Explanation:
[tex]we \: know \: that \: joule \: is \: the \: unit \: of \\ energy \: we \: have \: energy = \frac{1}{2} m {v}^{2} \\ unit \: of \: this \: is \\ joule = kg {( \frac{m}{ s }) }^{2} \\ thank \: you[/tex]
When your vehicle turns a corner, the tracks made by the rear tires are always: a) Outside of those made by your front tires b) Inside of those made by your front tires c) On top of those made by your front tires d) None are correct
Answer:
I think it's D
Explanation:
because I have seen the tracks of the tires
The rear wheels of a tractor are very wide. Why?
Answer:
The rear wheels of a tractor are very wide so that the weight of the tractor spread over the greatest surface area possible ,so it doesnot sink into the soil.please as brainliest
What is potential energy? What are some of its examples.
Answer:
the energy stored in an object because of its specific state or position is called its potential energyexamples:-a compressed springWater that is behind a dam.A car that is parked at the top of a hill. a moving car.Etc....
Explanation:
❣️jess bragoli❣️#keep learning!!
Explanation:
POTENTIAL energy is the energy that is stored in an object due to its position relative to some zero position.
1) With the aid of diagrams explain how two hollow cans be charged by induction using 5 units of positive charges.
Answer:
plz mark as a pure substance abuse and function of the equation for sulphur dioxideThe acceleration of the car with two washers added to the string would be
Answer:
[tex]a=0.33\ m/s^2[/tex]
Explanation:
For washer 2,
v₁ = 0.13 m/s
v₂ = 0.36 m/s
t₁ = 1.92
t₂ = 2.61
We need to find the acceleration of waster 2.
[tex]a=\dfrac{v_2-v_1}{t_2-t_1}\\\\a=\dfrac{0.36-0.13}{2.61-1.92}\\\\a=\dfrac{0.23}{0.69}\\\\a=0.33\ m/s^2[/tex]
So, the acceleration of washer 2 is [tex]0.33\ m/s^2[/tex].
Answer:
.33
Explanation:
A bus starts to move with the speed of 15m/s. Calculate the time taken by the bus to cover distance of 15000m.
Answer:
1000
Explanation:
the formula of time taken= d/s. t=15000÷15 t=1000. I hope it helps
formula of distance is S=Vt
so, 15000=15t
15000 divide by 15=t
1000=t or t=1000
a)Watt (W) is a derived unit.
b)The atomic clock is suitable for measuring time.
c)There is fluctuation in time measured by a pendulum clock.
d)The weight of an object is more at pole and less at equator of the earth.
e)The weight of an object on the moon is about one-sixth the weight it would have on the earth.
f)In average, the weight of 1 kilogram mass on the earth surface is 9.8 N.
please answer all questions
Answer:
a) Watt is a derived unit because it's not a “base unit.”
b) The atomic clock is suitable for measuring time because natural atomic oscillations happen at a higher frequency and as a result they are more stable.
c) There is fluctuation in time measured by a pendulum clock because the pendulum rod changes in length slightly with changes in temperature, causing changes in the rate of the clock. An increase in temperature causes the rod to expand, making the pendulum longer, so its period increases and the clock loses time.
D) The weight of an object is more at pole and less at equator of the earth because the distance of the pole is less than the distance of the equator from the centre of the earth.
e) The weight of an object on the moon is about one-sixth the weight it would have on the earth because the moon's gravitation force is determined by the mass and the size of the moon. Hence, the weight of an object on the moon is 1/6th its weight on the earth.
What is meant by measurement? l
Answer:
The action of measuring the size, length, or amount of something, as established is called measurement.
Explanation:
“Measurement” is the act of determining a target's size, length, weight, capacity, or other aspect. ... To use measurement tools as necessary. It is also appropriate to say that measurement is done by a worker using a measurement system, and instrumentation is done by a technician.
Use the ideal gas law, PV=nRT to solve. R=0.0821
If I have 15 moles of gas at a temperature of 299K and a volume of 92L, what is the pressure of the gas?
Answer:
The pressure of the gas=4.002 atm
Explanation:
We are given that
R=0.0821
Number of moles, n=15
Temperature, T=299 K
Volume of gas, V=92 L
We have to find the pressure of the gas.
[tex]PV=nRT[/tex]
Substitute the values
[tex]P\times 92=15\times 0.0821\times 299[/tex]
[tex]P=\frac{15\times 0.0821\times 299}{92}[/tex]
[tex]P=4.002 atm[/tex]
Hence, the pressure of the gas=4.002 atm
Answer:
According to the ideal gas law equation,
PV = nRT (here, P = 5.5 atm, V = 10L, T = 298K, R = 0.0821 atmL/mol K)
or, n = RT/PV = (0.0821 X 298)/(5.5 X 10) = 0.44 moles of He gas
Explanation:
Which of the following is NOT TRUE about food irradiation?
O It is practiced around the world.
O It leaves food mildly radioactive.
It is effective in killing microorganisms.
o It destroys microorganisms without cooking.
Answer:
It is practiced around the world .
The statement, that is, food irradiation leaves food mildly radioactive is not true.
• A technology, which uses ionizing radiation to improve safety and extend the shelf life of foods by eliminating and reducing insects and microbes is known as food irradiation.
• Irradiation is used in canning fruits and vegetables and pasteurizing milk to make food safer for consumption.
• Irradiation does not compromise nutritional quality, makes food radioactive, or change the texture, text, or appearance of food. The effect of irradiation is so minimal that it is not easy to identify that whether the food is irradiated.
• Food irradiation has been approved in over forty countries and is almost practiced globally.
Thus, the statement, that is, it leaves food mildly radioactive is incorrect.
To know more about:
https://brainly.com/question/19586033
A particle is moving on a circular path of radius R. What will be its displacement and distance covered after 3 ½ round?
(please help fast)
Answer:
2r or diameter
Explanation:
After 3 1/2 rounds it will end up on the other side of the circle and displacement will be 2 x the radius = d
Distance = 7 π R
Displacement = 2 R from the starting point directed through the center of the circle
one car accelerates at half the rate of another how much longer does it take the first car to travel a quarter mile
Answer:
t=1/4v1
Explanation:
Given data
Car one
Speed =v1
Time =t
Distance =1/4 mile
Given data
Car two
Speed =v1/2
Time =t
Distance =d
Speed =distance/time
v1=1/4/t
v1t=1/4
t=1/4*1/v1
t=1/4v1 seconds
by how much is the weight of body less on the moon surface than on earth surface why
Answer:
Our weight on moon is less than it would be on Earth.
Explanation:
Due to a difference of the strength of gravity on the moon. The moon's gravitation force is determined by the mass and the size of the moon. Since the moon has significantly less mass than the Earth, it will not pull objects toward itself at the strength that Earth will. This means that if you went to the moon you would weigh less, even though your mass stays the same.
Un proton penetra perpendiculares en un campo magnetico de 5 teslas con una velocidad de 2.10 m/s calcula
Answer:
The magnetic force acting on the proton is 1.68 x 10^-18 N.
Explanation:
magnetic field, B = 5 T
speed , v = 2.1 m/s
charge q = 1.6 x 10^-19 C
Angle, A = 90 degree
The magnetic force on the charge particle is given by
[tex]F = q v B sin A\\\\F = 1.6\times 10^{-19}\times 2.1\times 5\times sin 90\\\\F = 1.68\times 10^{-18} N[/tex]
You pull your little sister across a flat snowy field on a sled. Your sister plus the sled have a mass of . The rope is at an angle of 45 degrees to the ground. As you pull with a force of , the sled travels a distance of . How much work do you do
Answer:
W = 0.7071 F x, W = 35.355 J
Explanation:
Work is defined
W = F. d
bold indicates vectors,
W = F d cos θ
where the angle is between force and displacement.
As the system runs on snow, the friction force is negligible, therefore
W = F x cos 45
W = 0.7071 F x
Unfortunately the values of the force and the distance do not appear, suppose that the force is F = 10 N and the distance x = 5m
W = 0.7071 10 5
W = 35.355 J
Work is positive because force and displacement go in the same direction
Define standard 1 killogram
" standard 1 meter
" standard 1 second
Answer:
-standard 1 kg : Kilogram (kg), basic unit of mass in the metric system.
-standard 1 meter: The standard metre is the length of the path travelled by light in vaccum during a time interval of 1/299792458 of a second.
- standard 1 second : The second (abbreviation, s or sec) is the Standard International ( SI ) unit of time.
Explanation:
HOPE IT HELPS YOU !!
show that pv=nrt has the same unit with energy
Answer:
It is proved.
Explanation:
PV = n R T
where, P is the pressure, V is the volume, n is the number of moles, R is the gas constant, T is the absolute temperature.
Unit of pressure is Pascal= Newton/square meter = [tex][ML^{-1}T^{-2}][/tex]
Unit of volume is cubic meter = [tex][L^{3}][/tex]
So, the unit of P V
[tex][ML^{-1}T^{-2}] \times [L^{3}]\\\\[ML^2T^{-2}}[/tex]
[tex][ML^{2}T^{-2}][/tex]
It is same as the unit of energy.
hence proved.
A ball is dropped from a roof of a building and strikes the ground in 3 seconds. If a second ball is thrown horizontally from the roof, it will hit the ground in:
it will hit the ground maybe in like 1 second I guess
If a planet has the same mass as the earth, but has twice the radius, how does the surface gravity, g, compare to g on the surface of the earth
Answer:
The surface gravity g of the planet is 1/4 of the surface gravity on earth.
Explanation:
Surface gravity is given by the following formula:
[tex]g=G\frac{m}{r^{2}}[/tex]
So the gravity of both the earth and the planet is written in terms of their own radius, so we get:
[tex]g_{E}=G\frac{m}{r_{E}^{2}}[/tex]
[tex]g_{P}=G\frac{m}{r_{P}^{2}}[/tex]
The problem tells us the radius of the planet is twice that of the radius on earth, so:
[tex]r_{P}=2r_{E}[/tex]
If we substituted that into the gravity of the planet equation we would end up with the following formula:
[tex]g_{P}=G\frac{m}{(2r_{E})^{2}}[/tex]
Which yields:
[tex]g_{P}=G\frac{m}{4r_{E}^{2}}[/tex]
So we can now compare the two gravities:
[tex]\frac{g_{P}}{g_{E}}=\frac{G\frac{m}{4r_{E}^{2}}}{G\frac{m}{r_{E}^{2}}}[/tex]
When simplifying the ratio we end up with:
[tex]\frac{g_{P}}{g_{E}}=\frac{1}{4}[/tex]
So the gravity acceleration on the surface of the planet is 1/4 of that on the surface of Earth.
integrated science please help
Answer:
As we all knows that Matter is everything that occupies in space.
(A) There are three major types of Matter;
SolidGasLiquid(B) (I) If John took five ice cubes from the freezer and place them into a cup after 5 minutes, he returned and saw water this process is called melting.
(ii) if he put the same cup into the freezer and turned into ice in 5 minutes this
process is called freezing.
(iii) if John places the ice from the cup into a pot on a lit stove for 2 minutes and leaves, and he returned and find the pot empty this process is called evaporation.
The spin of Earth creates the Coriolis effect. This effect causes which current patterns to occur? Choose all that apply
Surface ocean water in the Northern Hemisphere moves clockwise.
Surface ocean water in the Southern Hemisphere moves clockwise.
Surface ocean water in the Northern Hemisphere moves counterclockwise.
Surface ocean water in the Southern Hemisphere moves counterclockwise.
Surface ocean water moves clockwise in both hemispheres.
Surface ocean water moves counterclockwise in both hemispheres.
Answer:
The correct answer is options (1) and (4).
Explanation:
Due to the rotation of the earth Coriolis force is generated. As the earth rotates from the west to the east, it changes the pattern of global wind and ocean water movement.
This force allows the ocean surface water to move in the clockwise direction in the northern hemisphere, and anticlockwise in the southern hemisphere.
Thus, the correct answer is options (1) and (4).
Amy throws a softball through the air. What are the different forces acting on the ball while it’s in the air?
The softball experiences
force as a result of Amy’s throw. As the ball moves, it experiences
from the air it passes through. It also experiences a downward pull because of
.
Answer:
1.the friction of air, gravity2.gravity
Answer:
The softball experiences an applied force as a result of Amy’s throw. As the ball moves, it experiences drag from the air it passes through. It also experiences a downward pull because of gravity.
Explanation:
Plato
An airplane with a ground speed of 550 km/hr travels along a heading of 30 degrees n of w at that high altitude there is a powerful 210 km/hr wind
Answer:
Determine the direction that the pilot is aiming the plane.
Explanation:
A car going around a curve with a radius of 15m experiences a centripetal acceleration of 2.5 m/s2. How fast is the car going?
0.17m/a
38 m/s
6.1 m/s
6.0 m/s
Answer:
Explanation:
The formula for centripetal acceleration is
[tex]a_c=\frac{v^2}{r}[/tex] . Filling in:
[tex]2.5=\frac{v^2}{15}[/tex] and
[tex]v=\sqrt{2.5(15)}[/tex] so
v = 6.1 m/s
orange light has a wavelength of 600nm. calculate the frequency if the speed of light in vacuum
the correct answer is ---- 122
Which part of this model represents a layer made of liquid rock that produces
a magnetic field?
A. B
B. A
C. D
D. C
Answer: C- the outer core
Explanation: The outer core is a thick layer of molten rock that encircles the inner core.
A cycle travels along a circular track of diameter 42 m. Calculate the distance travelled and the displacement of the cycle in (a) Half round (b)One round.
please explain it to me clearly,its so confusing
i will give brainlist to the one who explains it clearly
Answer:
(a) i) The distance travelled by the cycle in half round is approximately 65.97 m
ii) The displacement is 42 m
(b) (i) The distance travelled in one round is approximately 131.95 m
(ii) The displacement of the cycle in one round is 0
Explanation:
The diameter of the track through which the cycle travels, D = 42 m
(a) i) Half round is the motion of half the length of the circular path
The distance travelled by the cycle in half round = The length of half the circular track = (1/2) × π × D
∴ The distance travelled by the cycle in half round = (1/2) × π × 42 m = 21·π m ≈ 65.97 m
ii) The displacement half round = The change in the location of the cycle = The difference between the start and stop locations of the cycle on a straight line after half round
The angle at the center of the circular path the cycle turns in half round = 180°
Therefore, the path between the start and stop location of the cycle in half round = The diameter of the circular track
The displacement of the cycle in half round = The diameter of the circular track = 42 m
(b) (i) The distance travelled in one round = The perimeter of the circular track = π·D
∴ The distance travelled in one round = π × 42 m ≈ 131.95 m
(ii) The displacement of the cycle in one round = The change in the location of the cycle
The start and stop location of the cycle after moving one round is the same, therefore, there is no change in the location of the cycle.
Therefore we have;
The displacement of the cycle in one round = 0 (no change in location of the cycle)
Mary drives at a speed of 35 mph (mile/hour). How long does it take for her to drive 98 miles?
__ hours
Answer:
2.8 hours
Explanation:
98 ÷ 35 = 2.8
how much of the electro magnetic spectrum is visible to us
Answer:
The entire rainbow of radiation observable to the human eye only makes up a tiny portion of the electromagnetic spectrum – about 0.0035 percent. This range of wavelengths is known as visible light.
Explanation:
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A drone traveling horizontally at 100 m/s over flat ground at an elevation of 3000 meters must drop an emergency package on a target on the ground. The trajectory of the package is given by x=100t , y=−4.9t2+3000 ,t≥0 where the origin is the point on the ground directly beneath the drone at the moment of release. How many horizontal meters before the target should the package be released in order to hit the target? Round to the nearest meter.
Answer:
The package should be dropped 244.7 meters before the target
Explanation:
We need to find how long the package will take to hit the ground then solve for position.
y=0
-4.9t^2=-3000
t= sqrt (3000/4.9)
t= 24.74 seconds.
x= 247.4 meters.
