Answer:
Distance between Amber and Claire's house = 17.63 blocks
Step-by-step explanation:
In this graph three points are showing the locations of Amber's, Betsey's and Claire's houses.
Each unit on the graph represents 1 block.
Amber walks from her house to Claire's house, then on to Betsey's house.
We have to calculate the distance covered by Amber.
Since Distance from Claire's house to Betsey's house = 7 blocks = 7 units
and distance between Amber and Betsey's house = 8 blocks = 8 units
Now we will calculate the distance between Amber and Claire's house by Pythagoras theorem.
Distance² = 7² + 8² = 49 + 64 = 113
Distance = √113 units = 10.63 units
Therefore, total distance walked by Amber = 10.63 + 7 = 17.63 units = 17.63 blocks
Answer:
the answer might be 17. 63 because there are 7 blocks in between them so try that sorry if its wrong
(f⋅g) (x) = f(x) ⋅ g(x)
true
false**
Answer:
true
Step-by-step explanation:
(f×g)×x = f(x)×g(x)
Please answer of question num 20 and 21 only please
Answer:
Iam going to do question 21
Step-by-step explanation:
1/7*x=2
1/7x=2
x=2:1/7
x=2*7/1
x=14
Suppose U1 and U2 are i.i.d. Unif(0,1) withU1=0.1 and U2=0.8. Use the "cosine" version of Box-Muller to generate a single Nor(-1,4) random variate. Don't forget to use radians instead of degrees.
a. 0.326
b. 0.326
c. 0.663
d. 1.96
Answer:
0.663 ( c )
Step-by-step explanation:
U1 = 0.1 , U2 = 0.8
using the "cosine" version of Box-Muller to generate a single Nor(-1,4) random variable
first step : generate single obsⁿ from N ( -1,4 )
attached below is the detailed solution
Mr. Clinton went to the lumber company. He bought 6 boards at a cost of $4.12 per board and 5 pounds of nails at $0.78 per pound. What was the total cost for these items (not including tax)?
Answer:
djjdjdjdjdjdjdjdjdidi
$28.62 not including tax.
Which answers describe the shape below? Check all that apply.
A. Rectangle
B. Rhombus
C. Quadrilateral
D. Square
E. Parallelogram
F. Trapezoid
Answer:
E and C
Step-by-step explanation:
Suppose the sales (1000s of $) of a fast food restaurant are a linear function of the number of competing outlets within a 5 mile radius and the population (1000s of people) within a 1 mile radius. The regression equation quantifying this relation is (sales)
Answer:
[tex]Sales = 86.749[/tex]
Step-by-step explanation:
Given
[tex]Sales = 0.845*(competitors) + 5.79*(population) + 13.889[/tex]
[tex]Competitors = 4[/tex]
[tex]Population = 12000[/tex]
See comment for complete question
Required
The sales
We have:
[tex]Sales = 0.845*(competitors) + 5.79*(population) + 13.889[/tex]
Substitute values for competitors and population
[tex]Sales = 0.845*4 + 5.79*12 + 13.889[/tex]
[tex]Sales = 3.38 + 69.48 + 13.889[/tex]
[tex]Sales = 86.749[/tex]
how do we get 24 using 3,3,7 and7
Answer:
2 Answers. #1. +11. [3+(3/7)] times 7 is 24. DarkBlaze347 May 1, 2015. +5. Good job, DB! civonamzuk May 1, 2015.
35 Online Users.
Step-by-step explanation:
brainliest please and follow:D
What is the inverse of function f? f(x)=3-x/7
Answer:
[tex] {f}^{ - 1} (x) = \frac{x}{3} + \frac{7}{3} [/tex]
hence option d is the correct option.
Answer:
Option C is answer.
Step-by-step explanation:
Hey there!
Given;
f(x) = (3-x) /7
Let f(x) be "y".
y = (3-x) /7
Interchanging "x" and "y".
x = (3-y)/7
7x = 3-y
y = 3-7x
Therefore, f'(x) = 3-7x.
Hope it helps!
HELP ASAP! I don’t know how to solve this problem nor where to start. Can someone please help me out here?
===============================================
Explanation:
It might help to draw out the picture as shown below. The pool itself (just the water only) is the inner rectangle. The outer rectangle is the pool plus the border of those 1 by 1 tiles.
The pool is a rectangle 90 feet by 80 feet. If we add on the tiles, then we get a larger rectangle that is 90+2 = 92 feet by 80+2 = 82 feet.
We add on 2 since we're adding two copies of "1" on either side of each dimension.
The larger rectangle's area is 92*82 = 7544 square feet
The smaller rectangle's area is 90*80 = 7200 square feet
The difference in areas is 7544-7200 = 344 square feet.
Each 1 by 1 tile is of area 1*1 = 1 sq foot, meaning that 344 tiles will get us the 344 square foot border around the pool.
Question:
which is a y-intercept of the graphed function?
Answers:
A. (-9,0)
B. (-3,0)
C. (0,-9)
D. (0,-3)
Answer:
(0, -9)
Step-by-step explanation:
The y intercept is the y value when x =0
(0, -9)
1 point
Use log10 3-0.4771; log10 5 0.699010810 7 0.8451; log10 11 1.0414 to approximate the value of each expression-
log10 14710910 (147)
Answer:
[tex]\log_{10}(147) = 2.1673[/tex]
Step-by-step explanation:
Given
[tex]\log_{10} 3 = 0.4771[/tex]
[tex]\log_{10} 5 = 0.6990[/tex]
[tex]\log_{10} 7= 0.8451[/tex]
[tex]\log_{10} 11 = 1.0414[/tex]
Required
Evaluate [tex]\log_{10}(147)[/tex]
Expand
[tex]\log_{10}(147) = \log_{10}(49 * 3)[/tex]
Further expand
[tex]\log_{10}(147) = \log_{10}(7 * 7 * 3)[/tex]
Apply product rule of logarithm
[tex]\log_{10}(147) = \log_{10}(7) + \log_{10}(7) + \log_{10}(3)[/tex]
Substitute values for log(7) and log(3)
[tex]\log_{10}(147) = 0.8451 + 0.8451 + 0.4771[/tex]
[tex]\log_{10}(147) = 2.1673[/tex]
Hi Friends!
please help me with these questions !
Answer/Step-by-step explanation:
2. a. 5y - 3 = -18
Add 3 to both sides
5y - 3 + 3 = -18 + 3
5y = -15
Divide both sides by 5
5y/5 = -15/5
y = -3
b. -3x - 9 = 0
Add 9 to both sides
-3x - 9 + 9 = 0 + 9
-3x = 9
Divide both sides by -3
-3x/-3 = 9/-3
x = -3
c. 4 + 3(z - 8) = -23
Apply the distributive property to open the bracket
4 + 3z - 24 = -23
Add like terms
3z - 20 = -23
Add 20 to both sides
3z - 20 + 20 = - 23 + 20
3z = -3
Divide both sides by 3
3z/3 = -3/3
z = -1
d. 1 - 2(y - 4) = 5
1 - 2y + 8 = 5
-2y + 9 = 5
-2y + 9 - 9 = 5 - 9
-2y = -4
-2y/-2 = -4/-2
y = 2
3. First, find the sum of 3pq + 5p²q² + p³ and p³ - pq
(3pq + 5p²q² + p³) + (p³ - pq)
3pq + 5p²q² + p³ + p³ - pq
Add like terms
= 3pq - pq + 5p²q² + p³ + p³
= 2pq + 5p²q² + 2p³
Next, subtract 2pq + 5p²q² + 2p³ from 3p³ - 2p²q² + 4pq
(3p³ - 2p²q² + 4pq) - (2pq + 5p²q² + 2p³)
Apply distributive property to open the bracket
3p³ - 2p²q² + 4pq - 2pq - 5p²q² - 2p³
Add like terms
3p³ - 2p³ - 2p²q² - 5p²q² + 4pq - 2pq
= p³ - 7p²q² + 2pq
4. Perimeter of the rectangle = sum of all its sides
Perimeter = 2(L + B)
L = (5x - y)
B = 2(x + y)
Perimeter = 2[(5x - y) + 2(x + y)]
Perimeter = 2[5x - y + 2x + 2y]
Add like terms
Perimeter = 2(7x + y)
Substitute x = 1 and y = 2 into the equation
Perimeter = 2(7(1) + 2)
Perimeter = 2(7 + 2)
Perimeter = 2(9)
Perimeter = 18 units
5. First let's find the quotient to justify if the value we get is greater than or less than 2.25
7⅙ ÷ 3⅛
Convert to improper fraction
43/6 ÷ 25/8
Change the operation sign to multiplication and turn the fraction by the left upside down.
43/6 × 8/25
= (43 × 8)/(6 × 25)
= (43 × 4)/(3 × 25)
= 172/75
≈ 2.29
Therefore, the quotient of 7⅙ ÷ 3⅛ is greater than 2.25
Helppp and explain!!!!!!!!!!!!!
Answer:
6x -15
Step-by-step explanation:
plug in gx for x in fx. So you have 2(3x-9) + 3
one number is seven less than the second number. five times the first is 9 more than 6 times the second. find the numbers
Step-by-step explanation:
2nd number = x
1st number = x - 7
5 (x - 7) = 6x + 9
5x - 35 = 6x + 9
- x = 44
x = - 44
1st number = -51
2nd number = -44
Proof: 5 (-51) = 6(-44) + 9
-255 = -264 + 9
-255 = -255
hope it helps.
Also, I think that Brainly is an awesome app, but there's an app which is doing great work for me in maths, named Gauthmath. I will suggest it. Video concepts and answers from real tutors.
Help please!!!!!!!!!!!
Answer:
y = 14
Step-by-step explanation:
[tex] \frac{15}{21} = \frac{5}{7} [/tex]
[tex] \frac{10}{x} = \frac{5}{7} [/tex]
[tex]x = 14[/tex]
Now,
10/15 = y/21
15y = 10*21
y = 210/15
y = 14
This is a Right answer...
I hope you understand..
Mark me as brainliest...
How would I solve the 4 questions on the picture?
Answer:
l don't know
Step-by-step explanation:
What is the true solution to the equation below?
l n e Superscript l n x Baseline + l n e Superscript l n x squared Baseline = 2 l n 8
x = 2
Given:
The equation is:
[tex]\ln e^{\ln x}+\ln e^{\ln x^2}=2\ln 8[/tex]
To find:
The solution for the given equation.
Solution:
We have,
[tex]\ln e^{\ln x}+\ln e^{\ln x^2}=2\ln 8[/tex]
It can be written as:
[tex]\ln x+\ln x^2=2\ln 8[/tex] [tex][\because \ln e^x=x][/tex]
[tex]\ln (x\cdot x^2)=2\ln 8[/tex] [tex][\because \ln a+\ln b=\ln (ab)][/tex]
[tex]\ln (x^3)=\ln 8^2[/tex] [tex][\because \ln x^n=n\ln x ][/tex]
On comparing both sides, we get
[tex]x^3=8^2[/tex]
[tex]x^3=64[/tex]
Taking cube root, we get
[tex]x=\sqrt[3]{64}[/tex]
[tex]x=4[/tex]
Therefore, the required solution is [tex]x=4[/tex].
Answer:
x=4
Step-by-step explanation:
What is the true solution to the equation below?
ln e Superscript ln x Baseline + ln e Superscript ln x squared Baseline = 2 ln 8
x = 2
x = 4
x = 8
Assume the population is bell-shaped. Between what two values will approximately 95% of the population be
Answer:The 95% Rule states that approximately 95% of observations fall within two ... about 95% will be within two standard deviations of the mean, and about 99.7% will be ... Suppose the pulse rates of 200 college men are bell-shaped with a mean of 72 ... 1.2 - Samples & Populations ... 3.5 - Relations between Multiple Variables.
Step-by-step explanation:
The circle P has a center at (0, 0) and a point on the circle at (0, 4). If it is dilated by a factor of 4, what is the distance of the diameter for circle P’.
A. 32
B. 4
C. 8
D. 16
Answer:
A. 32
Step-by-step explanation:
If the center is (0, 0) and a point is (0, 4) then the distance from the center to that point is 4 units. That distance is the radius. If you are dilating by a factor of 4, multiply the radius by 4 and you get 16. The new radius is 16 and the diameter= radius*2.
16*2=32
emir is standing in a treehouse in looking down at a swing set in the yard next-door. The angle of depression from emir’s Highline to the swingset is 31.43°, and emir is 11 feet from the ground. How many feet is the base of the tree from the swing set
Answer:
18 feet
Step-by-step explanation:
The question is illustrated using the attached image.
From the image, we have:
[tex]\theta = 31.43^o[/tex] --- angle of depression
[tex]h = 11ft[/tex] --- Emir's height
Required
The distance from the base of the tree (x)
From the attached triangle, we have:
[tex]\tan(90 - \theta) = \frac{Opposite}{Adjacent}[/tex]
This gives:
[tex]\tan(90 - 31.43) = \frac{x}{11}[/tex]
[tex]\tan(58.57) = \frac{x}{11}[/tex]
Make x the subject
[tex]x = 11 * \tan(58.57)[/tex]
[tex]x = 18.00[/tex]
Answer:
18
Step-by-step explanation:
took the test
Round your answer to the nearest hundredth.
3
А
с
?
8
B
HELP!!!
Answer:
Step-by-step explanation:
This appears to be an SSA application of solving the triangle
We have 2 sides, so we will use the law of cosines
The law of cosines defines for a triangle ABC with side a/b/c with corresponding angles A/B/C
a^2 = b^2+c^2 - 2*b*c * (cos A)
this applies to the other 2 sides
first using the pythagorean theorem we find that BC = sqrt(55)
then we substitute all 3 sides into our equation to find angle A
55 = 64 + 9 - 2*8*3* (cos A)
18 = 2*8*3(cos A)
3/8 = (cos A)
and angle A is approximately 68 degrees
Please check if I'm correct
Answer:
67.98°
Step-by-step explanation:
Given 2 sides, you can find the missing angle of a right triangle using basic trig functions.
Since Cos∅=adjacent/ hypotenuse, we can use the adjacent side to the angle, 3 and they hypotenuse, 8 in the ratio by doing 3/8. This is 0.375. Then we use the inverse cosine function to find the angle. This gives 67.98°
Or
Cos∅=0.375
Cos^-1= 67.98
What is the general form of the equation for the given circle centered at [0, 0)?
Answer:
x^2+y^2=r^2 is quation of circle whose centre is (0,0)
why was it difficult for the woman to cross the road
For P = {5, 12, 13, 14), Q = {2, 7, 11), and R = {4, 7, 8, 11}, find PU (Q n R).
Answer:
(5 7 11 12 13 14)
Step-by-step explanation:
Q inter R = 7 and 11
So the union between p and 7 and 11 is the answer above
How would I simplify the expressions on the picture?
Answer:
7. [tex]x^{11}[/tex] 8. [tex]y^{2}\\[/tex] 9. [tex]p^{12}[/tex] 10.[tex]a^{3} b^{2}[/tex] 11.[tex]g^{16}[/tex] 12.[tex]r^{9} h^{3}[/tex] 13.[tex]m^{15} p^{6}[/tex] 14.[tex]k^{6} y[/tex] 15.[tex]x^6 z^4[/tex]
Step-by-step explanation:
7. [tex]x^3[/tex] × [tex]x^8[/tex] = [tex]x^{11}[/tex] when multiplying with exponents you add
8. [tex]\frac{y^{6} }{y^{4} }[/tex] = [tex]y^{2}[/tex] when dividing with exponents you subtract
9. [tex](p^{3})^4[/tex] = [tex]p^{12}\\[/tex] when it's power to power, you multiply
10. [tex]\frac{a^{9} b^{4}}{a^{6} b^{2}}[/tex] = [tex]a^{3} b^{2}[/tex] (subtract exponents)
11. [tex](g^{8})^2[/tex] = [tex]g^{16}[/tex] (multiply exponents)
12. [tex]r^{4} h^{2} r^{5} h[/tex] = [tex]r^{9} h^{3}[/tex] (add exponents [tex]r^4 + r^5\\[/tex] and [tex]h^2 +h^1\\[/tex] )
13. [tex](m^{5} p^{2})^3[/tex] = [tex]m^{15} p^{6}[/tex] (multiply exponents)
14. [tex]\frac{k^{7} y^{4}}{y^{3}k}[/tex] = [tex]k^{6} y[/tex] (subtract exponents [tex]k^7-k^1[/tex] and [tex]y^4-y^3\\[/tex] )
15. [tex]x^3 z^2 x^3 z^2[/tex] = [tex]x^6 z^4[/tex] (add exponents same as #12)
the campus bookshop sells exercise books and textbooks, where, the total cost of 10 exercise books and 2 textbooks is $1400.00. One also finds the total cost of 3 textbooks and 30 exercise books is $3000. Then determine the price of 1 exercise book?
Answer:
The price of 1 exercise book is $122.45.
Step-by-step explanation:
This question is solved using a system of equations.
I am going to say that:
x is the price of one exercise book.
y is the price of one textbook.
Total cost of 10 exercise books and 2 textbooks is $1400.00.
This means that:
[tex]10x + 2y = 1400[/tex]
Since we want x:
[tex]2y = 1400 - 10x[/tex]
[tex]y = 700 - 5x[/tex]
One also finds the total cost of 3 textbooks and 30 exercise books is $3000.
This means that:
[tex]3x + 30y = 3000[/tex]
Since [tex]y = 700 - 5x[/tex]
[tex]3x + 30(700 - 5x) = 3000[/tex]
[tex]3x + 21000 - 150x = 3000[/tex]
[tex]147x = 18000[/tex]
[tex]x = \frac{18000}{147}[/tex]
[tex]x = 122.45[/tex]
The price of 1 exercise book is $122.45.
calculate limits x>-infinity
-2x^5-3x+1
Given:
The limit problem is:
[tex]\lim_{x\to -\infty}(-2x^5-3x+1)[/tex]
To find:
The value of the given limit problem.
Solution:
We have,
[tex]\lim_{x\to -\infty}(-2x^5-3x+1)[/tex]
In the function [tex]-2x^5-3x+1[/tex], the degree of the polynomial is 5, which is an odd number and the leading coefficient is -2, which is a negative number.
So, the function approaches to positive infinity as x approaches to negative infinity.
[tex]\lim_{x\to -\infty}(-2x^5-3x+1)=\infty[/tex]
Therefore, [tex]\lim_{x\to -\infty}(-2x^5-3x+1)=\infty[/tex].
The owner of a busy coffee shop wanted to see if it was worth keeping tea on the menu. She logged the number of cups of tea she sold each day for seven days.
6 12 5 7 7 3 9
Calculate the mean, median, range, and midrange of the number of cups of tea sold for the week.
Answer:
mean = 7
median = 7
range = 9
mid range = 7.5
Step-by-step explanation:
3, 5, 6, 7, 7, 9, 12
Range is the difference between the highest and lowest values of a set of observations
Range = highest value - lowest value
12 - 3 = 9
Median can be described as the number that occurs in the middle of a set of numbers that are arranged either in ascending or descending order
3, 5, 6, 7, 7, 9, 12
median = 7
Mean is the average of a set of numbers. It is determined by adding the numbers together and dividing it by the total number
Mean = sum of the numbers / total number
(6 + 12 + 5 + 7+ 7 + 3 + 9) / 7 = 7
Mid range = (highest value + lowest value) / 2
(12 + 3) / 2 = 7.5
the shorter side of a rectangle is 60% of the longer side and the perimeter of the rectangle is 96 inches. find the side lengths
Answer:
Length of the rectangle:
[tex]x = \frac{4800}{106} = \frac{2400}{53} [/tex]
Breadth of the rectangle:
[tex]60\%(x) = \frac{60}{100} \times \frac{4800}{106} \: \: \: \: \: \: \: \: \: \: \: \\ =60 \times \frac{48}{106} \\ = \frac{2880}{106} [/tex]
Step-by-step explanation:
Longer side of the rectangle(length) = x
Shorter side of the rectangle(breadth) = (60%)x
Perimeter of the rectangle = 2(l+b) = 96 inches
Hence,
[tex]96 = 2(x + 60\%(x))[/tex]
[tex]96 = 2(x + \frac{6}{100 } x)[/tex]
[tex]96 = 2( \frac{100}{1 00} x + \frac{6}{100} x)[/tex]
[tex]96 = 2( \frac{106}{100} x)[/tex]
[tex]96 = \frac{106}{50} x[/tex]
[tex]96 \div \frac{106}{50} = x[/tex]
[tex]96 \times \frac{50}{106} = x[/tex]
[tex] \frac{4800}{106} = x[/tex]
Suppose 49% of American singers are Grammy award winners. If a random sample of size 502 is selected, what is the probability that the proportion of Grammy award winners will differ from the singers proportion by greater than 4%
Answer:
0.0726 = 7.26% probability that the proportion of Grammy award winners will differ from the singers proportion by greater than 4%
Step-by-step explanation:
To solve this question, we need to understand the normal probability distribution and the central limit theorem.
Normal Probability Distribution
Problems of normal distributions can be solved using the z-score formula.
In a set with mean [tex]\mu[/tex] and standard deviation [tex]\sigma[/tex], the z-score of a measure X is given by:
[tex]Z = \frac{X - \mu}{\sigma}[/tex]
The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the p-value, we get the probability that the value of the measure is greater than X.
Central Limit Theorem
The Central Limit Theorem establishes that, for a normally distributed random variable X, with mean [tex]\mu[/tex] and standard deviation [tex]\sigma[/tex], the sampling distribution of the sample means with size n can be approximated to a normal distribution with mean [tex]\mu[/tex] and standard deviation [tex]s = \frac{\sigma}{\sqrt{n}}[/tex].
For a skewed variable, the Central Limit Theorem can also be applied, as long as n is at least 30.
For a proportion p in a sample of size n, the sampling distribution of the sample proportion will be approximately normal with mean [tex]\mu = p[/tex] and standard deviation [tex]s = \sqrt{\frac{p(1-p)}{n}}[/tex]
Suppose 49% of American singers are Grammy award winners.
This means that [tex]p = 0.49[/tex]
Sample of size 502
This means that [tex]n = 502[/tex]
Mean and standard deviation:
[tex]\mu = p = 0.49[/tex]
[tex]s = \sqrt{\frac{p(1-p)}{n}} = \sqrt{\frac{0.49*0.51}{502}} = 0.0223[/tex]
What is the probability that the proportion of Grammy award winners will differ from the singers proportion by greater than 4%?
Proportion below 49% - 4% = 45% or above 49% + 4% = 53%. Since the normal distribution is symmetric, these probabilities are equal, so we find one of them and multiply by 2.
Probability the proportion is below 45%
p-value of Z when X = 0.45. So
[tex]Z = \frac{X - \mu}{\sigma}[/tex]
By the Central Limit Theorem
[tex]Z = \frac{X - \mu}{s}[/tex]
[tex]Z = \frac{0.45 - 0.49}{0.0223}[/tex]
[tex]Z = -1.79[/tex]
[tex]Z = -1.79[/tex] has a p-value of 0.0363.
2*0.0363 = 0.0726
0.0726 = 7.26% probability that the proportion of Grammy award winners will differ from the singers proportion by greater than 4%