Mr. Lord borrowed $100,000 from a bank at a rate of 8% per annum for 3 years. Calculate the amount accruing for the loan

Answer:

I think in 2 or 3 process. But I am not sure

Answer:

below

Step-by-step explanation:

Use the formula πr^2h to find volume of a cylinder

= π(11)^2(12)

= 4561.59253...

Rounding to the nearest 10th

= 4561.6 mi^3

Hope this helps!

Answer:

Step-by-step explanation:

Volume = pi * r^2 * h

r = 11

h = 12

Volume = pi * 11^2 * 12

Volume = 3.14 * 121 * 12

Volume = 4501.2 mi^3

Answer:

24s3

Step-by-step explanation:

24s3 is the greatest common factor of 24 S3 12 s4 and 18s.

Answer:

y=-4+2x

x=(4+y)/2

2x-y=4

Answer:

In March she sent 752 texts

In April she sent 617

Step-by-step explanation:

The phone bill is 35 + additional texts, so in both bills the value relative to the texts are:

72.6 - 35 = 37.6 for March

65.85 - 35 = 30.85 for April

Each texts costs 0.05, so if we divide the value relative to the texts by 0.05 we will have the number of texts she sent:

37.6/0.05 = 752 texts

30.85/0.05 = 617 texts

The correct solution graph to the inequalities are

[tex]4(9x-18)>3(8x+12)[/tex]  →  C

[tex]-\frac{1}{3}(12x+6) \geq -2x +14[/tex]  → A

[tex]1.6(x+8)\geq 38.4[/tex]  →  B

(NOTE: The graphs are labelled A, B and C from left to right)

For the first inequality,

[tex]4(9x-18)>3(8x+12)[/tex]

First, clear the brackets,

[tex]36x-72>24x+36[/tex]

Then, collect like terms

[tex]36x-24x>36+72\\12x >108[/tex]

Now divide both sides by 12

[tex]\frac{12x}{12} > \frac{108}{12}[/tex]

∴ [tex]x > 9[/tex]

For the second inequality

[tex]-\frac{1}{3}(12x+6) \geq -2x +14[/tex]

First, clear the fraction by multiplying both sides by 3

[tex]3 \times[-\frac{1}{3}(12x+6)] \geq3 \times( -2x +14)[/tex]

[tex]-1(12x+6) \geq -6x +42[/tex]

Now, open the bracket

[tex]-12x-6 \geq -6x +42[/tex]

Collect like terms

[tex]-6 -42\geq -6x +12x[/tex]

[tex]-48\geq 6x[/tex]

Divide both sides by 6

[tex]\frac{-48}{6} \geq \frac{6x}{6}[/tex]

[tex]-8\geq x[/tex]

∴ [tex]x\leq -8[/tex]

For the third inequality,

[tex]1.6(x+8)\geq 38.4[/tex]

First, clear the brackets

[tex]1.6x + 12.8\geq 38.4[/tex]

Collect likes terms

[tex]1.6x \geq 38.4-12.8[/tex]

[tex]1.6x \geq 25.6[/tex]

Divide both sides by 1.6

[tex]\frac{1.6x}{1.6}\geq \frac{25.6}{1.6}[/tex]

∴ [tex]x \geq 16[/tex]

Let the graphs be A, B and C from left to right

The first graph (A) shows [tex]x\leq -8[/tex] and this matches the 2nd inequality

The second graph (B) shows [tex]x \geq 16[/tex] and this matches the 3rd inequality

The third graph (C) shows [tex]x > 9[/tex] and this matches the 1st inequality

Hence, the correct solution graph to the inequalities are

[tex]4(9x-18)>3(8x+12)[/tex]  →  C

[tex]-\frac{1}{3}(12x+6) \geq -2x +14[/tex]  → A

[tex]1.6(x+8)\geq 38.4[/tex]  →  B

Learn more here: https://brainly.com/question/17448505

Answer:

4(9x − 18) > 3(8x + 12) = x > 9

(12x + 6) ≥ -2x + 14 = x ≤ -8

1.6(x + 8) ≥ 38.4 = x ≥ 16

Just follow the numbers with the dotted thing and see the numbers I underlined.

Step-by-step explanation:

Use the properties of inequality and real numbers to solve each inequality.

4(9x − 18) > 3(8x + 12)

36x − 72 > 24x + 36

12x − 72 > 36

12x > 108

x > 9

The graph has an open circle at 9, and moves toward the right on the number line.

(12x + 6) ≥ -2x + 14

12x + 6 ≤ 6x − 42

6x + 6 ≤ -42

6x ≤ -48

x ≤ -8

The graph has a closed circle at -8, and moves toward the left on the number line.

1.6(x + 8) ≥ 38.4

x + 8 ≥ 24

x ≥ 16

The graph has a closed circle at 16, and moves toward the right on the number line.

Answer:

always

never

always

always

12= 1*5^1+2*5^0

5+2

7

34=3*5^1+4*5^0

15+4

19

42=4*5^1+2*5^0

20+2

22

120=1*5^2+2*5^1+0*5^0

25+10+0

35

213=2*5^2+1*5^1+3*5^0

100+5+3

108

430=4*5^2+3*5^1+0*5^0

400+15+0

415

quinary

Standard form of a quadratic equation: ax^2 + bx + c = 0

3x - 4 = -x^2

x^2 + 3x - 4 = 0

Hope this helps!

Answer:

The terms are - 1, 7 and 15.

Step-by-step explanation:

Let the terms be a-d, a, a+d.

ATQ, a-d+a+a+d=21, a=7 and a+d-(a-d+a)=9. 2d-a=9, d=8. The terms are - 1, 7 and 15.

The first three terms will be :   -1, 7, 15

We have sum of first three terms of an arithmetic series is 21. It is given that if the sum of the first two terms is subtracted from the third term then it would be 9.

We have to find the three terms of the series.

An arithmetic progression or sequence with common difference [tex]d[/tex] is given as -

a, a + d, a + 2d, a + 3d .....

According to the question -

a + (a + d) + (a + 2d) = 21

3a + 3d = 21

3(a + d)=21

a + d = 7                             (Eqn. 1)

(a + 2d) - (a + a + d) = 9

a + 2d - a - a - d = 9

d - a = 9

a = d - 9

Substituting the value of 'a' in Eqn. 1, we get -

d - 9 + d = 7

2d - 9 = 7

2d = 16

d = 8

Therefore -

a = 8 - 9

a = -1

The three terms are -

a = -1

a + d = -1 + 8 = 7

a + 2d = -1 + 2 x 8 = 15

Hence, the first three terms will be - -1, 7, 15

To solve more questions on Arithmetic Sequences and finding the terms, visit the link below -

https://brainly.com/question/20384906

#SPJ2

Answer:

54

Step-by-step explanation:

find the area of each shape. you have a length of 3 and a height of 4.

3 • 4 = 12

you have this shape twice so 12 • 2 = 24

now you have a length of 5 and a height of 6.

5 • 6 = 30

so adding up all of the numbers (24 + 30), you have an answer of 54.

Answer:

D

Step-by-step explanation:

Instead of 2x + 11 = 5x + 16, you should have put 2x+11 = 5x - 16. There is a sign change right before the 16, and you may have accidentally written down +16 instead of -16. I think that's where the problem is.

2x + 11 = 5x - 16

subtract 5x from both sides to make all variables on one side

-3x + 11 = -16

subtract 11 from both sides to isolate the x and its coefficient

-3x = -27

divide both sides by -3 to isolate x

x = 9

Answer:

A^7

Step-by-step explanation:

Answer:

TRUE

Step-by-step explanation:

The answer is TRUE.

Answer:

There are 10 squares present in this picture

Answer:

as per me 18 ...... u try try u4self too

Answer:

5 percent ...................

Answer:

BG = 25

Step-by-step explanation:

The circumcentre is equally distant from the triangles 3 vertices, then

BG = CG = 25

Answer:

The price per toy is $6.25.

Step-by-step explanation:

The price per toy is calculated by dividing the cost of all toys by the number of toys.

$50/8 = $6.25

The price per toy is $6.25.

Answer:

x = 30

Step-by-step explanation:

The diagonals are bisected so DE =EB

67 = 2x+7

Subtract 7

67-7 = 2x+7-7

60 =2x

Divide by 2

60/2 =2x/2

30 = x

Answer:

the answer is option 1

Step-by-step explanation:

the negative angle => a quarter round angle (clockwise) = ¼ x ( -360°) = -90°

and

the positive angle => a full round angle + 270° = (360°)+270°

= 630°

Answer:

correct answer is -90 and 630

Step-by-step explanation:

Step-by-step explanation:

1. The equation graph is a parabola, so the maximum height will be the vertex of the parabola. You can find the vertex coordinate t using the formula:

t = -b/2a

t = -18/2•(-4.9)

t = -18/-9.8

t = 1.84 seconds

2. The height of the ground is 0, so the balls hit the ground when the equation result is 0:

0 = -4.9t²+18t+10

Now you solve it using Bhaskara:

Δ = b² -4ac

Δ = 18² -4•(-4.9)•10

Δ = 520

t = (-b ±√Δ)/2a

t = (-18 ± √520)/2•(-4.9)

t1 = (-18 - 20.8)/-9.8

t1 = 3.96 seconds

t2 = (-18 +20.8)/-9.8

t2 = -0.28

Doesn't exist negative time, so we pick the first value found, t = 3.96 seconds

3. Now you just need to put 3 in place of t to find the result:

h = -4.9•3² +18•3 +10

h = -4.9•9 + 54 + 10

h = -44.1 + 64

h = 19.9 meters

4. You just need to put 1 in place of t to find the height:

h = -4.9•1²+12

h = -4.9+12

h = 7.1 meters

Answer:

Tb bight by icing I jb Yves j by by by navy by iffy i by by by

Answer:

No

Step-by-step explanation:

One way to tell if a number is rational is if it can be written as a fraction. Anything that can be written as a fraction of two integers is rational.

-6/11 is a fraction with integer numerators and denominators.

Therefore it is rational.

Answer:

On a coordinate plane, a hyperbola is shown. One curve opens up and to the right in quadrant 1, and the other curve opens down and to the left in quadrant 3. A vertical asymptote is at x = 1, and the horizontal asymptote is at y = 4

Step-by-step explanation:

The given function is presented as follows;

[tex]f(x) = \dfrac{2}{x - 1} + 4[/tex]

From the given function, we have;

When x = 1, the denominator of the fraction, [tex]\dfrac{2}{x - 1}[/tex], which is (x - 1) = 0, and the function becomes, [tex]\dfrac{2}{1 - 1} + 4 = \dfrac{2}{0} + 4 = \infty + 4 = \infty[/tex] therefore, the function in undefined at x = 1, and the line x = 1 is a vertical asymptote

Also we have that in the given function, as x increases, the fraction [tex]\dfrac{2}{x - 1}[/tex] tends to 0, therefore as x increases, we have;

[tex]\lim_ {x \to \infty} \dfrac{2}{(x - 1)} \to 0, and \ \dfrac{2}{(x - 1)} + 4 \to 4[/tex]

Therefore, as x increases, f(x) → 4, and 4 is a horizontal asymptote of the function, forming a curve that opens up and to the right in quadrant 1

When -∞ < x < 1, we also have that as x becomes more negative, f(x) → 4. When x = 0, [tex]\dfrac{2}{0 - 1} + 4 = 2[/tex]. When x approaches 1 from the left, f(x) tends to -∞, forming a curve that opens down and to the left

Therefore, the correct option is on a coordinate plane, a hyperbola is shown. One curve opens up and to the right in quadrant 1, and the other curve opens down and to the left in quadrant 3. A vertical asymptote is at x = 1, and the horizontal asymptote is at y = 4.

Answer:

On a coordinate plane, a hyperbola is shown. One curve opens up and to the right in quadrant 1, and the other curve opens down and to the left in quadrant 3. A vertical asymptote is at x = 1, and the horizontal asymptote is at y = 4

Step-by-step explanation:

The given function is presented as follows;

From the given function, we have;

When x = 1, the denominator of the fraction, , which is (x - 1) = 0, and the function becomes,  therefore, the function in undefined at x = 1, and the line x = 1 is a vertical asymptote

Also we have that in the given function, as x increases, the fraction  tends to 0, therefore as x increases, we have;

Therefore, as x increases, f(x) → 4, and 4 is a horizontal asymptote of the function, forming a curve that opens up and to the right in quadrant 1

When -∞ < x < 1, we also have that as x becomes more negative, f(x) → 4. When x = 0, . When x approaches 1 from the left, f(x) tends to -∞, forming a curve that opens down and to the left

Therefore, the correct option is on a coordinate plane, a hyperbola is shown. One curve opens up and to the right in quadrant 1, and the other curve opens down and to the left in quadrant 3. A vertical asymptote is at x = 1, and the horizontal asymptote is at y = 4.

Answer:

A

Step-by-step explanation:

pgt states if the square of the length of the longest side of a triangle is equal to the sum of the squares of the other two sides, then the triangle is a right triangle.

Answer:

Does the answer help you?

Answer:

I think this is mistake because y=2x^2+6x-10 y=x+5 this is the right

Answer:

b

Step-by-step explanation:

(-x+2 ) +5 -(x - 2)  [tex]\geq[/tex] 0

-2x+ 9[tex]\geq[/tex]0

x [tex]\leq[/tex]9/2

Answer: the answer is 3 41/99

Step-by-step explanation: got it from khan pls mark me 5 stars