Answer:
The expressión that represents the length:
a = 2w + 1
a = length of the rectangle
w = width of the rectangle
HELPP NEEDED ASAP PLEASE.
There are 20n members in the Trumpington marching band, and when they line up in rows of 26, there are 4 band members left over. If n is an integer and there are fewer than 1000 band members, what is the maximum number of people that could be in the Trumpington marching band?
Answer:
The maximum number of people that can be in the Trumpington marching band is 940 people
Step-by-step explanation:
The number of members = 20·n
The number per row = 26
The number left = 4
Therefore, we have;
If there are x rows of 26, we have;
26 × x = 20·n - 4
We have;
26 × x < 996
26 × x < 20·n
20·n < 996 therefore, 20·n ≤ 980
We check that 980/26 = 37 and some fractions
26 × 37 = 962 which will leave a remainder of 2
Therefore, we note that for 26 to have a remainder of 4, the last digit of the factor x must be 6 so has to get the last digit of the product 26 × x to be 6 while the digit of the product 20×n is 0 which will live 4 members out to get to the next 10 as follows;
26 × 36 = 936 while 20 × 47 = 940
We get 940 - 936 = 4 members
Therefore, the maximum number of people that can be in the Trumpington marching band = 940.
A jar contains only red, white and blue marbles. The number of red marbles is 4/5 the number of white ones, and the number of white ones is 3/4 the number of blue ones. If there are 470 marbles in all, how any of them are blue?
•120
•200
•150
•184
Answer:
200
Step-by-step explanation:
i multiplied the answer choices by the fractions and 200 was the one that checked out
Need help pls will give you a good rating.
Answer:
x+4
.....................
Answer
[tex] \boxed{x + 4}[/tex]
Option C is the correct option
Step by step explanation
Let's find the expression which represents the length of the box:
[tex] \mathsf{length \times width \times height \: of \: prism \: = \: volume \: of \: prism}[/tex]
[tex] \mathsf{lengh \times \: (x - 1) \times (x + 8) = {x}^{3} + 11 {x}^{2} + 20x - 32}[/tex]
[tex] \mathsf{length = \frac{ {x}^{3} + 11 {x}^{2} + 20x - 32 }{(x - 1)(x + 8)} }[/tex]
Write 11x² as a sum
[tex] \mathsf{ = \frac{ {x}^{3} - {x}^{2} + 12 {x}^{2} + 20x - 32 }{(x - 1)(x + 8)} }[/tex]
Write 20x as a sum
[tex] \mathsf{ = \frac{ {x}^{3} - {x}^{2} + 12 {x}^{2} - 12x + 32x - 32 }{(x - 1)(x + 8)}}[/tex]
Factor out x² from the expression
[tex] \mathsf{ = \frac{ {x}^{2}(x - 1) + 12 {x}^{2} - 12x + 32x - 32 }{(x - 1)(x + 8)} }[/tex]
Factor out 12 from the expression
[tex] \mathsf{ = \frac{ {x}^{2}(x - 1) + 12x(x - 1) + 32x - 32 }{(x - 1)(x + 8)} }[/tex]
Factor out 32 from the expression
[tex] \mathsf{ = \frac{ {x}^{2}(x - 1) + 12x(x - 1) + 32(x - 1) }{(x - 1)(x + 8)} }[/tex]
Factor out x+1 from the expression
[tex] \mathsf{ = \frac{(x - 1)( {x}^{2} + 12x + 32) }{(x - 1)(x + 8)} } [/tex]
Factor out 12x as a sum
[tex] \mathsf{ = \frac{(x - 1)( {x}^{2} + 8x + 4x + 32) }{(x - 1)(x + 8)} }[/tex]
Reduce the fraction with x-1
[tex] \mathsf{ = \frac{ {x}^{2} + 8x + 4x + 32 }{(x + 8)} }[/tex]
Factor out x from the expression
[tex] \mathsf{ = \frac{x(x + 8) + 4x + 32}{(x + 8)} }[/tex]
Factor out 4 from the expression
[tex] \mathsf{ = \frac{x(x + 8) + 4(x + 8)}{x + 8} }[/tex]
Factor out x+8 from the expression
[tex] \mathsf{ = \frac{(x + 8)(x + 4)}{x + 8} } [/tex]
Reduce the fraction with x+8
[tex] \mathsf{ = x + 4}[/tex]
hence, x+4 is the expression that represents the length of a box.
Hope I helped!
Best regards!
A man gave his 8000$ as pocket money and his son 1000$ less.Express the girls money as a percentage of the total sum of money.
Answer:
About 89%
Step-by-step explanation:
8000 + 1000 = 9000.
To find the girls money as a percentage of the total sum of money, you must take 8000 and divide it by 9000.
8000/9000 = .8888 = 88.88 = 88.9% or about 89%.
A daycare facility is enclosing a rectangular area along the side of their building for the children to play outdoors. They need to maximize the area using 180ft of fencing on three sides of the yard. The quadratic equation A=−2x2+180x gives the area, A, of the yard for the length, x, of the building that will border the yard. Find the length of the building that should border the yard to maximize the area, and then find the maximum area.
Answer:
a) length x = 45ftb) maximum area = 4050 ft²Step-by-step explanation:
Given the quadratic equation A=−2x2+180x that gives the area A of the yard for the length x, to maximize the area of the yard then dA/dx must be equal to zero i.e dA/dx = 0
If A=−2x²+180x
dA/dx = -4x + 180 = 0
-4x + 180 = 0
Add 4x to both sides
-4x + 180 + 4x = 0 + 4x
180 = 4x
x = 180/4
x = 45
Hence the length of the building that should border the yard to maximize the area is 45 ft
To find the maximum area, we will substitute x = 45 into the modelled equation of the area i.e A=−2x²+180x
A = -2(45)²+180(45)
A = -2(2025)+8100
A = -4050 + 8100
A = 4050 ft²
Hence the maximum area of the yard is equal to 4050 ft²
Dos secretarias deben escribir el mismo número de cartas. La primera escribe 2 cartas por hora y la otra, 5 cartas por hora. Si la primera ha empezado 6 horas antes que la segunda. ¿Cuántas horas
trabajó la primera?
Ayuden!!
Answer:
El número de horas que trabajó la primera secretaria es de 10 horas
Step-by-step explanation:
Los parámetros dados son;
El número de letras que la primera secretaria puede escribir por hora = 2 letras
El número de letras que el segundo secretario puede escribir por hora = 5 letras
Dado que la primera secretaria comenzó 6 horas antes que la segunda secretaria, tenemos;
Sea el tiempo en horas en que ambas secretarias habrán escrito el mismo número de letras = [tex]t_e[/tex]
2 × [tex]t_e[/tex] + 2 × 6 = 5 × [tex]t_e[/tex]
2 × [tex]t_e[/tex] + 12 = 5 × [tex]t_e[/tex]
12 = 5 × [tex]t_e[/tex] - 2 × [tex]t_e[/tex] = 3 × [tex]t_e[/tex]
12 = 3 × [tex]t_e[/tex]
3 × [tex]t_e[/tex] = 12
[tex]t_e[/tex] = 12/3 = 4 horas
El número de horas que trabajó la primera secretaria = Tiempo de inicio anticipado + Tiempo que le toma a la segunda secretaria que comenzó 6 horas más tarde y a la primera secretaria que había estado escribiendo durante 6 horas (inicio anticipado) escribir la misma cantidad de cartas
El número de horas que trabajó la primera secretaria = 6 + 4 = 10 horas.
Por lo tanto, el número de horas que trabajó la primera secretaria = 10 horas.
how do you find the surface area of this triangular prism?
To find the area of a triangular prism you have to do A 1/2 bh or A bh/2 which means you have to multiply those two fractions and reduce them
Answer:
Find the area of the 2 triangle faces first and then find the area of the 3 rectangle faces and add them together to get [tex]159cm^{2}\\[/tex]
Step-by-step explanation:Step 1: Find the surface area of the 2 triangles
[tex]\frac{(6)(5.5)}{2}[/tex] x2 = [tex]33cm^2\\[/tex]
Step 2: Find the surface area of the 3 rectangles
(6x7) x 3 = [tex]126cm^2[/tex]
Step 3: Add the 2 surface areas together
[tex]33cm^2\\[/tex] + [tex]126cm^2[/tex] = [tex]159cm^2[/tex]
Therefore the surface area of the prism is [tex]159cm^{2}[/tex]
i need help :( please answer
Answer:
[tex] = - ( \frac{1}{3} \times \frac{1}{3} \times \frac{1}{3} \times \frac{1}{3} )[/tex]
Step-by-step explanation:
[tex] - {(3)}^{ - 4} = \\ - ( { 3}^{ - 4} )= \\ - (\frac{1}{ {3}^{4} } )[/tex]
[tex] = - ( \frac{1}{3} \times \frac{1}{3} \times \frac{1}{3} \times \frac{1}{3} )[/tex]
[tex] = - \frac{1}{81} [/tex]
I hope it helps
I need 51-55 Thanks You :D no
Answer:
Below
Step-by-step explanation:
All figures are squares. The area of a square is the side times itself
Let A be the area of the big square and A' the area of the small one in all the 5 exercices
51)
● (a) = A - A'
A = c^2 and A' = d^2
● (a) = c^2 - d^2
We can express this expression as a product.
● (b) = (c-d) (c+d)
■■■■■■■■■■■■■■■■■■■■■■■■■■
52)
● (a) = A-A'
A = (2x)^2 = 4x^2 and A'= y^2
● (a) = 4x^2 - y^2
● (b) = (2x-y) ( 2x+y)
■■■■■■■■■■■■■■■■■■■■■■■■■■
53)
● (a) = A-A'
A = x^2 and A' = y^2
● (a) = x^2-y^2
● (b) = (x+y) (x-y)
■■■■■■■■■■■■■■■■■■■■■■■■■■
54)
● (a) = A-A'
A = (5a)^2 = 25a^2 and A' =(2b)^2= 4b^2
● (a) = 25a^2 - 4b^2
● (a) = (5a-2b) (5a+2b)
■■■■■■■■■■■■■■■■■■■■■■■■■■
55)
● (a) = A - 4A'
A = (3x)^2 = 9x^2 and A'= (2y)^2 = 4y^2
● (a) = 9x^2 - 4 × 4y^2
● (a) = 9x^2 - 16y^2
● (a) = (3x - 4y) (3x + 4y)
Which of the following is a point-slope equation of a line that passes through the points (-1,4) and (8,2)
Answer:
y - 2 = -2/9( x - 8)
Step-by-step explanation:
hope this helps
let me know if u need more help
Answer:
y - 2 = -2/9(x - 8) or y - 4 = -2/9(x + 1)
Step-by-step explanation:
find slope first
(2 - 4)/(8 - -1) = -2/9
y - 2 = -2/9(x - 8)
Solve the following non-linear system of equations algebraically.
y = - 2x² - 4x + 5 and
y = 2x^2 + 4x + 5
Answer:
x = -2
Step-by-step explanation:
since y is common in both equations, you can equate them to be equal
-2x² - 4x + 5 = 2x² + 4x + 5
4x² + 8x = 0
factor out 4x
4x(x + 2) = 0
divide both sides by 4x
x + 2 = 0
x = -2
question : 4(3x + 2) -6 x 6
Answer:
x= 24
Step-by-step explanation:
open the bracket
4×3x =12x + 4 × 2 =8
12×+ 8-6×6
12×+ 12
x= 24
Answer:
12x - 28
Step-by-step explanation:
Because of PEMDAS you start with the parentheses and distribute the 4.
So,
(12x + 8) -6 x 6
Then, solve for the 6's
(12x + 8) -36
Remove the parentheses
12x + 8 - 36
Lastly, you get
12x - 28.
This is as far as you can go because there is no equals sign so you cannot actually solve for x.
Please help asap. I will give a thanks, rate your answer and mark the brainliest one too!
The formula v^2 - u^2 = 2as is used to model a moving object, where: u= starting speed (m/s) v = final speed (m/s) a = acceleration (m/s²) s = distance travelled (m) A car stops at some traffic lights. It then accelerates at 2.3 m/s² until it reaches a speed of 13.6 m/s. Find the distance, s, that it has travelled since stopping at the lights. Give your answer correct to 1 decimal place.
Answer:
s = 40.2 m
Step-by-step explanation:
It is given that,
Initial speed of the car, u = 0 m/s
Final speed of the car, v = 13.6 m/s
Acceleration of the car, a = 2.3 m/s²
We need to find the distance, s, that it has travelled since stopping at the lights. For this, we will use third equation of motion as :
[tex]v^2-u^2=2as[/tex]
s is distance
[tex]s=\dfrac{v^2-u^2}{2a}\\\\s=\dfrac{(13.6)^2-0}{2\times 2.3}\\\\s=40.2\ m[/tex]
So, the distance covered by the car is 40.2 meters.
Help me figure this out, I don’t understand
Answer:
0,3
1,1
-1,1
-2.55, -10
2.55, -10
Step-by-step explanation:
It's asking for you to graph it and figure out points from the equation.
What you can do is subsitute values for X and solve for Y or use a graphing calculator. I used desmos, an online calculator and looked for coordinates. Also the +3 is the y intercept, which means y is 3 when x is 0.
Question. 7 Let abc be a three-digit number. Then, abc + bca + cab is not divisible by (a) a + b + c (b) 3 (c) 37 (d) 9
Answer:
D. 9
Step-by-step explanation:
Let
abc=100a+10b+c
bca=100b+10c+a
cab=100c+10a+b
abc + bca + cab=(100a+10b+c) + (100b+10c+a) + (100c+10a+b)
=100a + 10b + c + 100b + 10c + a + 100c + 10a + b
Collect like terms
=100a + a + 10a + 10b + 100b + b + c + 10c + 100c
=111a + 111b + 111 c
Factorise
=111(a+b+c)
abc + bca + cab = 111(a+b+c)
Factors of 111(a+b+c)= 1, 3, 37, 111, and (a+b+c)
abc + bca + cab is divisible by a+b+c because it is a factor of 111(a+b+c)
abc + bca + cab is divisible by 3 because 3 is a factor of 111(a+b+c)
abc + bca + cab is divisible by 37 because 37 is a factor of 111(a+b+c)
abc + bca + cab is not divisible by 9 because 9 is not a factor of 111(a+b+c)
Complete the square.
3x^2-12x=96
Answer:
x = 8 and -4
Step-by-step explanation:
3x² - 12x = 96
3(x² - 4x + 4 = 32 + 4)
3[(x - 2)² = 6²]
x - 2 = +/- 6
x = 8
x = -4
1: The best statement for reason 6 of this proof is -∠A ≅ ∠C
-∠B ≅ ∠D
-∠B and ∠D are supplements
-∠B ≅ ∠B
2.The best reason for statements 3.5. and 7 in this proof is
- Alternate interior angles are congruent.
-Corresponding angles are congruent.
-Alternate exterior angles are congruent.
-Interior angles on the same sides of a transversal are supplements.
3. The best statement for reason 8 of this proof is
-∠B ≅ ∠B -∠A and ∠C are supplements.
-∠B ≅ ∠D
-∠A ≅ ∠C
Answer:
1) -∠B ≅ ∠D
2) -Interior angles on the same side of a transversal are supplementary
3) -∠A ≅ ∠C
Step-by-step explanation:
1) Given that ∠A and ∠B are supplements and ∠A and ∠D are supplements, we have; ∠B ≅ ∠D
2) Given that ABCD is a parallelogram, therefore ∠A and ∠B, ∠A and ∠D and ∠B and ∠C are interior angles on the same side of a transversal and are therefore supplementary
3) Given that ∠A and ∠B and ∠B and ∠C are supplementary, therefore, ∠A ≅ ∠C.
Find the product of 0.3×0.23
Answer:
0.069
Step-by-step explanation:
0.3*0.23=0.069
For all x, 5-3(x-4)=?
Answer:
the answer that i find is 17-3x
The standard normal curve shown below models the population distribution of a random variable. What proportion of the values in the population does not lie between the two z-scores indicated on the diagram? z = -1.2 z = 0.85
Answer:
31.28%
Step-by-step explanation:
The z score is used in statistics to determine by how many standard deviations the raw score is above or below the mean. If the raw score is above the mean then the z score is positive while if the raw score is below the mean then the z score is negative. It is given by:
[tex]z=\frac{x-\mu}{\sigma}[/tex]
Given the z score z = -1.2 z = 0.85. From the normally distribution table, the probability that a value falls between z = -1.2 and z = 0.85 = P(z < 0.85) - P(z < -1.2) = 0.8023 - 0.1151 = 0.6872
The proportion of values that do not fall between z = -1.2 and z = 0.85 = 1 - 0.6872 = 0.3128 = 31.28%
What collateral secures a mortgage?
O A.
5% of the purchase price of the house
B.
the house itself
C.
10% of the purchase price of the house
D.
none
Answer:
The House
Step-by-step explanation:
How many times larger is the value of
86,000,000 than 8,600?
Answer:
a 1000 times// just divide them
Answer:
10,000 times Larger
Step-by-step explanation:
To determine the multiple larger for 86,000,000 than 8,600, we simply will use the division operation and the result will be the multiple.
86,000,000 / 8,600 = 10,000
Hence, the number 86,000,000, is 10,000 times larger than 8,600.
Another method is simply to look at the additional zeroes that 86,000,000 has in comparison to 8,600. Since we can see that 86 is the only non-zero digit within the two numbers, we can use the properties of the decimal system to compare. Note that 86,000,000 has 6 zeroes, while 8,600 has two zeros. This means that we will need 4 zeroes as part of our tens multiple, so we can say that 10,000 is the multiple. Once again, we see that 86,000,000 is 10,000 times larger than 8,600.
Cheers.
I WILL GIVE BRAINLEST PLEASE HELP
Which of the following is an example of the difference of two squares?
A x2−9
B x3−9
C (x+9)2
D (x−9)2
I know the answer is either A or B i might be wrong tho pls help im not sure.
Answer:
A
Step-by-step explanation:
In this question, we are concerned with selecting which of the options best represents the difference of two squares.
Let’s have an exposition below as follows;
Consider two numbers, which are perfect squares and can be expressed as a square of their square roots;
a^2 and b^2
where a and b represents the square roots of the numbers respectively.
Inserting a difference between the two, we have;
a^2 - b^2
Now by applying the difference of two squares, these numbers will become;
a^2 - b^2 = (a + b)(a-b)
So our answer out of the options will be that option that could be expressed as above.
The correct answer to this is option A
Kindly note that;
x^2 -9 can be expressed as x^2 - 3^2 and consequently, this can be written as;
(x-3)(x + 3)
a piece of paper is 5.5 x 10^-4 inches thick. If jennifer has 35 such pieces,how thick is the whole stack? Write your answer in standard form.
Answer:
T = 0.01925 m
Step-by-step explanation:
It is given that,
Thickness of a piece of a paper is [tex]5.5\times 10^{-4}\ m[/tex]
Total number of pieces are 35
We need to find the thickness of the whole stack. It is simply a case of unitary method.
For 35 pieces, thickness is :
[tex]T=35\times 5.5\times 10^{-4}\\\\T=0.01925\ m[/tex]
So, the thickness of the whole stack is 0.01925 metres.
please please answer this question now
با )
Answer:
43/90
Step-by-step explanation:
We want to express 0.47777... as a ratio of two integers. To do so, we need to multiply by 10^n, where n is the number of repeating decimals. Only 7 is repeating so we multiply 0.47777... by 10. The trick to do this is to let x=0.47777... In other words, what we are doing is the following:
[tex]x=0.47777...\\10x=4.7777....\\\text{Subtract x}\\10x-x=4.7777...-x\\9x=4.7777...-0.4777...\\9x=4.3\\x=4.3/9=43/90=0.4\overline{7}[/tex]
8) There are 2116 students in a school .In how many equal rows and columns can they be arranged for a drill display?
Answer:
46
Explanation:
root of 2116
=46×46
Therefore 46 columns and 46 rows
Answer:
46 rows, 46 columns.
Step-by-step explanation:
First factor 2116:
2) 2116
2 } 2058
23 ) 529
23
2116 = 2*2*23*23
= 46 * 46
sandra is playing a trivia game.on her first turn she lost 75 points. on her second turn,she lost 35 points. on her third turn,she scored 100 points. What is sandras score after three turns?
Answer: -10 points
Step-by-step explanation:
She lost 110,so that loss -the gain(100) is the total score at the end of three games
Kameryn flips a coin, rolls a 6-sided die, and then spins an 8-section
spinner. How many possible outcomes are there?
Answer:
96 possible outcomes
Step-by-step explanation:
2 x 6 x 8 = 96
In the expression 3x2 + y -5, which of the following terms does not have a variable?
A.3x2
B. y
A
C. -5
D. None of these choices are correct.
Answer:
A, C
Step-by-step explanation:
Only B is containing a variable .
The -5 is not variable.
We have given that,
A.3x2
B. y
A
C. -5
In the expression 3x^2 + y -5
We have to determine which of the following terms does not have a variable.
What is the variable?
variable, In algebra, a symbol stands in for an unknown numerical value in an equation. Commonly used variables include x and y (real-number unknowns), z (complex-number unknowns), t (time), r (radius), and s (arc length).
Only C contains a variable.
The -5 is not variable.
To learn more about the variable visit:
https://brainly.com/question/2804470
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Select all of the numbers that are correctly written in scientific notation. 10.8\times10^{-3}10.8×10 −3 0.54\times10^60.54×10 6 1\times10^{-4}1×10 −4 7.6\times10^{2.5}7.6×10 2.5 9.8\times10^59.8×10 5
Answer:
1×10⁻⁴ and 9.8×10⁵Step-by-step explanation:
The standard form of writing a scientific notation is expressed as [tex]a.b*10^n[/tex] where a, b and n are integers. Note that a, b and n cannot be a fraction. When writing in scientific notation, the value of 'a' must not be equal to zero and it must not be a 'two digits values' but just 'a digit value'.
Based on the above conclusion, the following numbers are correctly written in scientific notation.
1×10⁻⁴ and 9.8×10⁵
- The expression 10.8×10 −3 is not correctly written because the value of a on comparison is a two digits number i.e 10.
- Also, 0.54×10^6 is not correctly written because a is zero on comparison
- 7.6×10 2.5 is not correctly written because the power is a decimal number i.e 2.5. We must only have an integer as the degree.
