Most of the energy produced today from wood to energy systems is related to the industries that produce wood residuals (pulp and paper, lumber mills, etc).A. TrueB. False

Answers

Answer 1

Answer:

The correct answer is false

Explanation:

Most of the energy produced today from wood to energy systems is related to woods used as fuels which are referred to as "woodfuel". Woodfuel could be in the solid form (as in firewood/fuelwood, charcoal and wood pellets), liquid form (bio-oil and bio-ethanol) and gaseous form (wood gas).

Woodfuel in the form of firewood is majorly used all over the world, particularly in developing countries, for cooking and in developed countries for making fire to regulate temperature.

NOTE: This answer assumes the question refers to energy produced from wood all over the world and not restricted to a particular country or location.


Related Questions

21.Which of the following contain the molecules with the highest average speed?
C
L 나
G G
ico
cube
at -10°C
water
at roon
temperature
wood
at room
temperature
steam
at 110°C​

Answers

Is this high school or college? I’m scared

things that affects the demand for electricity

Answers

New inventions like :
Solar panel
Wind mill
And etc .

A thin spherical shell has a radius of 0.70 m. An applied torque of 860 N m gives the shell an angular acceleration of 4.70 rad/s2 about an axis through the center of the shell. What is the rotational inertia of the shell about the axis of rotation

Answers

Answer:

[tex]I=182.97\ kg-m^2[/tex]

Explanation:

Given that,

Radius of a spherical shell, r = 0.7 m

Torque acting on the shell, [tex]\tau=860\ N[/tex]

Angular acceleration of the shell, [tex]\alpha =4.7\ m/s^2[/tex]

We need to find the rotational inertia of the shell about the axis of rotation. The relation between the torque and the angular acceleration is given by :

[tex]\tau=I\alpha[/tex]

I is the rotational inertia of the shell

[tex]I=\dfrac{\tau}{\alpha }\\\\I=\dfrac{860}{4.7}\\\\I=182.97\ kg-m^2[/tex]

So, the rotational inertia of the shell is [tex]182.97\ kg-m^2[/tex].

An artery with cross sectional area of 1 cm2 branches into 20 smaller arteries each with 0.5 cm2 cross sectional area. If the velocity of blood in the thicker artery is v, what is the velocity of the blood in the thinner arteries

Answers

Answer:

The velocity of the blood in the thinner arteries is 0.1 times that of the thicker artery.

Explanation:

To find the velocity of the blood we need to use the continuity equation:

[tex] n_{1}A_{1}v_{1} = n_{2}A_{2}v_{2} [/tex]   (1)  

Where:

n: is the number of branches

A: is the cross-sectional area

v: is the velocity

For artery 1, we have:

n₁ = 1, A₁ = 1 cm², v₁ = v

For the 20 arteries (2), we have:

n₂ = 20, A₂ = 0.5 cm², v₂ =?

By using equation (1):

[tex] n_{1}A_{1}v_{1} = n_{2}A_{2}v_{2} [/tex]

[tex] 1 cm^{2}*v = 20*0.5 cm^{2}*v_{2} [/tex]

[tex] v_{2} = \frac{1 cm^{2}*v}{20*0.5 cm^{2}} = \frac{v}{10} = 0.1v [/tex]

Therefore, the velocity of the blood in the thinner arteries is 0.1 times that of the thicker artery.

I hope it helps you!      

Full moon is located______

a. farthest from the Sun

b. at a 90 degree angle with the Sun and Earth

c. closest to the Sun

Answers

Answer:

Im going to take an educated guess and say its B.

Explanation:

A Full moon is located farthest from the Sun. Thus, the correct option for this question is A.

What is a Full moon?

A full moon may be defined as one of the types of lunar phases when the Moon significantly appears fully illuminated from Earth's perspective. This event typically occurred when Earth is located between the Sun and the Moon.

When the earth is located between the sum and the moon, it is the time when the moon is located farthest from the sun. And it directs to an event of a full moon. The average time duration of the full moon and the repetition of the same phase normally requires 29.53 days.

Therefore, the Full moon is located farthest from the Sun. Thus, the correct option for this question is A.

To learn more about the Full moon, refer to the link:

https://brainly.com/question/15032553

#SPJ2

Moderate injuries are generally __________.
A.
life-threatening
B.
soft tissue injuries
C.
bumps and bruises
D.
too serious for first aid


Please select the best answer from the choices provided.

A
B
C
D

Answers

Answer:

B. soft tissue injuries

Explanation:

i took the test on edge and its really the only one that would make sense if you payed attention to the lesson  :)

Based on the measured force between objects that are 10 meters apart, how can you find the force between objects that are any distance apart ?

Answers

Answer:

F' = 100 F/r²

Explanation:

The gravitational force of attraction between two objects is given by the Newton's Gravitational Formula. The Newton's Gravitational Formula is as follows:

F = Gm₁m₂/r²

where,

F = Force between objects

G = Universal Gravitational Constant

m₁ = mass of first object

m₂ = mass of second object

r = distance between objects = 10 m

Therefore,

F = Gm₁m₂/10²

Gm₁m₂ = 100F   --------------------- equation (1)

Now, we consider these objects at any distance r apart. So, the force becomes:

F' = Gm₁m₂/r²

using equation (1), we get:

F' = 100 F/r²

So, if the force (F) between objects 10 m apart is known, we can find it at any distance from the above formula.

The force between objects that are any distance apart is expressed as [tex]P'=\frac{100P}{r^2}[/tex]

According to the gravitational law, the force acting on an object is directly proportional to the product of their masses and inversely proportional to the square of their distance apart. Mathematically,

[tex]P=\frac{GMm}{r^2}[/tex]

M and m are the masses

r is the distance between the masses

If the force between objects that are 10 meters apart, hence;

[tex]P=\frac{GMm}{10^2}\\P=\frac{GMm}{100}\\GMm = 100P[/tex]

To find the force between objects that are any distance apart, we will use the same formula above to have;

[tex]P'=\frac{GMm}{r^2}\\[/tex]

Substitute the result above into the expression to have:

[tex]P'=\frac{100P}{r^2}[/tex]

Hence the force between objects that are any distance apart is expressed as [tex]P'=\frac{100P}{r^2}[/tex]

Learn more on gravitational law here: https://brainly.com/question/11760568

How would the photographer use the polarizing filter to find out the direction of polarization of the light coming from the blue sky?

Answers

Answer:

by rotating the filter                    

Explanation:

Rayleigh's scattering is given by the process of the scattering of light by molecules. This is very important physical phenomenon. Polarization is also an effect of light scattering.

A photographer wishes to capture photos of some cloud formation by using the polarizing filter. So the photographer will have to rotate the polarizing filter until the intensity of the light becomes maximum such that the light polarization is acts along the axis of the filter.

A car drives 150 km SE and then 50 km due N. What is the car's displacement?

Answers

Answer:

If the car travels 150 kilometers to the Southeast, and then 50 kilometers to the North, it is understood that the car does not travel the same way out as it does back. Therefore, the car's displacement will be the sum of both distances traveled, that is, 150 + 50, which is equal to 200. Therefore, the car traveled about 200 kilometers from its starting point.

A box with weight of magnitude F_G = 2.00 N is lowered by a rope down a smooth plane that is inclined at an angle φ = 30.0 degrees about ve the horizontal. The normal force acting on the box has a magnitude n = 1.73 N, the tension force is 1.00 N, and the displacement Δr of the box is 1.80 m down the cloned plane.

What is the work W_G done on the box by the gravity?

Answers

Answer:

1.8 J

Explanation:

I had this exact question today and found someone who had solved it before, this was their response to the work done by gravity. They used the name "physicsmom"

Vertical distance = 1.8 sin 30 = .9 m

W = 2 N * .9 m = 1.8J

Good luck! I hope this helps!

The work done on the box by the gravity is 0.072 J.

The given parameters;

weight of the box, [tex]F_g[/tex] = 2 Ninclination of the rope, φ = 30⁰normal force acting on the box, n = 1.73 Ntension on the rope, T = 1 Ndisplacement of the box, Δr = 1.8 m

The work done on the box by gravity is calculated as follows;

W = FΔr

where;

F is the net horizontal force on the block

The net horizontal force on the box  is calculated as follows;

[tex]\Sigma F_x = F_g sin(\theta ) - F_k\\\\ \Sigma F_x = F_g sin(\theta ) - \mu_k F_n \\\\ \Sigma F_x = 2 \times sin(30 ) - (tan \theta) \times F_n\\\\ \Sigma F_x = 1 - (tan\ 30) \times 1.73\\\\ \Sigma F_x = 0.04 \ N[/tex]

The work done on the box by gravity is calculated as;

W = 0.04 x 1.8

W = 0.072 J.

Thus, the work done on the box by the gravity is 0.072 J.

Learn more here: https://brainly.com/question/14945453

Which form of energy has the most potential globally

a) Solar energy

b) Bio energy

c) Wind energy

d) Geothermal energy

Answers

Answer:

i think the answer is solar,

Explanation:

because it is a natural resource im sorry if im wrong

Bicyclist travels at an average velocity of 11.2 km/h [W]. How far will the bicyclist travel in 175 minutes?

Answers

Answer:

32.67km

Explanation:

~= round off

11.2km/h~3.11m/s

175minutes=10500s

10500*3.11~32, 666.67m

=32.66667km

~ 32.67km

What is the momentum of 100 kg running at 4m/s north?

Answers

The momentum is known as mass x velocity then u should say that it will be 400 kg m/s

Two masses are to collide directly with each other. One has a mass of 5 kg and a velocity of 2 m/s. The other has a mass of 3 kg and a velocity of 1 m/2. The collision is perfectly inelastic. Find the velocity of the masses after the collision.

Answers

Answer:

v₃ = 1.625 [m/s]

Explanation:

To solve this problem we must use the definition of linear momentum conservation, which tells us that momentum is conserved before and after a collision.

Since the collision is inelastic, the two bodies are joined after the collision.

P = m*v [kg*m/s]

m = mass [kg]

v = velocity [m/s]

where:

P = lineal momentum [kg*m/s]

Now, it is important to clarify that in the following equation we will take the left side of the equation as the momentum before the collision and the right side of the equal sign as the momentum after the collision.

Pbefore = Pafter

(m₁*v₁) + (m₂*v₂) = (m₁+m₂)*v₃

where:

m₁ = mass one = 5 [kg]

v₁ = velocity of the mass one = 2 [m/s]

m₂ = mass two = 3 [kg]

v₂ = velocity of the mass two = 1 [m/s]

v₃ = velocity of the combined masses after the collision [m/s]

Now replacing we have:

(5*2) + (3*1) = (5 + 3)*v₃

10 + 3 = 8*v₃

v₃ = 13/8

v₃ = 1.625 [m/s]

What are the 6 basic machines, and what are they and what can the be, and look like.

Answers

Answer:

Pulleys, levers, inclined planes, wedges, screws, and wheel and axle.

Explanation:

It will be easier to lift a load in wheel barrow if the load is moved
towards the wheel.why​

Answers

Answer:

the moment

Explanation:

the shorter the distance from the force, the lesser the torque acting on it

HELP ASAP!!!!!!!!!
Mark and Steven were conducting an investigation where they were measuring the energy of a glass marble as it rolled down a ramp. According to their calculations, the total energy of the marble decreased. Which statement below is the best explanation for the decrease in total energy?
A) It decreased because it was destroyed by the interaction with the ramp
B) The total energy always decreases in an energy conversion
C) They were incorrect; the energy totals should have been the same
D) The energy decreased because heat resulted from friction between the marble and the ramp

Answers

B) The total energy always decreases in an energy conversion,

This is because: Energy decreases as it moves up trophic levels because energy is lost as metabolic heat when the organisms from one trophic level are consumed by organisms from the next level. Trophic level transfer efficiency (TLTE) measures the amount of energy that is transferred between trophic levels

Hope this helps! ✨

Please help with this physics question

Answers

The correct answer is A continúe moving with constant velocity

Can someone please help me with this problem. I’ve tried but I can’t seem to figure it out.

Answers

The last one, Tension = 30N, Normal force = 20 N

An electron (restricted to one dimension) is trapped between two rigid walls 1.40 nm apart. The electron's energy is approximately 19 eV. (a) What is the quantum number n for the energy state that the electron occupies? (b) Based on the quantum number you found in part (a), calculate a more precise value for the electron's energy in eV), expressed to at least three significant figures. (Use any physical constants or unit conversions to at least four significant figures in your calculations.) _________ eV

Answers

Answer:

a)    n = 9.9       b)      E₁₀ = 19.25 eV

Explanation:

Solving the Scrodinger equation for the electronegative box we get

         Eₙ = (h² / 8m L²2) n²

where l is the distance L = 1.40 nm = 1.40 10⁻⁹ m and n the quantum number

 In this case En = 19 eV let us reduce to the SI system

          En = 19 eV (1.6 10⁻¹⁹ J / 1 eV) = 30.4 10⁻¹⁹ J

          n = √ (In 8 m L² / h²)

let's calculate

          n = √ (8  9.1 10⁻³¹ (1.4 10⁻⁹)²  30.4 10⁻¹⁹ / (6.63 10⁻³⁴)²

          n = √ (98)            n = 9.9

since n must be an integer, we approximate them to 10

b) We substitute for the calculation of energy

        In = (h² / 8mL2² n²

        In = (6.63 10⁻³⁴) 2 / (8 9.1 10⁻³¹  (1.4 10⁻⁹)² 10²

        E₁₀ = 3.08 10⁻¹⁸ J

we reduce eV

      E₁₀ = 3.08 10⁻¹⁸ j (1ev / 1.6 10⁻¹⁹J)

      E₁₀ = 1.925 101 eV

      E₁₀ = 19.25 eV

the result with significant figures is

        E₁₀ = 19.25 eV

what is a factor that scientists use to classify orders of soil?

Answers

climate, plant type, soil composition.

how can voltage be produced by magnetism and motion?​

Answers

Answer:

Electromagnetic Induction by a Moving Magnet

Then the action of moving a coil or loop of wire through a magnetic field induces a voltage in the coil with the magnitude of this induced voltage being proportional to the speed or velocity of the movement.

Explanation:

If the jet is moving at a speed of 1140 km/h at the lowest point of the loop, determine the minimum radius of the circle so that the centripetal acceleration at the lowest point does not exceed 6.0 g's.

Answers

Answer:

The radius is  [tex]r =1705.44 \ m[/tex]

Explanation:

From the question we are told that

   The speed is [tex]v = 1140 \ km /h = \frac{1140 * 1000}{3600} = 316.67 \ m/s[/tex]

   The centripetal acceleration is  [tex]a = 6 g's = 6 * 9.8 = 58.8 \ m/s^2[/tex]

Generally the centripetal force acting on the jet is mathematically represented as  

        [tex]F_c = \frac{m * v^2 }{r}[/tex]

Generally this centripetal force is equal to the net force acting which according to Newton's third law is mathematically  represented as

      [tex]F = m * a[/tex]

So

      [tex]\frac{m * v^2 }{r} = ma[/tex]

=>   [tex]\frac{ v^2 }{r} = a[/tex]

=>  [tex]r = \frac{v^2}{a}[/tex]

=>  [tex]r = \frac{316.67^2}{58.8}[/tex]

=>  [tex]r =1705.44 \ m[/tex]

PLZ HELP help me help help

Answers

Answer:

matter

Explanation:

Hope I helped :)

How much tension must a rope withstand if it is used to accelerate a 1200-kg car vertically upwards at 0.8m/s2?

Answers

Answer:

T = 12732 [N]

Explanation:

To solve this problem we must use newton's second law which tells us that the sum of forces on a body is equal to the product of mass by acceleration.

By means of the attached free body diagram, we can better understand the solution to this problem.

As we see in the diagram the tension Force T lifts the car upwards so the movement is upwards. Therefore we have two forces one upward (positive) of the force T and the other negative downward due to the weight of the vehicle.

As the movement is up the acceleration is also up (with a positive sign).

ΣF = m*a

where:

F = forces [N] (units of Newtons)

m = mass = 1200 [kg]

a = acceleration = 0.8 [m/s²]

T - 1200*9.81 = 1200*(0.8)

T = 12732 [N]

Answer:

12,720

Explanation:

The Amazon rainforest has millions of trees down in South America. Pantanal, the largest wetland, or swamp, on Earth sits directly below the Amazon on a map. Explain this phenomenon using processes from the water cycle.

The subject is science just to let you know.

Answers

Answer:The Pantanal is, when the season changes of the river flow, the pantanal shrinks after a few river channels The amazon rainforest has a lot of trees.The vapor rises and condenses it into clouds.Water leaves the forest and comes back, the amazon leaves itself.If the amazon water was not to go by itself everything would be different.

Answer:

Nine, Brazil, Venezuela

Explanation:

You tie the loose end of a 0.1 kg yo-yo string to your finger and then release the yo-yo so that it spins down toward the ground (the yo-yo is released from rest and the end of the string tied to your finger remains motionless). After the yo-yo falls a distance of 0.9 m, it has a translational speed of 4 m/s and an angular speed of 180 rad/s. What is the moment of inertia of the yo-yo

Answers

Answer:

The answer is "[tex]5.06 \times 10^{-6} \ kg \ m^2[/tex]"

Explanation:

[tex]\to E_1=0..............(i)\\\\\to E_2= \frac{mV^2}{2} +\frac{Iw^2}{2} - mgh.............(ii)\\\\ \Delta E=0\\\\\to mgh= \frac{mV^2}{2} +\frac{Iw^2}{2} \\\\ \to 2 \ mgh= mV^2 +Iw^2\\\\ \to 2 \ mgh- mV^2 =Iw^2\\\\ \to m(2gh- V^2) =Iw^2\\\\ \to I= \frac{m(2gh- V^2)}{w^2}[/tex]

       [tex]= 5.06 \times 10^{-6} \ kg \ m^2[/tex]

A biker first accelerates from 0.0 m/s to 6.0 m/s in 6 s, then continues at this speed for 5 s. What is the total distance traveled by the biker?

100 m

80 m

30 m

48 m

PLZ heeeeelp ​

Answers

Answer:

48m

Explanation:

Given the following data;

Initial velocity = 0m/s

Final velocity = 6m/s

Time, t = 6 secs

Time, T2 = 5 secs

Mathematically, acceleration is given by the equation;

[tex]Acceleration (a) = \frac{final \; velocity - initial \; velocity}{time}[/tex]

Substituting into the equation;

[tex]a = \frac{6 - 0}{6}[/tex]

[tex]a = \frac{6}{6}[/tex]

Acceleration, a = 1m/s²

To find the distance covered in the first phase;

Solving for distance, we would use the second equation of motion;

[tex] S = ut + \frac {1}{2}at^{2}[/tex]

Substituting the values into the equation;

[tex] S = 0(6) + \frac {1}{2}*1*(6)^{2}[/tex]

[tex] S = 0 + \frac {1}{2}*1*36[/tex]

[tex] S = 0.5 *36[/tex]

Distance, S1 = 18m

For the second phase, time T2 = 5 secs;

Mathematically, speed is given by the equation;

[tex]Speed = \frac{distance}{time}[/tex]

Making distance the subject of formula, we have;

[tex]Distance, S = speed * time[/tex]

Substituting into the above equation;

[tex]Distance, S = 6 * 5[/tex]

Distance, S2 = 30m

Total distance = S1 + S2 = 18m + 30m = 48m

Total distance = 48m

Therefore, the total distance traveled by the biker is 48m.

Find an expression for the center of mass of a solid hemisphere, given as the distance R from the center of the flat part of the hemisphere. Express your answer in terms of R. Express the coefficients using three significant figures.

Answers

Answer:

z_c = ⅜R

Explanation:

If we assume that the hemisphere has uniform density, we can express the centre of mass as;

z_c = (ρ/M)∫∫∫ z•dV

We know that density(ρ) = mass(M)/volume(V)

Thus, Vρ = M

And volume of hemisphere = 2πr³/3

Thus;

2Vρπr³/3 = M

So;

z_c = (ρ/(2Vρπr³/3))∫∫∫ z•dV

Where r = R in this case.

ρ will cancel out to give;

z_c = (3/(2πr³))∫∫∫_V (z•dV)

In spherical coordinates,

r is radius

Φ = angle between the point and the z − axis

θ = azimuthal angle

Therefore, the integral becomes what it is in the attached image.

I've completed the explanation as well in the attachment.

Sean, whose mass is 60 kg, is riding on a 5.0 kg sled initially traveling at 8.0 m/s. He brakes the sled with a constant force, bringing it to a stop in 4.0 s. What force does he apply?

Answers

Answer:

130N

Explanation:

according to Newtons second law;

F = ma

F = m(v-u)/t

m is the mass = 60+5 = 65kg

v is the final velocity = 0m/s

initial velocity = 8m/s

time t = 4.0s

F = 65(8)/4

F = 65*2

F = 130N

Hence he applied a force of 130N

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