Need help ASAP !!!when creating a question for a survey , the way a question is written:

Answer:

1. a. 2

b. -½

c. y - 3 = -½(x - 8) => point-slope form

y = -½x + 7 => slope-intercept form

2. a. -1

b. 1

c. y - 5 = 1(x - 3) => point-slope form

y = x + 2 => slope-intercept form

Step-by-step explanation:

1. (8, 3) and (10, 7):

a. The gradient for the line joining the points:

Gradient = [tex] \frac{y_2 - y_1}{x_2 - x_1} [/tex]

Let,

[tex] (8, 3) = (x_1, y_1) [/tex]

[tex] (10, 7) = (x_2, y_2) [/tex]

Plug in the values

Gradient = [tex] \frac{7 - 3}{10 - 8} [/tex]

Gradient = [tex] \frac{4}{2} [/tex]

Gradient = 2

b. The gradient of the line perpendicular to this line = the negative reciprocal of 2

Negative reciprocal of 2 = -½

c. The equation of perpendicular line if it passes through the first point, (8, 3):

Equation of the perpendicular line in point-slope form can be expressed as y - b = m(x - a).

Where,

(a, b) = (8, 3)

Slope (m) = -½

Substitute (a, b) = (8, 3), and m = -½ into the point-slope equation, y - b = m(x - a).

Thus:

y - 3 = -½(x - 8) => point-slope form

We cam also express the equation of the perpendicular line in slope-intercept form by rewriting y - 3 = -½(x - 8) in the form of y = mx + b:

Thus:

y - 3 = -½(x - 8)

y - 3 = -½x + 4

y - 3 + 3 = -½x + 4 + 3

y = -½x + 7

2. (3, 5) and (4, 4):

a. The gradient for the line joining the points:

Gradient = [tex] \frac{y_2 - y_1}{x_2 - x_1} [/tex]

Let,

[tex] (3, 5) = (x_1, y_1) [/tex]

[tex] (4, 4) = (x_2, y_2) [/tex]

Plug in the values

Gradient = [tex] \frac{4 - 5}{4 - 3} [/tex]

Gradient = [tex] \frac{-1}{1} [/tex]

Gradient = -1

b. The gradient of the line perpendicular to this line = the negative reciprocal of -1

Negative reciprocal of -1 = 1

c. The equation of perpendicular line if it passes through the first point, (3, 5):

Equation of the perpendicular line in point-slope form can be expressed as y - b = m(x - a).

Where,

(a, b) = (3, 5)

Slope (m) = 1

Substitute (a, b) = (3, 5), and m = 1 into the point-slope equation, y - b = m(x - a).

Thus:

y - 5 = 1(x - 3) => point-slope form

We can also express the equation of the perpendicular line in slope-intercept form by rewriting y - 5 = 1(x - 3) in the form of y = mx + b:

Thus:

y - 5 = 1(x - 3)

y - 5 = x - 3

y - 5 + 5 = x - 3 + 5

y = x + 2

Answer:

59.04°

58.31 inches

Step-by-step explanation:

The solution triangle is attached below :

Since we have a right angled triangle, we can apply trigonometry to obtain the angle ladder makes with the ground;

Let the angle = θ

Tanθ = opposite / Adjacent

Tanθ = 50/30

θ = tan^-1(50/30)

θ = 59.036°

θ = 59.04°

The length of ladder can be obtained using Pythagoras :

Length of ladder is the hypotenus :

Hence,

Hypotenus = √(adjacent² + opposite²)

Hypotenus = √(50² + 30²)

Hypotenus = √(2500 + 900)

Hypotenus = 58.309

Length of ladder = 58.31 inches

Answer:

59°

58.3 inches

Step-by-step explanation:

Here is the full question :

A ladder is placed 30 inches from a wall. It touches the wall at a height of 50 inches from the ground. The angle made by the ladder with the ground is degrees, and the length of the ladder is inches.

Please check the attached image for a diagram explaining this question

The angle the ladder makes with the ground is labelled x in the diagram

To find the value of x given the opposite and adjacent lengths, use tan

tan⁻¹ (opposite / adjacent)

tan⁻¹  (50 / 30)

tan⁻¹ 1.667

= 59°

the length of the ladder can be determined using Pythagoras theorem

The Pythagoras theorem : a² + b² = c²

where a = length

b = base

c =  hypotenuse

√(50² + 30²)

√(2500 + 900)

√3400

= 58.3 inches

Answer:

[tex]\displaystyle x = \sqrt{y^2 + z^2}[/tex]

General Formulas and Concepts:

Pre-Algebra

Algebra i

Step-by-step explanation:

Step 1: Define

Identify

[tex]\displaystyle x^2 = y^2 + z^2[/tex]

Step 2: Solve for x

Answer:

Answer 60

Step-by-step explanation:

The distance from an exterior point to the incircle is equal to the tangent length in both cases.

So the 19 is made up of 9 and 10.

The length of the other portion of the tangent from the end of 19 to the tangent point on the right is also 10.

By a similar argument the lower length of the line to the tangent point is 11.

So you have

9 + 9 + 10 + 10 + 11 + 11

18 + 20 + 22 = 60.

Answer:

the correct answer is b and I know this because I just had it

Step-by-step explanation:

what to find then??.........

19/25 which is likely

count the ones with y and put that over 25

Answer:

C

Step-by-step explanation:

7+(-4x^2) where x=0, 7+0=7

Answer:

C. 7

Step-by-step explanation:

[tex]7+(-4x^2)[/tex]

Replace x with 0

[tex]7+(-4(0)^2)[/tex]

0 squared is 0. -4 times 0 is also 0.

7+0=7

I hope this helps!

The calculated measure of the angle QSR is 68 degrees

From the question, we have the following parameters that can be used in our computation:

Angle b = 136 degrees

The measure of angle QSR can be calculated using

QSR = 1/2 * Angle b

substitute the known values in the above equation, so, we have the following representation

QSR = 1/2 * 136 degrees

Evaluate

QSR = 68 degrees

Hence, the measure of angle QSR is 68 degrees

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Answer:

[tex]{ \tt{1 \: mg = 1 \times {10}^{ - 3} \: g}} \\ { \tt{75 \: mg = (75 \times 1 \times {10}^{ - 3} ) \: g}} \\ { \bf{ = 75 \times 10 {}^{ - 3} \: grams}} \\ { \bf{ = 0.075 \: grams}}[/tex]

Answer:

a) a=-12

b) a=27

Step-by-step explanation:

a) parallel lines have = slopes SO

-3/2 = -3/2

-3/2 = 18/a

-3a/2 = 18

-3a = 18 * 2 = 36

a = -12

b) perpendicular lines have negative inverse slopes SO

- 3/2 ---> 2/3

2/3 = 18/a

2a/3 = 18

2a = 18 * 3 = 54

a = 54/2 = 27

Answer:

[tex]x = -6.5c[/tex]

[tex]c = -\frac{x}{6.5}[/tex]

Step-by-step explanation:

In both cases, you are simply isolating the variable you are trying to solve for:

[tex]\frac{-x}{c} = 6.5[/tex]

Solve for x. Isolate the variable, x. Note the equal sign, what you do to one side, you do to the other. First, multiply c to both sides, and then divide -1 from both sides:

[tex]\frac{-x}{c} = 6.5\\\frac{-x}{c} * c = 6.5 * c\\-x = 6.5c\\\frac{-x}{-1} = \frac{6.5c}{-1}\\x = -6.5c[/tex]

Solve for c. Isolate the variable, c. Note the equal sign, what you do to one side, you do to the other. Multiply -1/x to both sides of the equation:

[tex]\frac{-x}{c} = 6.5\\\frac{-x}{c}(c)) = 6.5(c) \\-x = 6.5c\\\frac{-x}{6.5} = \frac{6.5c}{6.5}\\c = -\frac{x}{6.5}[/tex]

Answer:

x = -6.5c

-x/6.5 = c

Step-by-step explanation:

-x/c=6.5

Multiply each side by -c

-x/c * -c=6.5*-c

x = -6.5c

-x/c=6.5

Multiply each side by c

-x/c *c=6.5*c

-x = 6.5c

Divide each side by 6.5

-x/6.5 = 6.5c/6.5

-x/6.5 = c

Answer:

fourth time ...

same problem...

the red line crosses a corner of a box at (4,20) and (2,10)

20/4 = 5

and

10/2 = 5

the slope , constant, gradient for this relationship is "5"

Step-by-step explanation:

Answer:

The radius is 3.5cm

Step-by-step explanation:

Given

[tex]V = 192.5cm^3[/tex]

[tex]h = 5cm[/tex]

Required

The volume (V)

The volume of the vase is:

[tex]V = \pi r^2h[/tex]

So, we have:

[tex]192.5 = 22/7 * r^2 * 5[/tex]

Divide by 5

[tex]38.5 = 22/7 * r^2[/tex]

Multiply by 7/22

[tex]12.25= r^2[/tex]

Take positive square roots

[tex]r = 3.5[/tex]

The quotient of 40 and 5

40÷5=8

=> Product of that number with 7 and 8

So number to find is : 7x8=56

The product of 7 and the quotient of 40 divided by 5 is 56.

The quotient is the result which is derived by the division of two numbers.

For example, the quotient of 30 divided by 3 is 10.

The product is the multiplication of two numbers which is written as a*b.

For example, the product of 8 and 9 is 72.

Here given we have to calculate the product of 7 and the quotient of 40 divided by 5.

The quotient of 40 divided by 5 is 40/5= 8

The product of 7 and The quotient of 40 divided by 5= 7*8= 56

Therefore the product of 7 and the quotient of 40 divided by 5 is 56.

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Explanation:

Cut the x coefficient (10) in half to get 10/2 = 5. Then square this to get 5^2 = 25.

We'll add 1 to both sides so that the "24" turns into "25", thereby completing the square

x^2 + 10x + 24 = 0

x^2 + 10x + 24+1 = 0+1

x^2 + 10x + 25 = 1

Notice on the left hand side we have something of the form A^2+2AB+B^2 where A = x and B = 5. We can factor this into (A+B)^2, which is the whole reason why we completed the square. You can use the FOIL rule to see how (A+B)^2 expands out into A^2+2AB+B^2. Factoring reverses this process.

This means x^2+10x+25 factors to (x+5)^2 and we now have these steps

(x+5)^2 = 1

x+5 = sqrt(1) or x+5 = -sqrt(1)

x+5 = 1 or x+5 = -1

x = 1-5 or x = -1-5

x = -4 or x = -6 are the two solutions

------------------

Let's check x = -4 to see if it works or not

x^2 + 10x + 24 = 0

(-4)^2 + 10(-4) + 24 = 0

16 - 40 + 24 = 0

-24 + 24 = 0

0 = 0

We get a true equation. That confirms x = -4 is a solution.

If we tried x = -6, then,

x^2 + 10x + 24 = 0

(-6)^2 + 10(-6) + 24 = 0

36 - 60 + 24 = 0

-24 + 24 = 0

0 = 0

That x value is confirmed as well.

If two parallel lines are intersected by a transversal, then internal opposite angles are equal.

So, x° = 61°

=> x = 60

Because they are internal opposite angles.

9514 1404 393

Answer:

  g(x) = 7x -1

Step-by-step explanation:

The y-coordinate of a function tells how many units the function value lies above the x-axis. Translating that value down 4 units is the same as subtracting 4 from the function value.

  g(x) = f(x) -4

  g(x) = 7x +3 -4

  g(x) = 7x -1

Answer:

Hello

Step-by-step explanation:

Axis of symmetry is vertical:

x=-7 (since (-7,-3) is the vertex)

Answer:

x = -7

Step-by-step explanation:

y = (x+7)^2 -3

This is in vertex form

y =a(x-h)^2+k  where (h,k) is the vertex and the line of symmetry for a vertical parabola is x=h

y = (x- -7)^2 -3

x = -7

Answer:

Step-by-step explanation:

Step 1

Find the height:

Step 2

Find the area:

Answer:

Step-by-step explanation:

To solve this divide the amount of sugar by the number of dollars:

Per 10dollar she brought=19pounds

Per dollar

[tex]\\ \sf\longmapsto \dfrac{19}{10}[/tex]

[tex]\\ \sf\longmapsto 1.9pounds[/tex]

Answer:

they are not similar. their one angle is only equal

Answer:

14.32

Step-by-step explanation:

Since this is a right triangle, we can us the Pythagorean theorem

a^2 + b^2 = c^2

3^2 + 14^2 = JL ^2

9+196 = JL ^2

205 = JL ^2

Taking the square root of each side

sqrt(205) = JL

14.31782106 = JL

To 2 decimal places

14.32

If a ★ b = 0.5ab, then

0.1 ★ b = 0.5 (0.1) b = 0.05b = 10

==>   b = 10/0.05 = 200

Answer:

[tex]\frac{dy}{dx}[/tex] = 2x + 3

Step-by-step explanation:

Differentiate each term using the power rule

[tex]\frac{d}{dx}[/tex] (a[tex]x^{n}[/tex] ) = na[tex]x^{n-1}[/tex]

y = x² + 3x

[tex]\frac{dy}{dx}[/tex] = 2[tex]x^{(2-1)}[/tex] + 3[tex]x^{(1-1)}[/tex]

   =  2x + 3[tex]x^{0}[/tex]

   = 2x + 3

Answer:

23.5

Step-by-step explanation:

m∠Y = (m∠RTS - m∠VTX)/2

m∠Y = ((180 - m∠RTV) - (180 - m∠VTX))/2

m∠Y = ((180 - 95) - (180 - 142))/2

m∠Y = (85 - 38)/2

m∠Y = 47/2

m∠Y = 23.5

Answer:

a. (0,-5)

Step-by-step explanation:

Answer:

r=-11

Step-by-step explanation:

7r+2=5(r-4)

7r+2=5r-20

2r=-22

r=-11

Answer:

Below,...

Step-by-step explanation:

They are saying that if you add a odd number + a odd number than you'd get a even number,... odd + even = odd,... odd x even = even,... and so on,...

Hope it helps,... Chow!

Answer:

4x+y=-32

Step-by-step explanation:

given,

slope (m) = -4

point: (-8,0)

as we know the slope intercept form of the line is, y=mx+b, b=y-mx, now we put x=-8, y=0 to find b [because the point is given (-8,0) so it must satisfy the equation]

so,

b = 0-(-4)×(-8) = -32

y=mx+b

or, y=-4x-32

or, 4x+y=-32

(this is the standard form of the line)

Using the equation y - y1 = m(x - x1)

y - 0 = -4(x - (-8))

y = -4(x + 8)

y = -4x - 32