Answer:
16974J of energy are required
Explanation:
The energy required is:
* The energy to heat solid water from -15°C to 0°C using:
q = m*S*ΔT
* The energy to convert the solid water to liquid water:
q = dH*m
* The energy required to increase the temperature of liquid water from 0°C to 75°C
q = m*S*ΔT
The first energy is:
q = m*S*ΔT
m = Mass water = 25g
S is specific heat of ice = 2.03J/g°C
ΔT is change in temperature = 0°C - (-15°C) = 15°C
q = 25g*2.03J/g°C*15°C
q = 761.3J
The second energy is:
q = dH*m
m = Mass water = 25g
dH is heat of fusion of water = 80cal/g
q = 80cal/g*25g
q = 2000cal * (4.184J/1cal) = 8368J
The third energy is:
q = m*S*ΔT
m = Mass water = 25g
S is specific heat of water= 4.184J/g°C
ΔT is change in temperature = 75°C-0°C = 75°C
q = 25g*4.184J/g°C*75°C
q = 7845J
The energy is: 7845J + 8368J + 761J =
16974J of energy are required
What must happen for ice to melt at a given pressure?
A. The average kinetic energy of the water molecules must decrease.
B. Thermal energy must be transferred to the ice from its
surroundings.
C. The orderliness of the water molecules must decrease.
D. Thermal energy must be transferred from the ice to its
surroundings.
Answer:
D
Explanation:
thermal energy must be transferred from the ice to it's surroundings
Thermal energy is the heat and energy present in the system. The thermal energy must be dissipated from ice to the surroundings to melt and produce liquid. Thus, option D is correct.
What is thermal energy?Thermal energy is present in any substance in the form of energy and heat that depends on kinetic energy, orderliness, randomness, temperature, etc. It is passed from a substance to the surrounding at a lesser temperature.
The ice can melt into a liquid when it loses its thermal energy and heat to the surrounding with increased kinetic energy and releases the temperature to the area with a temperature less than the ice.
Therefore, the heat from ice will get dissipated to the outer environment to melt.
Learn more about thermal energy here:
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Convert speed of 581 miles an hour to units of feet per minute Also so the unit analysis by dragging components into the unit factor factor's
Explanation:
answer is in photo above
What is the price coke difference between a strong and weak acid?
Explanation:
Strong acids are those that are completely ionized in body fluids, and weak acids are those that are incompletely ionized in body fluids. Hydrochloric acid (HCl) is considered a strong acid because it is present only in a completely ionized form in the body, whereas carbonic acid (H2 CO3) is a weak acid because it is ionized incompletely, and, at equilibrium, all three reactants are present in body fluids. See the reactions below.
H2 CO3 (acid)↔H+ + HCO3- (base)
MAY IT HELPS U MATE ☃️☃️
Look at this picture.
Which process in the water cycle is shown in the picture?
evaporation
transpiration
condensation
precipitation
Answer:
condensation
Explanation:
the water has condensed from the gaseous form into rain drops
Answer:
precipitation
Explanation:
Molecule contains carbon, hydrogen and sulfur atoms. When a sample of 0.535g of this compound is burnt in oxygen, 1.119 g of CO2and 0.229 gof H2O and 0.407g of SO2are obtained.
Calculate its empirical formula.
Answer:
The empirical formula is, C4H4S
Explanation:
Number of moles of carbon = 1.119 g/ 44g/mol = 0.025 moles
Mass of Carbon= 0.025 moles × 12 g/ mole = 0.3 g
Number of moles of hydrogen = 0.229/18g/mol × 2 = 0.025 moles
Mass of hydrogen = 0.025 moles × 1 = 0.025 g
Number of moles of sulphur = 0.407g/ 64 g/mol = 0.0064 moles
Mass of sulphur= 0.0064 moles ×32 = 0.2 g
Now we obtain the mole ratios by dividing through by the lowest ratio.
C- 0.025 moles/ 0.0064 moles, H- 0.025 moles/ 0.0064 moles, S- 0.0064 moles/0.0064 moles
C4H4S
A diver exhales a bubble with volume of 250 mL at pressure of 2.4 atm and temperature of 15 C. How many gas particulate in this bubble?
Answer:
1.5x10²² particulates
Explanation:
Assuming ideal behaviour, we can solve this problem by using the PV=nRT formula, where:
P = 2.4 atmV = 250 mL ⇒ 250 / 1000 = 0.250 Ln = ?R = 0.082 atm·L·mol⁻¹·K⁻¹T = 15 °C ⇒ 15 + 273 = 288 KWe input the given data:
2.4 atm * 0.250 L = n * 0.082 atm·L·mol⁻¹·K⁻¹ * 288 KAnd solve for n:
n = 0.025 molFinally we calculate how many particulates are there in 0.025 moles, using Avogadro's number:
0.025 mol * 6.023x10²³ particulates/mol = 1.5x10²² particulatesWhat is erosion?
A) Weathered materials staying in one place
B) The movement of weathered materials by wind, water or ice
C) New materials on a land form
Answer:
B. The movement of weathered materials by wind, water or ice.
You are an intermediate product of an industrial process which intends to separate iron from its ore. A well known iron ore is hematite. Which of these ores does not contain iron?
Goethite
Malachite
Siderite
Limonite
Answer:
Malachite
Explanation:
Malachite is a copper carbonate hydroxide mineral, with the equation Cu2CO3(OH)2. This dark, green-joined mineral solidifies in the monoclinic precious stone framework, and frequently shapes botryoidal, sinewy, or stalagmitic masses, in cracks and profound, underground spaces, where the water table and aqueous liquids give the way to synthetic precipitation. So, the answer is malachite. Best of Luck!
Emily spills concentrated sodium hydroxide solution on her lab bench. What she should do first?
Answer:
Explanation: hell noo
1. Determine the volume of SO2 (at STP) formed from the reaction of 96.7 mol FeS2 and 55.0 L of O2 at 358 K and 1.20 atm.
4 FeS2(s) + 11O2(g) 2Fe2O3(s) + 8SO2(g)
Answer:
40.0L of SO2 are produced
Explanation:
To solve this question we need to find the moles of O2 using PV = nRT in order to find the moles. Thus, we can find the limiting reactant and the moles (And volume) of SO2 produced as follows:
Moles O2:
n = PV/RT
n = 1.20atm*55.0L / 0.082atmL/molK*358K
n = 2.25 moles of O2.
Clearly, limiting reactant is O2.
The moles of SO2 produced are:
2.25 moles of O2 * (8mol SO2 / 11mol O2) = 1.6351 moles SO2
Volume SO2:
V = nRT/P
V = 1.6351 moles SO2*0.082atmL/molK*358K / 1.20atm
V = 40.0L of SO2 are produced
Air bags are activated when a severe impact causes a steel ball to compress a spring and electrically ignite a detonator cap. This causes sodium azide (NaN3) to decompose explosively according to the following reaction. 2 NaN3(s) --> 2 Na(s) 3 N2(g) What mass in grams of NaN3(s) must be reacted in order to inflate an air bag to 79.5 L at STP
Answer:
154 g
Explanation:
Step 1: Write the balanced decomposition equation
2 NaN₃(s) ⇒ 2 Na(s) + 3 N₂(g)
Step 2: Calculate the moles corresponding to 79.5 L of N₂ at STP
At STP, 1 mole of N₂ occupies 22.4 L.
79.5 L × 1 mol/22.4 L = 3.55 mol
Step 3: Calculate the number of moles of NaN₃ needed to form 3.55 moles of N₂
The molar ratio of NaN₃ to N₂ is 2:3. The moles of NaN₃ needed are 2/3 × 3.55 mol = 2.37 mol.
Step 4: Calculate the mass corresponding to 2.37 moles of NaN₃
The molar mass of NaN₃ is 65.01 g/mol.
2.37 mol × 65.01 g/mol = 154 g
identify the organ system pictured below and state two functions of this system in the body
Answer:
skeletal system
Explanation:
to create and fliter blood and provide frame-work to the human body and support
1 What direction do
molecules move in?
Answer:
The majority of the molecules move from higher to lower concentration, although there will be some that move from low to high. The overall (or net) movement is thus from high to low concentration.
hope this helps!<3
Identify the alkene obtained on dehydration of each of the following alcohols:
a. 3-Ethyl-3-pentanol
b. 1-Propanol
c. 2-Propanol
d. 2,3,3-Trimethyl-2-butanol
Answer:
Explanation:
The information below explains how dehydration of alcohol occurs to produce alkene.
Under the influence of a catalyst, alcohol dehydrates to produce an alkene and water. To produce alkene and water, the reaction eliminates the OH group from alcohol containing the carbon atom and the hydrogen atom from a neighboring carbon atom via the same molecule.
The –OH group in alcohol contribute two(2) electrons to H+ out from the acid reagent, resulting in the formation of an alkyloxonium ion. This ion serves as an excellent leaving group, allowing a carbocation to form. The nucleophile which acts as the deprotonated acid subsequently attacks and creates a double bond with the hydrogen next to the carbocation.
Over time, rocks break down into sediment by wind, water, ice, and/or gravity. This process is commonly referred to as
chemical change
Answer:
Explanation:
Chemical change
What volume in mL of 0.220 M HBr solution is required to produce 0.0130 moles of HBr?
Answer: A volume of 59 mL of 0.220 M HBr solution is required to produce 0.0130 moles of HBr.
Explanation:
Given: Moles = 0.0130 mol
Molarity = 0.220 M
Molarity is the number of moles of solute present in liter of a solution.
[tex]Molarity = \frac{moles}{volume (in L)}[/tex]
Substitute the values into above formula as follows.
[tex]Molarity = \frac{moles}{volume (in L)}\\0.220 M = \frac{0.0130 mol}{Volume (in L)}\\Volume (in L) = 0.059 L[/tex]
As 1 L = 1000 mL
So, 0.059 L = 59 mL
Thus, we can conclude that a volume of 59 mL of 0.220 M HBr solution is required to produce 0.0130 moles of HBr.
la. A man was traveling by sie is allowed a maximum of 20kg luggage. The man
weighing 3.5kg, 15kg.2kg and 15kg
Find the excess weight of his luggage.
Express the excess weight as a percentage of the maximum weight allowed
Answer: The excess weight of the luggage is 15.5 kg and its percentage is 77.5%
Explanation:
Given values:
Maximum amount of luggage allowed = 20 kg
Amount of luggage man is carrying = [3.5 + 15 + 2 + 15] kg = 35.5 kg
Excessive weight of the luggage carried = Amount of luggage carrying - Maximum amount of luggage allowed
Excessive weight of the luggage carried = [35.5 - 20] = 15.5 kg
To calculate the percentage of excess weight, we use the equation:
[tex]\% \text{excess weight}=\frac{\text{Excess weight carried}}{\text{Maximum allowed}}\times 100[/tex]
Putting values in above equation, we get:
[tex]\% \text{excess weight}=\frac{15.5kg}{20kg}\times 100\\\\\% \text{excess weight}=77.5%[/tex]
Hence, the excess weight of the luggage is 15.5 kg and its percentage is 77.5%
Calculate the number of representative particles of 0.0391 mol Neon gas.
i need help ASAP !
Answer:
2.35 × 10²² particles
Explanation:
To get the number of particles in a substance, we multiply the number of moles (n) of that substance by Avogadro's number (nA).
That is, we say;
number of atoms = n × 6.02 × 10²³
In this question, Neon gas is said to have 0.0391 moles. The number of atoms in that field.
number of particles = 0.0391 × 6.02 × 10²³
number of particles = 0.235 × 10²³
number of particles = 2.35 × 10²² particles
What is the molar mass of Na2SO4?
O A. 142.04 g/mol
O B. 71.05 g/mol
O c. 238.22 g/mol
O D. 94.04 g/mol
Answer: A. 142.04 g/mol
Explanation:
What is the mass (g) of 1.00 L water if the density is 1.000 g/mL.
Answer:
1000g
Explanation:
1 * 1000 = 1000
What is the total number of joules released when a 5.00-gram sample of water changes from liquid to solid a 0° C?
For each system listed in the first column of the table below, decide (if possible) whether the change described in the second column will increase in GPS of the system, decrease S, or leave S unchanged. If you don’t have enough information to decide, check the “not enough information“ button in the last column. Note for advanced students: you may assume ideal gas and ideal solution behavior.
Answer:
For each system listed in first column of the table below, decide (if possible) whether the change described in the second column will increase the entropy S of the system, decrease S , or leave S unchanged. If you don?t have enough information to decide, check the not enough information button in the last column
Read excerpt and answer 3 questions I’ll mark brainliest. Pls thank you
Answer:
please also share the excerpt
Explanation:
Thank you
An infant acetaminophen suspension contains 80 mg/0.80 mL suspension. The recommended dose is 15 mg/kg body weight.
How many milliliters of this suspension should be given to an infant weighing 13 lb.
Answer:
0.8853 mL
Explanation:
First we convert 13 lb to kg, keeping in mind that 1 lb = 0.454 kg:
13 lb * [tex]\frac{0.454kg}{1lb}[/tex] = 5.902 kgThen we calculate how many mg of acetaminophen should be given, using the recommended dose and infant mass:
15 mg/kg * 5.902 kg = 88.53 mgFinally we calculate the required mL of suspension, using its concentration:
88.53 mg ÷ (80 mg/0.80 mL) = 0.8853 mLWrite the structural formula for a primary, a secondary, and a tertiary constitutionally isomeric alcohol of the molecular formula C5H12O.
Answer:
The structures of all isomeric alcohols of molecular formula C5H12O along with their IUPAC names are as shown.
Their classification of primary, secondary, and tertiary alcohols are -
1-pentanol -
2-pentanol -
3-pentanol
2-methylbutan-1-ol
2-methylbutan-2-ol
3-methylbutan-2-ol
3-methylbutan-1-ol
2,2-dimethylpropanol
Calculate the molality of a 35.4 % (by mass) aqueous solution of phosphoric acid (H3PO4) (35.4 % means 35.4 g of H3PO4in 100 g of solution)
Answer:
3.6124 m/kg
Explanation:
Molality is calculated as moles of solute (mol) divided by kilogram of solvent (kg). Here, we can find these numbers by using the 35.4%, which gives us 35.4 g of H3PO4 and 100 g of solution to work with.
To go from grams to moles for the phosphoric acid, you need to find the molar mass of the compound or element and divide the grams of the compound or element by that molar mass.
Here, the molar mass for phosphoric acid is 97.9952 g/mol. The equation would look like this:
35.4 g x 1 mol / 97.9952 g = 0.3612422 mol
Next, the 100 g of solvent can easily be converted to 0.1 kg of solvent.
To find the molality, divide the moles of solute and kilograms of solution.
0.3612422 mol / 0.1 kg = 3.6124 m/kg
Use the following information to calculate the concentration, Ka and pka for an unknown monoprotic weak acid. (8 pts.) 20.00 mL
Volume of unknown weak acid used : 20.00 mL Total volume of 0.20 M NaOH required to reach the equivalence point: 18.50 mL Initial pH of the weak acid 2.87
Answer:
Concentration: 0.185M HX
Ka = 9.836x10⁻⁶
pKa = 5.01
Explanation:
A weak acid, HX, reacts with NaOH as follows:
HX + NaOH → NaX + H2O
Where 1 mole of HX reacts with 1 mole of NaOH
To solve this question we need to find the moles of NaOH at equivalence point (Were moles HX = Moles NaOH).
18.50mL = 0.01850L * (0.20mol / L) = 0.00370 moles NaOH = Moles HX
In 20.0mL = 0.0200L =
0.00370 moles HX / 0.0200L = 0.185M HX
The equilibrium of HX is:
HX(aq) ⇄ H⁺(aq) + X⁻(aq)
And Ka is defined as:
Ka = [H⁺] [X⁻] / [HX]
Where [H⁺] = [X⁻] because comes from the same equilibrium
As pH = 2.87, [H+] = 10^-pH = 1.349x10⁻³M
Replacing:
Ka = [H⁺] [H⁺] / [HX]
Ka = [1.349x10⁻³M]² / [0.185M]
Ka = 9.836x10⁻⁶
pKa = -log Ka
pKa = 5.01How much energy does an X-ray with an 8 nm (8 x 10-9m) wavelength have?
A. 1.99 x 10-25 J
B. 3.33 x 1016 J
C. 2.48 x 10-17 j
D. 8.28 x 10-26 J
Answer:
it would be option C
Explanation:
Speed of light = 3×10^8m/s
Planck's constant = 6.626×10^-34 Js
Wavelength = 8 x 10^-9 m
Energy = [(3×10^8) * (6.626×10^-34)] / 8 x 10^-9
Energy = [19.878×10^(8-34)] / 8 x 10^-9
Energy = 2.48475 × 10^(-26+9)
Energy = 2.48×10^-17 J
Please write the right question. I’ll mark as brainliest if it’s right
Answer:
The correct answer is - A. alkane and E. Branched.
Explanation:
Alkane is saturated hydrocarbons that are combined with a single bond they can be either linear, branched, or cyclic hydrocarbons. A branched-chain or branched compound is a compound that has alkyl groups bonded to its central carbon chain.
Branched alkanes contain only carbon atoms and hydrogen atoms bonded with these carbon atoms in different branches, with carbons connected to other carbons by single bonds only, but the molecules contain branches.
Wat are representative elements
Answer:
the representative elements are elements where the the s and p orbitals are filling. The transition elements are elements where the d orbitals (groups 3-11 on the periodic table) are filling, and the inner transition metals are the elements where the f orbitals are filling.
Explanation:
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