:

The y-coordinate of a function tells how many units the function value lies above the x-axis. Translating that value down 4 units is the same as subtracting 4 from the function value.

  g(x) = f(x) -4

  g(x) = 7x +3 -4

  g(x) = 7x -1

Answer:

2 sqrt(2x-1)

Step-by-step explanation:

f(x) = sqrt(x+7)

g(x) = 8x-11

f(g(x))=

Place g(x) in for x in the function f(x)

f(g(x)) = sqrt( 8x-11 +7)

          = sqrt( 8x -4)

Factor out 4

          = sqrt( 4(2x-1)

          = 2 sqrt(2x-1)

[tex]\\ \sf\longmapsto f(x)=\sqrt{x+7}[/tex]

[tex]\\ \sf\longmapsto g(x)=8x-11[/tex]

[tex]\\ \sf\longmapsto f(g(x))=\sqrt{8x-11+7}[/tex]

[tex]\\ \sf\longmapsto f(g(x))=\sqrt{8x-4}[/tex]

[tex]\\ \sf\longmapsto f(g(x))=\sqrt{4(2x-1)}[/tex]

[tex]\\ \sf\longmapsto f(g(x))=2\sqrt{2x-1}[/tex]

Answer:

The radius is 3.5cm

Step-by-step explanation:

Given

[tex]V = 192.5cm^3[/tex]

[tex]h = 5cm[/tex]

Required

The volume (V)

The volume of the vase is:

[tex]V = \pi r^2h[/tex]

So, we have:

[tex]192.5 = 22/7 * r^2 * 5[/tex]

Divide by 5

[tex]38.5 = 22/7 * r^2[/tex]

Multiply by 7/22

[tex]12.25= r^2[/tex]

Take positive square roots

[tex]r = 3.5[/tex]

19/25 which is likely

count the ones with y and put that over 25

Answer:

C

Step-by-step explanation:

7+(-4x^2) where x=0, 7+0=7

Answer:

C. 7

Step-by-step explanation:

[tex]7+(-4x^2)[/tex]

Replace x with 0

[tex]7+(-4(0)^2)[/tex]

0 squared is 0. -4 times 0 is also 0.

7+0=7

I hope this helps!

Answer:

1. a. 2

b. -½

c. y - 3 = -½(x - 8) => point-slope form

y = -½x + 7 => slope-intercept form

2. a. -1

b. 1

c. y - 5 = 1(x - 3) => point-slope form

y = x + 2 => slope-intercept form

Step-by-step explanation:

1. (8, 3) and (10, 7):

a. The gradient for the line joining the points:

Gradient = [tex] \frac{y_2 - y_1}{x_2 - x_1} [/tex]

Let,

[tex] (8, 3) = (x_1, y_1) [/tex]

[tex] (10, 7) = (x_2, y_2) [/tex]

Plug in the values

Gradient = [tex] \frac{7 - 3}{10 - 8} [/tex]

Gradient = [tex] \frac{4}{2} [/tex]

Gradient = 2

b. The gradient of the line perpendicular to this line = the negative reciprocal of 2

Negative reciprocal of 2 = -½

c. The equation of perpendicular line if it passes through the first point, (8, 3):

Equation of the perpendicular line in point-slope form can be expressed as y - b = m(x - a).

Where,

(a, b) = (8, 3)

Slope (m) = -½

Substitute (a, b) = (8, 3), and m = -½ into the point-slope equation, y - b = m(x - a).

Thus:

y - 3 = -½(x - 8) => point-slope form

We cam also express the equation of the perpendicular line in slope-intercept form by rewriting y - 3 = -½(x - 8) in the form of y = mx + b:

Thus:

y - 3 = -½(x - 8)

y - 3 = -½x + 4

y - 3 + 3 = -½x + 4 + 3

y = -½x + 7

2. (3, 5) and (4, 4):

a. The gradient for the line joining the points:

Gradient = [tex] \frac{y_2 - y_1}{x_2 - x_1} [/tex]

Let,

[tex] (3, 5) = (x_1, y_1) [/tex]

[tex] (4, 4) = (x_2, y_2) [/tex]

Plug in the values

Gradient = [tex] \frac{4 - 5}{4 - 3} [/tex]

Gradient = [tex] \frac{-1}{1} [/tex]

Gradient = -1

b. The gradient of the line perpendicular to this line = the negative reciprocal of -1

Negative reciprocal of -1 = 1

c. The equation of perpendicular line if it passes through the first point, (3, 5):

Equation of the perpendicular line in point-slope form can be expressed as y - b = m(x - a).

Where,

(a, b) = (3, 5)

Slope (m) = 1

Substitute (a, b) = (3, 5), and m = 1 into the point-slope equation, y - b = m(x - a).

Thus:

y - 5 = 1(x - 3) => point-slope form

We can also express the equation of the perpendicular line in slope-intercept form by rewriting y - 5 = 1(x - 3) in the form of y = mx + b:

Thus:

y - 5 = 1(x - 3)

y - 5 = x - 3

y - 5 + 5 = x - 3 + 5

y = x + 2

Answer:

a. (0,-5)

Step-by-step explanation:

The calculated measure of the angle QSR is 68 degrees

From the question, we have the following parameters that can be used in our computation:

Angle b = 136 degrees

The measure of angle QSR can be calculated using

QSR = 1/2 * Angle b

substitute the known values in the above equation, so, we have the following representation

QSR = 1/2 * 136 degrees

Evaluate

QSR = 68 degrees

Hence, the measure of angle QSR is 68 degrees

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Answer:

Answer 60

Step-by-step explanation:

The distance from an exterior point to the incircle is equal to the tangent length in both cases.

So the 19 is made up of 9 and 10.

The length of the other portion of the tangent from the end of 19 to the tangent point on the right is also 10.

By a similar argument the lower length of the line to the tangent point is 11.

So you have

9 + 9 + 10 + 10 + 11 + 11

18 + 20 + 22 = 60.

Answer:

the correct answer is b and I know this because I just had it

Step-by-step explanation:

what to find then??.........

Answer:

Step-by-step explanation:

To solve this divide the amount of sugar by the number of dollars:

Per 10dollar she brought=19pounds

Per dollar

[tex]\\ \sf\longmapsto \dfrac{19}{10}[/tex]

[tex]\\ \sf\longmapsto 1.9pounds[/tex]

Answer:

14.32

Step-by-step explanation:

Since this is a right triangle, we can us the Pythagorean theorem

a^2 + b^2 = c^2

3^2 + 14^2 = JL ^2

9+196 = JL ^2

205 = JL ^2

Taking the square root of each side

sqrt(205) = JL

14.31782106 = JL

To 2 decimal places

14.32

Answer:

When one solves, they arrive at a step where |x| is equal to a negative number. Since | x| can never be negative, there is no solution.

Step-by-step explanation:

6|x| + 25 = 15

Subtract 25 from each side

6|x| + 25-25 = 15-25

6|x|  = -10

Divide by 6

6|x| /6 = -10/6

|x|  = -5/3

There is no solution because the absolute value must be greater than or equal to zero.  This equation has it negative.

Answer:

x = 7

Step-by-step explanation:

27 = 7x + 6 - 4x      (Given)

27 = 3x + 6             (Simplify)

27 - 6 = 3x + 6 - 6  (Subtract 6 on both sides)

21 = 3x                    (Simplify)

21/3 = 3x/3             (Divide 3 on both sides)

7 = x                        (Simplify)

The quotient of 40 and 5

40÷5=8

=> Product of that number with 7 and 8

So number to find is : 7x8=56

The product of 7 and the quotient of 40 divided by 5 is 56.

The quotient is the result which is derived by the division of two numbers.

For example, the quotient of 30 divided by 3 is 10.

The product is the multiplication of two numbers which is written as a*b.

For example, the product of 8 and 9 is 72.

Here given we have to calculate the product of 7 and the quotient of 40 divided by 5.

The quotient of 40 divided by 5 is 40/5= 8

The product of 7 and The quotient of 40 divided by 5= 7*8= 56

Therefore the product of 7 and the quotient of 40 divided by 5 is 56.

Learn more about quotient

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Answer:

a) a=-12

b) a=27

Step-by-step explanation:

a) parallel lines have = slopes SO

-3/2 = -3/2

-3/2 = 18/a

-3a/2 = 18

-3a = 18 * 2 = 36

a = -12

b) perpendicular lines have negative inverse slopes SO

- 3/2 ---> 2/3

2/3 = 18/a

2a/3 = 18

2a = 18 * 3 = 54

a = 54/2 = 27

If a ★ b = 0.5ab, then

0.1 ★ b = 0.5 (0.1) b = 0.05b = 10

==>   b = 10/0.05 = 200

Answer:

4x+y=-32

Step-by-step explanation:

given,

slope (m) = -4

point: (-8,0)

as we know the slope intercept form of the line is, y=mx+b, b=y-mx, now we put x=-8, y=0 to find b [because the point is given (-8,0) so it must satisfy the equation]

so,

b = 0-(-4)×(-8) = -32

y=mx+b

or, y=-4x-32

or, 4x+y=-32

(this is the standard form of the line)

Using the equation y - y1 = m(x - x1)

y - 0 = -4(x - (-8))

y = -4(x + 8)

y = -4x - 32

Answer:

[tex]\displaystyle x = \sqrt{y^2 + z^2}[/tex]

General Formulas and Concepts:

Pre-Algebra

Algebra i

Step-by-step explanation:

Step 1: Define

Identify

[tex]\displaystyle x^2 = y^2 + z^2[/tex]

Step 2: Solve for x

Answer:

Step-by-step explanation:

Step 1

Find the height:

Step 2

Find the area:

Answer:

they are not similar. their one angle is only equal

Answer:

[tex]\frac{dy}{dx}[/tex] = 2x + 3

Step-by-step explanation:

Differentiate each term using the power rule

[tex]\frac{d}{dx}[/tex] (a[tex]x^{n}[/tex] ) = na[tex]x^{n-1}[/tex]

y = x² + 3x

[tex]\frac{dy}{dx}[/tex] = 2[tex]x^{(2-1)}[/tex] + 3[tex]x^{(1-1)}[/tex]

   =  2x + 3[tex]x^{0}[/tex]

   = 2x + 3

Answer:

59.04°

58.31 inches

Step-by-step explanation:

The solution triangle is attached below :

Since we have a right angled triangle, we can apply trigonometry to obtain the angle ladder makes with the ground;

Let the angle = θ

Tanθ = opposite / Adjacent

Tanθ = 50/30

θ = tan^-1(50/30)

θ = 59.036°

θ = 59.04°

The length of ladder can be obtained using Pythagoras :

Length of ladder is the hypotenus :

Hence,

Hypotenus = √(adjacent² + opposite²)

Hypotenus = √(50² + 30²)

Hypotenus = √(2500 + 900)

Hypotenus = 58.309

Length of ladder = 58.31 inches

Answer:

59°

58.3 inches

Step-by-step explanation:

Here is the full question :

A ladder is placed 30 inches from a wall. It touches the wall at a height of 50 inches from the ground. The angle made by the ladder with the ground is degrees, and the length of the ladder is inches.

Please check the attached image for a diagram explaining this question

The angle the ladder makes with the ground is labelled x in the diagram

To find the value of x given the opposite and adjacent lengths, use tan

tan⁻¹ (opposite / adjacent)

tan⁻¹  (50 / 30)

tan⁻¹ 1.667

= 59°

the length of the ladder can be determined using Pythagoras theorem

The Pythagoras theorem : a² + b² = c²

where a = length

b = base

c =  hypotenuse

√(50² + 30²)

√(2500 + 900)

√3400

= 58.3 inches