Mia is trying to find the height of a radio antenna on the roof of a local building. She stands at a horizontal distance of 15 meters from the building. The angle of elevation from her eyes to the roof (point A) is 18 degrees, and the angle of elevation from her eyes to the top of the antenna (point B) is 53 degrees. If her eyes are 1.75 meters from the ground, find the height of the antenna (the distance from point A to point B). Round your answer to the nearest tenth of a meter if necessary.

The linear correlation between the given two variables be,

4.5y + 5.2x = 168.34

Given, data for a classroom of students who measured each (approximately) in inches.

Femur Length 18.7 14.2 20.5 15.9 16.2 13.1 15.0 12.4 19.0 16.2 21.3

Tibia Length  15.8 21.0 16.2 14.3 12.1 15.8 13.0 18.8 14.3 18.7 13.8

we have to find a linear correlation between the two variables,

linear correlation be,

(y - 15.8)/(x - 18.7) = (15.8 - 21.0)/(18.7 - 14.2)

(y - 15.8)/(x - 18.7) = (- 5.2)/4.5

4.5y - 71.1 = -5.2x + 97.24

4.5y + 5.2x = 168.34

So, the linear correlation between the given two variables be,

4.5y + 5.2x = 168.34

Hence, the linear correlation between the given two variables be,

4.5y + 5.2x = 168.34

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Answer:(0,-3)

Step-by-step explanation:

Answer:

(0,-3)

Step-by-step explanation:

just fill in the coordinates to see if it’s true

3=2(2)-3

3=4-3

3-1

Not true

-1=2(-2)-3

-1=-4-3

-1=-7

Not true

1=2(4)-3

1=8-3

1=5

Not true

-3=2(0)-3

-3=0-3

-3=-3

True

Hopes this helps please mark brainliest

Answer:

[tex]\huge\boxed{\sf h = 24}[/tex]

Step-by-step explanation:

So,

2h + 8 + 3h - 3 + 31 + h = 180

Combine like terms

2h + 3h + h + 8 - 3 + 31 = 180

6h + 36 = 180

Subtract 36 to both sides

6h = 180 - 36

6h = 144

Divide 6 to both sides

h = 144/6

[tex]\rule[225]{225}{2}[/tex]

Answer:i don't know I just need the points

Step-by-step explanation:

The value of x from the inequality equation | 4x + 1 | ≤ 6 , is

-7/4 ≤ x ≤ 5/4

What is an Inequality Equation?

Inequalities are the mathematical expressions in which both sides are not equal. In inequality, unlike in equations, we compare two values. The equal sign in between is replaced by less than (or less than or equal to), greater than (or greater than or equal to), or not equal to sign.

In an inequality, the two expressions are not necessarily equal which is indicated by the symbols: >, <, ≤ or ≥.

Given data ,

Let the equation be A

The value of the equation A is | 4x + 1 | ≤ 6   be equation (1)

From the modulus function rule , we know

If , | x | ≤ a , then -a ≤ x ≤ a

So , on simplifying the equation , we get

-6 ≤ 4x + 1 ≤ 6

Now , the two values are

4x + 1 ≥ -6   be equation (2)

4x + 1 ≤ 6    be equation (3)

From equation (2) , 4x + 1 ≥ -6

Subtracting 1 on both sides , we get

4x ≥ -7

Divide by 4 , we get

x ≥ -7/4

And , From equation (3) , 4x + 1 ≤ 6

Subtracting 1 on both sides , we get

4x ≤ 5

Divide by 4 on both sides , we get

x ≤ 5/4

Therefore , the solution is -7/4 ≤ x ≤ 5/4 and the graph is given below

Hence , The value of x from the inequality equation | 4x + 1 | ≤ 6 , is

-7/4 ≤ x ≤ 5/4

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The statemet 2, the variable K represent carrying capacity and the variable N represent population size, is correct.

In the given question we have to review the video to determine whether each statement about the following equation is true or false.

The given equation is:

[tex]\frac{dN}{dt}=rN(\frac{K-N}{K})[/tex]

The given equation is used to find the annual growth of population.

In which, dN/dt = the annual increase for the population,

r = the annual growth rate,

N = the population size, and

K = the carrying capacity.

So the statemet two, the variable K represent carrying capacity and the variable N represent population size, is correct.

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We have sufficient evidence to conclude that the over all percentages of 3 categories are not same.

The percentage refers to a specific percentage out of a hundred. It is a fraction with the denominator 100, and the sign for it is 1%.

The Latin word per centum, which means "hundred" or "by the hundred," is the source of the word "percent." The Italian phrase per cento, which means "for a hundred," gradually shrank to become the symbol for "percent," which is now used globally. It finally vanished totally. The word "per" was frequently shortened to "p." The contemporary "%" symbol was created by condensing the "cento" to two circles divided by a horizontal line.

Category    Observed([tex]O_{i}[/tex])          Expected([tex]E_{i}[/tex])              ([tex]O_{i}[/tex]-[tex]E_{i}[/tex])²/[tex]E_{i}[/tex]

A or B           100                           120                          3.333

C                   130                           105                          5.9524

D or F             70                            75                            0.056

Total               300                        300                         9.3417

H₀:over percentages are same at UC Davis and at SSC

H₁:They are not same

Test statistic

X²=∑  ([tex]O_{i}[/tex]-[tex]E_{i}[/tex])²/[tex]E_{i}[/tex]

=9.3417

P-value=P(X²(n-1)>9.3417)

=0.0094

Here we can see that the P-value is very low(<0.05 and <0.01)

So, we reject the null hypothesis H₀.

Therefore, we have sufficient evidence to conclude that the over all percentages of 3 categories are not same.

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The amount of money that Margret needs to deposit to reach this amount is $8.

Expression simply refers to the mathematical statements which have at least two terms which are related by an operator and contain either numbers, variables, or both. Addition, subtraction, multiplication, and division are all possible mathematical operations.

Since Margret has $32.00 in a savings account. Margret wants to have a balance of $40.00 in the account, the amount needed will be:

= $40 - $32

= $8

She'll need $8 more.

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The sum of x and y i.e (x+y) is equal to 23

When two diagonals of a parallelogram bisect each other. Each diagonal bisects the parallelogram into two congruent triangles. The Sum of the square of all the sides of a parallelogram is equal to the sum of the square of its diagonals.

This implies that line uz = wz, and vz= tz

therefore 3y+6= 2x equation 1

since vt = 78

5y-1= 78-(5y-1) equation 2

5y-1= 78-5y+1

collecting like terms,

5y+5y= 78+1+1

10y= 80

divide both sides by 10

y= 80/10

y= 8

substituting 8 for y in equation 1

3×8+6= 2x

24+6= 2x

30= 2x

divide both sides by 2

x= 30/2= 15

therefore the sum of x and y = 15+8= 23

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By using the concept of maxima, it can be calculated that

Volume is maximum if the radius of the cone is 40 cm

What is maxima of a function?

Maxima of a function gives the maximum value of the function on a certain interval or on the whole domain.

Let the height of the cylinder be h and radius be r

Sum of height and circumference = h + 2πr

By the problem,

h + 2πr = 60

h = 60 -2πr

Volume(V) = π[tex]r^2[/tex] h

             = π[tex]r^2[/tex](60 - r)

             = 60π[tex]r^2[/tex] - π[tex]r^3[/tex]

[tex]\frac{dV}{dr} = 120\pi r - 3 \pi r^2[/tex]

For maximum volume

[tex]\frac{dV}{dr} = 0[/tex]

[tex]120\pi r - 3 \pi r^2 = 0\\[/tex]

[tex]3 r^2 = 120 r\\3r = 120 [r \neq 0]\\r = \frac{120}{3}\\r = 40 \ cm[/tex]

[tex]\frac{d^2V}{dr^2} = 120 \pi - 6 \pi r\\[/tex]

Putting r = 40

[tex]\frac{d^2V}{dr^2} = 120 \pi - 6 \pi \times 40\\\frac{d^2V}{dr^2} =120\pi - 240 \pi\\\frac{d^2V}{dr^2} = -120\pi < 0[/tex]

Hence Volume is maximum

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In this Trigonometric Functions F(x) = 1 + cos(1/X):  n=3 (12.01, 8.10),  n=4 (11.65,8.50), and n=6 (11.24, 9.12), with their upper and lower value

What is Trigonometric Functions?

Trigonometry uses six fundamental trigonometric operations. Trigonometric ratios describe these operations. The sine function, cosine function, secant function, co-secant function, tangent function, and co-tangent function are the six fundamental trigonometric functions. The ratio of sides of a right-angled triangle is the basis for trigonometric functions and identities. Using trigonometric formulas, the sine, cosine, tangent, secant, and cotangent values are calculated for the perpendicular side, hypotenuse, and base of a right triangle.

F(x) = 1 + cos(1/X)

for n=3

Upper sum = 12.01

Lower sum = 8.10

Δx = (b-a)/n = 2π / 3

for n=4

Upper sum = 11.65

Lower sum = 8.50

Δx = (b-a)/n = π / 2

for n=6

Upper sum = 11.24

Lower sum = 9.12

Δx = (b-a)/n = π / 3

Hence, n=3 (12.01, 8.10),  n=4 (11.65,8.50), and n=6 (11.24, 9.12), with their upper and lower value.

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The system of equations are

The solution of the equation from the graph is

The system of equations is derived from the statements as interpreted below

If x represents the number of hours lifeguarding and y represents the number of hours tutoring

number of hours lifeguarding = x  

number of hours tutoring = y

she can work no more than 11 total hours

x + y not more than 11 hours

x + y < 11

making $14 per hour lifeguarding and making $25 per hour tutoring and must earn no less than $200

$14x + $25y no less than $200

14x + 25y > 200

The required equations are

14x + 25y > 200

x + y < 11

The graph is attached

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The angles ∠BCD and ∠BAD are opposite interior angles of a parallelogram. in which the alternate interior angles  ∠BAC  and  ∠ACD and ∠BCA and ∠DAC are congruent, from which by angle addition property, ∠BCD ≅ ∠BAD

Alternate interior angles are angles formed by the transversal to two parallel lines on the inside of the parallel lines, and on opposite sides of the transversal.

The two column-method used to  prove that ∠BCA is congruent to ∠DAC can be presented as follows;

Step       [tex]{}[/tex]         Statement                                          Reason

1.        [tex]\overline{BC}[/tex]║ [tex]\overline{AD}[/tex],  [tex]\overline{AB}[/tex]║[tex]\overline{CD}[/tex]   [tex]{}[/tex]       Given

2. [tex]{}[/tex]    ∠BCA ≅ ∠DAC                  ║ lines cut by a trans. form ≅ int.  ∠s

3. [tex]{}[/tex]    [tex]\overline{AC}[/tex]║[tex]\overline{CA}[/tex]     [tex]{}[/tex]                         Reflexive Property

4.     ∠BAC ≅ ∠ACD [tex]{}[/tex]                  Alternate interion angles

5.     ∠BCA = ∠DAC[tex]{}[/tex]                    Definition of congruency

[tex]{}[/tex]        ∠BAC = ∠ACD

6.    ∠BCD = ∠BCA + ∠ACD[tex]{}[/tex]       Angle addition property

      ∠BAD = ∠BAC + ∠DAC

7.    ∠BCD = ∠BCA + ∠ACD  [tex]{}[/tex]       Substitution property

8. [tex]{}[/tex]   ∠BCD = ∠BAD   [tex]{}[/tex]                    Substitution property

9.    ∠BCD ≅ ∠BAD   [tex]{}[/tex]                    Definition of congruency

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Answer: a

Step-by-step explanation:

The value of n from the given parallel lines is 6. Therefore, the option A is the correct answer.

Angles in parallel lines are angles that are created when two parallel lines are intersected by another line called a transversal.

Given that, the angles from the parallel lines are (3n+16)° and (5n+4)°.

Here, (3n+16)°=(5n+4)° (Interior alternate angles are equal)

5n-3n=16-4

2n=12

n=6

Therefore, the option A is the correct answer.

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The graph that shows the equation, y = -5x + 45, that represents the scenario given is shown in the attachment.

Determine the slope (m) and the y-intercept (b), then input the values in the equation, y = mx + b, to write the equation of the line that would be graphed.

Given the information above, we have the following:

Let x = hours, and y = quantity  of gallons of paint left

Slope (m) = -5

Y-intercept (b) = 45

Write the equation of the graph by substituting m = 5 and b = 45 into y = mx + b:

y = -5x + 45

The graph shown below for y = 5x + 45 would be labelled as follows:

x-axis = hours

y-axis = quantity of paint (in gallons)

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The journey along Line segment X Y is longer than the path along Line segment Z Y, and the path along Line segment Z Y is longer than the path along Line segment A B, hence Option-A is the correct answer.

Given that,

He makes paths that follow Line segments A and B, X and Y, and Z and Y through the garden.

We have to find which accurately compares the pathways' lengths.

We know that,

The length of the third side in a triangle is proportional to the angle Ф  if the lengths of the two sides that make up the angle Ф are fixed.

XY > YZ because XY's opposing angle (79°) is greater than YZ's (65°).

As before, YZ > AB because the opposing angle of YZ (65°) is greater than that of AB (36°).

Since both sides of the angle are the same length (8 feet),

As a result, assertion A. is accurate. (Answer)

Therefore, The journey along Line segment X Y is longer than the path along Line segment Z Y, and the path along Line segment Z Y is longer than the path along Line segment A B, hence Option-A is the correct answer.

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Answer:

It's A

Step-by-step explanation:

I got 100 on the quiz

If Kayden is a stunt driver and one time, during a gig where she escaped from a building about to explode . the equation for the relationship between the distance and number of seconds is : D(t) = -25t + 160.

First step is to find kayden speed using this formula

Speed = Distance/Time

Speed = 85-160/3

Speed = -75/3

Speed = -25t

Hence, the equation for the relationship  between the distance and number of seconds is

D(t) = -25t + 160

Therefore we can conclude that  the equation is D(t) = -25t + 160.

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The length of the other leg of the given right triangle is [tex]\sqrt{70}[/tex].

A triangle is classified as a right triangle when it presents one of your angles equal to 90º.  The greatest side of a right triangle is called the hypotenuse. And, the other two sides are called legs.

The math tools applied for finding angles or sides in a right triangle are the trigonometric ratios or the Pythagorean Theorem.

The Pythagorean Theorem says (hypotenuse)²= (leg1)²+(leg2)². And the main trigonometric ratios are: sin (x) , cos  (x) and tan  (x) .

The question gives:

Therefore, from the Pythagorean Theorem, you will find the value of the other leg. See below.

[tex]9^2={\sqrt{11}^2 +{leg_2}^2[/tex]

[tex]81=11 +{leg_2}^2[/tex]

[tex]{leg_2}^2=81-11\\ \\ {leg_2}^2=70\\ \\ leg_2=\sqrt{70}[/tex]

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On simplifying for variable, we get -

G = - 20

A mathematical expression is made up of terms (constants and variables) separated by mathematical operators. A mathematical equation is used to equate two expressions. Equation modelling is the process of writing a mathematical verbal expression in the form of a mathematical expression for correct analysis, observations and results of the given problem.

We have the following equation -

(G-2)/(2-24) = 0

We have -

(G-2)/(2-24) = 0

G - 2 = 2 - 24

G - 2 = - 22

G = - 22 + 2

G = - 20

Therefore, on simplifying for variable, we get -

G = - 20

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The smallest number of consumers that Timex can survey to guarantee a margin error of 0.05 or less at a 99% confidence level is 700. Option D.

The z critical value at 99% confidence interval is given as 2.58

To get the sample size, we have to make use of the formula that is written as

n = (Z critical / ME)² p(1 - p)

the proportion is not given, hence we would assume it to be 50 percent

When we put the values in the formula above we would have:

(2.58 / 0.05)²0.5(1 - 0.5)

2662.56 * 0.5 * 0.5

= 665.64

This value would be approximated to the nearest hundred, hence the sample number would be 700. Option D.

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Answer:

15 cats

Step-by-step explanation:

c:d

3:5

5=25

25/5=5

5*3=15

15 cats

======================================================

Explanation:

The tape diagram is shown below.

"C" represents a sub-group of cats, and "D" represents a sub-group of dogs. Each sub-group has the same number of animals.

There are 3 copies of "C" and 5 copies of "D" to represent the ratio 3:5 of cats to dogs. For every 3 cats, there are 5 dogs.

We are told there are 25 dogs available for adoption. This consists of all five blocks of "D" combined. If each "D" is the same number of dogs, then there must be 25/5 = 5 dogs per "D" block. By extension, there are 5 cats per "C" block.

In short, each block has 5 animals.

3 blocks of C = 3*5 = 15 cats are available.

-----------------

Another approach:

C = number of cats available = unknown

D = number of dogs available = 25

C/D = 3/5

C/25 = 3/5

5C = 25*3 ... cross multiply

5C = 75

C = 75/5

C = 15 cats are available

-----------------

A third approach:

The ratio 3:5 scales up to 15:25 after multiplying both parts by 5. This is so the "5" in "3:5" becomes "25".

The ratio of cats to dogs of 15:25 reduces to 3:5 when you divide both parts by the GCF 5.

So this is another way to see how 15 cats are available.

ΔXYZ will also be an equilateral triangle.

What is equilateral triangle?

An equilateral triangle in geometry is a triangle with equal-length sides on all three sides. In the well-known Euclidean space, an equilateral triangle also is equiangular, meaning that each of its three internal angles is 60 degrees and congruent with the others. It's also referred to it as a regular triangle because it is a regular polygon.

As X,Y,Z are the midpoints of sides of equilateral triangle so when we will join the X,Y,Z we will find that distances XY=YZ=XZ are three are equal because this is proved by similarity of triangles which in itself is a detailed and vast topic

Hence XYZ will also be an equilateral triangle

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Answer:

ratio of amount of skills to time is 1:4

Step-by-step explanation:

1 skill is 4 seconds. so for 5 skills it would be 20 seconds

Answer:

(i)  See below for proof.

(ii)  x = 1.823,   x = -0.823

Step-by-step explanation:

Given equation:

[tex]\dfrac{x+2}{x+1}+\dfrac{3}{x}=3[/tex]

Make the denominators of the fractions the same:

[tex]\implies \dfrac{x+2}{x+1}\cdot \dfrac{x}{x}+\dfrac{3}{x}\cdot \dfrac{x+1}{x+1}=3[/tex]

[tex]\implies \dfrac{x(x+2)}{x(x+1)}+\dfrac{3(x+1)}{x(x+1)}=3[/tex]

[tex]\textsf{Apply the fraction rule} \quad \dfrac{a}{c}+\dfrac{b}{c}=\dfrac{a+b}{c}:[/tex]

[tex]\implies \dfrac{x(x+2)+3(x+1)}{x(x+1)}=3[/tex]

Multiply both sides of the equation by x(x + 1) to eliminate the denominator of the fraction on the LHS:

[tex]\implies x(x+2)+3(x+1)=3x(x+1)[/tex]

Expand the brackets:

[tex]\implies x^2+2x+3x+3=3x^2+3x[/tex]

[tex]\implies x^2+5x+3=3x^2+3x[/tex]

Subtract x² from both sides:

[tex]\implies 5x+3=2x^2+3x[/tex]

Subtract 5x from both sides:

[tex]\implies 3=2x^2-2x[/tex]

Subtract 3 from both sides:

[tex]\implies 0=2x^2-2x-3[/tex]

[tex]\implies 2x^2-2x-3=0[/tex]

[tex]\boxed{\begin{minipage}{3.6 cm}\underline{Quadratic Formula}\\\\$x=\dfrac{-b \pm \sqrt{b^2-4ac}}{2a}$\\\\when $ax^2+bx+c=0$ \\\end{minipage}}[/tex]

To solve the quadratic equation  [tex]2x^2-2x-3=0[/tex],  use the quadratic formula.

Therefore:

Substitute these values into the formula and solve for x:

[tex]\implies x=\dfrac{-(-2) \pm \sqrt{(-2)^2-4(2)(-3)}}{2(2)}[/tex]

[tex]\implies x=\dfrac{2 \pm \sqrt{4+24}}{4}[/tex]

[tex]\implies x=\dfrac{2 \pm \sqrt{28}}{4}[/tex]

[tex]\implies x=\dfrac{2 \pm \sqrt{4 \cdot 7}}{4}[/tex]

[tex]\implies x=\dfrac{2 \pm \sqrt{4} \sqrt{7}}{4}[/tex]

[tex]\implies x=\dfrac{2 \pm 2 \sqrt{7}}{4}[/tex]

[tex]\implies x=\dfrac{1 \pm \sqrt{7}}{2}[/tex]

Therefore, the solutions correct to 3 decimal places are:

[tex]x=1.823,\;\; x= -0.823[/tex]

The mean lifetime of a bulb is 149.37 hours.

What is the meaning of mean?

By dividing the sum of the given numbers by the entire number of numbers, the mean—the average of the given numbers—is determined. Mean is equal to (Sum of All Observations/Total Observations).

The given table represents a continuous data.

The table attached in below. To get mean lifetime of a bulb, find the mean of the given table.

The formula for mean is = Σ fm/N

Where f is frequency and m is midpoint of the class.

N is total number of observation.

From the table, Σ fm = 53175

Total number of bulb is 356.

The mean lifetime is 53175/ 356 = 149.37 hours

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To maximize the profit 29.6 units must be produced.

What is the maxima or minima?

The maxima and minima of a function collectively referred to as extrema in mathematical analysis, are the highest and lowest values of the function, either on the whole domain or within a specific range.

We have given,

The revenue function is,

R(x)=3x

Cost function,

C(x)=0.05x^2+0.04x+10,

Where

x = number of units produced.

Thus, profit = revenue - cost

P(x) = 3x - (0.05x^2+0.04x+10)

= -0.05x^2 + 2.96x - 10

Differentiating with respect to x,

P'(x) = -0.1x + 2.96

Again differentiating with respect to x,

P''(x) = -0.1

For maxima or minima,

P'(x) = 0,

0 = -0.1x + 2.96

-0.1x = -2.96

x = 2.96/0.1

For x = 29.6,

P''(x) = negative,

Hence, to maximize the profit 29.6 units must be produced.

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When presenting chunks of information, bar charts should be used. As long as there aren't too many categories to contrast, vertical bar charts can be useful for comparing several discrete or categorical variables, such as age groups, courses, and schools. For time series data, they are also highly beneficial.

Why would one use a bar chart?

To show a frequency distribution for qualitative data, bar charts are frequently employed.

                   The axis used to measure the bars should always begin at zero, unless there is a valid reason for doing otherwise.

                  Otherwise, the axis can be stretched to magnify differences in the lengths of the bars. A title and the axis labels are required for bar charts.

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True, Alyssa is learning to drive and is paying close attention to the road conditions, other vehicles on the road, and traffic signs and signals. This focus is a quality of hers.

What is Focus during the Drive?

It means to concentrate only on driving during the time of driving to avoid accidents etc. Yeah when she is driving the car she must focus intently on car and on nothing else because she is a beginner. When people get experience in driving cars they use mobile phones etc kind of things easily during driving but beginners have to be careful a lot regarding this. Its very very good if she is also focusing road signs like zebra crossing and where traffic signals are there it would help her in great way

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#SPJ4

x=0

Step-by-step explanation:

4(x+1)=2x+4

Distribute

4x+4 = 2x+4

Subtract 4 from each side

4x+4-4 = 2x+4-4

4x= 2x

Subtract 2x from each side

4x-2x = 2x-2x

2x=0

Divide by 2

x =0