Methane (CH4) is the major component of natural gas. 40.0 grams of methane were placed in a commercial calorimeter and subjected to a combustion reaction. The reaction released 2800 kJ of energy.
1. Compare this energy value to the energy values of paraffin and isopropanol. Is methane a good choice as a fuel?

Answers

Answer 1

Based on comparison of energy produced per kilogram, a given mass of methane produces more energy than similar masses of either paraffin or isopropanol, therefore;

Methane is a good choice as a fuel

The reason for the above comparison conclusion is as follows:

The given information:

The details of the combustion of the methane gas, CH₄, are as follows;

The mass of the methane gas placed in the calorimeter, m = 40.0 g

The amount of heat released from the combustion of the 40.0 grams of methane = 2,800 kJ

The data from online resources of paraffin  and isopropanol includes

1. The energy value of paraffin = 46 MJ/kg

The energy value of isopropanol = 33.6 MJ/kg

The energy produced from 1 kilogram of methane gas is given as follows;

40.0 g of methane gas produces 2,800 kJ of energy, therefore;

1 kg = 1,000 g of methane gas will produce, 2,800kJ/(40.0 g) × 1,000 g = 70,000,000 J

Therefore;

1 kg of methane produces 70,000,000 J = 70 MJ of energy

Therefore, energy produced from methane = 70 MJ/kg

Given that methane produces more than twice the amount of energy that

is produced from similar mass of isopropanol and more than one and half

times the amount of energy that is produced from the same mass of

paraffin, methane is a good choice as a fuel for energy

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Related Questions

A sample of gas is held at constant volume. If the number of moles of this sample of gas is doubled and the pressure of this sample of gas is halved, what happens to the absolute temperature of the gas?
Select one
a. The absolute temperature is doubled.
b. The absolute temperature is halved.
c. The absolute temperature is quadrupled.
d. The absolute temperature is quartered.
e. The absolute temperature stays the same.

Answers

Answer:

number of moles of gas increases the volume also increases.

In a quantitative analysis, a methanol (CH3OH) contaminated water sample was titrated with 0.0021 mol L- potassium permanganate (KMnO4). 50.00 mL samples of the water to be tested were acidified by sulfuric acid, then titrated with the permanganate solution. The results are shown below. Burette reading, ml 1st titration 2nd titration 3rd titration 4th titration Final volume 12.40 19.60 26.60 17.25 Initial volume 4.45 12.50 19.60 10.15 Titre 7.95 7.10 7.00 7.10 The complete equation for the redox titration reaction is: 4MnO4- + 12H+ + 5CH3OH → 4Mn2+ + 11H2O + 5HCOOH a. [5] Calculate the concentration of the methanol in mol L-1.​

Answers

In a REDOX titration, one specie is oxidized while the other is reduced. The concentration of methanol is 0.012  mol L-1. Methanol is the oxidizing agent while permanganate is the reducing agent.

The average titre value is; [tex]\frac{7.95 + 7.10 + 7.00 + 7.10}{4}[/tex] = 7.29 mL

Equation of the reaction is:

[tex]4MnO4- + 12H+ + 5CH3OH ----> 4Mn2+ + 11H2O + 5HCOOH[/tex]

Concentration of oxidizing agent = CA = ?

Concentration of reducing agent = CB = 0.0021 mol L-1

Volume of oxidizing agent =  VA= 7.29 mL

Volume of reducing agent = VB = 50.00 mL

Number of moles of oxidizing agent NA = 4

Number of moles of reducing agent NB = 5

Note that NA and NB are obtained from the balanced reaction equation

CAVA/CBVB = NA/NB

CAVANB = CBVBNA

CA =  CBVBNA/VANB

CA = 0.0021 mol L-1 * 50.00 mL * 4/7.29 mL * 5

CA= 0.012  mol L-1

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Consider the reaction between CaCO3 and HCl. Which of the following could speed up the reaction?
I. Increasing concentration of the HCl
II. Increasing size of the CaCO3 pieces
III. Increasing temperature
a) I and III only
b) I, II, and III
c) I only
d) II and III only

Answers

It's d






Jdhxhdhdhhdjddh

H2SO4 ????????????????

Answers

Explanation:

Sulfuric Acid (H2SO4) is a strong mineral acid that has is colorless when pure. This chemical is used as a chemical intermediate to manufacture other chemicals and cleaning metal surfaces. The formula for sulfuric acid is H2SO4. The molar mass of sulfuric acid is 98.07848 g mol.

The specific heat capacity of lead is 0.13 J/g-K. How much heat (in J) is required to raise the temperature of 15 g of lead from 22 °C to 37 °C? a. 5.8 × 10-4 J b. 0.13 J c. 29 J d. 2.0 J e. -0.13 J

Answers

Answer:

c. 29 J

Explanation:

Step 1: Given data

Specific heat capacity of Pb (c): 0.13 J/g.K (= 0.13 J/g.°C)Mass of Pb (m): 15 gInitial temperature: 22 °CFinal temperature: 37 °C

Step 2: Calculate the temperature change

ΔT = 37 °C - 22 °C = 15 °C

Step 3: Calculate the heat (Q) required to raise the temperature of the lead piece

We will use the following expression.

Q = c × m × ΔT

Q = 0.13 J/g.°C × 15 g × 15 °C = 29 J

Based on periodic properties, choose the more metallic element from each of the following pairs.
Match the words in the left column to the appropriate blanks in the sentences on the right.
Between Sr and Sb, the more metallic element is ______
Between \rm Sr and \rm Sb, the more metallic element is _______
Between As and Bi, the more metallic element is ______
Between \rm As and \rm Bi, the more metallic element is _______
Between Cl and O, the more metallic element is ______
Between \rm Cl and \rm O, the more metallic element is ______
Between S and As, the more metallic element is ______
Between \rm S and \rm As, the more metallic element is _______

Answers

Answer:

Sr is the more metallic element

Bi is the more metallic element

O is the more metallic element

As is the more metallic element

Explanation:

One thing should be clear; metallic character increases down the group but decreases across the period.

Hence, as we move across the period, elements become less metallic. As we move down the group elements become more metallic.

This is the basis upon which decisions were made about the metallic character of each of the elements listed above.

Name the following cycloalkane:
H3C-
CH2CH3
A. 1-ethyl-4-methylcyclohexane
B. 4-ethyl-1-methylcyclohexane
C. 1-methyl-4-ethylcyclohexane

Answers

Answer:

A

Explanation:

1-ethyl-4-methylcyclohexane

i believe it is A

hope that helped :)

Sodium acetate is produced by the reaction of baking soda and vinegar. The resultant solution is then heated until it becomes saturated and allowed to cool. As a result, the solution has become supercooled. Upon addition of a small seed crystal, the solution temperature increases as sodium acetate trihydrate crystallizes. Its molar enthalpy of fusion is 35.9 kJ/mol. How much thermal energy would be released by 276.0 g of sodium acetate trihydrate (molar mass

Answers

Answer: The thermal energy that would be released by 276.0g of sodium acetate trihydrate is 71.8kJ.

Explanation:

Supercooling is the process of lowering the temperature a liquid below its freezing point, without it becoming solid. A liquid below its freezing point will crystallize in the presence of a seed crystal because it serves as a structure for formation of crystals. From the question,

The given mass of sodium acetate trihydrate

(CH3COONa.3H2O)= 276.0g

Molar mass of sodium acetate

trihydrate= 136.08g/mol

Thermal heat of fusion of sodium acetate

trihydrate = 35.9 kJ/mol

From the given mass the number of moles present= 276.0/ 136.08

= 2.0moles

Therefore the heat (thermal) energy of the given mass of sodium acetate

trihydrate = 2.0 × 35.9

= 71.8kJ

Therefore, upon addition of a small seed crystal, the solution temperature increases as sodium acetate trihydrate crystallizes.

Nucleophilic aromatic substitution involves the formation of a resonance-stabilized carbanion intermediate called a Meisenheimer complex as the nucleophile attacks the ring carbon carrying the eventual leaving group.

a. True
b. False

Answers

Answer:

True

Explanation:

Aromatic rings undergo nucleophillic substitution reactions in the presence of a electron withdrawing group which stabilizes the Meisenheimer complex.

When the nucleophile attacks the ring carbon atom carrying the eventual leaving group. A resonance-stabilized carbanion intermediate called a Meisenheimer complex is formed.

Subsequent loss of the leaving group from the intermediate complex yields the product of the reaction.

what are the five main points of kinetic theory of gas?​

Answers

The kinetic-molecular theory of gases assumes that ideal gas molecules

(1) are constantly moving;

(2) have negligible volume;

(3) have negligible intermolecular forces;

(4) undergo perfectly elastic collisions; and

(5) have an average kinetic energy proportional to the ideal gas's absolute temperature.

The five main postulates of the KMT are as follows:

(1) the particles in a gas are in constant, random motion,

(2) the combined volume of the particles is negligible

(3) the particles exert no forces on one another,

(4) any collisions between the particles are completely elastic.

(5) the average kinetic energy of the particles is proportional to the temperature in kelvins.

For each reaction, write the chemical formulae of the oxidized reactants.

a. ZnCl2 (aq) + 2Na(s) → Zn(s) + 2NaCl(aq)
b. Al(s) + FeBrz (aq) → AlBrz (aq) + Fe(s)
c. FeSO4 (aq) + Zn (s) → Fe(s) + ZnSO4(aq)

Answers

Answer:

a. Na(s); b. Al(s); c. Zn(s)

Explanation:

Let's consider the following redox reactions.

a. ZnCl₂ (aq) + 2 Na(s) → Zn(s) + 2 NaCl(aq)

Na is oxidized because its oxidation number increases from 0 to +1 (in NaCl) whereas Zn is reduced because its oxidation number decreases from 2+ (in ZnCl₂) to 0.

b. Al(s) + FeBr₃ (aq) → AlBr₃ (aq) + Fe(s)

Al is oxidized because its oxidation number increases from 0 to +3 (in AlBr₃) whereas Fe is reduced because its oxidation number decreases from 3+ (in FeBr₃) to 0.

c. FeSO₄ (aq) + Zn(s) → Fe(s) + ZnSO₄(aq)

Zn is oxidized because its oxidation number increases from 0 to +2 (in ZnSO₄) whereas Fe is reduced because its oxidation number decreases from 2+ (in FeSO₄) to 0.

Tapeworm is grouped in the phylum Platyhelminthes​

Answers

Answer:

Tapeworm, also called cestode, any member of the invertebrate class Cestoda (phylum Platyhelminthes), a group of parasitic flatworms containing about 5,000 species. ... Tapeworms also lack a circulatory system and an organ specialized for gas exchange.

HELP!!!!! Substance A and substance B are mixed together. To separate the mixture, water is added, and substance A is filtered out. Then, the remaining liquid is heated to remove the water, leaving a residue of substance B. Which statement about substance A and substance B could be correct?

A. Substance A is rice, and substance B is sugar.

B. Substance A is alcohol, and substance B is salt.

C. Substance A is sand, and substance B is alcohol.

D. Substance A is sugar, and substance B is instant coffee.

Answers

The answer is A

EXPLANATION

Substance A which is rice when mixed with water can be filtered to get the rice back

Substance B which is sugar when mixed with water becomes Diluted and you can get it back only by heating or boiling For the water to Evaporate and sugar crystals will Be left To form on The sides Of the pot in which it’s Heated which is the residue of substance

The statement that "substance A is rice, and substance B is sugar" is correct.

WHAT IS A MIXTURE?

A mixture in chemistry is a substance that contains two or more different substances.

One notable characteristics of a mixture is that it can easily be separated using physical means.

According to this question, a mixture contains two substances A and B. Water is added to this mixture for easy separation.

Substance A is filtered out. This means that substance A is a solid that is insoluble in water. This substance is RICE.

The remaining liquid is heated to remove the water content leaving a residue of substance B. This shows that substance B is also a solid but soluble in water. SUGAR best fits this description.

Therefore, in the mixture of two substances A and B, substance A is rice, and substance B is sugar.

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what is the charge on the Mn ions in Mn2o3? 1+, 2+, 3+,3-,4+?

Answers

hey here’s your answer hope this helps you!!!!

What is Bose Einstein state of matter and their examples

Answers

Answer:

A BEC ( Bose - Einstein condensate ) is a state of matter of a dilute gas of bosons cooled to temperatures very close to absolute zero is called BEC.

Examples - Superconductors and superfluids are the two examples of BEC.

Explanation:

What is the minimum pressure in kPa that must be applied at 25 °C to obtain pure water by reverse osmosis from water that is 0.690 M in sodium chloride and 0.08 M in zinc sulfate? Assume complete dissociation for electrolytes.

Answers

Answer:

1. Water purification method by reverse osmosis – membrane filtration

2. Method of purifying pure water by filter

3. Demineralization by ion exchange method

3. Demineralization by ion exchange method

Explanation:

calculate the total consumer surplus in the amusement park market if they a 12

Answers

Answer:

The total consumer surplus is 240.

Explanation:

If p=12 then q=20

0.5×(36−12)×20=240

here's the graph to help you see the change.

What does quantization refer to?

Answers

Answer:

Quantization is the process of constraining an input from a continuous or otherwise large set of values (such as the real numbers) to a discrete set (such as the integers).

Explanation:

Quantization refers to the situation where an electromagnetic field consists of discrete energy parcels, photons.

What is Quantatization in Chemistry ?

In Chemistry , the concept that a system cannot have any possible energy value but instead is limited to certain specific energy values (states). This states depend on the specific system in question.

Under this system, Energy could be gained or lost only in integral multiples of some smallest unit of energy, a quantum (the smallest possible unit of energy).

Hence, Quantization refers to the situation where an electromagnetic field consists of discrete energy parcels, photons.

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Which of the following are examples of single replacement reactions? Select all that apply.

Answers

Answer:

Na2S(aq)+Cd(No3)2(aq)=CdS(s)+2NaNo3(aq)

Answer: it’s checkbox 2&3

What can be found on the periodic table?
A. the name of molecules formed by the element
B. the number of isotopes an element has
C. the date an element was discovered
D. the number of protons an element has​

Answers

Answer:

I think the answer is..

The name of molecules formed by the element.

I hope it will help you !

I think it’s A, none of the other letters showed up when I looked at the periodic table

The solubility of lithium fluoride, LiF, is 1.6 g/L, or 6.2 x 10â2 M.
a. Write the balanced solubility equilibrium equation for LiF.
b. Determine the molar concentration of the lithium ion and the fluoride ion.
c. Write the Ksp expression for the reaction.
d. Calculate Ksp for lithium fluoride.

Answers

Answer:

a. LiF(s) ⇄ Li⁺(aq) + F⁻(aq)

b. [Li⁺] = [F⁻] = 6.2 x 10⁻² M

c. Ksp = [Li⁺] [F⁻]

d. Ksp = 3.8 × 10⁻³

Explanation:

The solubility (S) of lithium fluoride, LiF, is 1.6 g/L, or 6.2 x 10⁻² M.

a. The balanced solubility equilibrium equation for LiF is:

LiF(s) ⇄ Li⁺(aq) + F⁻(aq)

b. We will make an ICE chart.

        LiF(s) ⇄ Li⁺(aq) + F⁻(aq)

I                       0           0

C                     +S         +S

E                       S           S

Then, [Li⁺] = [F⁻] = S = 6.2 x 10⁻² M

c. The solubility product constant, Ksp​, is the equilibrium constant for a solid substance dissolving in an aqueous solution.

Ksp = [Li⁺] [F⁻]

d.

Ksp = [Li⁺] [F⁻] = (6.2 x 10⁻²)² = 3.8 × 10⁻³

3 molecules NaOH determine the amount of grams

Answers

Answer:

In three mocelus 0.0001 gram.

The color cyan has a frequency of 5.902x10^14 What is the wavelength in nm ? Record your answer with 2
decimals.

Answers

The wavelength of the color cyan is 508 nm.

To solve the problem, we use the following equation that relates the frequency (ν) and the wavelength (λ) of a wave:

c = λ x ν

Given:

c = speed of light = 3.00 x 10⁸ m/s (is a constant)

ν = 5.902 x 10¹⁴ Hz = 5.902 s⁻¹

We introduce the data to calculate the wavelength in m:

λ = c/ν = (3.00 x 10⁸ m/s)/(5.902 s⁻¹) = 5.08 x 10⁻⁷ m

We know that 10⁻⁹m = 1 nm, so we convert λ to nm:

λ = 5.08 x 10⁻⁷ m x 1 nm/10⁻⁹m = 508 nm

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Give the amino acid sequence in the following tetrapeptide using both 3-letter and 1-letter abbreviations for the amino acids. (Capitalize amino acid abbreviations appropriately.) ball

Answers

Answer:

ggggggggggggg

Explanation:

gggggggggggthyjum

what is calcium anyone tell plz​

Answers

Answer:

Calcium is a chemical element with the symbol Ca and atomic number 20.

Calcium is a mineral that is necessary for life. In addition to building bones and keeping them healthy, calcium enables our blood to clot, our muscles to contract, and our heart to beat. About 99% of the calcium in our bodies is in our bones and teeth.

Which of the following substances can be used to neutralize HF?

A: HF
B: SO2
C: HCI
D: NaOH

Answers

Answer:

option (D) NaOH is right answer

A neutralization reaction is "a reaction in which an acid and a base react to form water and a salt and involves H+ ions and OH- ions to produce water.

What is an acid?

An acid is "any hydrogen-containing substance that is capable of donating a proton or hydrogen ion to another substance".

What is base?

Base is "a substance that gets dissociated in an aqueous solution to form hydroxide ions OH-".

Hence, NaOH can be used to neutralize HF.

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Hydrogengasand oxygengas react to form water vapor. Suppose you have of and of in a reactor. Calculate the largest amount of that could be produced. Round your answer to the nearest .

Answers

The question is incomplete. The complete question is :

Hydrogen [tex](H_2)[/tex] gas and oxygen [tex](O_2)[/tex] gas react to form water vapor [tex](H_2O)[/tex]. Suppose you have 11.0 mol of [tex]H_2[/tex] and 13.0 mol of [tex]O_2[/tex] in a reactor. Calculate the largest amount of [tex]H_2O[/tex] that could be produced. Round your answer to the nearest 0.1 mol .

Solution :

The balanced reaction for reaction is :

[tex]$2H_2(g) \ \ \ \ + \ \ \ \ \ O_2(g)\ \ \ \rightarrow \ \ \ \ 2H_2O(g)$[/tex]

11.0                      13.0

11/2                       13/1     (dividing by the co-efficient)

6.5 mol               13 mol    (minimum is limiting reagent as it is completely consumed during the reaction)

Therefore, [tex]H_2[/tex] is limiting reagent. It's stoichiometry decides the product formation amount from equation above it is clear that number of moles for [tex]H_2O[/tex] will be produced = number of moles of [tex]H_2[/tex]

                                     = 11.0 mol

the ability for carbon to form long chain or rings is

Answers

califactual. thsi is correct bcuz carbon takes 20 minutes to dissolve and ring making it a factual

Calculate the enthalpy change for the reaction of hydrogen and chlorine using the bond energies below.
"BOND." " BOND ENERGY "
H-H. 436
CL-CL. 242
H-CL. 431 ​

Answers

Answer:

final-intial temperature= enthalpy change

What volume (in liters) of a solution contains 0.14 mol of KCl?
1.8 M KCl
Express your answer using two significant figures.

Answers

Answer:

[tex]\boxed {\boxed {\sf 0.078 \ L }}[/tex]

Explanation:

We are asked to find the volume of a solution given the moles of solute and molarity.

Molarity is a measure of concentration in moles per liter. It is calculated using the following formula:

[tex]molarity= \frac{moles \ of \ solute}{liters \ of \ solution}[/tex]

We know there are 0.14 moles of potassium chloride (KCl), which is the solute. The molarity of the solution is 1.8 molar or 1.8 moles of potassium chloride per liter.

moles of solute = 0.14 mol KCl molarity= 1.8 mol KCl/ Lliters of solution=x

Substitute these values/variables into the formula.

[tex]1.8 \ mol \ KCl/ L = \frac { 0.14 \ mol \ KCl}{x}[/tex]

We are solving for x, so we must isolate the variable. First, cross multiply. Multiply the first numerator and second denominator, then the first denominator and second numerator.

[tex]\frac {1.8 \ mol \ KCl/L}{1} = \frac{0.14 \ mol \ KCl}{x}[/tex]

[tex]1.8 \ mol \ KCl/ L *x = 1*0.14 \ mol \ KCl[/tex]

[tex]1.8 \ mol \ KCl/ L *x = 0.14 \ mol \ KCl[/tex]

Now x is being multiplied by 1.8 moles of potassium chloride per liter. The inverse operation of multiplication is division, so we divide both sides by 1.8 mol KCl/L.

[tex]\frac {1.8 \ mol \ KCl/ L *x}{1.8 \ mol \ KCl/L} = \frac{0.14 \ mol \ KCl}{1.8 \ mol \ KCl/L}[/tex]

[tex]x= \frac{0.14 \ mol \ KCl}{1.8 \ mol \ KCl/L}[/tex]

The units of moles of potassium chloride cancel.

[tex]x= \frac{0.14 }{1.8 L}[/tex]

[tex]x=0.07777777778 \ L[/tex]

The original measurements of moles and molarity have 2 significant figures, so our answer must have the same. For the number we found, that is the thousandth place. The 7 in the ten-thousandth place tells us to round the 7 up to a 8.

[tex]x \approx 0.078 \ L[/tex]

There are approximately 0.078 liters of solution.

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