Na2CO3 is a/an ____________ compound where its electrons are _______. *
1.covalent, shared
2.covalent, gained/lost
3.ionic, gained/lost
4.ionic, shared

Answer:

False,not all chemicals pollute the enviorment

Explanation:

Hope this helps!

Brainliest?

Answer:

False

Explanation:

Oxygen?

Answer:

Radioactive isotopes ranging from 11O to 26O have also been characterized, all short-lived. The longest-lived radioisotope is 15O with a half-life of 122.24 seconds, while the shortest-lived isotope is 12O with a half-life of 580(30)×10−24 seconds (the half-life of the unbound 11O is still unknown).

The number of particles in a substance can be calculated by multiplying the number of moles of the substance by Avogadro's Number ~ 6.02 × 10²³ particles/mol. Therefore to find the number of moles based on the number of particles, you would divide the number of moles by Avogadro's Number.

Since # of particles of H₂O = 5.3×10¹² particles

     then # of moles of H₂O = 5.3×10¹² particles ÷ 6.02 × 10²³ particles/mol

                                             = 8.804 × 10⁻¹² moles

Answer:

?

Explanation:

What are the statements? You've given the passage but not the statements

Answer:

Explanation: As the good witch Azura said when she was in the bog of immediate regret I challenge you to a witches duel.

im sorry if that was bad i got nothing lol

also took it from The Owl House

Answer:

P IBr: 15.454atm

I₂: 0.923 atm

P Br₂: 0.923atm

Explanation:

Basados en la reacción:

I₂(g) + Br₂(g) ⇄ 2 IBr(g)

La constante de equilibrio, Keq, es definida como:

[tex]Keq = \frac{P_{IBr}^2}{P_{I_2}P_{Br_2}}[/tex]

Se cumple la relación de Keq = 280 cuando las presiones están en equilibrio

Usando PV = nRT, la presión inicial de IBr es:

P = nRT / V; 0.500mol*0.082atmL/molK*423.15K / 1.00L = 17.3 atm

Siendo las presiones en equilibrio:

P IBr: 17.3 - 2X

P I₂: X

P Br₂: X

Donde X representa el avance de reacción.

Remplazando en Keq:

280 = (17.3 - 2X)² / X²

280X² = 4X² - 69.2X + 299.29

0 = -276X² - 69.2X + 299.29

Resolviendo para X:

X = -1.174 → Solución falsa. No existen presiones negativas

X = 0.923 → Solución real

Así, las presiones parciales en equilibrio de cada compuesto son:

P IBr: 17.3 - 2X = 15.454atm

P I₂: X = 0.923atm

P Br₂: X = 0.923atm

Answer:

[tex]p_{I_2}=0.926atm\\p_{Br_2}=0.926atm\\p_{IBr}=15.5atm[/tex]

Explanation:

Hello,

In this case, given the initial load of 0.500 mol of IBr in the 1.00-L, we compute its initial concentration:

[tex][IBr]_0=\frac{0.500mol}{1.00L}=0.500M[/tex]

Hence, by knowing the original reaction, we should invert it as IBr will produce iodine and bromine considering the initial load:

[tex]2IBr(g)\rightleftharpoons I_2(g) + Br_2(g)[/tex]

Therefore, the equilibrium constant should be inverted:

[tex]K'=\frac{1}{Keq}=\frac{1}{280}=3.57x10^{-3}[/tex]

So we write the law of mass action:

[tex]K'=\frac{[I_2][Br_2]}{[IBr]^2}[/tex]

That in terms of the change [tex]x[/tex] due to the reaction extent turns out:[tex]3.57x10^{-3}=\frac{(x)(x)}{(0.500-2x)^2}[/tex]

In such a way, solving by using solver or quadratic equation we obtain:

[tex]x_1=-0.0339M\\x_2=0.0267M[/tex]

Clearly, the solution is 0.0267M, thus, the equilibrium concentrations are:

[tex][I_2]=x=0.0267M[/tex]

[tex][Br_2]=x=0.0267M[/tex]

[tex][IBr]=0.5M-2x=0.5M-2*0.0267M=0.447M[/tex]

Thus, with the given temperature (150+273.15=423.15K), we compute the partial pressures by using the ideal gas equation:

[tex]p_{I_2}=[I_2]RT=0.0267\frac{mol}{L} *0.082\frac{atm*L}{mol*K}*423.15K\\\\p_{I_2}=0.926atm\\\\p_{Br_2}=[Br_2]RT=0.0267\frac{mol}{L} *0.082\frac{atm*L}{mol*K}*423.15K\\\\p_{Br_2}=0.926atm\\\\p_{IBr}=[IBr]RT=0.447\frac{mol}{L} *0.082\frac{atm*L}{mol*K}*423.15K\\\\p_{IBr}=15.5atm[/tex]

Best regards.

Answer:

Ideal Gas Law

PV = nRT

Explanation:

Pressure is proportional to temperature;

The heat of the fire would cause increased pressure inside the closed aerosol vessel, eventually resulting in explosion of the vessel, once the temperature rises enough.

Answer: 1- gas 2- solid

Explanation:

Answer:

5 electron groups, see saw

Explanation:

During the formation of SF4, the sulfur atom usually bonds with each of four fluorine atoms where 8 of valence electrons are used. The four fluorine atoms have 3 lone pairs of electrons in its octet which will further utilize 24 valence electrons. In addition, two electrons are present as a lone pair on the sulfur atom. We can determine sulfur’s hybridization state by counting of the number of regions of electron density on sulphur (the central atom in the molecule). When bonding takes place there is a formation of 4 single bonds to sulfur and it has 1 lone pair. Looking at this, we can say that the number of regions of electron density is 5. The hybridization state is sp3d.

SF4 molecular geometry is seesaw with one pair of valence electrons. The molecule is polar. The equatorial fluorine atoms have 102° bond angles instead of the actual 120° angle. The axial fluorine atom angle is 173° instead of the actual 180° bond angle.

Answer:

hypothalamus

Explanation:

Answer:

610.3g

Explanation:

Zn:

m = 1.912

Zn : ZnI₂

1 : 1

1.912 : 1.912

ZnI₂:

m = 1.912  Mr = 65.4 + 2(126.9) = 319.2

mass = m×Mr:

mass = 1.912×319.2

mass = 610.3104 → 610.3g

The theoretical yield of Znl2, if 1.912 mol of zinc is used is 610.3g

Since Zinc reacts with iodine in a synthesis reaction: Zn + I2 → Znl2

And, there is 1.912 mol of zinc

So,

Zn : ZnI₂

1 : 1

And,

1.912 : 1.912

For

ZnI₂:

m = 1.912  Mr = 65.4 + 2(126.9) = 319.2

Now

mass = m×Mr:

= 1.912×319.2

= 610.3104

= 610.3g

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Answer:

An organ

Explanation:

An organ is one or more tissues that work together to form a specific function.

- Hope that helps! Please let me know if you need further explanation.

Answer: The rate at which a vibration occurs that constitutes a wave, either in a material (as in sound waves), or in an electromagnetic field (as in radio waves and light), usually measured per second. Also it is measured in Hertz.

Explanation:

Answer frequency is the number of occurrences of a repeating event per unit of time. Frequency is measured in Hertz. Unit frequency is measured as the number of wave cycles that occur in one second.

The unit of frequency measurement is hertz

Explanation:

Answer:

- From octane: [tex]m_{CO_2}=1.54x10^5gCO_2[/tex]

- From ethanol: [tex]m_{CO_2}=9.57x10^4gCO_2[/tex]

Explanation:

Hello,

At first, for the combustion of octane, the following chemical reaction is carried out:

[tex]C_8H_{18}+\frac{25}{2} O_2\rightarrow 8CO_2+9H_2O[/tex]

Thus, the produced mass of carbon dioxide is:

[tex]m_{CO_2}=5.00x10^4gC_8H_{18}*\frac{1molC_8H_{18}}{114gC_8H_{18}}*\frac{8molCO_2}{1molC_8H_{18}}*\frac{44gCO_2}{1molCO_2} \\\\m_{CO_2}=1.54x10^5gCO_2[/tex]

Now, for ethanol:

[tex]C_2H_6O+3O_2\rightarrow 2CO_2+3H_2O[/tex]

[tex]m_{CO_2}=5.00x10^4gC_2H_6O*\frac{1molC_2H_6O}{46gC_2H_6O}*\frac{2molCO_2}{1molC_2H_6O}*\frac{44gCO_2}{1molCO_2} \\\\m_{CO_2}=9.57x10^4gCO_2[/tex]

Best regards.

Answer:

- [tex][H^+]=1x10^{-12}[/tex]

- Basic.

Explanation:

Hello,

In this case, given the concentration of hydroxyl ions, one could compute the pOH as shown below:

[tex]pOH=-log([OH^-])=pOH=-log(1x10^{-2})=2[/tex]

Then, since the pOH and the pH are related by:

[tex]pH+pOH=14[/tex]

One computes the pH:

[tex]pH=14-pOH=14-2=12[/tex]

Now, we compute the concentration of hydronium by:

[tex][H^+]=10^{-pH}=10^{-12}[/tex]

[tex][H^+]=1x10^{-12}[/tex]

Finally, since the pH is greater than 7 (neutral point) we conclude that the solution is basic.

Best regards.

Answer:

A. Hydrogen ion concentration, [H+] is 1x10^–12 mol/L

B. Since the pH is 12, the solution is basic.

Explanation:

Data obtained from the question. This includes the following:

Concentration of Hydroxide ion, [OH-] = 1x10^–2 mol/L

Concentration of Hydrogen ion, [H+] =.?

pH =..?

A. Determination of the hydrogen ion concentration, [H+] .

The hydrogen ion concentration, [H+] can be obtained as follow:

[H+] x [OH-] = 1x10^–14

[OH-] = 1x10^–2

[H+] x 1x10^–2 = 1x10^–14

Divide both side by 1x10^–2

[H+] = 1x10^–14 / 1x10^–2

[H+] = 1x10^–12 mol/L

B. Determination of the pH of the solution.

The pH of the solution can be obtained as follow:

pH = –Log [H+]

[H+] = 1x10^–12 mol/L

pH = –Log 1x10^–12

pH = 12.

Then pH of a solution ranges between 0 and 14.

A pH reading between 0 and 6 is termed an acidic solution, a pH reading of 7 is termed a neutral solution and a pH reading between 8 and 14 indicates an alkaline or a basic solution.

The higher the pH value, the more alkaline or basic the solution becomes.

Since the pH is 12, the solution is basic.

Answer:

[tex]4.6\,\,moL\,\,L^{-1}[/tex]

Explanation:

Molarity refers to a measure of concentration.

Molarity = moles of solute/Litres of solution

Molarity refers to number of moles of solute present in this solution.

In order to find a solution's molarity, use value for the number of moles of solute  and the total volume of the solution expressed in liters

As molarity of 2.3 mol of Kl is dissolved in 0.5 L of water,

Molarity = [tex]\frac{2.3}{0.5} =4.6\,\,moL\,\,L^{-1}[/tex]

gas with the smallest amount of molecular weight will effuse the quickest

Answer:

B) 88.6%

Explanation:

Percent yield equals actual yield divided by theoretical yield

actual yield is 31.0g

theoretical yield is 35g

percent yield was 88.57 which rounds up to 88.6%

Answer:

Oxygen is the limiting reactant.

Explanation:

Hello,

In this case, given the reaction:

[tex]C_2H_6O(g) + 3O_2(g)\rightarrow 2CO_2(g) + 3H_2O(g)[/tex]

Hence, given the masses of both ethanol and oxygen, we are able to compute the available moles ethanol by:

[tex]n_{C_2H_6O}^{available}=0.461g*\frac{1mol}{46g}=0.01mol C_2H_6O[/tex]

Next, we compute the moles of ethanol that react with the 0.640 grams of oxygen considering their 1:3 molar ratio in the chemical reaction:

[tex]n_{C_2H_6O}^{consumed\ by\ O_2}=0.64gO_2*\frac{1molO_2}{32gO_2}*\frac{1molC_2H_6O}{3molO_2} =0.0067molC_2H_6O[/tex]

In such a way, since there are 0.01 available moles of ethanol but just 0.0067 moles are reacting, we evidence ethanol is in excess, therefore the oxygen is the limiting reactant.

Best regards.

Answer:

Oxygen O₂ will be the limiting reagent.

Explanation:

C₂H₆O(g) + 3 O₂(g) ⇒ 2 CO₂(g) + 3 H₂O(g)

First of all you must know by stoichiometry (that is, the relationship between the amount of reagents and products in a chemical reaction) how much mass of each compound reacts. First of all, being:

the molar mass of each reagent is:

Then, since 1 mol of C₂H₆O and 3 moles of O₂ react by stoichiometry, the amount of mass that reacts is:

Now you apply a rule of three as follows: if 46 g of C₂H₆O reacts with 96 g of O₂ by stoichiometry, 0.461 g of C₂H₆O with how much mass of O₂ will they react?

[tex]mass of O_{2} =\frac{0.461 grams of C_{2}H_{6} O*96 grams ofO_{2} }{46 grams of C_{2}H_{6} O}[/tex]

mass of O₂= 0.962 grams

But 0.962 grams of O₂ are not available, 0.640 grams are available. Since you have less mass than you need to react with 0.461 g of C₂H₆O, oxygen O₂ will be the limiting reagent.

Answer:

28.69 grams

Explanation:

To find the mass, we first need to find the moles. Once we have the moles, it is easy to use the molar mass of H2SO4 to find its mass.

To find the moles, remember that molarity (M) is equal to the moles divided by the volume (L). The volume HAS TO be converted to liters!

M = moles / V

5.85 M = moles / 0.05 L

moles = 0.2925

Now we know that we have 0.2925 moles of sulfuric acid. The molar mass of sulfuric acid is 98.08 g/mol.

0.2925 moles * (98.08 g / mol) = 28.69 grams

Make sense? If you have any questions, don't hesitate to ask!

Answer:

The "Parkfield earthquake prediction experiment" was the most heralded scientific earthquake prediction ever. It was based on an observation that the Parkfield segment of the San Andreas Fault breaks regularly with a moderate earthquake of about M 6 every several decades: 1857, 1881, 1901, 1922, 1934, and 1966.

Explanation:

this is the best I could come up with. luv u.

Answer:

[tex]x = 6.634\times 10^{23}\,atoms[/tex]

Explanation:

The quantity of atoms within the mass of copper is determined by multiplying the quantity of moles by the Avogadro's Number:

[tex]x = \left(\frac{70\,g}{63.546\,\frac{g}{mol}} \right)\cdot \left(6.022\times 10^{23}\,\frac{atoms}{mol} \right)[/tex]

[tex]x = 6.634\times 10^{23}\,atoms[/tex]

Answer:

6.64x10^23 atoms.

Explanation:

From Avogadro's hypothesis, 1 mole of any substance contains 6.02x10^23 atoms. This implies that 1 mole of Cu also contains 6.02x10^23 atoms.

1 mole of Cu = 63.5g

If 63.5g of Cu contains 6.02x10^23 atoms,

Then 70g of Cu will contain = (70x6.02x10^23) /63.5 = 6.64x10^23 atoms.

Therefore, there are 6.64x10^23 atoms in 70g oh Cu

Answer: The total volume of the sun is 1.4 x 10 27cubic meters. About 1.3 million Earths could fit inside the sun. The mass of the sun is 1.989 x 10 30 kilograms, about 333,000 times the mass of the Earth.

Explanation: So if you divide the volume of the Sun by the volume of the Earth, you get 1,300,000.

Answer:

The density is 6

Explanation:

p = m × v

p = 3 × 2

p = 6

Hope this helped! :)

The density of the substance depends on the mass and the volume of the substance or object. It is given by the ratio of mass and volume. The density of 3 gm solid is 1.5 g/cm³.

In chemistry and physics, density is a quantitative measurement that tells about the tightness of the substance packed in an area. It relates to two parameters that include mass and volume.

The density can be said to have a proportion of mass to the volume of the substance. The mass can be in grams or kilograms, while volume can be in a liter, cubic meter, and cubic centimeter.

Given,

Mass of solid (M) = 3 gm

The volume of solid (V) = 2 cm³

Density (ρ) is calculated as:

ρ = M ÷ V

= 3 ÷ 2

= 1.5 gm/cm³

Therefore, 1.5 gm/cm³ is the density of 3 gm solid.

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Answer:

1/ 421.2 g KNO3

2/ 66.6 g  S

3/ 275.0 g CO2

Explanation:

Please see the step-by-step solution in the picture attached below.

Hope this answer can help you. Have a nice day!

Answer:

pH=4.05

Explanation:

C7H6O2  -> C7H6O-  + H+

ka= [C7H6O-] [H+]/[C7H6O2]

During equilibrium

[C7H6O-]= [H+]= x^2

[C7H6O2]=0.12-x

Replace

ka= x^2/0.12-x

6.5 x10^-5= x^2/0.12-x

7.8x10^-6 - 6.5 x10^-5x=x^2

x^2+ 6.5 x10^-5x - 7.8x10^-6

Solution of quadratic equation

x=8.8 x10^-5

pH= -log [H+]= -log 8.8 x10^-5=4.05

The pH value of the benzoic acid solution is equal to 4.05.

pH can be defined the negative logarithm of hydrogen ion concentration. pH can be seen as an abbreviation of the power of hydrogen or the concentration of hydrogen ions in a solution.

Mathematically, pH equals the negative logarithmic value of the concentration of hydrogen ion (H⁺).

pH = -log [H⁺]

The pH scale have range from 0 to 14 when 7.0 is neutral. A low pH is acidic and a high pH is basic. Pure water has a pH of 7.0.

The partial dissociation of benzoic acid in an aqueous solution can be shown as:

[tex]C_6H_5COOH +H_2O[/tex]  ⇄  [tex]C_6H_5COO^- +H_3O^+[/tex]

ka= [C₆H₅O⁻] [H₃O⁺]/[C₆H₅COOH]

At equlibrium:[C₆H₅O⁻] = [H₃O⁺] = x²

[C₆H₅COOH] = 0.12-x

The equilibrium constant: ka= x²/0.12-x

6.5 × 10⁻⁵ = x²/0.12-x

7.8 × 10⁻⁶- 6.5  × 10⁻⁵ x = x²

x²+  6.5  × 10⁻⁵ x- 7.8 × 10⁻⁶ = 0

The solution of the given quadratic equation will be:

x = 8.8 × 10⁻⁵

pH= -log [H⁺]= -log [8.8 × 10⁻⁵] =  4.05

Therefore, the pH of the given benzoic acid solution is 4.05.

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Answer:

Hydrogen bonding.

Explanation:

Ammonium lauryl sulfate is also known as ammonium dodecyl sulfate there are two parts in Ammonium lauryl sulfate one is nonpolar hydrocarbon and other part polar sulfate group.

Due to polarity of sulfate group its form hydrogen bond very easily.

It is mainly used as foaming agent the main reason of its use is very much soluble in water and making hydrogen bond with water.

Answer:A heating curve graphically represents the phase transitions that a substance undergoes as heat is added to it. The plateaus on the curve mark the phase changes. The temperature remains constant during these phase transitions.