Answer:
is it like this
64653=65000
Answer:
là 64652/64654
Find the equation of a line that passes through the points (2,7) and (4,6). Leave your answer in the form y = m x + c
Answer:
I think the answer would be
y = 0.5x -8
tough this might be wrong?
Step-by-step explanation:
(2, 7) ( 4,6)
to find the gradient- mx
y2-y1/ x2 - x1
chose which would be 1/ 2
if I chose (2,7) as 1 then (4, 6) as 2
mx = 6- 7/ 4-2
= -0.5x
y = -0.5x + c
substitute
6 = -0.5(4) + c
6= -2+ c
c = -8
If the amount of waking time 4 year old children spend alone with their fathers each day is 42 minutes while the daily waking time spent in daycare is 6 hours, what is the ratio of time with father to time in daycare?
42 minutes is .7hours so the ratio is .7:6 but you would rewrite it as 7:60 so you don’t have the decimal.
Can anyone explain please?
Answer:
x = 55
Step-by-step explanation:
In a rhombus, each diagonal bisects a pair of opposite angles.
For this parallelogram t be a rhombus, the angles with measures 2x - 40 and x + 15 must be congruent.
2x - 40 = x + 15
Subtract x from both sides.
x - 40 = 15
Add 40 to both sides.
x = 55
Answer:
Hello,
x=55
Step-by-step explanation:
The rhombus is formed of 2 isocele triangles
(since sides are equals)
The drawn diagonal bissects the angle
x+15=2x-40
2x-x=15+40
x=55
identify the function as a power function, a polynomial function, or neither.
f(x)=4(x^3)^3
Answer:7
Step-by-step explanation:7
A professor has learned that nine students in her class of 35 will cheat on the exam. She decides to focus her attention on ten randomly chosen students during the exam. a. What is the probability that she finds at least one of the students cheating
Answer:
[tex]\frac{73,331}{75,516}\approx 97.11\%[/tex]
Step-by-step explanation:
The probability that she will find at least one student cheating is equal to the probability that she finds no students cheating subtracted from 1.
Each time she randomly chooses a student the probability she will catch a cheater is equal to the number of cheaters divided by the number of students.
Therefore, for the first student she chooses, there is a [tex]\frac{9}{35}[/tex] chance that the student chosen is a cheater and therefore a [tex]\frac{26}{35}[/tex] chance she does not catch a cheater. For the second student, there are only 34 students to choose from. If we stipulate that the first student chosen was not a cheater, then there is a [tex]\frac{9}{34}[/tex] chance she will catch a cheater and a [tex]\frac{25}{34}[/tex] chance she does not catch the cheater.
Therefore, the probability she does not catch a single cheater after randomly choosing ten students is equal to:
[tex]\frac{26}{35}\cdot \frac{25}{34}\cdot \frac{24}{33}\cdot \frac{23}{32}\cdot \frac{22}{31}\cdot \frac{21}{30}\cdot \frac{20}{29}\cdot \frac{19}{28}\cdot \frac{18}{27}\cdot \frac{17}{26}[/tex]
Subtract this from one to get the probability she finds at least one of the students cheating after randomly selecting nine students. Let event A occur when the professor finds at least one student cheating after randomly selecting ten students from a group of 35 students.
[tex]P(A)=1-\frac{26}{35}\cdot \frac{25}{34}\cdot \frac{24}{33}\cdot \frac{23}{32}\cdot \frac{22}{31}\cdot \frac{21}{30}\cdot \frac{20}{29}\cdot \frac{19}{28}\cdot \frac{18}{27}\cdot \frac{17}{26},\\\\P(A)=1-\frac{2,185}{75,516},\\\\P(A)=\boxed{\frac{73,331}{75,516}}\approx 0.97106573441\approx \boxed{97.11\%}[/tex]
A group of dental researchers are testing the effects of acidic drinks on dental crowns. They have five containers of crowns labeled V, W, X, Y, and Z. They will randomly select one of the containers to be the control for the experiment by drawing one of five well-mixed slips of paper with the same labels from a hat. Which of the following is the probability model for the control container?
Answer:
[tex]\begin{array}{cccccc}{x} & {V} & {W} & {X} & {Y} & {Z} & P(x) & {0.20} & {0.20} & {0.20} & {0.20} & {0.20} \ \end{array}[/tex]
Step-by-step explanation:
Given
[tex]S = \{V,W,X,Y,Z\}[/tex]
[tex]n(S) = 5[/tex]
Required
The probability model
To do this, we simply calculate the probability of each container.
So, we have:
[tex]P(V) = \frac{n(V)}{n(S)} = \frac{1}{5} = 0.20[/tex]
[tex]P(W) = \frac{n(W)}{n(S)} = \frac{1}{5} = 0.20[/tex]
[tex]P(X) = \frac{n(X)}{n(S)} = \frac{1}{5} = 0.20[/tex]
[tex]P(Y) = \frac{n(Y)}{n(S)} = \frac{1}{5} = 0.20[/tex]
[tex]P(Z) = \frac{n(Z)}{n(S)} = \frac{1}{5} = 0.20[/tex]
So, the probability model is:
[tex]\begin{array}{cccccc}{x} & {V} & {W} & {X} & {Y} & {Z} & P(x) & {0.20} & {0.20} & {0.20} & {0.20} & {0.20} \ \end{array}[/tex]
Answer:
answer is V=.20, W=.20, X=.20, Y=.20, X=.20
Step-by-step explanation:
I need to know what goes in the amount box is someone will be kind enough to help me that would be very appreciated
Answer:
123
Step-by-step explanation:
Yw
A data set contains an independent and a dependent variable. Which must be true of the data set if a linear function can be used to represent the data?
The set must have a constant additive rate of change.
The set must have a constant multiplicative rate of change.
The values in the set must be positive.
The values in the set must be increasing.
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Answer:
(a) The set must have a constant additive rate of change
Step-by-step explanation:
If a linear function is suitable for representing the data, the data will demonstrate a constant slope. That is, for evenly spaced values of the independent variable, the differences of the values of the dependent variable will be constant. We can say ...
The set must have a constant additive rate of change.
How to do questions 19 and 20
Answer & Step-by-step explanation:
Using the information given in the question we can form the following 3 equations (in the order of the first 3 sentences)
w = 2h (twice the price)
t = h - 4 ($4 less)
3w + 2h + 5t = 136 (total purchasing and cost)
We can solve all 3 equations for h first, by substituting the first two equations, into the third equations w and t
3(2h) + 2h + 5(h-4) = 136
Simplify
6h + 2h + 5h - 20 = 136
13h = 136 + 20
13h = 156
h = 156/13
h = $12
Using this information, we can solve for w and t
w = 2h
w = 2(12)
w = $24
And finally
t = h - 4
t = 12 - 4
t = $8
Two cars start moving from the same point. One travels south at 52 mi/h and the other travels west at 39 mi/h. At what rate is the distance between the cars increasing two hours later
Answer:
The distance between them is 91 mi/h
Step-by-step explanation:
The Damon family owns a large grape vineyard in western New York along Lake Erie. The grapevines must be sprayed at the beginning of the growing season to protect against various insects and diseases. Two new insecticides have just been marketed: Pernod 5 and Action. To test their effectiveness, three long rows were selected and sprayed with Pernod 5, and three others were sprayed with Action. When the grapes ripened, 390 of the vines treated with Pernod 5 were checked for infestation. Likewise, a sample of 420 vines sprayed with Action were checked. The results are:
Insecticide Number of Vines Checked (sample size) Number of Infested Vines
Pernod 5 390 23
Action 420 46
At the 0.05 significance level, can we conclude that there is a difference in the proportion of vines infested using Pernod 5 as opposed to Action?
Answer:
The p-value of the test is 0.0088 < 0.05, which means that at the 0.05 significance level, we can conclude that there is a difference in the proportion of vines infested using Pernod 5 as opposed to Action.
Step-by-step explanation:
Before testing the hypothesis, we need to understand the central limit theorem and subtraction of normal variables.
Central Limit Theorem
The Central Limit Theorem establishes that, for a normally distributed random variable X, with mean [tex]\mu[/tex] and standard deviation [tex]\sigma[/tex], the sampling distribution of the sample means with size n can be approximated to a normal distribution with mean [tex]\mu[/tex] and standard deviation [tex]s = \frac{\sigma}{\sqrt{n}}[/tex].
For a skewed variable, the Central Limit Theorem can also be applied, as long as n is at least 30.
For a proportion p in a sample of size n, the sampling distribution of the sample proportion will be approximately normal with mean [tex]\mu = p[/tex] and standard deviation [tex]s = \sqrt{\frac{p(1-p)}{n}}[/tex]
Subtraction between normal variables:
When two normal variables are subtracted, the mean is the difference of the means, while the standard deviation is the square root of the sum of the variances.
Pernod 5:
23 out of 390, so:
[tex]p_P = \frac{23}{390} = 0.059[/tex]
[tex]s_P = \sqrt{\frac{0.059*0.941}{390}} = 0.0119[/tex]
Action:
46 out of 420, so:
[tex]p_A = \frac{46}{420} = 0.1095[/tex]
[tex]s_A = \sqrt{\frac{0.1095*0.8905}{420}} = 0.0152[/tex]
Test if there is a difference in proportions:
At the null hypothesis, we test if there is not a difference, that is, the subtraction of the proportions is 0. So
[tex]H_0: p_A - p_P = 0[/tex]
At the alternative hypothesis, we test if there is a difference, that is, the subtraction of the proportions is different of 0. So
[tex]H_1: p_A - p_P \neq 0[/tex]
The test statistic is:
[tex]z = \frac{X - \mu}{s}[/tex]
In which X is the sample mean, [tex]\mu[/tex] is the value tested at the null hypothesis, and s is the standard error.
0 is tested at the null hypothesis:
This means that [tex]\mu = 0[/tex]
From the samples:
[tex]X = p_A - p_P = 0.1095 - 0.059 = 0.0505[/tex]
[tex]s = \sqrt{s_A^2+s_P^2} = \sqrt{0.0119^2+0.0152^2} = 0.0193[/tex]
Value of the test statistic:
[tex]z = \frac{X - \mu}{s}[/tex]
[tex]z = \frac{0.0505 - 0}{0.0193}[/tex]
[tex]z = 2.62[/tex]
P-value of the test and decision:
The p-value of the test is the probability of a difference in proportions of at least 0.0505 to either side, which is P(|z| > 2.62), that is, 2 multiplied by the p-value of z = -2.62.
Looking at the z-table, z = -2.62 has a p-value of 0.0044.
2*0.0044 = 0.0088
The p-value of the test is 0.0088 < 0.05, which means that at the 0.05 significance level, we can conclude that there is a difference in the proportion of vines infested using Pernod 5 as opposed to Action.
Q4 Compute the shearing stress at the very top of the vertical web just below the flange. for a beam with the T shaped cross section shown in Figure. The shearing force V on the section of interest is 6000 N. Le
ʕ•ﻌ•ʔ[tex]\huge\bold\pink{hello!!!}[/tex]ʕ•ﻌ•ʔ
HERE IS UR ANSWER
_____________________
formula used to calculate shear stresses due to bending, τ = VQ/It. We have just read the internal shear force, V, off of the shear diagram. We also already calculated the moment of inertia for this particular section.
τ=6000N
Which is equivalent to 104
༡/16**?
o (10)4x
4(10)3
o (10)**
O (10)
Answer:
I think it is the last one.
Apply radical rule
= (10^1/2)3/4x
Apply exponent rule: (a^b)^c = a^bc
= 10^1/2 . 3/4x
Simplify: 1/2 . 3/4x: 3x/8
= 10^3x/8
How can the distributive property be use to solve this expression?
53x24
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Answer:
= 53(20 +4) or =24(50 +3) or =(20 +4)(50 +3)
Step-by-step explanation:
Either number can be rewritten as a sum. Typically, the sum will be based on place value: 53 = 50 + 3, for example, as opposed to something like 53 = 26 +27.
The usual method of multiplication taught in grade school makes use of this sort of rewriting.
53 × 24 = 53 × (4 +20) = 53×4 +53×20 = 212 +1060 = 1272
__
Additional comment
We find this easier to multiply as 53(20 +4) than as 24(50 +3) because doubling (multiplying by 2) and doubling again (multiplying by 4) is generally easier than multiplying by 3 or 5.
In grade school, we did this digit by digit, so ...
53×24 = (3 +50)(4 +20) = 3(4 +20) +50(4 +20) = 3×4 +3×20 +50×4 +50×20
= 12 +60 +200 +1000 = 1272
Whats is the job of dentisy
Answer:
A dentist, also known as a dental surgeon, is a medical professional who specializes in dentistry, the diagnosis, prevention, and treatment of diseases and conditions of the oral cavity. The dentist's supporting team aids in providing oral health services. Wikipedia
PLS HELP
Let f(x) = -6x + 3 and g(x) = 5x + 4. Find f · g and state its domain.
A) -30x2 - 9x + 12; all real numbers
B) -30x2 - 9x + 12; all real numbers except x = 4
C) -18x2 - 39x + 20; all real numbers
D) -18x2 - 39x + 20; all real numbers except x = 1
Answer:
-30x^2-9x+12 all real numbers
Step-by-step explanation:
f(x) = -6x + 3 and g(x) = 5x + 4
f(x) * g(x) = (-6x + 3) * ( 5x + 4)
FOIL
= -30x^2 -24x+15x +12
Combine like terms
=-30x^2-9x+12
The domain is what numbers x can take
There are no restrictions so all real numbers
At a store, 2 gallons of milk cost $6.
Which is the value of the ratio of dollars to gallons of milk?
0.33
per gallon
$3 per gallon
Answer:
B
Step-by-step explanation:
$3 per gallon
that is the procedure above
A normal population has mean and standard deviation . (a) What proportion of the population is greater than ? (b) What is the probability that a randomly chosen value will be less than .
Answer:
0.0171
0.89158
Step-by-step explanation:
Given :
μ = 60
Standard deviation , σ = 17
The probability that a randomly chosen score is greater than 96;
P(Z > Zscore)
Zscore = (score, x - μ) / σ
Zscore = (96 - 60) / 17 = 2.118
P(Z > 2.118) = 1 - P(Z < 2.118) = 1 - 0.9829 = 0.0171
The probability that a randomly chosen score is less than 81;
P(Z < Zscore)
Zscore = (score, x - μ) / σ
Zscore = (81 - 60) / 17 = 1.235
P(Z < 1.235) = 0.89158
A party rental company has chairs and tables for rent. The total cost to rent 2 chairs and 5 tables is $53. The total cost to rent 8 chairs and 3 tables is $42. What is the cost to rent each chair and each table?
Answer:
c=cost of one chair rental
t=cost of one table rental
8c+3t=42
2c+5t=53
multiply the second equation, each term on both sides, by -4
8c+3t=42
-8c-20t=-212
add the two equations
-17t=-170
divide both sides by -17
t=$10 to rent one table
substitute t=10 into either original equation
2c+5(10)=53
2c+50=53
2c=3
c=$1.50 to rent one chair
Owens Orchards sells apples in a large bag by weight. A sample of seven bags contained the following numbers of apples: 23, 19, 26, 17, 21, 24, 22. a. Compute the mean and median number of apples in a bag. (Round your answers to 2 decimal places.)
Answer:
The mean and median number of apples in a bag are 21.71 and 22 respectively.
Step-by-step explanation:
The mean is the arithmetic mean of a set of numbers. In other words, the mean is the average value of all my data.
The mean is calculated by adding all the values and dividing the sum by the total number of values. In this case:
[tex]Mean=\frac{23+19+26+17+21+24+22}{7}[/tex]
[tex]Mean=\frac{152}{7}[/tex]
Mean= 21.71
The median of a set of numbers is the average number in the set, that is, it is the value that occupies the central place of all the values.
The median can be calculated by putting the numbers in ascending order and then:
if the quantity is numbers it is odd: the median is the number in the center of that distribution. if the number of numbers is even: the median is the mean of the two middle numbers.In this case:
Putting the numbers in ascending order: 17, 19, 21, 22, 23, 24, 26
Since the quantity is odd numbers, the median is the number in the center of that distribution. So Median= 22
The mean and median number of apples in a bag are 21.71 and 22 respectively.
A motorist travels 90 miles at a rate of 20 miles per hour. If he returns the same distance at a rate of 40 miles per hour, what is the average speed for the entire trip, in miles per hour? (Explain)
Answer:
26 2/3
Step-by-step explanation:
Average speed is total distance divided by total time.
The time for the first trip was ...
(90 mi)/(20 mi/h) = 4.5 h
The time for the return trip was ...
(90 mi)/(40 mi/h) = 2.25 h
Then the average for the trip and return is ...
total miles/total time = (90 +90)/(4.5 +2.25) = 26 2/3 . . . . mi/h
The average speed for the round trip was 26 2/3 miles per hour.
what is the slope intercept equation of the line below?
Answer:
[tex]{ \tt{slope, \: m = \frac{1 - ( - 1)}{1 - 0} }} \\m = 2 \\ y - intercept : y = mx + c \\ { \tt{1 = (2 \times 1) + c}} \\ c = - 1 \\ { \boxed{ \bf{y = 2x - 1}}}[/tex]
Solve the following equation algebraically
3x 4 – 1 = 1874
Which of the following is equal to the rational expression below when x≠7
Answer:
nothing wlill be equql
Step-by-step explanation:
its will be not equal because the sine given is not equals to
A rectangle with a length of 5 cm and a width of 2 cm is enlarged by a scale factor of 5. What would be the area of the new rectangle?
Area of old rectangle is multiplied by 25
Area of old rectangle is multiplied by 5
Area of old rectangle is multiplied by 20
Area of old rectangle is multiplied by 10
Area is in square units.
Square the factor: 5^2 = 25
The new area would be the area of the old rectangle multiplied by 25
Answer: Area of old rectangle is multiplied by 25
Step-by-step explanation:
Original rectangle
Length = 5 cmWidth = 2 cmArea = 2 · 5 = 10 cm²
New rectangle
Length = 5 · 5 = 25 cmWidth = 2 · 5 = 10 cmArea = 25 · 10 = 250 cm²
The area of the new rectangle = area of old rectangle × 25
factorise yf -cg - yg+ cf
Answer:
(f-g) (y+c)
Step-by-step explanation:
yf -cg - yg+ cf
Using factor by grouping, y from the first group and c from the second group
yf - yg+ cf -cg
y( f-g) +c(f-g)
Factor out (f-g)
(f-g) (y+c)
Someone help so lost I didn’t understand the course and now I’m stuck please help a girl out
Answer:
the answer is b. you are basically multiplying them
If f(2) = 13 and f '(x) ≥ 2 for 2 ≤ x ≤ 7, how small can f(7) possibly be?
Answer:
23
Step-by-step explanation:
We are given that
f(2)=13
[tex]f'(x)\geq 2[/tex]
[tex]2\leq x\leq 7[/tex]
We have to find the possible small value of f(7).
We know that
[tex]f'(x)=\frac{f(b)-f(a)}{b-a}[/tex]
Using the formula
[tex]f'(x)=\frac{f(7)-f(2)}{7-2}[/tex]
[tex]f'(x)=\frac{f(7)-13}{5}[/tex]
We have
[tex]f'(x)\geq 2[/tex]
[tex]\frac{f(7)-13}{5}\geq 2[/tex]
[tex]f(7)-13\geq 2\times 5[/tex]
[tex]f(7)-13\geq 10[/tex]
[tex]f(7)\geq 10+13[/tex]
[tex]f(7)\geq 23[/tex]
The small value of f(7) can be 23.
Which of the following best describes a type of growth that is exponential at
first but slows as the amount reaches a certain maximum value?
A. Exponential decay
B. Exponential growth
C. Linear growth
D. Logistic growth
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Answer:
D. Logistic growth
Step-by-step explanation:
The logistic growth function models a situation where the rate of growth is jointly proportional to the population and to the difference between the population and the carrying capacity.
Attached is an example of such a function.
g Find the probability of the following card hands from a 52-card deck. In poker, aces are either high or low. A bridge hand is made up of 13 cards. In poker, a flush (5 in same suit) in any suit
Answer:
The answer is "[tex]1.54 \times 10^{-6}[/tex]".
Step-by-step explanation:
Calculating the probability of the cards that hand from a 52-card deck.
The aces are high or low in poker.
There are 13 cards in the bridge hand.
A royal flush (5 suit top cards) in poker.
There are 5 various poker hands with [tex]\binom{52}{5}[/tex].
There are four royal flushes, one in each suit.
[tex]P (royal\ flush) =\frac{4}{\binom{52}{5}}\\\\[/tex]
[tex]=\frac{4}{2598960}\approx 1.54 \times 10^{-6}[/tex]
